Does -p flag overwrite EXPOSE? - docker

I'm confused with the Docker doc's EXPOSE vs -p. Here's what I understand: EXPOSE serves for inter-container communication only and cannot be accessed from the outside.
But the developer guide writes "The EXPOSE instruction does not actually publish the port. It functions as a type of documentation between the person who builds the image and the person who runs the container, about which ports are intended to be published."
Does it mean that if I have EXPOSE as 8001 and -p as 8002, the -p flag will overwrite EXPOSE and the container will be published on 8002? I guess I'm confused by the word "publish".

The developer documentation you quoted is accurate, the EXPOSE entry in the Dockerfile is documentation from the developer creating the image to the users running the image.
If you use -P then docker will publish all exposed ports on the host (note that uppercase P, different from the lowercase option).
For container to container communication, you only need to be in the same docker network. Containers talk on the port the application is listening on directly, no exposing of ports or publishing to the host needed.
Publishing the port is done at runtime with the -p option and maps a port from the host to one in the container to make it available outside of docker. Exposing ports has no impact on publishing with -p, it's just documentation, and metadata in the image.

EXPOSE means that your container will be accessible inside docker network by this port
-p flag means all above but for your outside communication
For example:
EXPOSE 8001 - exposing inside docker network
-p 8002:8001 - making port from 8001 inside to 8002 outside

Related

What is the use of Expose in docker file for ASP.NET Core application [duplicate]

I'm experimenting with Dockerfiles, and I think I understand most of the logic. However, I don't see the difference between "exposing" and "publishing" a port in this context.
All the tutorials I have seen first include the EXPOSE command in the Dockerfile:
...
EXPOSE 8080
...
They then build an image from this Dockerfile:
$ docker build -t an_image - < Dockerfile
And then publish the same port as above when running the image:
$ docker run -d -p 8080 an_image
or publish all ports using
$ docker run -d -P an_image
What is the point of exposing a port in the Dockerfile, if it will be published anyway? Would there ever be a need to expose a port first, and not publish it later? Effectively, I would like to specify all the ports that I will use in the Dockerfile when creating the image, and then not bother with them again, running them simply with:
$ docker run -d an_image
Is this possible?
Basically, you have three (four) options:
Neither specify EXPOSE nor -p
Only specify EXPOSE
Specify EXPOSE and -p
Only specify -p which implicitly does EXPOSE
If you specify neither EXPOSE nor -p, the service in the container will only be accessible from inside the container itself.
If you EXPOSE a port, the service in the container is not accessible from outside Docker, but from inside other Docker containers. So this is good for inter-container communication.
If you EXPOSE and -p a port, the service in the container is accessible from anywhere, even outside Docker.
If you do -p, but do not EXPOSE, Docker does an implicit EXPOSE. This is because if a port is open to the public, it is automatically also open to other Docker containers. Hence -p includes EXPOSE. This is effectively same as 3).
The reason why both are separated is IMHO because:
choosing a host port depends on the host and hence does not belong to the Dockerfile (otherwise it would be depending on the host),
and often it's enough if a service in a container is accessible from other containers.
The documentation explicitly states:
The EXPOSE instruction exposes ports for use within links.
It also points you to how to link containers, which basically is the inter-container communication I talked about.
Short answer:
EXPOSE is a way of documenting
--publish (or -p) is a way of mapping a host port to a running container port
Notice below that:
EXPOSE is related to Dockerfiles ( documenting )
--publish is related to docker run ... ( execution / run-time )
Exposing and publishing ports
In Docker networking, there are two different mechanisms that directly involve network ports: exposing and publishing ports. This applies to the default bridge network and user-defined bridge networks.
You expose ports using the EXPOSE keyword in the Dockerfile or the --expose flag to docker run. Exposing ports is a way of documenting which ports are used, but does not actually map or open any ports. Exposing ports is optional.
You publish ports using the --publish or --publish-all flag to docker run. This tells Docker which ports to open on the container’s network interface. When a port is published, it is mapped to an available high-order port (higher than 30000) on the host machine, unless you specify the port to map to on the host machine at runtime. You cannot specify the port to map to on the host machine when you build the image (in the Dockerfile), because there is no way to guarantee that the port will be available on the host machine where you run the image.
from: Docker container networking
Update October 2019: the above piece of text is no longer in the docs but an archived version is here: docs.docker.com/v17.09/engine/userguide/networking/#exposing-and-publishing-ports
Maybe the current documentation is the below:
Published ports
By default, when you create a container, it does not publish any of its ports to the outside world. To make a port available to services outside of Docker, or to Docker containers which are not connected to the container's network, use the --publish or -p flag. This creates a firewall rule which maps a container port to a port on the Docker host.
and can be found here: docs.docker.com/config/containers/container-networking/#published-ports
Also,
EXPOSE
...The EXPOSE instruction does not actually publish the port. It functions as a type of documentation between the person who builds the image and the person who runs the container, about which ports are intended to be published.
from: Dockerfile reference
Service access when EXPOSE / --publish are not defined:
At #Golo Roden's answer it is stated that::
"If you do not specify any of those, the service in the container will not be accessible from anywhere except from inside the container itself."
Maybe that was the case at the time the answer was being written, but now it seems that even if you do not use EXPOSE or --publish, the host and other containers of the same network will be able to access a service you may start inside that container.
How to test this:
I've used the following Dockerfile. Basically, I start with ubuntu and install a tiny web-server:
FROM ubuntu
RUN apt-get update && apt-get install -y mini-httpd
I build the image as "testexpose" and run a new container with:
docker run --rm -it testexpose bash
Inside the container, I launch a few instances of mini-httpd:
root#fb8f7dd1322d:/# mini_httpd -p 80
root#fb8f7dd1322d:/# mini_httpd -p 8080
root#fb8f7dd1322d:/# mini_httpd -p 8090
I am then able to use curl from the host or other containers to fetch the home page of mini-httpd.
Further reading
Very detailed articles on the subject by Ivan Pepelnjak:
Exposed ports
Published ports
See the official documentation reference: https://docs.docker.com/engine/reference/builder/#expose
The EXPOSE allows you to define private (container) and public (host) ports to expose at image build time for when the container is running if you run the container with -P.
$ docker help run
...
-P, --publish-all Publish all exposed ports to random ports
...
The public port and protocol are optional, if not a public port is specified, a random port will be selected on host by docker to expose the specified container port on Dockerfile.
A good pratice is do not specify public port, because it limits only one container per host ( a second container will throw a port already in use ).
You can use -p in docker run to control what public port the exposed container ports will be connectable.
Anyway, If you do not use EXPOSE (with -P on docker run) nor -p, no ports will be exposed.
If you always use -p at docker run you do not need EXPOSE but if you use EXPOSE your docker run command may be more simple, EXPOSE can be useful if you don't care what port will be exposed on host, or if you are sure of only one container will be loaded.
You expose ports using the EXPOSE keyword in the Dockerfile or the
--expose flag to docker run. Exposing ports is a way of documenting which
ports are used, but does not actually map or open any ports. Exposing ports
is optional.
Source: github commit
Most people use docker compose with networks. The documentation states:
The Docker network feature supports creating networks without the need to expose ports within the network, for detailed information see the overview of this feature).
Which means that if you use networks for communication between containers you don't need to worry about exposing ports.
EXPOSE keyword lets owner to inform others that which ports are going to be used by the container mainly.
You can publish any port even if you don't specify the port in EXPOSE.
For example we create a Dockerfile with nginx image that exposes port 1234
FROM nginx:latest
EXPOSE 1234
and build it
docker build -t porttest .
And run it with publishing 80 port to localhost:80
docker run -p 80:80 porttest
When you go localhost:80, you will see nginx default page.
Nginx default page
expose - will only allow that specific port to connect with container and it will use as "inter container communication " only
-p ( publish ) will map the host port with container port ( which you have already exposed in step 1 or in docker file ) and once you expose it , you will need to map it so we use publish , it will then access container outside world/internet.
EXPOSE is used to map local port container port
ie : if you specify expose in docker file like
EXPOSE 8090
What will does it will map localhost port 8090 to container port 8090

Does docker EXPOSE refer to the container port or the host port?

The Dockerfile command EXPOSE and the docker run argument --expose tells docker that the port must be exposed.
When publishing ports with -p, you can map an outer host port to a different inner container port, e.g. docker run -p 8080:80, where 8080 is the host port and 80 is the container port.
My question is, does EXPOSE refer to the inner container port or the outer host port?
The EXPOSE instruction in a Dockerfile refers to the container port.
The EXPOSE instruction documents the port on which an application inside the container is expected to be listening. The important word there is "documents". It does not change the behavior of docker running your container, it does not publish the port, and does not impact the ability to connect between containers.
Whether or not you expose the port, you need to separately publish the port to access it from outside the container network. And whether or not you expose the port, you can connect between containers on the same docker network.
There are various tools that can use this image metadata to automatically discover your application. This includes the -P flag to publish all container ports on random high numbered host ports. You will also see reverse proxies (like traefik) use this when querying the docker engine to determine the default port to use for your container.
EXPOSE just means those exposed ports of this current container are available/exposed to all containers that are in the same network.
According to the documentation, the EXPOSE instruction informs Docker that the container listens on the specified network ports at runtime. So it refers to the inner container.
EXPOSE allow communication between the container and other containers in the same network. But it does not allow communication with the host machine, or containers in another network! In order to permit that, you need to publish the port, with -p option.

Docker and Neo4J

I'm trying to get a Neo4J database up and running in a docker container.
Currently i have it running by using the command:
docker run -d -p 7474:7474 -p 7687:7687 neo4j
.. and it's working fine.
I want to put it in a Dockerfile so i can do some server configuration, but when i use the Dockerfile, it does not expose the ports that i have set it to expose unless i explicitly expose them when i do "docker run":
FROM neo4j
ENV NEO4J_AUTH neo4j/password
EXPOSE 7474:7474
EXPOSE 7687:7687
Did i misunderstand something, or shouldn't the ports be exposed automatically with this configuration?
The EXPOSE instruction informs Docker that the container listens on
the specified network ports at runtime. EXPOSE does not make the ports
of the container accessible to the host. To do that, you must use
either the -p flag to publish a range of ports or the -P flag to
publish all of the exposed ports. You can expose one port number and
publish it externally under another number.
To set up port redirection on the host system, see using the -P flag.
The Docker network feature supports creating networks without the need
to expose ports within the network, for detailed information see the
overview of this feature).
https://docs.docker.com/engine/reference/builder/

is there a way to do bind particular port on host to container port using docker file

is there a way to do bind particular port on host to container port using docker file
I have following item in docker file
Step 1 : EXPOSE 8090:8080
but when i run docker run, container binds to port 8080 instead of 8090 as described in docker file.
any idea how i can achieve this using docker file or is there any better way to achieve this.
Can't see that docker implements the EXPOSE feature as You described it.
From the documentation:
EXPOSE
EXPOSE <port> [<port>...]
The EXPOSE instructions informs Docker that the container will listen on the specified network ports at runtime. Docker uses this information to interconnect containers using links (see the Docker User Guide).
EXPOSE isn't an equivalent for the vagrant forwarded_port functionality.
It's useful when You need to link containers.
If You need to forward a port from the container to the host use the -p flag.
Example:
docker run -it -p 80:80 5959f94a4d10 /bin/bash
is there a way to do bind particular port on host to container port using docker file
No. The Dockerfile is designed to include only portable configuration. Binding to a host port is not portable because the host port may not be available on every system. These configuration flags may be available at runtime, but are not included in the Dockerfile syntax (and resulting Docker images).
Under the hood, host ports and other non-portable configuration (e.g. volume mounts) are part of the HostConfig structure of the container. These are only available at container runtime.

What is the difference between "expose" and "publish" in Docker?

I'm experimenting with Dockerfiles, and I think I understand most of the logic. However, I don't see the difference between "exposing" and "publishing" a port in this context.
All the tutorials I have seen first include the EXPOSE command in the Dockerfile:
...
EXPOSE 8080
...
They then build an image from this Dockerfile:
$ docker build -t an_image - < Dockerfile
And then publish the same port as above when running the image:
$ docker run -d -p 8080 an_image
or publish all ports using
$ docker run -d -P an_image
What is the point of exposing a port in the Dockerfile, if it will be published anyway? Would there ever be a need to expose a port first, and not publish it later? Effectively, I would like to specify all the ports that I will use in the Dockerfile when creating the image, and then not bother with them again, running them simply with:
$ docker run -d an_image
Is this possible?
Basically, you have three (four) options:
Neither specify EXPOSE nor -p
Only specify EXPOSE
Specify EXPOSE and -p
Only specify -p which implicitly does EXPOSE
If you specify neither EXPOSE nor -p, the service in the container will only be accessible from inside the container itself.
If you EXPOSE a port, the service in the container is not accessible from outside Docker, but from inside other Docker containers. So this is good for inter-container communication.
If you EXPOSE and -p a port, the service in the container is accessible from anywhere, even outside Docker.
If you do -p, but do not EXPOSE, Docker does an implicit EXPOSE. This is because if a port is open to the public, it is automatically also open to other Docker containers. Hence -p includes EXPOSE. This is effectively same as 3).
The reason why both are separated is IMHO because:
choosing a host port depends on the host and hence does not belong to the Dockerfile (otherwise it would be depending on the host),
and often it's enough if a service in a container is accessible from other containers.
The documentation explicitly states:
The EXPOSE instruction exposes ports for use within links.
It also points you to how to link containers, which basically is the inter-container communication I talked about.
Short answer:
EXPOSE is a way of documenting
--publish (or -p) is a way of mapping a host port to a running container port
Notice below that:
EXPOSE is related to Dockerfiles ( documenting )
--publish is related to docker run ... ( execution / run-time )
Exposing and publishing ports
In Docker networking, there are two different mechanisms that directly involve network ports: exposing and publishing ports. This applies to the default bridge network and user-defined bridge networks.
You expose ports using the EXPOSE keyword in the Dockerfile or the --expose flag to docker run. Exposing ports is a way of documenting which ports are used, but does not actually map or open any ports. Exposing ports is optional.
You publish ports using the --publish or --publish-all flag to docker run. This tells Docker which ports to open on the container’s network interface. When a port is published, it is mapped to an available high-order port (higher than 30000) on the host machine, unless you specify the port to map to on the host machine at runtime. You cannot specify the port to map to on the host machine when you build the image (in the Dockerfile), because there is no way to guarantee that the port will be available on the host machine where you run the image.
from: Docker container networking
Update October 2019: the above piece of text is no longer in the docs but an archived version is here: docs.docker.com/v17.09/engine/userguide/networking/#exposing-and-publishing-ports
Maybe the current documentation is the below:
Published ports
By default, when you create a container, it does not publish any of its ports to the outside world. To make a port available to services outside of Docker, or to Docker containers which are not connected to the container's network, use the --publish or -p flag. This creates a firewall rule which maps a container port to a port on the Docker host.
and can be found here: docs.docker.com/config/containers/container-networking/#published-ports
Also,
EXPOSE
...The EXPOSE instruction does not actually publish the port. It functions as a type of documentation between the person who builds the image and the person who runs the container, about which ports are intended to be published.
from: Dockerfile reference
Service access when EXPOSE / --publish are not defined:
At #Golo Roden's answer it is stated that::
"If you do not specify any of those, the service in the container will not be accessible from anywhere except from inside the container itself."
Maybe that was the case at the time the answer was being written, but now it seems that even if you do not use EXPOSE or --publish, the host and other containers of the same network will be able to access a service you may start inside that container.
How to test this:
I've used the following Dockerfile. Basically, I start with ubuntu and install a tiny web-server:
FROM ubuntu
RUN apt-get update && apt-get install -y mini-httpd
I build the image as "testexpose" and run a new container with:
docker run --rm -it testexpose bash
Inside the container, I launch a few instances of mini-httpd:
root#fb8f7dd1322d:/# mini_httpd -p 80
root#fb8f7dd1322d:/# mini_httpd -p 8080
root#fb8f7dd1322d:/# mini_httpd -p 8090
I am then able to use curl from the host or other containers to fetch the home page of mini-httpd.
Further reading
Very detailed articles on the subject by Ivan Pepelnjak:
Exposed ports
Published ports
See the official documentation reference: https://docs.docker.com/engine/reference/builder/#expose
The EXPOSE allows you to define private (container) and public (host) ports to expose at image build time for when the container is running if you run the container with -P.
$ docker help run
...
-P, --publish-all Publish all exposed ports to random ports
...
The public port and protocol are optional, if not a public port is specified, a random port will be selected on host by docker to expose the specified container port on Dockerfile.
A good pratice is do not specify public port, because it limits only one container per host ( a second container will throw a port already in use ).
You can use -p in docker run to control what public port the exposed container ports will be connectable.
Anyway, If you do not use EXPOSE (with -P on docker run) nor -p, no ports will be exposed.
If you always use -p at docker run you do not need EXPOSE but if you use EXPOSE your docker run command may be more simple, EXPOSE can be useful if you don't care what port will be exposed on host, or if you are sure of only one container will be loaded.
You expose ports using the EXPOSE keyword in the Dockerfile or the
--expose flag to docker run. Exposing ports is a way of documenting which
ports are used, but does not actually map or open any ports. Exposing ports
is optional.
Source: github commit
Most people use docker compose with networks. The documentation states:
The Docker network feature supports creating networks without the need to expose ports within the network, for detailed information see the overview of this feature).
Which means that if you use networks for communication between containers you don't need to worry about exposing ports.
EXPOSE keyword lets owner to inform others that which ports are going to be used by the container mainly.
You can publish any port even if you don't specify the port in EXPOSE.
For example we create a Dockerfile with nginx image that exposes port 1234
FROM nginx:latest
EXPOSE 1234
and build it
docker build -t porttest .
And run it with publishing 80 port to localhost:80
docker run -p 80:80 porttest
When you go localhost:80, you will see nginx default page.
Nginx default page
expose - will only allow that specific port to connect with container and it will use as "inter container communication " only
-p ( publish ) will map the host port with container port ( which you have already exposed in step 1 or in docker file ) and once you expose it , you will need to map it so we use publish , it will then access container outside world/internet.
EXPOSE is used to map local port container port
ie : if you specify expose in docker file like
EXPOSE 8090
What will does it will map localhost port 8090 to container port 8090

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