How can you determine iPhone X Simulator programmatically? - ios

Question

I am trying to size my app for iPhone X and am having trouble.
Currently I define screen sizes like so:
#define IS_IPAD (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)
#define IS_IPHONE (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
#define IS_RETINA ([[UIScreen mainScreen] scale] >= 2.0)
#define SCREEN_WIDTH ([[UIScreen mainScreen] bounds].size.width)
#define SCREEN_HEIGHT ([[UIScreen mainScreen] bounds].size.height)
#define SCREEN_MAX_LENGTH (MAX(SCREEN_WIDTH, SCREEN_HEIGHT))
#define SCREEN_MIN_LENGTH (MIN(SCREEN_WIDTH, SCREEN_HEIGHT))
#define IS_IPHONE_4_OR_LESS (IS_IPHONE && SCREEN_MAX_LENGTH < 568.0)
#define IS_IPHONE_5 (IS_IPHONE && SCREEN_MAX_LENGTH == 568.0)
#define IS_IPHONE_6 (IS_IPHONE && SCREEN_MAX_LENGTH == 667.0)
#define IS_IPHONE_6P (IS_IPHONE && SCREEN_MAX_LENGTH == 736.0)
and constrain based on the phone type. (Yes i know not optimal but its what ive done)
When you use the iPhone X simulator, for some reason it reads its screen height and width like an iPhone 6.
So then I searched stack overflox and found this:
How to get device make and model on iOS?
Only issue is, when you run on the iPhone X simulator it returns x86-64 and not a device type!
I obviously dont have an iPhone X so how do I detect that this is an iPhone X Simulator and not an iPhone 6 (based on screen size) so I can constrain properly for this new phone!
Thank you people!

Answer 1

func modelIdentifier() -> String {
if let simulatorModelIdentifier = ProcessInfo().environment["SIMULATOR_MODEL_IDENTIFIER"] { return simulatorModelIdentifier }
var sysinfo = utsname()
uname(&sysinfo) // ignore return value
return String(bytes: Data(bytes: &sysinfo.machine, count: Int(_SYS_NAMELEN)), encoding: .ascii)!.trimmingCharacters(in: .controlCharacters)
}
from here
Objective-c:
- (NSString *)modelIdentifier {
NSString *simulatorModelIdentifier = [NSProcessInfo processInfo].environment[#"SIMULATOR_MODEL_IDENTIFIER"];
NSLog(#"%#",simulatorModelIdentifier);
if (simulatorModelIdentifier) {
return simulatorModelIdentifier;
}
struct utsname sysInfo;
uname(&sysInfo);
return [NSString stringWithCString:sysInfo.machine encoding:NSUTF8StringEncoding];
}
Don't forget:
#import <sys/utsname.h>
Use: (In viewDidLoad for example):
NSString *model = [self modelIdentifier];
NSLog(#"Device: %#", model);
If model is iPhone10,3, it is a iPhone X.

Answer 2

I don't recommend doing it this way, but if you must, the following code will return "iPhone10,3" or "iPhone10,6" for an iPhoneX.
NSString *GetHardwareName(void)
{
NSString *result = nil;
struct utsname platform;
if ( uname(&platform) == 0 )
{
if ( platform.machine[0] )
result = [NSString stringWithCString:platform.machine encoding:NSUTF8StringEncoding];
}
return result;
}

Answer 3

Hi you can use below micro to check iPhoneX size.
#define IS_IPHONE (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)
#define IS_IPHONE_4 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 480.0)
#define IS_IPHONE_5 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 568.0)
#define IS_IPHONE_6 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 667.0)
#define IS_IPHONE_6PLUS (IS_IPHONE && [[UIScreen mainScreen] nativeScale] == 3.0f)
#define IS_IPHONE_6_PLUS (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 736.0)
#define IS_IPHONE_X (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 812.0)
#define IS_RETINA ([[UIScreen mainScreen] scale] == 2.0)
#define IS_IPAD_DEVICE [(NSString*)[UIDevice currentDevice].model hasPrefix:#"iPad"]