Neural network implementation to produce a better estimation of the input - machine-learning

I have to configure a neural network where I do not have a real 'target dataset', but I would like to produce a better estimation of my input.
The input u is a function of 2 parameters:
u(a,b)=f(a)+g(b)
where f and g are linear functions.
I have as 'training dataset' values of 'u' for given a and b.
My aim is to produce a better estimation of this variable 'u' based on the fact that it should not exceed a maximum error.
Can someone help me with some idea on how to proceed? Should I consider unsupervised NN ?
Thanks for any kind of help!

Related

Do we understand the mathematics behind Neural Networks?

So I read somewhere that we as humans don't understand what exactly happens in a neural network, we just know that a neuron does something using the biases and the inputs given to it and leads us to a specific output.
My question here is, do we understand (mathematically speaking) how X input leads the computer to give Y input? If we don't, then why don't we understand it?
Let X be an input Matrix and Y be the associated output vector (our target). Let theta be the parameter of our model, representing the weights and the bias of each neuron.
Mathematically, a neural network can be represented as a function f such as f(X, theta) = Y + epsilon. Epsilon is the error of the model. The goal is to find the value of theta that is minimizing epsilon. To do so, we just have to find the global minimum of the multivariate function epsilon(theta) = f(X, theta) - Y. This is an optimization problem that can be solved thanks to gradient descent. So yes, mathematically, we understand how X input leads the computer to give output Y: it is just a matter of finding the minimum of a function. Additionally, as the structure of a neural network is quite simple (linear layers + activation functions), we are able to calculate easily the derivatives of epsilon() and propagate them throw the network.
However, it's not because we can explain mathematically a neural network that we can interpret it. It's very difficult to know the specific role played by each neuron in the prediction. In contrary, decision trees are much more interpretable, as we know which feature was used to make a split at each node of the tree.

Should I find regularization parameter or degree first for Support Vector Regression algorithm?

I am working on a problem to predict revenue generated by a film. I am using sklearn's support vector regression algorithm with polynomial kernel. I tried to find the degree which gives best accuracy using default value of regularization parameter. But, I got error percentage in the 7 digit range. So, I decided to increase variance, by tuning the regularization parameter.
So should I first assume a degree and find the regularization parameter which gives best result or vice versa? Or is there something else that I should consider?
Generally, doing a grid search with degree and regularization parameter is a common practice. There is some information about this is sklearn here:
https://scikit-learn.org/stable/modules/grid_search.html
This will allow you to make a dictionary of the kernels that you can try (rbf, poly, etc) and their respective hyperparameters and the regularization parameter and attempt to find the best one.

Output of the logit function as addtional input to a Neural Network

This is w.r.t a hybrid of ANN and logistic regression in a binary classification problem. For example in one of the papers I came across they state that "A hybrid model type is constructed by using the logistic regression model to calculate the probability of failure and then adding that value as an additional input variable into the ANN. This type of model is defined as a Plogit-ANN model".
So, for n input variables, I'm trying to understand how the additional input n+1 to a ANN is treated by the activation function (eg. a logit function) and in the summation of weights multiplied by inputs. Do we treat this probability variable n+1 as one of the standalone weights like a special type of b0 that we add in the sum of weights multiplied by inputs e.g. Summation for each Neuron = (Sum (Wi*Xi))+additional variable.
Thank you for your assistance.
According to the description provided the easiest way is to treat this as additional feature of your data. So you have a model that predicts something about your original dataset (probability of some additional thing), thus you get x -> f(x). You simply concatenate it to your feature vector so x' = [x1 x2 ... xk f(x)], and push it through the network.
However the described approach is quite naive, since you are doing these two things (training f and training neural net) completely independently), what might be more beneficial is to instead treat fitting f as an auxiliary loss and train your model jointly.

Can neural networks approximate any function given enough hidden neurons?

I understand neural networks with any number of hidden layers can approximate nonlinear functions, however, can it approximate:
f(x) = x^2
I can't think of how it could. It seems like a very obvious limitation of neural networks that can potentially limit what it can do. For example, because of this limitation, neural networks probably can't properly approximate many functions used in statistics like Exponential Moving Average, or even variance.
Speaking of moving average, can recurrent neural networks properly approximate that? I understand how a feedforward neural network or even a single linear neuron can output a moving average using the sliding window technique, but how would recurrent neural networks do it without X amount of hidden layers (X being the moving average size)?
Also, let us assume we don't know the original function f, which happens to get the average of the last 500 inputs, and then output a 1 if it's higher than 3, and 0 if it's not. But for a second, pretend we don't know that, it's a black box.
How would a recurrent neural network approximate that? We would first need to know how many timesteps it should have, which we don't. Perhaps a LSTM network could, but even then, what if it's not a simple moving average, it's an exponential moving average? I don't think even LSTM can do it.
Even worse still, what if f(x,x1) that we are trying to learn is simply
f(x,x1) = x * x1
That seems very simple and straightforward. Can a neural network learn it? I don't see how.
Am I missing something huge here or are machine learning algorithms extremely limited? Are there other learning techniques besides neural networks that can actually do any of this?
The key point to understand is compact:
Neural networks (as any other approximation structure like, polynomials, splines, or Radial Basis Functions) can approximate any continuous function only within a compact set.
In other words the theory states that, given:
A continuous function f(x),
A finite range for the input x, [a,b], and
A desired approximation accuracy ε>0,
then there exists a neural network that approximates f(x) with an approximation error less than ε, everywhere within [a,b].
Regarding your example of f(x) = x2, yes you can approximate it with a neural network within any finite range: [-1,1], [0, 1000], etc. To visualise this, imagine that you approximate f(x) within [-1,1] with a Step Function. Can you do it on paper? Note that if you make the steps narrow enough you can achieve any desired accuracy. The way neural networks approximate f(x) is not much different than this.
But again, there is no neural network (or any other approximation structure) with a finite number of parameters that can approximate f(x) = x2 for all x in [-∞, +∞].
The question is very legitimate and unfortunately many of the answers show how little practitioners seem to know about the theory of neural networks. The only rigorous theorem that exists about the ability of neural networks to approximate different kinds of functions is the Universal Approximation Theorem.
The UAT states that any continuous function on a compact domain can be approximated by a neural network with only one hidden layer provided the activation functions used are BOUNDED, continuous and monotonically increasing. Now, a finite sum of bounded functions is bounded by definition.
A polynomial is not bounded so the best we can do is provide a neural network approximation of that polynomial over a compact subset of R^n. Outside of this compact subset, the approximation will fail miserably as the polynomial will grow without bound. In other words, the neural network will work well on the training set but will not generalize!
The question is neither off-topic nor does it represent the OP's opinion.
I am not sure why there is such a visceral reaction, I think it is a legitimate question that is hard to find by googling it, even though I think it is widely appreciated and repeated outloud. I think in this case you are looking for the actually citations showing that a neural net can approximate any function. This recent paper explains it nicely, in my opinion. They also cite the original paper by Barron from 1993 that proved a less general result. The conclusion: a two-layer neural network can represent any bounded degree polynomial, under certain (seemingly non-restrictive) conditions.
Just in case the link does not work, it is called "Learning Polynomials with Neural Networks" by Andoni et al., 2014.
I understand neural networks with any number of hidden layers can approximate nonlinear functions, however, can it approximate:
f(x) = x^2
The only way I can make sense of that question is that you're talking about extrapolation. So e.g. given training samples in the range -1 < x < +1 can a neural network learn the right values for x > 100? Is that what you mean?
If you had prior knowledge, that the functions you're trying to approximate are likely to be low-order polynomials (or any other set of functions), then you could surely build a neural network that can represent these functions, and extrapolate x^2 everywhere.
If you don't have prior knowledge, things are a bit more difficult: There are infinitely many smooth functions that fit x^2 in the range -1..+1 perfectly, and there's no good reason why we would expect x^2 to give better predictions than any other function. In other words: If we had no prior knowledge about the function we're trying to learn, why would we want to learn x -> x^2? In the realm of artificial training sets, x^2 might be a likely function, but in the real world, it probably isn't.
To give an example: Let's say the temperature on Monday (t=0) is 0°, on Tuesday it's 1°, on Wednesday it's 4°. We have no reason to believe temperatures behave like low-order polynomials, so we wouldn't want to infer from that data that the temperature next Monday will probably be around 49°.
Also, let us assume we don't know the original function f, which happens to get the average of the last 500 inputs, and then output a 1 if it's higher than 3, and 0 if it's not. But for a second, pretend we don't know that, it's a black box.
How would a recurrent neural network approximate that?
I think that's two questions: First, can a neural network represent that function? I.e. is there a set of weights that would give exactly that behavior? It obviously depends on the network architecture, but I think we can come up with architectures that can represent (or at least closely approximate) this kind of function.
Question two: Can it learn this function, given enough training samples? Well, if your learning algorithm doesn't get stuck in a local minimum, sure: If you have enough training samples, any set of weights that doesn't approximate your function gives a training error greater that 0, while a set of weights that fit the function you're trying to learn has a training error=0. So if you find a global optimum, the network must fit the function.
A network can learn x|->x * x if it has a neuron that calculates x * x. Or more generally, a node that calculates x**p and learns p. These aren't commonly used, but the statement that "no neural network can learn..." is too strong.
A network with ReLUs and a linear output layer can learn x|->2*x, even on an unbounded range of x values. The error will be unbounded, but the proportional error will be bounded. Any function learnt by such a network is piecewise linear, and in particular asymptotically linear.
However, there is a risk with ReLUs: once a ReLU is off for all training examples it ceases learning. With a large domain, it will turn on for some possible test examples, and give an erroneous result. So ReLUs are only a good choice if test cases are likely to be within the convex hull of the training set. This is easier to guarantee if the dimensionality is low. One work around is to prefer LeakyReLU.
One other issue: how many neurons do you need to achieve the approximation you want? Each ReLU or LeakyReLU implements a single change of gradient. So the number needed depends on the maximum absolute value of the second differential of the objective function, divided by the maximum error to be tolerated.
There are theoretical limitations of Neural Networks. No neural network can ever learn the function f(x) = x*x
Nor can it learn an infinite number of other functions, unless you assume the impractical:
1- an infinite number of training examples
2- an infinite number of units
3- an infinite amount of time to converge
NNs are good in learning low-level pattern recognition problems (signals that in the end have some statistical pattern that can be represented by some "continuous" function!), but that's it!
No more!
Here's a hint:
Try to build a NN that takes n+1 data inputs (x0, x1, x2, ... xn) and it will return true (or 1) if (2 * x0) is in the rest of the sequence. And, good luck.
Infinite functions especially those that are recursive cannot be learned. They just are!

Estimating parameters in multivariate classification

Newbie here typesetting my question, so excuse me if this don't work.
I am trying to give a bayesian classifier for a multivariate classification problem where input is assumed to have multivariate normal distribution. I choose to use a discriminant function defined as log(likelihood * prior).
However, from the distribution,
$${f(x \mid\mu,\Sigma) = (2\pi)^{-Nd/2}\det(\Sigma)^{-N/2}exp[(-1/2)(x-\mu)'\Sigma^{-1}(x-\mu)]}$$
i encounter a term -log(det($S_i$)), where $S_i$ is my sample covariance matrix for a specific class i. Since my input actually represents a square image data, my $S_i$ discovers quite some correlation and resulting in det(S_i) being zero. Then my discriminant function all turn Inf, which is disastrous for me.
I know there must be a lot of things go wrong here, anyone willling to help me out?
UPDATE: Anyone can help how to get the formula working?
I do not analyze the concept, as it is not very clear to me what you are trying to accomplish here, and do not know the dataset, but regarding the problem with the covariance matrix:
The most obvious solution for data, where you need a covariance matrix and its determinant, and from numerical reasons it is not feasible is to use some kind of dimensionality reduction technique in order to capture the most informative dimensions and simply discard the rest. One such method is Principal Component Analysis (PCA), which applied to your data and truncated after for example 5-20 dimensions would yield the reduced covariance matrix with non-zero determinant.
PS. It may be a good idea to post this question on Cross Validated
Probably you do not have enough data to infer parameters in a space of dimension d. Typically, the way you would get around this is to take an MAP estimate as opposed to an ML.
For the multivariate normal, this is a normal-inverse-wishart distribution. The MAP estimate adds the matrix parameter of inverse Wishart distribution to the ML covariance matrix estimate and, if chosen correctly, will get rid of the singularity problem.
If you are actually trying to create a classifier for normally distributed data, and not just doing an experiment, then a better way to do this would be with a discriminative method. The decision boundary for a multivariate normal is quadratic, so just use a quadratic kernel in conjunction with an SVM.

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