I am writing a generic Log() function in lua which utilizes lua print function:
Log (variable, 'String: %s ', str, 'Word: %d', w)
Currently I'm using below approach:
print(string.format (variable, 'String: %s ', str, 'Word: %d', w))
I tried something like:
Log = function(...) begin
return print(string.format(...))
end
But it doesn't work, Is this correct approach? Or Is there any better more generic way to get this done?
If you just want to print a sequence of values, you can do that with print:
print(variable, 'String: %s ', str, 'Word: %d', w)
What you seem to want is something more complicated. Your algorithm seems to be:
For each argument:
If the argument is not a string, then convert it to a string and print it.
If the argument is a string, figure out how many % patterns it has (let us call this number k). Pass string.format the current argument string and the following k parameters, printing the resulting string. Advance k parameters.
That's a much more complicated algorithm than can be done in a one-line system.
Using Lua 5.3, here's what such a function would look like (note: barely tested code):
function Log(...)
local values = {}
local params = table.pack(...)
local curr_ix = 1
while (curr_ix <= params.n) do
local value = params[curr_ix]
if(type(value) == "string") then
--Count the number of `%` characters, *except* for
--sequential `%%`.
local num_formats = 0
for _ in value:gmatch("%%[^%%]") do
num_formats = num_formats + 1
end
value = string.format(table.unpack(params, curr_ix, num_formats + curr_ix))
curr_ix = curr_ix + num_formats
end
values[#values + 1] = value
curr_ix = curr_ix + 1
end
print(table.unpack(values))
end
I don't think your current approach works, because the first argument of string.format expects the format specifier, not the rest of the arguments.
Anyway, this is the way to combine formatting and printing together:
Log = function(...)
return print(string.format(...))
end
And call it like this:
Log("String: %s Number: %d", 'hello' , 42)
Also, it might be better to make the format specifier argument more explicit, and use io.write instead of print to get more control over printing:
function Log(fmt, ...)
return io.write(string.format(fmt, ...))
end
Related
I'm trying to iterate through a table with a variable amount of elements and get all possible combinations, only using every element one time. I've landed on the solution below.
arr = {"a","b","c","d","e","f"}
function tablelen(table)
local count = 0
for _ in pairs(table) do
count = count + 1
end
return count
end
function spellsub(table,start,offset)
local str = table[start]
for i = start+offset, (tablelen(table)+1)-(start+offset) do
str = str..","..table[i+1]
end
return str
end
print(spellsub(arr,1,2)) -- Outputs: "a,d,e" correctly
print(spellsub(arr,2,2)) -- Outputs: "b" supposed to be "b,e,f"
I'm still missing some further functions, but I'm getting stuck with my current code. What is it that I'm missing? It prints correctly the first time but not the second?
A solution with a coroutine iterator called recursively:
local wrap, yield = coroutine.wrap, coroutine.yield
-- This function clones the array t and appends the item new to it.
local function append (t, new)
local clone = {}
for _, item in ipairs (t) do
clone [#clone + 1] = item
end
clone [#clone + 1] = new
return clone
end
--[[
Yields combinations of non-repeating items of tbl.
tbl is the source of items,
sub is a combination of items that all yielded combination ought to contain,
min it the minimum key of items that can be added to yielded combinations.
--]]
local function unique_combinations (tbl, sub, min)
sub = sub or {}
min = min or 1
return wrap (function ()
if #sub > 0 then
yield (sub) -- yield short combination.
end
if #sub < #tbl then
for i = min, #tbl do -- iterate over longer combinations.
for combo in unique_combinations (tbl, append (sub, tbl [i]), i + 1) do
yield (combo)
end
end
end
end)
end
for combo in unique_combinations {'a', 'b', 'c', 'd', 'e', 'f'} do
print (table.concat (combo, ', '))
end
For a tables with consecutive integer keys starting at 1 like yours you can simply use the length operator #. Your tablelen function is superfluous.
Using table as a local variable name shadows Lua's table library. I suggest you use tbl or some other name that does not prevent you from using table's methods.
The issue with your code can be solved by printing some values for debugging:
local arr = {"a","b","c","d","e","f"}
function spellsub(tbl,start,offset)
local str = tbl[start]
print("first str:", str)
print(string.format("loop from %d to %d", start+offset, #tbl+1-(start+offset)))
for i = start+offset, (#tbl+1)-(start+offset) do
print(string.format("tbl[%d]: %s", i+1, tbl[i+1]))
str = str..","..tbl[i+1]
end
return str
end
print(spellsub(arr,1,2)) -- Outputs: "a,d,e" correctly
print(spellsub(arr,2,2)) -- Outputs: "b" supposed to be "b,e,f"
prints:
first str: a
loop from 3 to 4
tbl[4]: d
tbl[5]: e
a,d,e
first str: b
loop from 4 to 3
b
As you see your second loop does not ran as the start value is already greater than the limit value. Hence you only print the first value b
I don't understand how your code is related to what you want to achieve so I'll leave it up to you to fix it.
--encode
function strToBytes(str)
local bytes = { str:byte(1, -1)
for i = 1, #bytes do
bytes[i] = bytes[i] + 100
end
return table.concat(bytes, ',')
end
--decode
function bytesToStr(str)
local function gsub(c)return string.char(c - 100) end
return str:gsub('(%d+),?', gsub) end
implemented :
str = "hello world"
strbyte = strToBytes(str)
bytestr = bytesToStr(strbyte)
print(strbyte)
Output :
204,201,208,208,211,132,219,211,214,208,200
print(bytestr)
Output :
"Hello world"
Hi, I need improving my code above. Actually encode and decode functions is work fine, but I need a little bit change.
I want to make encode functions similar like code above, but, the results is table like below :
{204,201,208,208,211,132,219,211,214,208,200}
Then, same as like my first decode functions, all bytes inside the table should be back to "hello world".
I hope my purpose and explanation above is easy to understand. Thanks in advance for any help and suggestions.
Update explanation :
It is a little bit complicated to explain what is my purposes. But I will try to explain as good as I can.
I am trying to make scripts encoder. Encode functions is in encoder scripts side, and decode function is in encoded scripts side. So I must write concatenate decode function before encoded string.
To clearly my explanation, encoder scripts will load undecode source code.
file = io.open(path, "r")
local data = file:read("*l")
The problem is, table cant concatenate with string.
local data = encode(str)--the result is byte array
local data = "decode("..data..")"
file:write(data)
file:close()
local data = string.dump(load(data),true,true)
My first purpose is to hide some important string, because string.dump result is not hide all string.
My second purpose is, to make an obsfucated code using byteArray.
Any solution or suggestion?
SOLVED
function strToBytes(str)
local byteArray= { str:byte(1, -1) }
for i = 1, #byteArray do
byteArray[i] = byteArray[i] + 100
encoded = '{' ..table.concat(byteArray, ',') .. '}'
end
return "load(string.dump(load(bytesToStr("..encoded.."))))()\n"
end
Thank you so much... đź‘Ť
Your code was very close to what you were looking for.
--encode
function strToBytes(str)
local byteArray= { str:byte(1, -1) }
for i = 1, #byteArray do
byteArray[i] = byteArray[i] + 100
end
return '{' .. table.concat(byteArray, ',') .. '}'
end
For the encode I removed the table.concat and now just return the byteArray
--decode
function bytesToStr(byteArray)
local output = "" --initialize output variable
for _,b in ipairs(byteArray) do --use ipairs to preserve order
output = output .. string.char(b - 100) --convert each byte to a char and add to output
end
return output
end
For the decode I use a for loop with ipairs to iterate over each byte and concatenate the values into an output variable.
-- test
str = "hello world!"
strbyte = strToBytes(str)
bytestr = 'return bytesToStr(' .. strbyte .. ')'
strBack = string.dump(load(bytestr),true,true)
print(strbyte)
print(bytestr)
print(load(strBack)())
Test output:
{204,201,208,208,211,132,219,211,214,208,200,133}
return bytesToStr({204,201,208,208,211,132,219,211,214,208,200,133})
hello world!
I have a txt file with the following text:
5;2;8;3;
I need get the numeric values, using ; as delimiter, and put them into an array. How could this be achieved?
The easiest way is to just use string.gmatch to match the numbers:
local example = "5;2;8;3;"
for i in string.gmatch(example, "%d+") do
print(i)
end
Output:
5
2
8
3
A "harder" way with a specific Split function:
function split(str, delimiter)
local result = {}
local regex = string.format("([^%s]+)%s", delimiter, delimiter)
for entry in str:gmatch(regex) do
table.insert(result, entry)
end
return result
end
local split_ex = split(example, ";")
print(unpack(split_ex))
Output:
5 2 8 3
Have a look at a sample program here.
Good evening
Will you help me solve this problem?
ERROR: race/util_server.lua:440: attempt to index local 'self' (a nil value)
function string:split(separator)
if separator == '.' then
separator = '%.'
end
local result = {}
for part in self:gmatch('(.-)' .. separator) do
result[#result+1] = part
end
result[#result+1] = self:match('.*' .. separator .. '(.*)$') or self
return result
end
You're probably calling it wrong.
function string:split(separator)
Is short hand for:
function string.split(self, separator)
Given a string and separator:
s = 'This is a test'
separator = ' '
You need to call it like this:
string.split(s, separator)
Or:
s:split(separator)
If you call it like this:
s.split(separator)
You're failing to provide a value for the self argument.
Side note, you can write split more simply like this:
function string:split(separators)
local result = {}
for part in self:gmatch('[^'..separators..']+') do
result[#result + 1] = part
end
return result
end
This has the disadvantage that you can't used multi-character strings as delimiters, but the advantage that you can specify more than one delimiter. For instance, you could strip all the punctuation from a sentence and grab just the words:
s = 'This is an example: homemade, freshly-baked pies are delicious!'
for _,word in pairs(s:split(' :.,!-')) do
print(word)
end
Output:
This
is
an
example
homemade
freshly
baked
pies
are
delicious
I'm trying to use in pairs inside a function but it doesn't work, it just prints the first row (key). This is my code:
set = {1,2,3,4};
unset = {5,6,7,8};
function listen(ftype)
if (ftype == [[~]]) then
for num,str in pairs(set) do
return str;
end
end
if (ftype == [[$]]) then
for num,str in pairs(unset) do
return str;
end
end
end
print(listen([[~]])..[[ =:= ]]..listen([[$]]));
If I do something like this..
for num,str in pairs(unset) do
print(str);
end
It works like a charm. That’s exactly what I want but inside a function.
You can build your own iterator:
function double_pair(t1, t2)
local i = 0
return function() i = i + 1
return t1[i] and t1[i] .. " =:= " .. t2[i]
end
end
Then you can use it like this:
for str in double_pair(set, unset) do
print(str)
end
Output:
1 =:= 5
2 =:= 6
3 =:= 7
4 =:= 8
Note that you don't need semicolons to end your statement, unless the statements are in one line and you want to make them clear. And [[ =:= ]] is usually used to build long multi-line strings, normally we choose to use double quote " =:= " or single quote ' =:= '.
A function can't return multiple times. Putting an unconditional return inside a loop is nonsensical - it will never get to the second iteration of the loop.
You are essentially trying to return multiple values from the function. Lua supports that; you could, for instance, just return 1,2,3,4. For an unknown number of return values, you can build them up in a table and call unpack on it, like so:
function listen(ftype)
local result = {}
local num, str
if (ftype == [[~]]) then
for num,str in pairs(set) do
table.insert(result, str)
end
elseif (ftype == [[$]]) then
for num,str in pairs(unset) do
table.insert(result, str)
end
end
return unpack(result)
end
But since your results are already in a couple tables, it would be silly to reconstruct them that way. You can just unpack the originals:
function listen(ftype)
if (ftype == [[~]]) then
return unpack(set)
elseif (ftype == [[$]]) then
return unpack(unset)
end
end
Great. But when you put the function call into an expression like your print statement, it will only return the first value, which puts you back where you started.
So to print out your pairs, you can't avoid having to either:
1) do some iteration outside the function
or
2) do the actual printing inside the function
The cleanest solution is probably a custom iterator, as suggested by #YuHao.