The UWP application use too many memory when I use Stream - stream

I create a app to read ZipArchive(100+ photo),And Use Stream, MemoryStream, IRandomAccessStream, and BinaryReader to setSource of the bitmapImage.
private byte[] GetBytes(ZipArchiveEntry entity)
{
Stream stream = entity.Open();
MemoryStream ms = new MemoryStream();
BinaryReader reader = null;
byte[] imageData = null;
try
{
stream.CopyTo(ms);
imageData = new byte[ms.Length];
string fileclass = "";
reader = new BinaryReader(ms);
ms.Seek(0, 0);
imageData = reader.ReadBytes((int)ms.Length);
//Verify png jpg bmp
some code and return imageData
//throw exception,return null
else
{
throw new Exception();
}
}
catch (Exception ex)
{
return null;
}
//Dispose
}
BitmapImage.SetSource by byte[]
public async Task<MangaPageEntity> GetImageFromZipArchiveEntry(ZipArchiveEntry entity, int index)
{
MangaPageEntity mpe = new MangaPageEntity();
mpe.Index = index;
IRandomAccessStream iras = null;
try
{
byte[] data = GetBytes(entity);
iras = data.AsBuffer().AsStream().AsRandomAccessStream();
iras.Seek(0);
await mpe.Picture.SetSourceAsync(iras);
}//catch and dispose
return mpe;
In this way, It use too many memory too run at phone ..

Try to put your streams and other IDisposable into using statement:
private byte[] GetBytes(ZipArchiveEntry entity)
{
using (Stream stream = entity.Open())
using (MemoryStream ms = new MemoryStream())
{
byte[] imageData = null;
try
{
stream.CopyTo(ms);
imageData = new byte[ms.Length];
string fileclass = "";
using (BinaryReader reader = new BinaryReader(ms))
{
ms.Seek(0, 0);
imageData = reader.ReadBytes((int)ms.Length);
}
//Verify png jpg bmp some code and return imageData
//throw exception,return null
else
{
throw new Exception();
}
}
catch (Exception ex)
{
return null;
}
}
//Dispose
}
public async Task<MangaPageEntity> GetImageFromZipArchiveEntry(ZipArchiveEntry entity, int index)
{
MangaPageEntity mpe = new MangaPageEntity();
mpe.Index = index;
try
{
byte[] data = GetBytes(entity);
using (IRandomAccessStream iras = data.AsBuffer().AsStream().AsRandomAccessStream())
{
iras.Seek(0);
await mpe.Picture.SetSourceAsync(iras);
}
}//catch and dispose
return mpe;
}
When your code leaves using it calls Dispose(). Some more to read: Uses of “using” in C#, What is the C# Using block and why should I use it? and probably some more.

Related

Illegal Argument Exception when trying to convert byte to Bitmap in blackberry

Here is my code where i am getting profile image bytes from twitter api,
new Thread() {
public void run() {
byte dbata[] = getBitmap(profle_pic_str);
if (dbata != null) {
EncodedImage bitmap_img = EncodedImage.createEncodedImage(dbata, 0, -1);
Bitmap image =bitmap_img.getBitmap();
final Bitmap profle_pic_bmp = image;
final Bitmap scld_bmp = new Bitmap(90, 100);
Application.getApplication().invokeLater(new Runnable() {
public void run() {
if (profle_pic_bmp != null) {
profle_pic_bmp.scaleInto(scld_bmp, Bitmap.FILTER_LANCZOS);
phot_profle.setBitmap(scld_bmp);
} else {
Dialog.alert("null");
}
}
});
// } else {
// Dialog.alert("bytes are null");
}
}
}.start();
Here i have method getBitmap(profle_pic_str); which returning bytes array of image,
public byte[] getBitmap(String url) {
Bitmap bitmap = null;
String strg = HttpConnector.getConnectionString();
byte b[] = null;
try {
b = getXML(url + strg);
} catch (IOException ie) {
ie.printStackTrace();
}
return b;
}
the url which i used is this one
http://api.twitter.com/1/users/profile_image?screen_name=screen_nameof_user&size=bigger
public byte[] getXML(String url) throws IOException {
ContentConnection connection =
(ContentConnection) javax.microedition.io.Connector.open(url);
java.io.DataInputStream iStrm = connection.openDataInputStream();
java.io.ByteArrayOutputStream bStrm = null;
byte xmlData[] = null;
try {
// ContentConnection includes a length method
int length = (int) connection.getLength();
if (length != -1) {
xmlData = new byte[length];
// Read the png into an array
// iStrm.read(imageData);
iStrm.readFully(xmlData);
} else // Length not available...
{
bStrm = new java.io.ByteArrayOutputStream();
int ch;
while ((ch = iStrm.read()) != -1) bStrm.write(ch);
xmlData = bStrm.toByteArray();
bStrm.close();
}
} catch (Exception e) {
e.printStackTrace();
} finally {
// Clean up
if (iStrm != null) iStrm.close();
if (connection != null) connection.close();
if (bStrm != null) bStrm.close();
}
return xmlData;
}
When i am trying to convert byte array to EncodedImage
EncodedImage bitmap_img = EncodedImage.createEncodedImage(dbata, 0, -1);
in this line of code i am getting illegal argument exception.
same code is working for Facebook profile image. I dont know why this code giving error when i am doing for twitter. Please help me friends.
try this -
EncodedImage _encoded_img = EncodedImage.createEncodedImage(dbata, 0, dbata.length);
On your code,
EncodedImage bitmap_img = EncodedImage.createEncodedImage(dbata, 0,-1);
-1 is the length of the array. Its not static. Change -1 to dbata.length.

get image from bytes blackberry

I am developing a blackberry application which retrieves image from the server , some of images are being retreived and other give error in the encodedImage Line
ImageFromUrl _img = new ImageFromUrl(item.getThumbLink());
byte[] bytes = _img.getbitmap();
Bitmap newBitmap = new Bitmap(width, fieldHeight);
if (bytes != null) {
// bitmap = Bitmap.createBitmapFromBytes(bytes, 0,
// bytes.length, Bitmap.SCALE_TO_FIT);
EncodedImage image = EncodedImage.createEncodedImage(bytes,
0, bytes.length);
}
and that's the connection which get the bytes
ImageFromUrl(String url) {
this.url = url;
}
public byte[] getbitmap() {
try {
connection = (HttpConnection) Connector.open(
url + Connection.getBlackBerryConnectionParams(),
Connector.READ, true);
InputStream is = connection.openInputStream();
DataInputStream dis = new DataInputStream(is);
ByteArrayOutputStream bStrm = new ByteArrayOutputStream();
int ch;
while ((ch = dis.read()) != -1) {
// System.out.println((char) ch);
// msg = msg + (char) ch;
bStrm.write(ch);
}
dataArray = bStrm.toByteArray();
} catch (IOException e) {
e.printStackTrace();
}
return dataArray;
}
how can I solve that to get all images without errors ?
Try this code:
public Bitmap getBitmapFromUrl(String url)
{
Bitmap bitmap=null;
try
{
HttpConnection connection=(HttpConnection)Connector.open(url);
connection.setRequestMethod(HttpConnection.GET);
InputStream is=connection.openInputStream();
int length=is.available();
byte[] data=new byte[length];
data=IOUtilities.streamToBytes(is);
connection.close();
is.close();
bitmap=Bitmap.createBitmapFromBytes(data,0,data.length,1);
if(bitmap!=null)
return bitmap;
else
return bitmap=Bitmap.getBitmapResource("noimage.png");
}
catch (Exception e)
{
return bitmap=Bitmap.getBitmapResource("noimage.png");
}
}

How to get bitmap from URL in Blackberry

I want to get the Bitmap from URL like -
"https://graph.facebook.com/100003506521332/picture"
I tried how-i-can-display-images-from-url-in-blackberry . But its showing http error 302 .It dont showing the Bitmap. How to resolve the problem ?.
String url = "https://graph.facebook.com/100003506521332/picture";
try
{
bitmap = globleDeclaration.getLiveImage(url, 50, 50);
bitmapField.setBitmap(bitmap);
}
catch (IOException e)
{
e.printStackTrace();
Dialog.alert(e.getMessage());
}
public Bitmap getLiveImage(String url,int width,int height) throws IOException
{
Bitmap bitmap = null;
try
{
byte[] responseData = new byte[10000];
int length = 0;
StringBuffer rawResponse = new StringBuffer();
httpconnection = (HttpConnection) Connector.open(url, Connector.READ, true);
String location=httpconnection.getHeaderField("location");
if(location!=null){
httpconnection = (HttpConnection) Connector.open(location, Connector.READ, true);
}else{
httpconnection = (HttpConnection) Connector.open(url, Connector.READ, true);
}
inputStream = httpconnection.openInputStream();
while (-1 != (length = inputStream.read(responseData)))
{
rawResponse.append(new String(responseData, 0, length));
}
int responseCode = httpconnection.getResponseCode();
if (responseCode != HttpConnection.HTTP_OK)
{
throw new IOException("HTTP response code: "
+ responseCode);
}
final String result = rawResponse.toString();
byte[] dataArray = result.getBytes();
encodeImageBitmap = EncodedImage.createEncodedImage(dataArray, 0, dataArray.length);
}
catch (final Exception ex)
{
System.out.print("Exception (" + ex.getClass() + "): " + ex.getMessage());
}
finally
{
try
{
inputStream.close();
inputStream = null;
httpconnection.close();
httpconnection = null;
}
catch(Exception e){}
}
return bitmap;
}
If you done get responce from this code httpconnection = (HttpConnection) Connector.open(url, Connector.READ, true); which is mention in above answer than u can also use alternative solution for that..
You can pass your your id here http://graph.facebook.com/100003506521332/?fields=picture&type=large than you will get one json responce like that {"picture": "http://profile.ak.fbcdn.net/hprofile-ak-snc4/70678_100003506521332_1415569305_n.jpg"}
parse this json and get which you want exaclty .. than you will get responce using httpconnection = (HttpConnection) Connector.open(url, Connector.READ, true); also .
if you dont want larger image than remove &type=large from the above url.
//YOUR PACKAGE NAME
package ...........;
//*************************
import java.io.InputStream;
import javax.microedition.io.Connector;
import javax.microedition.io.HttpConnection;
import net.rim.device.api.system.Bitmap;
public class Util_ImageLoader {
public static Bitmap getImageFromUrl(String url) {
Bitmap bitmap = null;
try {
String bitmapData = getDataFromUrl(url);
bitmap = Bitmap.createBitmapFromBytes(bitmapData.getBytes(), 0,
bitmapData.length(), 1);
} catch (Exception e1) {
e1.printStackTrace();
}
return bitmap;
}
private static String getDataFromUrl(String url) {
StringBuffer b = new StringBuffer();
InputStream is = null;
HttpConnection c = null;
long len = 0;
int ch = 0;
try {
c = (HttpConnection) Connector.open(url);
is = c.openInputStream();
len = c.getLength();
if (len != -1) {
for (int i = 0; i < len; i++)
if ((ch = is.read()) != -1) {
b.append((char) ch);
}
} else {
while ((ch = is.read()) != -1) {
len = is.available();
b.append((char) ch);
}
}
is.close();
c.close();
} catch (Exception e) {
e.printStackTrace();
}
return b.toString();
}
}
copy this to your package....
Now, to use this class do like this>>>>>>>>
CREATE BITMAP OBJECT:
Bitmap IMAGE;
After That:
IMAGE=Util_ImageLoader.getImageFromUrl("https://graph.facebook.com/100003506521332/picture");
By the way, I think you have missed extension
like JPG,PNG, on your URL.... Check That
Now, add your bitmap where you would like to display the image......
ENJOY!
add(IMAGE);

Read Image stored in Oracle using Long DataType

I want to read the image stored in Oracle Long datatype.
Number of images are stored in a remote Oracle database in a column with datatype long. I just need to retrieve those images and show them on my aspx page.
I could retrieve the image from database but when tried to caste it to byte array, it threw error that, string can not be converted to byte[]'.
Anybody have any suggestions on how to retrieve these images stored in long column in database.
byte[] signatureBlobReceived = cls_TBL_BROKER_BL.GetInstance().GetSignatureBlobFromAccountNumber_BL(strCRNnumber);
return File(signatureBlobReceived, "image/jpeg");
public byte[] GetSignatureBlobFromAccountNumber_BL()
{
object SignatureBlob = null;
Database db = DatabaseFactory.CreateDatabase("imageConnectionString");
DbCommand dbc = db.GetSqlStringCommand(ConfigurationSettings.AppSettings["signqry"].ToString());
dbc.CommandType = CommandType.Text;
SignatureBlob = db.ExecuteScalar(dbc);
byte[] array = Encoding.ASCII.GetBytes(Convert.ToString(SignatureBlob));
string aa = string.Empty;
return array;
}
Query used is:
<add key="signqry" value="SELECT image FROM table1"/> `
Try this (odp.net)
string connStr = "User Id=user;Password=pwd;Data Source=mySID;";
OracleConnection _conn = new OracleConnection(connStr);
_conn.Open();
string sel = #"select long_raw_col from long_raw_test";
OracleCommand cmd = new OracleCommand(sel, _conn);
cmd.InitialLONGFetchSize = 5000;
OracleDataReader reader = cmd.ExecuteReader();
int rows = 0;
// loop through rows from table
while (reader.Read())
{
rows++;
byte[] buf = new byte[5000];
long bytesRead = reader.GetBytes(reader.GetOrdinal("long_raw_col"), 0, buf, 0, 5000);
FileStream fs = new FileStream("C:\\test\\test_long" + rows + ".dat", FileMode.Create);
fs.Write(buf, 0, (int)bytesRead);
fs.Close();
Console.WriteLine("Row " + rows + ": Read " + bytesRead + " bytes from table, see test_long" + rows + ".dat");
}
This example just reads the long raw data from Oracle into a byte array, then outputs to a file. Note the InitalLONGFetchSize > 0.
I use this class :my database is informix and the images are stored in Byte type .Hope this can help you.
public class MyPhoto
{
public static Stream RetrievePhoto()
{
DBConnection DAL_Helper = new DBConnection(ConfigurationSettings.AppSettings["connection"].ToString());
Byte[] myByteBuff;
Stream myImgStream;
string qry = "----------";
DataTable dt = DAL_Helper.Return_DataTable(qry);
try
{
if (dt.Rows.Count > 0)
{
if (!string.IsNullOrEmpty(dt.Rows[0][0].ToString()))
{
myByteBuff = (Byte[])((object)(dt.Rows[0][0]));
myImgStream = new MemoryStream(myByteBuff);
}
else
{
myImgStream = RetrievePhotoNoProfile();
}
}
else
{
myImgStream = RetrievePhotoNoProfile();
}
}
catch (Exception ex)
{
myImgStream = RetrievePhotoNoProfile();
}
return myImgStream;
}
public static byte[] StreamToByteArray(Stream stream)
{
if (stream is MemoryStream)
{
return ((MemoryStream)stream).ToArray();
}
else
{
return ReadFully(stream);
}
}
public static byte[] ReadFully(Stream input)
{
byte[] buffer = new byte[input.Length];
using (MemoryStream ms = new MemoryStream())
{
int read;
while ((read = input.Read(buffer, 0, buffer.Length)) > 0)
{
ms.Write(buffer, 0, read);
}
return ms.ToArray();
}
}
private static Stream RetrievePhotoNoProfile()
{
string noprofileimgPath = HttpContext.Current.Server.MapPath("~/images/noprofile.png");
System.IO.FileStream fs = new System.IO.FileStream(noprofileimgPath, System.IO.FileMode.Open, FileAccess.Read);
byte[] ba = new byte[fs.Length];
fs.Read(ba, 0, (int)fs.Length);
Stream myImgStream = new MemoryStream(ba);
fs.Close();
return myImgStream;
}
public static Image byteArrayToImage(byte[] byteArrayIn)
{
MemoryStream ms = new MemoryStream(byteArrayIn);
Image returnImage = Image.FromStream(ms);
return returnImage;
}
}

how to send mail with image attachment in blackberry

I am developing a BlackBerry application that uses the Mail functionality. My problem is
I want to send mail with an image attachment. How can I do that?
You can convert the image to byte array and then use the following method to send the file as attachment.
public synchronized boolean sendMail(final byte []data)
{
Folder[] folders = store.list(4);
Folder sentfolder = folders[0];
// create a new message and store it in the sent folder
msg = new Message(sentfolder);
multipart = new Multipart();
textPart = new TextBodyPart(multipart,"Image");
Address recipients[] = new Address[1];
try {
recipients[0] = new Address(address, "XYZ");
msg.addRecipients(Message.RecipientType.TO, recipients);
msg.setSubject("Image");
try {
Thread thread = new Thread("Send mail") {
public void run() {
try {
attach = new SupportedAttachmentPart(
multipart, "application/octet-stream",
"title",data);
multipart.addBodyPart(textPart);
multipart.addBodyPart(attach);
msg.setContent(multipart);
Transport.send(msg);
}
catch(SendFailedException e)
{
}
catch (final MessagingException e) {
}
catch (final Exception e) {
}
}
};
thread.start();
return true;
}
catch (final Exception e)
{
}
}catch (final Exception e) {
}
return false;
}
This may be help you check it
//create a multipart
Multipart mp = new Multipart();
//data for the content of the file
String fileData = "<html>just a simple test</html>";
String messageData = "Mail Attachment Demo";
//create the file
SupportedAttachmentPart sap = new SupportedAttachmentPart(mp,"text/html","file.html",fileData.getBytes());
TextBodyPart tbp = new TextBodyPart(mp,messageData);
//add the file to the multipart
mp.addBodyPart(tbp);
mp.addBodyPart(sap);
//create a message in the sent items folder
Folder folders[] = Session.getDefaultInstance().getStore().list(Folder.SENT);
Message message = new Message(folders[0]);
//add recipients to the message and send
try {
Address toAdd = new Address("email#company.com","my email");
Address toAdds[] = new Address[1];
toAdds[0] = toAdd;
message.addRecipients(Message.RecipientType.TO,toAdds);
message.setContent(mp);
Transport.send(message);
} catch (Exception e) {
Dialog.inform(e.toString());
}
this is for Image file
InputStream inputStream;
FileConnection fconn = (FileConnection) Connector.open(fName, Connector.READ_WRITE);
if(fconn.exists()){
inputStream=fconn.openInputStream();
byte[] data = IOUtilities.streamToBytes(inputStream);
inputStream.close();
fconn.close();
Multipart multipart = new Multipart();
SupportedAttachmentPart attach = new SupportedAttachmentPart(multipart, ".txt/.jpeg", "attachment1", data);
multipart.addBodyPart(attach);
}

Resources