I set the language of the simulator to French. To check the language code, I used a couple of solutions:
let lang = NSLocale.autoupdatingCurrent.languageCode
print(lang)
let pre = Locale.preferredLanguages[0]
print(pre)
The result are:
Optional("en")
fr-US
What I expected to get is:
fr
How can I achieve that?
Try below code,
let requiredString = pre.components(separatedBy: "-").first ?? pre //fr
/*if pre.contains("-"), then requiredString = before("-") else requiredString = pre*/
print(Locale.components(fromIdentifier: Locale.preferredLanguages[0])["kCFLocaleLanguageCodeKey"]!)
this will print language code only.
If you want the Language instead of the Language_Region, then I suggest to take the sub string before the _ from the string to neglect the Region.
(If the string contains no _ then take the entire string since it doesn't contain the region in it)
Related
I have a to compare a string with the string from the db.
var variableFromDB = "test"
if "test" == variableFromDB{
print("Success")
}
It works fine in the English Language. I don't know how to compare it in the arabic language. Is the need to check in arabic language also. Please tell me know to check it.
In general it's a bad idea for your code to make decisions based on display strings. That goes double for display strings.
If your primary audience is Arabic-speaking, you could make your development language Arabic and then localize for other languages as needed.
In any case, I would suggest using a set of fixed strings as keys, and then calling NSLocalizedString(_:tableName:bundle:value:comment:) or one of it's variants to fetch a display string. Example:
Put this code somewhere central so the keys can be shared:
let screen1Prompt = "screen1Prompt"
Then when you need a localized string for display:
let prompt = NSLocalizedString(screen1Prompt)
Where the actual prompt string might be "Please select the date for your payment." in English, Arabic, etc.
Then if you need to match something in your database, look it up using the unlocalized key, not the localized display string.
That way if you later change the display string, your code still works.
var language: String
UserDefaults.standard.set("AE", forKey: "Apple") // manually set language
UserDefaults.standard.synchronize()
self.language = UserDefaults.standard.object(forKey: "Apple")as! String
// self.language = Locale.current.languageCode // your device language
extension String {
func stringlocalized(lang:String) ->String {
let path = Bundle.main.path(forResource: lang, ofType: "lproj")
let bundle = Bundle(path: path!)
return NSLocalizedString(self, tableName: nil, bundle: bundle!, value: "", comment: "")
}}
// Check You Localization string from your current language
let str = “ test”.localized(lang: self.language! )
if str ==variableFromDB
{ // Your logic here
}
I have string like so "/blah//hahaha//lalala/"
Which needs to be translated into an Array of strings so that if I printed the array it would look like this print(arrayOfStrings) // prints ["blah","hahaha","lalala"]
I am new to swift so forgive me if this question is foolish
Given
let text = "/blah//hahaha//lalala/"
you can
let chunks = String(text.characters.dropFirst().dropLast()).componentsSeparatedByString("//")
and this is what you get
["blah", "hahaha", "lalala"]
There's also the URL solution
let string = "/blah//hahaha//lalala/"
let components = NSURL(fileURLWithPath: string).pathComponents!.dropFirst()
print(components)
I am using the following method to encode a string in objective - C:
+(NSString*)urlEncoded:(NSString*)string
{ return ((NSString *)CFBridgingRelease(CFURLCreateStringByAddingPercentEscapes (NULL,(CFStringRef)string, NULL,(CFStringRef)#"! '=();#&+$%#",kCFStringEncodingUTF8 )));}
Is there any counterpart for this method in Swift 2.0 ? I have tried using many solutions present on stack, but none of them could solve my problem.
You probably want to use stringByAddingPercentEncodingWithAllowedCharacters with NSCharacterSet's URL-component specific character sets:
let title = "NSURL / NSURLComponents"
let escapedTitle = title.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLQueryAllowedCharacterSet())
The idea behind those character sets is that they're probably more correct for the uses they describe than any finite set you have. That said, you could use the same method with a set you generate yourself:
let escapeSet = NSCharacterSet(charactersInString: "! '=();#&+$%#")
let string = "sdfT&*w5e#sto([+peW7)%y9pqf])"
let escapedString = string.stringByAddingPercentEncodingWithAllowedCharacters(escapeSet.invertedSet)
// "sdfT%26*w5e%23sto%28[%2BpeW7%29%25y9pqf]%29"
I have a database on the server that contains all the languages keywords that I use inside my applications and these languages could be changed any time.
In the language table of database there is column for Language (id , key, value, lang).
In the android application I read the language from device and it returns for example en-GB or en-US.
But in the iOS application I can't get the language like the above example , It always returns just the language (en , es, fr).
So I can't query to database to get the language specified keywords on the iOS application. Because the languages on the database is en-GB, en-US style.
var langId: String? = NSLocale.preferredLanguages().first as? String
How can I get the language with more details ?
Start with the currentLocale() and ask questions about it. For example:
let lang = NSLocale.currentLocale().localeIdentifier
Or, at a finer level of granularity:
let langId = NSLocale.currentLocale().objectForKey(NSLocaleLanguageCode) as! String
let countryId = NSLocale.currentLocale().objectForKey(NSLocaleCountryCode) as! String
let language = "\(langId)-\(countryId)" // en-US on my machine
Swift 3 does not have an NSLocaleCountryCode, this is replaced by regionCode
https://developer.apple.com/reference/foundation/nslocale.key/1417845-countrycode
solution in Swift 5:
let langCode = Locale.current.languageCode ?? ""
let regionCode = Locale.current.regionCode ?? ""
let language = "\(langCode)-\(regionCode)"
Another solution is NSLocale.current.identifier
This will return e.g. en_us
You could replace _ for -. it will look like this: NSLocale.current.identifier.replacingOccurrences(of: "_", with: "-")
No need an extra effort, just use the following as per your requirement.
Locale.current.identifier //en_US
Locale.current.collatorIdentifier //en-US
For Swift 4 use instead:
NSLocale.current.identifier //Output: en-US, pt-BR
Swift 5
Locale.currentLanguage.rawValue
just use this code line can solve:
let identifier = Locale.current.identifier
How can I make this:
var originalString = "http://name.domain.com/image.jpg"
becomes this:
originalString = "http://name.domain.com/image_new.jpg"
I could not find any document about the new Range<String.Index> in Swift.
This is not a problem in Obj-C, but without any reference about Range, it suddenly becomes so confusing.
Thanks.
Edit:
Well, thanks for these solutions. However, let me give you more details about this question.
After uploading an image to server, it responds back with a String link, like above, and the image name is a random string.
The server also generates different versions of uploaded image (like Flickr). In order to get these images, I have to append a suffix into image name, it looks like this:
originalString = "http://image.domain.com/randomName_large.jpg" or "http://image.domain.com/randomName_medium.jpg"
So that's why I need to insert a String into another String. My solution is find the first . by scan the link backwardly and append a suffix before it, but the new Range<String.Index> makes it confusing.
There are some nice and useful methods on NSString that you should be able to use:
let originalString: NSString = "http://name.domain.com/image.jpg"
let extension = originalString.pathExtension // "jpg"
let withoutExt = originalString.stringByDeletingPathExtension() // "http://name.domain.com/image"
let imageName = withoutExt.lastPathComponent // "image"
let withoutFilename = withoutExt.stringByDeletingLastPathComponent() // "http://name.domain.com/"
let newString = withoutFilename
.stringByAppendingPathComponent("\(imageName)_new")
.stringByAppendingPathExtension(extension)
I only typed this into the browser (it's untested) but it should give you an idea...
This can be done with String manipulation functions. But what if the string
is
var originalString = "http://images.domain.com/image.jpg"
? You probably do not want to replace the first or all occurrences of the string
"image" here.
A better tool for this purpose might be NSURLComponents, which lets you
modify all components of a URL separately:
var originalString = "http://name.domain.com/image.jpg"
let urlComps = NSURLComponents(string: originalString)!
urlComps.path = "/image_new.jpg"
originalString = urlComps.URL!.absoluteString!
println(originalString) // http://name.domain.com/image_new.jpg
Why not using string interpolation?
var imageName = "image_new"
originalString = "http://images.domain.com/\(imageName).jpg"