How to scroll UICollectionView that is underneath another UICollectionView? - ios

Question

So heres my issue, the 4 orange rectangles you see on the gif are a single vertical UICollectionView = orangeCollectionView.
The Green and Purple "card" views are part of another UICollectionView = overlayCollectionView.
overlayCollectionView has 3 cells, one of which is just a blank UICollectionViewCell, the other 2 are the cards.
When the overlayCollectionView is showing the blank UICollectionViewCell, I want to be able to scroll the orangeCollectionView.
override func point(inside point: CGPoint, with event: UIEvent?) -> Bool {
guard let superr = superview else { return true}
for view in superr.subviews {
if view.isKind(of: OrangeCollectionView.self) {
view.point(inside: point, with: event)
return false
}
}
return true
}
This allows me to scroll the orangeCollectionView HOWEVER this doesn't actually work to fix my issue. I need to be able to scroll left and right to show the cards, however this blocks all touches becuase the point always falls on the OrangeCollectionView.
How can I check to see if they are scrolling left/right to show the cards? Otherwise if they are on the blank cell, scroll the orangeViewController up and down.

Answer 1

Had this issue as well... Didn't find a nice way to do it, but this works.
First, you need to access the scroll view delegate method scrollViewDidScroll(). There you call:
if scrollView == overlayScrollView {
if scrollView.contentOffset.x == self.view.frame.width { // don't know which coordinate you need
self.overlayScrollView.alpa = 0
}
}
After that, you add a blank view onto of the orange collection view. The view's alpha is 0 (I think, maybe the color is just clear; try it out if it works).
In the code, you then add a UISwipeGestureRecognizer to the view you just created and and detect whether there's a swipe to the left or to the right.
By detecting the direction of that swipe, you can simply change the contentOffset.x axis of your overlayScrollView to 0 or self.view.frame.width * 2.
Sorry I can't provide my working sample code, I'm answering from my mobile. It's not the proper solution, but when I made a food app for a big client it worked perfectly and no one ever complained :)