When you set the date range for historical prices the js redirects with url variables period1 and period2. For example for Time Period: Jul 30, 2015 - Aug 30, 2015 the resulting url is as follows. period1=1438228800&period2=1440907200
https://ca.finance.yahoo.com/quote/GOOG/history?period1=1438228800&period2=1440907200&interval=1d&filter=history&frequency=1d
Anyone know how period1 and period2 were calculated?
Unix timestamp (seconds since January 1, 1970)
Related
I have a spreadsheet where I'm tracking my net worth over time. Once a month, I add in my account balances.
In one sheet, I have this structure:
Date
Year
Net Worth
Account1
Account2
Account3
Jan 31, 2021
2021
$320
$200
$140
-$20
Feb 28, 2021
2021
$340
$200
$150
-$10
Mar 31, 2021
2021
$410
$250
$200
-$40
Apr 30, 2021
May 31, 2021
...rest of months for the year
The formula in the Year column is =if(C3<>"", year(A3), "").
The formula in the Net worth column is =if(sum(D3:F3)<>0, sum(D3:F3), "").
The Problem:
I'd like to have a cell which lists the greatest 1 month change (so $410 - $340 = $70), without having to update the formula every month. (In an ideal world, I never need to touch it again, only ever having to enter account balances once a month.)
What I've got so far:
=if(
abs(min(ArrayFormula(C3:C400 - C2:C399)))=max(ArrayFormula(abs(C3:C400 - C2:C399))),
min(ArrayFormula(C3:C400 - C2:C399)),
max(ArrayFormula(C3:C400 - C2:C399))
)
However, this includes the change from $410 to "", which is coerced to $0. So instead of the expected $70, I'm instead getting $410.
How can I get the greatest 1 month change, but ignore the empty string values?
Easiest way to fix it is just to put in an if clause I think:
=ArrayFormula(max(if(C3:C400<>"",abs(C3:C400-C2:C399),)))
because Max will ignore the empty string generated by the If statement
or slightly shorter:
=ArrayFormula(max((C3:C400<>"")*abs(C3:C400-C2:C399)))
so that the change for any empty cells is set to zero.
These assume that C2 itself is not blank!
I have an integer that represents a unix epoch time in millisecond precision and a time zone string. I need to create a TimeWithZone object with them.
epoch_ms_integer = 1586653140000
time_zone = "America/Los_Angeles"
Trying to convert to:
Sat, 11 Apr 2020 20:59:00 PDT -07:00
I was able to accomplish this by doing:
Time.at(epoch_ms_integer/1000).asctime.in_time_zone("America/Los_Angeles")
but was wondering if this is the best way to achieve this. The app I'm working on is configured to EST/EDT time zone so Time.at(epoch_ms_integer/1000) returns 2020-04-11 20:59:00 -0400.
I was able to find the asctime solution in one of the answers here Ruby / Rails - Change the timezone of a Time, without changing the value
the same question was asked here but no answer converting epoch time with milliseconds to datetime.
Assuming that the timestamp is in milliseconds, then 1586653140000 is
Epoch: 1586653140
GMT: Sunday, April 12, 2020 12:59:00 AM
PDT: Saturday, April 11, 2020 17:59:00 PM -in time zone America/Los Angeles
These are just 3 different ways to refer to a specific point in time around the world.
Sat, 11 Apr 2020 20:59:00 PDT -07:00 and 2020-04-11 20:59:00 -0400 each refer to different points in time and not the same as epoch(1586653140)
Since the Unix epoch (or Unix time or POSIX time or Unix timestamp) is the number of seconds that have elapsed since January 1, 1970 (midnight UTC/GMT), it wouldn't make sense to take 1586653140 and only change the time zone without adding the zone's offset because now you are talking about another point in time.
To get the right "translation" from the epoch to any time zone you could just do
Time.zone = "GMT"
Time.zone.at(1586653140)
=> Sun, 12 Apr 2020 00:59:00 GMT +00:00
Time.zone = "America/Los_Angeles"
Time.zone.at(1586653140)
=> Sat, 11 Apr 2020 17:59:00 PDT -07:00
When working with dates in time zones in rails it is important to only use functions that take the set time zone into account:
DON’T USE
Time.now
Date.today
Date.today.to_time
Time.parse("2015-07-04 17:05:37")
Time.strptime(string, "%Y-%m-%dT%H:%M:%S%z")
DO USE
Time.current
2.hours.ago
Time.zone.today
Date.current
1.day.from_now
Time.zone.parse("2015-07-04 17:05:37")
Time.strptime(string, "%Y-%m-%dT%H:%M:%S%z").in_time_zone
Also keep in mind that in a Rails app, we have three different time zones:
system time,
application time, and
database time.
This post by thoughtbot explains things clearly.
I am reading list of Google Sheet cells containing DateTime, using Google Apps Script.
The values in the cells are:
A1: Jul 26 13:00
A2: Jul 27 0:00
var dateValues = SpreadsheetApp.getActiveSheet().getRange("A1:A2").getValues();
However, values read are 1 hour behind. This is what I see in the debugger:
dateValues[0] = Wed Jul 26 2017 12:00:00 GMT+0200 (EET)
dateValues[1] = Wed Jul 26 2017 23:00:00 GMT+0200 (EET)
I guess this is a time zone issue, but I don't really understand the concept.
My time zone is currently (due to DTS) GMT + 3. Indeed, outside the DTS period it is GMT +2. The spread sheet time zone is Jerusalem GMT+2.
EET - don't underrated why it is being used.
Basically, I would expect to get in code the values with in the sheet.
What is the concept?
there are two ways to solved this
Use getDisplayValues() rather than getValues(). This will force to do some conversions, as getDisplayValues() returns strings not dates
make you script editor time zone match the sheet tz.
In my case the sheet was (GMT+2 Jerusalem), but the script editor was different (GMT+2 Moscow) for some reason.
Setting the script editor TZ, solved the problem.
I have a really big spreadsheet in google docs. I have a collumn with time in UTC format. For instance (2013, 10, 14, 12, 17) for 14 Oct 2013, 12:17 am
I want to change it to ISO 8601. I have started to change them one by one, but the data is huge. Is there any other way to do it automatic?
If you want to turn (2013, 10, 14, 12, 17) (assumed in A1) into a more conventional format:
=SPLIT(mid(A1,2,len(A1)-2),",")
to populate B1:F1 then:
=date(B1,C1,D1)+(E1+F1/60)/24
to convert to a date time index recognised by Google Sheets. The result might be formatted:
dd MMM yyyy, HH:mm AM/PM
to show: 14 Oct 2013, 12:17 PM
or formatted otherwise by choice (ISO 8601 does not require a unique format).
This does not attempt to address any strange convention for the likes of 12:17 (ie treats that as 17 minutes after noon, not after midnight) nor any time difference due to location.
As the question states, what date format is "ds1248083197360" ? Is this a standard date format or a custom one to an application?
ds1248083197360 is 20/07/2009 (or in US format, 07/20/2009)
this might be miliseconds after 1.january year 1970 GMT 00:00. In this case, your example is 20.07.2009 10:46:37,360
It is probably the Unix time format, specified i milliseconds, meaning that it's the number of milliseconds since January 1st 1970. Wikipedia's entry on Unix time.
1248083197.360 is Monday the 20th of July 2009 09:46:37.360 GMT.