He guys. I want the website to open in reading mode. I want it to open without unnecessary ads and buttons. How can I do that on webView. Sorry for my very bad English. Thanks.
UPDATE FOR SWIFT 4, iOS 11
The SFSafariViewController init function that takes an entersReaderIfAvailable parameter has been replaced by one that takes an SFSafariViewController.Configuration property. To get the old behaviour you can replace the code used in answers above by this:
let urlString = "http://www.google.com"
let url = URL(string: urlString)!
let config = SFSafariViewController.Configuration()
config.entersReaderIfAvailable = true
let safariVC = SFSafariViewController(url: url, configuration: config)
present(safariVC, animated: true, completion: nil)
This will do the trick!
First thing you cannot enable "Reader" mode for WKWebView or UIWebView.
You need to use SFSafariViewController
Then you need to set entersReaderIfAvailable to true when initializing the instance.
Here an example :
let urlString = "http://google.com"
let url = URL(string: urlString)
let safariVC = SFSafariViewController(url: url!, entersReaderIfAvailable: true)
present(safariVC, animated: true, completion: nil)
Related
I am currently trying to enable the functionality to share a video on WhatsApp but without using UIActivityViewController, as Tik Tok does for example. When you click on "share" on WhatsApp, it directly redirects you to WhatsApp and contacts pop up so that you can share the video.
I kinda succeeded in sharing it but with ActivityViewController, this way:
let path = Bundle.main.url(forResource: "Rap God", withExtension: "mp4")!.relativePath
let fileUrl = NSURL(fileURLWithPath: path)
controller = UIDocumentInteractionController(url: fileUrl as URL)
controller.uti = "net.whatsapp.movie"
controller.presentOpenInMenu(from: CGRect.zero, in: self.view, animated: true)
I would be glad to know someone can help me out.
Try using UIApplication's canOpenURL(_:) and open(_:options:completionHandler:),
let urlString = "https://stackoverflow.com/questions/60282744/how-to-share-video-on-whatsapp-without-using-uiactivityviewcontroller"
let shareString = "whatsapp://send?text=\(urlString)"
if let url = URL(string: shareString), UIApplication.shared.canOpenURL(url) {
UIApplication.shared.open(url, options: [:]) { (completed) in
print(completed)
}
}
This problem is iPad specific.
When I use a WKWebView inside my app, its User Agent field is identical to the one sent by Safari. However, the page returned by Wikipedia to my App includes the standard Wikipedia side-bar. Safari on the iPad does not show the side bar.
I would like WKWebview to behave the same was as Safari. I would appreciate suggestions.
You can use SFSafariViewController instead Its behaviour is identical to Safari
if let url = URL(string: urlString) {
let config = SFSafariViewController.Configuration()
config.entersReaderIfAvailable = true
let vc = SFSafariViewController(url: url, configuration: config)
present(vc, animated: true)
}
Using SFSafariViewController, works well but for some reason when I go to this webpage [knowitall.ch], it starts up by opening a zoomed view? with a small black box that I need to press to get the full webpage.
My code couldn't be simpler.
if let url = URL(string: url2U) {
let vc = SFSafariViewController(url: url, entersReaderIfAvailable: true)
vc.delegate = self
present(vc, animated: true)
}
If I press the box I get the correct view, how to code around this so I open with the second view here? black box not required :)
That "zoomed view" is the Reader Mode. It shows up because you asked for it. Set entersReaderIfAvailable to false if you don't want it. Also, init(url:entersReaderIfAvailable:) has been deprecated in iOS 11. You need to initialize it with a config object:
if let url = URL(string: url2U) {
let vc: SFSafariViewController
if #available(iOS 11.0, *) {
let config = SFSafariViewController.Configuration()
config.entersReaderIfAvailable = false
vc = SFSafariViewController(url: url, configuration: config)
} else {
vc = SFSafariViewController(url: url, entersReaderIfAvailable: false)
}
vc.delegate = self
present(vc, animated: true)
}
how I can open url in native inner browser in app, like this
Attention: this is not UIWebView
Try this code for swift, you can open default browser (Safari) in your APP using below code
import UIKit
import SafariServices
let url = URL(string: "https://www.google.com")
let vc = SFSafariViewController(url: url!)
present(vc, animated: true, completion: nil)
I am trying to open a URL using Safari when the app gets a push notification. This works successfully when the app is in the first viewcontroller. But if the app is further into the program I get an error
<SFSafariViewController: 0x10b20ae60> on <AdViewController: 0x100b14530> whose view is not in the window hierarchy!
(AdViewController is my first view controller, so it is still focused on that one. )
I have searched this site and have tried all the suggestions for this error but have come up short. Currently, my code looks like this:
if MessageUrl != nil , let url = URL(string: MessageUrl!) {
let safari = SFSafariViewController(url: url)
self.window?.rootViewController?.presentedViewController?.present(safari, animated: true, completion: nil)
}
Get top most UIViewController I used extension UIApplication in Appdeleagte from the "swift 3" answer at bottom of that page and changed my code to:
if MessageUrl != nil , let url = URL(string: MessageUrl!) {
let safari = SFSafariViewController(url: url)
UIApplication.topViewController()?.present(safari, animated: true, completion: nil)
}