This question already has answers here:
How do you create a Swift Date object?
(11 answers)
Closed 5 years ago.
In Swift, I have a var datePicker = UIDatePicker(). I'm trying to set the datePicker to have a minimum value of Jan, 1st, 1920 (I want a range from Jan, 1st, 1920 to current date. I read how to set the maximumDate of the UIDatePicker, that was easy, but I couldn't find how to set the minimum to a specific date. I read that it should be datePicker.minimumDate but I'm not sure how to set the exact date from above. Suggestions?
Create appropriate date components
let components = DateComponents(year: 1920, month: 1, day: 1)
Create a date from the components
let minimumDate = Calendar.current.date(from: components)
Set the minimum date
let picker = UIDatePicker()
picker.minimumDate = minimumDate
You can use the NSDateFormatter as the following:
let dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "YYYY-MM-DD"
let date = dateFormatter.dateFromString("1920-01-01")
let datePicker = UIDatePicker()
datePicker.minimumDate = date
Related
I now that there is a thread that discussing about minimum and maximum date time in here Minimum and maximum date in UIDatePicker
but I am a beginner now in programming, and I have little bit confused with date and time object. I have tried but I can't set up my date time picker properly. So I want to set my date time picker to have minimum and maximum limited time.
the minimum is Now, and the maximum is 1 month from now. what code do I have to use? Thanks in advance
https://i.stack.imgur.com/RxXUX.png
You can try
self.datePicker.minimumDate = Date()
self.datePicker.maximumDate = Calendar.current.date(byAdding: .day, value: 30 , to:Date())!
or
self.datePicker.maximumDate = Calendar.current.date(byAdding: .month, value: 1 , to:Date())!
I recommend to use the date math skills of Calendar. It calculates the same day in the next month. If the day does not exist (for example Feb 30) it returns the next closest available date.
let now = Date()
let calendar = Calendar.current
let dayComponents = calendar.dateComponents([.day], from: now)
let maximumDate = calendar.nextDate(after: now, matching: dayComponents, matchingPolicy: .nextTime)
To get a Date exactly one month in the future from now (taking into account different month lengths), you can use Date.date(byAdding:value:to:), e.g. as in this answer. You'd take the result and set it as maximumDate of your picker.
I have to set min and max dates AND time in date picker which I achieved with following properties:
datePicker.datePickerMode = UIDatePickerMode.dateAndTime
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = self.dateFormat
let minDate = dateFormatter.date(from: self.fromDate) //Day before yesterday
let maxDate = dateFormatter.date(from: self.toDate) //Yesterday
datePicker.minimumDate = minDate
datePicker.maximumDate = maxDate
However, I am also showing Time Picker with this, but it is limiting to only 00:00 value after changing time or date.
How do I set min time as 00:00 for 24-hrs time and 12:00 am for 12-hrs time? (Same for max time as 23:59 and 11:59 pm)
I am trying to make an somewhat alarm app which has mandatory settings at first but the user can configure it by using the UIDatePicker.
The alarm app first has a defalut setting such as a week later from the current time, but it can be changed as the user scrolls the UIDatePicker. I searched a lot but cannot find a suitable answer.
can somebody please help me!
You can set the UIDatePicker date to your desired date time.
let numberOfDays = 6
datePicker.date = NSDate(timeIntervalSinceNow: (((24 * 60) * 60) * numberOfDays))
Hope it will help you..
Swift 4.1:
datePicker.date = Date(timeIntervalSinceNow: (((24 * 60) * 60) * numberOfDays))
Add this line of code when you create date picker.
datePicker.maximumDate = Calendar.current.date(byAdding: .day, value: 0, to: Date())
You can set value increase or decrease and complete your requirement.
let dateString = "Thursday, 19 Jan 2017"
let df = DateFormatter()
df.dateFormat = "eeee, dd MM yyyy"
let date = df.date(from: dateString)
if let unwrappedDate = date {
myDatePicker.setDate(unwrappedDate, animated: false) //set your own date
}
This question already has an answer here:
How to get the number of weeks from given year
(1 answer)
Closed 6 years ago.
How can we calculate total number fo week in selected year?
suppose i select year 2000 then it should be calculate total number of year in 2000 year.
thanks in advance.
Get the weeks of a given year -
var dateformater = NSDateFormatter()
dateformater.dateFormat = "YYYY/MM/dd"
var dateString:String = "2015-01-1"
let date:NSDate = dateformater.dateFromString(dateString)!
let calendar = NSCalendar.currentCalendar()
let components = calendar.rangeOfUnit(.WeekOfYear, inUnit: .Year, forDate: date)
print("weekOfYear = \( Int (components.length))")
I have a problem with my UIDatePicker:
When it first appears on the view as you'll see in the screenshot,
the initial value of the UIDatePicker says Today 3:00 pm, but if I click on the done button the label shows 3:07 ( which is the actual time ).
I want the Label to display the same time as the UIDatePicker.
here is my code:
override func viewDidLoad() {
super.viewDidLoad()
myDatePicker.minuteInterval = 15
}
#IBAction func datePickerAction(sender: AnyObject) {
var dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "dd-MM-yyyy HH:mm"
var strDate = dateFormatter.stringFromDate(myDatePicker.date)
self.selectedDate.text = strDate
}
You need to adjust the initial date to the discrete minute amounts at first. I am sure your date picker works just fine once you change the value, right? When you set the date picker to a date (like 3:07) but the date picker is set to show only increments of 15 minutes, it will show 3:00, but the set date is still 3:07.
let allUnits = NSCalendarUnit(rawValue: UInt.max)
let components = NSCalendar.currentCalendar().components(allUnits, fromDate: NSDate())
var minute = components.minute
minute = (minute / 15) * 15
components.minute = minute
let datePickerDate = NSCalendar.currentCalendar().dateFromComponents(components)
This always rounds the minutes downwards (while you might want to round up if the minute % 15 > 7 and then account for rounding up to 60), but you get the idea.