I have an array of strings. I would like to display 3 unique items from this array randomly. Then every 5 seconds, one of the items gets replaced with another unique item (my idea here is adding an animation with a delay).
I can display the 3 strings, however sometimes they repeat, and the timer is not updating the factLabel label.
Here's my progress:
override func viewDidLoad() {
super.viewDidLoad()
updateUI()
}
func randomFact() -> String {
let arrayCount = model.cancunFacts.count
let randomIndex = Int(arc4random_uniform(UInt32(arrayCount)))
return model.cancunFacts[randomIndex]
}
// Display the facts
func updateUI() {
Timer.scheduledTimer(timeInterval: 5, target: self, selector: #selector(randomFact), userInfo: nil, repeats: true)
factLabel.text = randomFact() + " " + randomFact() + " " + randomFact()
}
How do I get the text to always update randomly, without the 3 facts repeating?
Create an array of indexes. Remove a random index from the array, use it to index into your strings. When the array of indexes is empty, refill it.
Here is some sample code that will generate random, non-repeating strings:
var randomStrings = ["Traitor", "Lord Dampnut", "Cheeto-In-Chief",
"F***face Von Clownstick", "Short-Fingered Vulgarian",
"Drumpf", "Der Gropenführer", "Pumpkin in a suit"]
var indexes = [Int]()
func randomString() -> String {
if indexes.isEmpty {
indexes = Array(0...randomStrings.count-1)
}
let index = Int(arc4random_uniform(UInt32(indexes.count)))
let randomIndex = indexes.remove(at: index)
return randomStrings[randomIndex]
}
for i in 1...100 {
print (randomString())
}
(Note that it may still generate repeating strings in the case when the array of indexes is empty and it needs to be refilled. You'd need to add extra logic to prevent that case.)
Version 2:
Here is the same code, modified slightly to avoid repeats when the array of indexes is empty and needs to be refilled:
var randomStrings = ["tiny-fingered", "cheeto-faced", "ferret-wearing", "sh*tgibbon"]
var indexes = [Int]()
var lastIndex: Int?
func randomString() -> String {
if indexes.isEmpty {
indexes = Array(0...randomStrings.count-1)
}
var randomIndex: Int
repeat {
let index = Int(arc4random_uniform(UInt32(indexes.count)))
randomIndex = indexes.remove(at: index)
} while randomIndex == lastIndex
lastIndex = randomIndex
return randomStrings[randomIndex]
}
for i in 1...10000 {
print (randomString())
}
Even though it's using a repeat...while statement, the repeat condition will never fire twice in a row, because you'll never get a repeat except right after refilling the array of indexes.
With that code, if there is a repeat, the selected string will be skipped on that pass through the array. To avoid that, you'd need to adjust the code slightly to not remove a given index from the array until you verify that it is not a repeat.
Version 3:
Version 2, above, will skip an entry if it picks a repeat when it refills the array. I wrote a 3rd version of the code that refills the array, removes the last item it returned so that it can't repeat, and then adds it back to the array once it's picked a random item. This third version will always return every item in the source array before refilling it and will also never repeat an item. Thus it's truly random with no bias:
import UIKit
var randomStrings = ["Traitor", "Lord Dampnut", "Cheeto-In-Chief",
"F***face Von Clownstick", "Short-Fingered Vulgarian",
"Drumpf", "Der Gropenführer", "Pumpkin in a suit"]
var indexes = [Int]()
var lastIndex: Int?
var indexToPutBack: Int?
func randomString() -> String {
//If our array of indexes is empty, fill it.
if indexes.isEmpty {
indexes = Array(0...randomStrings.count-1)
print("") //Print a blank line each time we refill the array so you can see
//If we have returned an item previously, find and remove that index
//From the refilled array
if let lastIndex = lastIndex,
let indexToRemove = indexes.index(of: lastIndex) {
indexes.remove(at: indexToRemove)
indexToPutBack = indexToRemove //Remember the index we removed so we can put it back.
}
}
var randomIndex: Int
let index = Int(arc4random_uniform(UInt32(indexes.count)))
randomIndex = indexes.remove(at: index)
//If we refilled the array and removed an index to avoid repeats, put the removed index back in the array
if indexToPutBack != nil{
indexes.append(indexToPutBack!)
indexToPutBack = nil
}
lastIndex = randomIndex
return randomStrings[randomIndex]
}
for i in 1...30 {
print (randomString())
}
Sample output:
Short-Fingered Vulgarian
F***face Von Clownstick
Pumpkin in a suit
Drumpf
Lord Dampnut
Traitor
Der Gropenführer
Cheeto-In-Chief
Der Gropenführer
Drumpf
Lord Dampnut
Short-Fingered Vulgarian
Cheeto-In-Chief
Pumpkin in a suit
Traitor
F***face Von Clownstick
Short-Fingered Vulgarian
F***face Von Clownstick
Drumpf
Traitor
Cheeto-In-Chief
Lord Dampnut
Pumpkin in a suit
Der Gropenführer
Lord Dampnut
Short-Fingered Vulgarian
Pumpkin in a suit
Cheeto-In-Chief
Der Gropenführer
F***face Von Clownstick
Your timer is calling random fact, which simply returns a fact and doesn't do anything. You should probably have some third method called initializeTimer that does the Timer.scheduledtimer, which you should take out of your updateUI method. That timer should call updateUI. This would fix your labels updating. Also you would call initializeTimer in your viewDidLoad instead of updateUI. As far as preventing the repetition of facts, Duncan C's idea of having a separate array that you remove items from as you set new random facts then fill back up when it's empty seems like a good idea.
It may be easiest to maintain two arrays, usedStrings and unusedStrings, of random strings, like this:
var unusedStrings: [String] = ["king", "philip", "calls", "out", "for", "good", "soup"]
var usedStrings: [String] = []
func randomString() -> String {
if unusedStrings.isEmpty() {
unusedStrings = usedStrings
usedStrings = []
}
let randomIndex = Int(arc4random_uniform(unusedStrings.count))
let randomString = unusedStrings[randomIndex]
usedStrings.append(randomString)
return randomString
}
Related
Here I am just getting array count and using for loop but got crashed at let arr = arrayAdaptor[i] this line after completing my array count don't know why it's crashing can anyone help me how to resolve this
var arrayAdaptor = [Struct_Row_Rating]()
for i in 0...arrayAdaptor.count {
let arr = arrayAdaptor[i]
let number = arr.row
let row = number + 1
dict.updateValue("\(arr.rating)", forKey: "\(row)")
print(dict)
}
struct Struct_Row_Rating {
var row: Int
var rating: Double
init(row: Int , rating: Double) {
self.row = row
self.rating = rating
}}
The operator ... exceeds the range of the array. You have to write
for i in 0..<arrayAdaptor.count
or
for i in 0...arrayAdaptor.count - 1
Basically don't use these index based for loops in Swift at all.
Use Fast Enumeration:
for arr in arrayAdaptor {
and if you really need the index
for (index, arr) in arrayAdaptor.enumerated() {
Why you are using 0...arrayAdaptor.count range style avoid it and Simply Use enumerated() of an Array:
for (_,value) in arrayAdaptor.enumerated() {
let number = value.row
let row = number + 1
dict.updateValue("\(arr.rating)", forKey: "\(row)")
print(dict)
}
If you don't want any index to try with this:
for value in arrayAdaptor {
let number = value.row
let row = number + 1
dict.updateValue("\(arr.rating)", forKey: "\(row)")
print(dict)
}
See this
One of the options not mentioned in the answers is forEach approach.
arrayAdaptor.forEach { item in
print(item)
}
or
arrayAdaptor.forEach {
print($0) // without named parameter
}
// Your case:
arrayAdaptor.forEach { item in
let arr = item
let number = item.row
let row = number + 1
dict.updateValue("\(arr.rating)", forKey: "\(row)")
print(dict)
}
This is pretty much the same as the handy for..in mentioned in vadian's answer:
for arr in arrayAdaptor { ... }
From Swift 4 you can use One sided ranges.
i... is favored over i..< because the latter is ugly. We have to pick one, two would be redundant and likely to cause confusion over which is the "right" one. Either would be reasonable on pedantic correctness grounds – (i as Int)... includes Int.max consistent with ..., whereas a[i...] is interpreted as a[i..<a.endIndex] consistent with i..<.
Example:
var names = ["Jack", "New", "peter"]
let first = names[0...]
let second = names[..<names.count]
print(first)//prints ["Jack", "New", "peter"]
print(second)//prints ["Jack", "New", "peter"]
You can also iterate loop by 'map' function:
let _ = arrayAdaptor.map({ adaptor in
let number = adaptor.row
let row = number + 1
dict.updateValue("\(adaptor.rating)", forKey: "\(row)")
print(dict)
})
I have an array of Super Hero objects. I want to group the superheroes based on the name property into separated arrays and then count how many objects are in each individual separated array
Object:
class SuperHero{
var name: String?
var power: Bool?
}
Array of superheroes (there can be an infinite num of superheroes)
var superHeroes = [SuperHero]()
let superHero1 = SuperHero()
superHero1.name = "SuperMan"
superHero1.power = true
superHeroes.append(superHero1)
let superHero2 = SuperHero()
superHero2.name = "BatMan"
superHero2.power = true
superHeroes.append(superHero2)
let superHero3 = SuperHero()
superHero3.name = "BatMan"
superHero3.power = true
superHeroes.append(superHero3)
let superHero4 = SuperHero()
superHero4.name = "SuperMan"
superHero4.power = true
superHeroes.append(superHero4)
//etc...
Use name property to sort:
let sortedHeros = superHeroes.sort{$0.name < $1.name}
for hero in sortedHeros{
print(hero.name)
/*
prints
BatMan
BatMan
SuperMan
SuperMan
*/
}
How do I put the sorted array into separate arrays then print the count of each separated array?
//this is what I want
separatedArraysOfSuperHeroes = [[superHero2, superHero3], [superHero1, superHero4]]
//subscriprting isn't ideal because i'll never know the exact number of separated arrays
print(separatedArraysOfSuperHeroes[0].count)
print(separatedArraysOfSuperHeroes[1].count)
As per the comments the reason why I want sub arrays is because I want to use them to populate different tableview sections. For i.e. inside my tableview I would now have a 2 sections. The first section would have a header that says "Batman" with 2 Batman objects inside of it and the second section would have a header that says Superman with 2 Superman objects inside of it. The count property would show the number of super hero objects inside each section.
func getSeparatedArrayBasedOnName(superHeroes: [SuperHero]) -> [[SuperHero]] {
guard let superNames = NSOrderedSet.init(array: superHeroes.map { $0.name ?? "" }).array as? [String] else {
print("Something went wrong with conversion")
return [[SuperHero]]()
}
var filteredArray = [[SuperHero]]()
for superName in superNames {
let innerArray = superHeroes.filter({ return $0.name == superName })
filteredArray.append(innerArray)
}
for array in filteredArray {
for hero in array {
print(hero.name ?? "")
}
}
return filteredArray
}
Here is my code so far
var counter = 0
for i in 0...9 {
var val = NamePicker()
// array to find duplicates
var buttonValues = ["", "", "", "", "", "", "", "", "", ""] // array for button names
buttonValues.insert(val, at: counter)
print(buttonValues[counter])
counter += 1
}
This code is putting 10 string values into my array. What I would like to do is find a way to check each value in my array. for eample if my end result array is ["a","a","a","b","b","c","c","e","f","c"] I want to see if there is a triple of the same name(single and duplicates are fine). However if there is a triple I would like to change the 3rd value to another val from my NamePicker() function.
so with my array of
["a","a","a","b","b","c","c","e","f","c"]
there are 3 "a" and 3 "c", having two of the same is ok, i would like to change the 3rd to a new values and if the new value makes another triple it will change until there are no more triples.
so that array could possible have an end result of
["a","a","f","b","b","c","c","e","f","z"]
this is where the triples where changed.
Any help on how to do this efficiently?
Both options below asume that your NamePciker() function can generate at least 5 distinct values so there exists an array that satisfies your requirement.
Your requirement is better handled by not generating so many duplicates to begin with. If all you want is an array of names when each name cannot be repeated more than twice, try this:
var buttonValues = [String]()
var dict = [String: Int]()
while buttonValues.count < 10 {
let name = NamePicker()
let count = dict[name] ?? 0
guard count < 2 else { continue }
buttonValues.append(name)
dict[name] = count + 1
}
If you already have the array and want to correct it, do this:
var buttonValues = ["a","a","a","b","b","c","c","e","f","c"]
// Scan the array to tally how many times each name appears
var totalDict = [String: Int]()
buttonValues.forEach { totalDict[$0] = (totalDict[$0] ?? 0) + 1 }
// Now scan it again to update names that appear too many times
var runningDict = [String: Int]()
for (index, value) in buttonValues.enumerated() {
let count = runningDict[value] ?? 0
if count >= 2 {
while true {
let newValue = NamePicker()
let newTotal = (totalDict[newValue] ?? 0) + 1
if newTotal < 3 {
buttonValues[index] = newValue
totalDict[newValue] = newTotal
break
}
}
} else {
runningDict[value] = count + 1
}
}
Dictionary is the best way I think. Have the key be the character and the value be the count of that character. Your runtime will be O(n) since you only have to run through each input once. Here is an example:
let chars = ["a","a","a","b","b","c","c","e","f","c"]
var dict = [String: Int]()
for char in chars {
//If already in Dictionary, increase by one
if var count = dict[char] {
count += 1
dict[char] = count
} else {//else is not in the dictionary already, init with 1
dict[char] = 1
}
}
Output:
["b": 2, "e": 1, "a": 3, "f": 1, "c": 3]
Now I'm not sure how you want to replace the value that's the same character for a third time, but this is probably the best way to group the strings to determine which are over the limit.
Instead of inserting the wrong value and then checking if the values are correct, I would suggest to automatically create the correct array.
//array for button names
var buttonValues = Array<String>()
//tracks what value has been inserted how many times
var trackerDict = [String: Int]()
for i in 0...9 {
//we initialize a new variable that tells us if we found a valid value (if the value has not been inserted 2 times already)
var foundValidValue = false
while !foundValidValue{
var val = NamePicker()
//now we check if the value exists and if it is inserted less than 2 times
if let count = trackerDict[val] {
if count < 2 {
foundValidValue = true
}
}
//if we found the value, we can add it
if foundValidValue {
trackerDict[val] = (trackerDict[val] ?? 0) + 1
buttonValues.append(val)
}
//if we did not find it, we just run through the loop again
}
}
I added a dictionary because it is faster to keep track of the count in a dictionary than counting the number of occurrences in the array every time.
I am using arc4random to generate 10 random numbers so I can then query firebase to get the questions that contain the randomly generated numbers. The problem is that I don't want any number to appear more than once so then there are not duplicate questions. Current code below...
import UIKit
import Firebase
class QuestionViewController: UIViewController {
var amountOfQuestions: UInt32 = 40
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view.
// Use a for loop to get 10 questions
for _ in 1...10{
// generate a random number between 1 and the amount of questions you have
let randomNumber = Int(arc4random_uniform(amountOfQuestions - 1)) + 1
print(randomNumber)
// The reference to your questions in firebase (this is an example from firebase itself)
let ref = Firebase(url: "https://test.firebaseio.com/questions")
// Order the questions on their value and get the one that has the random value
ref.queryOrderedByChild("value").queryEqualToValue(randomNumber)
.observeEventType(.ChildAdded, withBlock: {
snapshot in
// Do something with the question
print(snapshot.key)
})
}
}
#IBAction func truepressed(sender: AnyObject) {
}
#IBAction func falsePressed(sender: AnyObject) {
}
}
You can have an array to store the value you want to random with, in your case, [1,2,3....10], and then use arc4random to get the random index of any value inside (0..9), get the value and remove it from array. Then you will never get the same number from the array.
Given the total number of questions
let questionsCount = 100
you can generate a sequence of integers
var naturals = [Int](0..<questionsCount)
Now given the quantity of unique random numbers you need
let randomsCount = 10
that of course should not exceed the total number of questions
assert(randomsCount <= questionsCount)
you can build your list of unique integers
let uniqueRandoms = (1..<randomsCount).map { _ -> Int in
let index = Int(arc4random_uniform(UInt32(naturals.count)))
return naturals.removeAtIndex(index)
}
As an alternative to generating the random number on the client and requesting a question at that specified number, you could download the entire array of questions and shuffle the array. GameKit provides a built-in method to shuffle the array.
import GameKit
// ...
let ref = Firebase(url: "https://test.firebaseio.com/questions")
// Order the questions on their value and get the one that has the random value
ref.queryOrderedByChild("value")
.observeEventType(.ChildAdded, withBlock: {
snapshot in
// Shuffle your array
let shuffledQuestions = GKRandomSource.sharedRandom().arrayByShufflingObjectsInArray(snapshot)
// Store your array somewhere and iterate through it for the duration of your game
})
You could generate random numbers and store each number in an NSArray. However, when you append it to the array you can check if the array already contains that number.
For example:
for _ in 1...10 {
let amountOfQuestions: UInt32 = 40
var intArray: [Int] = []
let randomNumber = Int(arc4random_uniform(amountOfQuestions - 1)) + 1
if intArray.contains(randomNumber) {
repeat {
randomNumber = Int(arc4random_uniform(amountOfQuestions - 1)) + 1
} while intArray.contains(randomNumber)
if !intArray.contains(randomNumber) {
intArray.append(randomNumber)
}
} else {
intArray.append(randomNumber)
}
print(intArray)
}
After that you can make a FireBase request with your uniquely generated integers. I hope I was able to help :).
Create unsorted Array of ten random Int 0..99
var set = Set<Int>()
while set.count < 10 {
let num = Int(arc4random_uniform(100))
set.insert(num)
}
let arr = Array(set)
I have this code, where i would call this "checkingfunction" function. I am not using any threading in my app, I would love to use if it benefits the performance of my app.
The "checkingfunction", takes more time than i expected. It takes more than 30 seconds to complete the execution. I cant wait that long in my app. That is not good, in middle of the game.
Somebody help me out here to rewrite the function, so that i can execute it in a faster way. Some functional programming way, if possible.
func returnCharactersFromAFourLetterString(inputString : String) -> (First : Character,Second : Character, Third : Character, Fourth : Character)
{
return (inputString[advance(inputString.startIndex, 0)],inputString[advance(inputString.startIndex, 1)],inputString[advance(inputString.startIndex, 2)],inputString[advance(inputString.startIndex, 3)])
}
func checkingWords(userEnteredWord : String)
{
var tupleFourLetters = self.returnCharactersFromAFourLetterString(userEnteredWord)
var firstLetter = String(tupleFourLetters.First)
var secondLetter = String(tupleFourLetters.Second)
var thirdLetter = String(tupleFourLetters.Third)
var fourthLetter = String(tupleFourLetters.Fourth)
var mainArrayOfWords : [String] = [] // This array contains around 0.2 million words
var userEnteredTheseWords : [String] = [] // This array contains less than 10 elements
// Check for FirstLetter
for index in 0..<array.count // Array of Letters as Strings , count = 200
{
var input = array[index]
var firstWord = "\(input)\(secondLetter)\(thirdLetter)\(fourthLetter)"
var secondWord = "\(firstLetter)\(input)\(thirdLetter)\(fourthLetter)"
var thirdWord = "\(firstLetter)\(secondLetter)\(input)\(fourthLetter)"
var fourthWord = "\(firstLetter)\(secondLetter)\(thirdLetter)\(input)"
if !contains(userEnteredTheseWords, firstWord) && !contains(userEnteredTheseWords, secondWord) && !contains(userEnteredTheseWords, thirdWord) && !contains(userEnteredTheseWords, fourthWord)
{
if contains(mainArrayOfWords, firstWord )
{
self.delegate?.wordMatchedFromDictionary(firstWord)
return
}
else if contains(mainArrayOfWords, secondWord)
{
self.delegate?.wordMatchedFromDictionary(secondWord)
return
}
else if contains(mainArrayOfWords, thirdWord)
{
self.delegate?.wordMatchedFromDictionary(thirdWord)
return
}
else if contains(mainArrayOfWords, fourthWord)
{
self.delegate?.wordMatchedFromDictionary(fourthWord)
return
}
}
if index == array.count - 1
{
self.delegate?.wordMatchedFromDictionary("NoWord")
}
}
}
Input of this function is a four letter word, Inside this function i am changing each letter by looping through that 200 letters, and checking in the mainArray that, whether any of these changed words exists in mainArray. If exists, then return me that word, otherwise just return NoWord. So totally, we can see that we are checking that contains(mainArray, word) thing around 800 times, i think this is the line which consumes more time, cause mainArray contains 0.2 million words.
Use dictionaries to look up things.
When you measure times, especially with Swift code, measure a release build, not a debug build. On the other hand, measure on the slowest device capable of running your code.