Related
I want to get the current week start and end date and I also want to use the previous
week start and end date and next week of the start and end date in current month.
Thanks in Advance.
rangeOfUnit:startDate:interval:forDate:. It gives you the start and the interval for a certain time unit. With it it is easy to find the start of the week in the used calendar and add the range-1 to get the latest second in that week.
NSCalendar *cal = [NSCalendar currentCalendar];
NSDate *now = [NSDate date];
NSDate *startOfTheWeek;
NSDate *endOfWeek;
NSTimeInterval interval;
[cal rangeOfUnit:NSWeekCalendarUnit
startDate:&startOfTheWeek
interval:&interval
forDate:now];
//startOfWeek holds now the first day of the week, according to locale (monday vs. sunday)
endOfWeek = [startOfTheWeek dateByAddingTimeInterval:interval-1];
// holds 23:59:59 of last day in week.
I solve the problem thanks for Support
Code :- it give the current week start and end date.
NSDate *today = [NSDate date];
NSLog(#"Today date is %#",today);
dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:#"yyyy-MM-dd"];// you can use your format.
//Week Start Date
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *components = [gregorian components:NSWeekdayCalendarUnit | NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:today];
int dayofweek = [[[NSCalendar currentCalendar] components:NSWeekdayCalendarUnit fromDate:today] weekday];// this will give you current day of week
[components setDay:([components day] - ((dayofweek) - 2))];// for beginning of the week.
NSDate *beginningOfWeek = [gregorian dateFromComponents:components];
NSDateFormatter *dateFormat_first = [[NSDateFormatter alloc] init];
[dateFormat_first setDateFormat:#"yyyy-MM-dd"];
dateString2Prev = [dateFormat stringFromDate:beginningOfWeek];
weekstartPrev = [[dateFormat_first dateFromString:dateString2Prev] retain];
NSLog(#"%#",weekstartPrev);
//Week End Date
NSCalendar *gregorianEnd = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *componentsEnd = [gregorianEnd components:NSWeekdayCalendarUnit | NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:today];
int Enddayofweek = [[[NSCalendar currentCalendar] components:NSWeekdayCalendarUnit fromDate:today] weekday];// this will give you current day of week
[componentsEnd setDay:([componentsEnd day]+(7-Enddayofweek)+1)];// for end day of the week
NSDate *EndOfWeek = [gregorianEnd dateFromComponents:componentsEnd];
NSDateFormatter *dateFormat_End = [[NSDateFormatter alloc] init];
[dateFormat_End setDateFormat:#"yyyy-MM-dd"];
dateEndPrev = [dateFormat stringFromDate:EndOfWeek];
weekEndPrev = [[dateFormat_End dateFromString:dateEndPrev] retain];
NSLog(#"%#",weekEndPrev);
Here is Swift 3 Version:-
extension Date {
var startOfWeek: Date? {
let gregorian = Calendar(identifier: .gregorian)
guard let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return nil }
return gregorian.date(byAdding: .day, value: 1, to: sunday)
}
var endOfWeek: Date? {
let gregorian = Calendar(identifier: .gregorian)
guard let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return nil }
return gregorian.date(byAdding: .day, value: 7, to: sunday)
}
}
You can get the week start date and end date like this :
let startWeek = Date().startOfWeek
let endWeek = Date().endOfWeek
print(startWeek ?? "not found start date")
print(endWeek ?? "not found end date")
A Swift version
of vikingosegundo's answer:
let calendar = NSCalendar.currentCalendar()
var startOfTheWeek: NSDate?
var endOfWeek: NSDate!
var interval = NSTimeInterval(0)
calendar.rangeOfUnit(.WeekOfMonth, startDate: &startOfTheWeek, interval: &interval, forDate: NSDate())
endOfWeek = startOfTheWeek!.dateByAddingTimeInterval(interval - 1)
Here's an elegant way for Swift 3 (Xcode 8+):
extension Date {
var startOfWeek: Date {
let date = Calendar.current.date(from: Calendar.current.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self))!
let dslTimeOffset = NSTimeZone.local.daylightSavingTimeOffset(for: date)
return date.addingTimeInterval(dslTimeOffset)
}
var endOfWeek: Date {
return Calendar.current.date(byAdding: .second, value: 604799, to: self.startOfWeek)!
}
}
And we can use this extension like this:
print(Date().startOfWeek)
print(Date().endOfWeek)
Swift 4 Solution
I have figured out according to my requirement, where I have find out dates for following.
1. Today
2. Tomorrow
3. This Week
4. This Weekend
5. Next Week
6. Next Weekend
So, I have created Date Extension to get Dates of Current Week and Next Week.
CODE
extension Date {
func getWeekDates() -> (thisWeek:[Date],nextWeek:[Date]) {
var tuple: (thisWeek:[Date],nextWeek:[Date])
var arrThisWeek: [Date] = []
for i in 0..<7 {
arrThisWeek.append(Calendar.current.date(byAdding: .day, value: i, to: startOfWeek)!)
}
var arrNextWeek: [Date] = []
for i in 1...7 {
arrNextWeek.append(Calendar.current.date(byAdding: .day, value: i, to: arrThisWeek.last!)!)
}
tuple = (thisWeek: arrThisWeek,nextWeek: arrNextWeek)
return tuple
}
var tomorrow: Date {
return Calendar.current.date(byAdding: .day, value: 1, to: noon)!
}
var noon: Date {
return Calendar.current.date(bySettingHour: 12, minute: 0, second: 0, of: self)!
}
var startOfWeek: Date {
let gregorian = Calendar(identifier: .gregorian)
let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self))
return gregorian.date(byAdding: .day, value: 1, to: sunday!)!
}
func toDate(format: String) -> String {
let formatter = DateFormatter()
formatter.dateFormat = format
return formatter.string(from: self)
}
}
USAGE:
let arrWeekDates = Date().getWeekDates() // Get dates of Current and Next week.
let dateFormat = "MMM dd" // Date format
let thisMon = arrWeekDates.thisWeek.first!.toDate(format: dateFormat)
let thisSat = arrWeekDates.thisWeek[arrWeekDates.thisWeek.count - 2].toDate(format: dateFormat)
let thisSun = arrWeekDates.thisWeek[arrWeekDates.thisWeek.count - 1].toDate(format: dateFormat)
let nextMon = arrWeekDates.nextWeek.first!.toDate(format: dateFormat)
let nextSat = arrWeekDates.nextWeek[arrWeekDates.nextWeek.count - 2].toDate(format: dateFormat)
let nextSun = arrWeekDates.nextWeek[arrWeekDates.nextWeek.count - 1].toDate(format: dateFormat)
print("Today: \(Date().toDate(format: dateFormat))") // Sep 26
print("Tomorrow: \(Date().tomorrow.toDate(format: dateFormat))") // Sep 27
print("This Week: \(thisMon) - \(thisSun)") // Sep 24 - Sep 30
print("This Weekend: \(thisSat) - \(thisSun)") // Sep 29 - Sep 30
print("Next Week: \(nextMon) - \(nextSun)") // Oct 01 - Oct 07
print("Next Weekend: \(nextSat) - \(nextSun)") // Oct 06 - Oct 07
You can modify Extension according to your need.
Thanks!
Solution for Swift 5.x
Create Date extension:
func weekPeriod() -> (startDate: Date, endDate: Date) {
let calendar = Calendar(identifier: .gregorian)
guard let sundayDate = calendar.date(from: calendar.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return (startDate: Date(), endDate: Date()) }
if calendar.isDateInToday(sundayDate) {
let startDate = calendar.date(byAdding: .day, value: -6, to: sundayDate) ?? Date()
let endDate = sundayDate
return (startDate: startDate, endDate: endDate)
}
let startDate = calendar.date(byAdding: .day, value: 1, to: sundayDate) ?? Date()
let endDate = calendar.date(byAdding: .day, value: 6, to: startDate) ?? Date()
return (startDate: startDate, endDate: endDate)
}
First find the current date...
NSDate *today = [NSDate date];
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *weekdayComponents = [gregorian components:NSWeekdayCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit fromDate:today];
Calcuate number of days to substract from today, in order to get the first day of the week. In this case, the first day of the week is monday. This is represented by first subtracting 0 with the weekday integer followed by adding 2 to the setDay.
Sunday = 1, Monday = 2, Tuesday = 3, Wednesday = 4, Thursday = 5, Friday = 6 and Saturday = 7. By adding more to this integers, you will go into the next week.
NSDateComponents *componentsToSubtract = [[NSDateComponents alloc] init];
[componentsToSubtract setDay: (0 - [weekdayComponents weekday]) + 2];
[componentsToSubtract setHour: 0 - [weekdayComponents hour]];
[componentsToSubtract setMinute: 0 - [weekdayComponents minute]];
[componentsToSubtract setSecond: 0 - [weekdayComponents second]];
Create date for first day in week
NSDate *beginningOfWeek = [gregorian dateByAddingComponents:componentsToSubtract toDate:today options:0];
By adding 6 to the date of the first day, we can get the last day, in our example Sunday.
NSDateComponents *componentsToAdd = [gregorian components:NSDayCalendarUnit fromDate:beginningOfWeek];
[componentsToAdd setDay:6];
NSDate *endOfWeek = [gregorian dateByAddingComponents:componentsToAdd toDate:beginningOfWeek options:0];
for next and previous ....
-(IBAction)Week_CalendarActionEvents:(id)sender{
NSCalendar *gregorian = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
NSDateComponents *offsetComponents = [[[NSDateComponents alloc] init] autorelease];
NSDate *nextDate;
if(sender==Week_prevBarBtn) // Previous button events
[offsetComponents setDay:-7];
else if(sender==Week_nextBarBtn) // next button events
[offsetComponents setDay:7];
nextDate = [gregorian dateByAddingComponents:offsetComponents toDate:selectedDate options:0];
selectedDate = nextDate;
[selectedDate retain];
NSDateComponents *components = [gregorian components:NSWeekCalendarUnit fromDate:selectedDate];
NSInteger week = [components week];
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:#"MMMM YYYY"];
NSString *stringFromDate = [formatter stringFromDate:selectedDate];
[formatter release];
[Week_weekBarBtn setTitle:[NSString stringWithFormat:#"%#,Week %d",stringFromDate,week]];
}
Here's some code and it also checks an edge case where the beginning of the week starts in the prior month. You can get end of week by setting setWeekday to 7 and you can get the prior week by subtracting 1 from [components week]
// Finds the date for the first day of the week
- (NSDate *)getFirstDayOfTheWeekFromDate:(NSDate *)givenDate
{
NSCalendar *calendar = [NSCalendar currentCalendar];
// Edge case where beginning of week starts in the prior month
NSDateComponents *edgeCase = [[NSDateComponents alloc] init];
[edgeCase setMonth:2];
[edgeCase setDay:1];
[edgeCase setYear:2013];
NSDate *edgeCaseDate = [calendar dateFromComponents:edgeCase];
NSDateComponents *components = [calendar components:NSYearCalendarUnit|NSMonthCalendarUnit|NSWeekCalendarUnit|NSWeekdayCalendarUnit fromDate:edgeCaseDate];
[components setWeekday:1]; // 1 == Sunday, 7 == Saturday
[components setWeek:[components week]];
NSLog(#"Edge case date is %# and beginning of that week is %#", edgeCaseDate , [calendar dateFromComponents:components]);
// Find Sunday for the given date
components = [calendar components:NSYearCalendarUnit|NSMonthCalendarUnit|NSWeekCalendarUnit|NSWeekdayCalendarUnit fromDate:givenDate];
[components setWeekday:1]; // 1 == Sunday, 7 == Saturday
[components setWeek:[components week]];
NSLog(#"Original date is %# and beginning of week is %#", givenDate , [calendar dateFromComponents:components]);
return [calendar dateFromComponents:components];
}
Here is a solution for the swift4,
we can get all the days for the current week.
var calendar = Calendar(identifier: Calendar.Identifier.gregorian)
let today = calendar.startOfDay(for: Date())
let dayOfWeek = calendar.component(.weekday, from: today) - calendar.firstWeekday
let weekdays = calendar.range(of: .weekday, in: .weekOfYear, for: today)!
let days = (weekdays.lowerBound ..< weekdays.upperBound)
.flatMap { calendar.date(byAdding: .day, value: $0 - dayOfWeek, to: today) }
//Begining of Week Date
- (NSDate*) beginingOfWeekOfDate{
NSCalendar *tmpCalendar = [NSCalendar currentCalendar];
NSDateComponents *components = [tmpCalendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitWeekOfYear|NSCalendarUnitWeekday fromDate:self];//get the required calendar units
NSInteger weekday = tmpCalendar.firstWeekday;
components.weekday = weekday; //weekday
components.hour = 0;
components.minute = 0;
components.second = 0;
NSDate *fireDate = [tmpCalendar dateFromComponents:components];
return fireDate;
}
//End of Week Date
-(NSDate *)endOfWeekFromDate{
NSCalendar *tmpCalendar = [NSCalendar currentCalendar];
NSDateComponents *components = [tmpCalendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitWeekOfYear|NSCalendarUnitWeekday fromDate:self];//get the required calendar units
int weekday = 7; //Saturday
if (tmpCalendar.firstWeekday != 1) {
weekday = 1;
}
components.weekday = weekday;//weekday
components.hour = 23;
components.minute = 59;
components.second = 59;
NSDate *fireDate = [tmpCalendar dateFromComponents:components];
return fireDate;
}
You can get current day and date by following code:
NSDate *today = [NSDate date];
NSDateFormatter *dateFormat = [[[NSDateFormatter alloc] init] autorelease];
[dateFormat setDateFormat:#"EEEE"];
NSString *weekDay = [dateFormat stringFromDate:today];
[dateFormat setDateFormat:#"dd"];
NSString *thedate=[dateFormat stringFromDate:today];
//[dateFormat release];
NSLog(#"%# %#", weekDay,thedate);
Now, You need to put some logic in it to calculate starting date and end date of the week. The logic will be such kind,
if the week day is Monday
then
starting date = current date - 0
end date = current date + 6
and so on
I think you can get the idea of it.
By take advantage of the method rangeOfUnit:startDate:interval:forDate: of NSDate, there is a simpler way to achieve this:
- (void)startDate:(NSDate **)start andEndDate:(NSDate **)end ofWeekOn:(NSDate *)date{
NSDate *startDate = nil;
NSTimeInterval duration = 0;
BOOL b = [[NSCalendar currentCalendar] rangeOfUnit:NSWeekCalendarUnit startDate:&startDate interval:&duration forDate:date];
if(! b){
*start = nil;
*end = nil;
return;
}
NSDate *endDate = [startDate dateByAddingTimeInterval:duration-1];
*start = startDate;
*end = endDate;
}
NSDate *this_start = nil, *this_end = nil;
[self startDate:&this_start andEndDate:&this_end ofWeekOn:[NSDate date]];
So now you have the start date and end date of this week. Then last week:
NSDate *lastWeekDate = [this_start dateByAddingTimeInterval:-10];
NSDate *last_start = nil, *last_end = nil;
[self startDate:&last_start andEndDate:&last_end ofWeekOn:lastWeekDate];
Next week:
NSDate *nextWeekDate = [this_end dateByAddingTimeInterval:10];
NSDate *next_start = nil, *next_end = nil;
[self startDate:&next_start andEndDate:&next_end ofWeekOn:nextWeekDate];
Now you have them all.
Swift 3
First find the current date...
let today = Date()
let gregorian = Calendar(identifier: .gregorian)
var weekdayComponents: DateComponents? = gregorian.dateComponents([.weekday], from: today)
Sunday = 1, Monday = 2, Tuesday = 3, Wednesday = 4, Thursday = 5, Friday = 6 and Saturday = 7.
var componentsToSubtract = DateComponents()
componentsToSubtract.day = (0 - (weekdayComponents?.weekday!)!) + 2
beginningOfWeek = gregorian.date(byAdding: componentsToSubtract, to: today)
var componentsToAdd: DateComponents? = gregorian.dateComponents([.day], from: beginningOfWeek!)
componentsToAdd?.day = 6
endOfWeek = gregorian.date(byAdding: componentsToAdd!, to: beginningOfWeek!)
let components: DateComponents? = gregorian.dateComponents([.month], from: beginningOfWeek!)
let month: Int? = components?.month
let components1: DateComponents? = gregorian.dateComponents([.month], from: endOfWeek!)
let month1: Int? = components1?.month
print("\(month) - \(month1)")
showDate(start:beginningOfWeek!, end:endOfWeek!, strtMn:month!, endMn:month1!)
func showDate(start:Date, end:Date, strtMn:Int, endMn:Int) {
if strtMn == endMn{
let formatter = DateFormatter()
formatter.dateFormat = "MMM dd"
let stringFromDate: String = formatter.string(from: start)
let formatter1 = DateFormatter()
formatter1.dateFormat = "dd"
let stringFromDate1: String = formatter1.string(from: end)
print("\(stringFromDate) - \(stringFromDate1)")
lblDate.text = "\(stringFromDate) - \(stringFromDate1)"
}
else{
let formatter = DateFormatter()
formatter.dateFormat = "MMM dd"
let stringFromDate: String = formatter.string(from: start)
let formatter1 = DateFormatter()
formatter1.dateFormat = "MMM dd"
let stringFromDate1: String = formatter1.string(from: end)
print("\(stringFromDate) - \(stringFromDate1)")
lblDate.text = "\(stringFromDate) - \(stringFromDate1)"
}
}
for next and previous ....
#IBAction func week_CalendarActionEvents(_ sender: UIButton) {
let gregorian = Calendar(identifier: .gregorian)
var offsetComponents = DateComponents()
var nextStrtDate: Date?
var nextEndDate: Date?
var startDate: Date?
var endDate: Date?
startDate = beginningOfWeek
endDate = endOfWeek
if sender.tag == 1 {
offsetComponents.day = -7
}
else if sender.tag == 2 {
offsetComponents.day = 7
}
nextStrtDate = gregorian.date(byAdding: offsetComponents, to:startDate!)
startDate = nextStrtDate
beginningOfWeek = startDate
nextEndDate = gregorian.date(byAdding: offsetComponents, to: endDate!)
endDate = nextEndDate
endOfWeek = endDate
let components: DateComponents? = gregorian.dateComponents([.month], from: startDate!)
let month: Int? = components?.month
let components1: DateComponents? = gregorian.dateComponents([.month], from: endDate!)
let month1: Int? = components1?.month
print("\(month)- \(month1)")
showDate(start:startDate!, end:endDate!, strtMn:month!, endMn:month1!)
}
Swift 3+: Simple solution with extension
extension Date {
var startOfWeek: Date? {
let gregorian = Calendar(identifier: .gregorian)
guard let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return nil }
return gregorian.date(byAdding: .day, value: 1, to: sunday)
}
var endOfWeek: Date? {
let gregorian = Calendar(identifier: .gregorian)
guard let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return nil }
return gregorian.date(byAdding: .day, value: 7, to: sunday)
}
var yesterdayDate: Date? {
return NSCalendar.current.date(byAdding: .day, value: -1, to: noon)!
}
var tommorowDate: Date? {
return NSCalendar.current.date(byAdding: .day, value: 1, to: noon)!
}
var previousDate: Date? {
let oneDay:Double = 60 * 60 * 24
return self.addingTimeInterval(-(Double(oneDay)))
}
var nextDate: Date? {
let oneDay:Double = 60 * 60 * 24
return self.addingTimeInterval(oneDay)
}
var noon: Date {
return NSCalendar.current.date(bySettingHour: 12, minute: 0, second: 0, of: self)!
}
var month: Int {
return Calendar.current.component(.month, from: self)
}
}
Swift 4.2
If you want to show the current week dates, here is the code.
override func viewDidLoad() {
super.viewDidLoad()
for dateIndex in 0..<7 {
guard let startWeek = Date().startOfWeek else { return }
let date = Calendar.current.date(byAdding: .day, value: dateIndex + 1, to: startWeek)
print(date)
}
}
extension Date {
var startOfWeek: Date? {
let gregorian = Calendar(identifier: .gregorian)
guard let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return nil }
return gregorian.date(byAdding: .day, value: 1, to: sunday)
}
}
In swift 3.0
let cal = NSCalendar.current
//weekday
let weekday = cal.component(.weekday, from: Date())
var dateComp = cal.dateComponents([.hour, .minute, .second, .day, .month, .year], from: Date())
print(dateComp.day!)
//Start Date of the week - Sunday
dateComp.day = dateComp.day! - (weekday - 1)// start date of week
print(cal.date(from: dateComp)!)
//End Date of the Week - Saturday
dateComp = cal.dateComponents([.hour, .minute, .second, .day, .month, .year], from: Date())
dateComp.day = dateComp.day! + (7 - weekday)
print(cal.date(from: dateComp)!)
There are 3 steps to get Start date and End date of week from any region.
Find week day of current day.
func getTodayWeekDay() -> String {
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "EEEE"
let weekDay = dateFormatter.string(from: Date())
return weekDay
}
Make emun class for subtraction and addition of days.
i.e. if current week day is Wednesday then for getting Monday of current week we have to subtract -2 from current day.
And for getting Sunday of current week we have to add 4 into current day.
enum WeekDays: String {
case monday = "Monday"
case tuesday = "Tuesday"
case wednesday = "Wednesday"
case thursday = "Thursday"
case friday = "Friday"
case saturday = "Saturday"
case sunday = "Sunday"
var daysToSubstract: Int {
switch self {
case .monday: return 0
case .tuesday: return -1
case .wednesday: return -2
case .thursday: return -3
case .friday: return -4
case .saturday: return -5
case .sunday: return -6
}
}
var daysToAdd: Int {
switch self {
case .monday: return 6
case .tuesday: return 5
case .wednesday: return 4
case .thursday: return 3
case .friday: return 2
case .saturday: return 1
case .sunday: return 0
}
}
}
Get Start-week and End-week by subtraction and addition from current day.
extension Date {
var startOfWeek: String? {
let gregorian = Calendar(identifier: .gregorian)
let startWeek = dateFormatter.string(from:gregorian.date(byAdding: .day, value: WeekDays(rawValue: getTodayWeekDay())?.daysToSubstract ?? 0, to: self)!)
print("start-week--- \(startWeek)")
return startWeek
}
var endOfWeek: String? {
let gregorian = Calendar(identifier: .gregorian)
let endWeek = dateFormatter.string(from:gregorian.date(byAdding: .day, value: WeekDays(rawValue: getTodayWeekDay())?.daysToAdd ?? 6, to: self)!)
print("end-week--- \(endWeek)")
return endWeek
}
}
You can use functions like below:
Date().startOfWeek
Date().endOfWeek
In UILocalNotification we use NSCalendarUnitMinute like repetition ..... but I can't find in iOS 10 UserNotification doc ... How can I use NSCalendarUnitMinute like repetition in iOS 10 UserNotification?
here is the code which will schedule local notification at 8:30 pm and will repeat after every one minute.
UILocalNotification* localNotification = [[UILocalNotification alloc] init];
localNotification.fireDate = pickerDate;
localNotification.alertBody = self.textField.text;
localNotification.timeZone = [NSTimeZone defaultTimeZone];
localNotification.repeatInterval = NSCalendarUnitMinute;
localNotification.applicationIconBadgeNumber = [[UIApplication sharedApplication] applicationIconBadgeNumber] + 1;
[[UIApplication sharedApplication] scheduleLocalNotification:localNotification];
Although it appears that the old notifications framework had better support regarding this, it's only until, we realise that the new one is better!!
I had similar problems, and below is a sample of how the old notifications can go hand in hand with the new ones.
To be on a safer side, this is Swift2.3.
// Retrieve interval to be used for repeating the notification
private func retrieveRepeatInterval(repeatTemp: RepeatInterval) {
switch repeatTemp {
case .Never:
if #available(iOS 10.0, *) {
toDateComponents = NSCalendar.currentCalendar().components([.Hour, .Minute, .Day, .Month, .Year], fromDate: timeTemp!)
toDateComponents.second = 0
repeatNotification = false
} else {
repeatIntervalTemp = nil
}
case .EveryMinute:
if #available(iOS 10.0, *) {
toDateComponents.second = 0
repeatNotification = true
} else {
repeatIntervalTemp = .Minute
}
case .EveryHour:
if #available(iOS 10.0, *) {
toDateComponents = NSCalendar.currentCalendar().components([.Minute], fromDate: timeTemp!)
toDateComponents.second = 0
repeatNotification = true
} else {
repeatIntervalTemp = .Hour
}
case .EveryDay:
if #available(iOS 10.0, *) {
toDateComponents = NSCalendar.currentCalendar().components([.Hour, .Minute], fromDate: timeTemp!)
toDateComponents.second = 0
repeatNotification = true
} else {
repeatIntervalTemp = .Day
}
case .EveryWeek:
if #available(iOS 10.0, *) {
toDateComponents = NSCalendar.currentCalendar().components([.Hour, .Minute, .Weekday], fromDate: timeTemp!)
toDateComponents.second = 0
repeatNotification = true
} else {
repeatIntervalTemp = .WeekOfYear
}
case .EveryMonth:
if #available(iOS 10.0, *) {
toDateComponents = NSCalendar.currentCalendar().components([.Hour, .Minute, .Day], fromDate: timeTemp!)
toDateComponents.second = 0
repeatNotification = true
} else {
repeatIntervalTemp = .Month
}
case .EveryYear:
if #available(iOS 10.0, *) {
toDateComponents = NSCalendar.currentCalendar().components([.Hour, .Minute, .Day, .Month], fromDate: timeTemp!)
toDateComponents.second = 0
repeatNotification = true
} else {
repeatIntervalTemp = .Year
}
}
}
Although this isn't exhaustive, I've pretty much covered everything from a minute to a year.
And to be more detailed,
// RepeatInterval
enum RepeatInterval : String, CustomStringConvertible {
case Never = "Never"
case EveryMinute = "Every Minute"
case EveryHour = "Every Hour"
case EveryDay = "Every Day"
case EveryWeek = "Every Week"
case EveryMonth = "Every Month"
case EveryYear = "Every Year"
var description : String { return rawValue }
static let allValues = [Never, EveryMinute, EveryHour, EveryDay, EveryWeek, EveryMonth, EveryYear]
}
var repeatTemp: RepeatInterval?
var repeatIntervalTemp: NSCalendarUnit?
var timeTemp: NSDate?
var toDateComponents = NSDateComponents()
As this works for me, it should probably for the rest of you. Please try and let me know if there is an issue.
And, for the exact solution to this question, I'd advise the below.
(Probably, Apple didn't think about such a scenario, but it can be handled)
Schedule a notification for 8:30 PM
When the notification is triggered, remove it and schedule another notification with a different identifier, for the NSCalendarUnitMinute equivalent shown above.
Voila, it works!! (Or did it not?)
Use a UNCalendarNotificationTrigger with DateComponents instead of NSCalendar:
var date = DateComponents()
date.hour = 8
date.minute = 30
let trigger = UNCalendarNotificationTrigger(dateMatching: date, repeats: true)
let content = UNNotificationContent()
// edit your content
let notification = UNNotificationRequest(identifier: "myNotification", content: content, trigger: trigger)
You set up the date with a DateComponents instance and specify if the notification should repeat with the repeats parameter of the UNCalendarNotificationTrigger initializer.
UNCalendarNotificationTrigger Documentation
Just a heads up that there is a typo in the Apple Docs (as of 6/13). If you use NSDateComponents instead of DateComponents, you will need to explicitly cast your date as DateComponents in the dateMatching parameter.
In response to your comment, I don't believe the behavior you want (changing the frequency of your repeated notification) is supported by UNCalendarNotificationTrigger.
Bear with me this is my first post.
We needed the 1 minute repeat interval for our app in ios 10, and used as a workaround a combination the old and new framework.
scheduling the repeating local notifications with the old:
UILocalNotification *ln = [[UILocalNotification alloc] init];
...
ln.repeatInterval = kCFCalendarUnitMinute;
ln.userInfo = #{#"alarmID": ...}
...
[[UIApplication sharedApplication] scheduleLocalNotification:ln];
This will create and schedule the usual repeating LNs that will show up as UNNotification with a UNLegacyNotificationTrigger
I used a alarmID to connect old and new framework.
Try:
UNUserNotificationCenter* center = [UNUserNotificationCenter
currentNotificationCenter];
[center getPendingNotificationRequestsWithCompletionHandler:^(NSArray<UNNotificationRequest *> * _Nonnull requests) {
NSLog(#"----------------- PendingNotificationRequests %i -------------- ", (int)requests.count);
for (UNNotificationRequest *req in requests) {
UNNotificationTrigger *trigger = req.trigger;
NSLog(#"trigger %#", trigger);
}
}];
responding to actions and fire-ing notifications, manipulating the notification centre:
With the new framework UNUserNotificationCenter methods:
willPresentNotification:
didReceiveNotificationResponse:
Request authorization and category registration I did for both frameworks in the usual way.
Hope this helps
I have a time interval, say, 12600, which is equivalent to 3 hours 30 minutes. How could I format any such time interval so that only the highest part of the interval (for example in this case figure, the hours) is kept and have the correct locale abbreviation be appended to the number. For example 10m (10 minutes), 3d (3 days), 1y (1 years).
EDIT: Here are some examples:
Time interval in: 90000 Whole string: 1d String out: 1d
Time interval in: 900 Whole string: 15m String out: 15m
Time interval in: 13500 Whole String: 3h 45m String out: 4h
As a general rule, apply the normal rounding rules (3.4 rounds down, 3.6 rounds up).
If you are targeting newer OS versions (iOS 13.5+, OS X 10.15+), you can use RelativeDateTimeFormatter:
let formatter = RelativeDateTimeFormatter()
formatter.dateTimeStyle = .named
for d in [-12600.0, -90000.0, -900.0, 13500.0] {
let str = formatter.localizedString(fromTimeInterval: d)
print("\(d): \(str)")
}
// Output
-12600.0: 3 hours ago
-90000.0: yesterday
-900.0: 15 minutes ago
13500.0: in 3 hours
For older OS versions, use DateComponentFormatter, available since iOS 8:
func format(duration: TimeInterval) -> String {
let formatter = DateComponentsFormatter()
formatter.allowedUnits = [.day, .hour, .minute, .second]
formatter.unitsStyle = .abbreviated
formatter.maximumUnitCount = 1
return formatter.string(from: duration)!
}
for d in [12600.0, 90000.0, 900.0, 13500.0] {
let str = format(duration: d)
print("\(d): \(str)")
}
This prints:
12600.0: 4h
90000.0: 1d
900.0: 15m
13500.0: 4h
Just in case anyone wants it.. Swift 4
extension TimeInterval {
func format(using units: NSCalendar.Unit) -> String? {
let formatter = DateComponentsFormatter()
formatter.allowedUnits = units
formatter.unitsStyle = .abbreviated
formatter.zeroFormattingBehavior = .pad
return formatter.string(from: self)
}
}
Example usage:
let value:TimeInterval = 12600.0
print("\(value.format(using: [.hour, .minute, .second])!)")
and the result will be:
3h 30m 0s
Swift 3 extension:
extension TimeInterval {
func format() -> String? {
let formatter = DateComponentsFormatter()
formatter.allowedUnits = [.day, .hour, .minute, .second, .nanosecond]
formatter.unitsStyle = .abbreviated
formatter.maximumUnitCount = 1
return formatter.string(from: self)
}
}
Take a look at the NSDateComponentsFormatter class. It lets you calculate whatever units you want either using 2 dates or using an NSTimeInterval, and supports different languages and locales automatically. There have been a couple of posts here in SO on the subject.
You can use NSDate and NSCalendar. You can say something like:
let timeInterval:Double = 12600
let calendar = NSCalendar.currentCalendar()
let date = NSDate(timeInterval: -timeInterval, sinceDate: NSDate())
let components = calendar.components([.Year,.Day,.Hour, .Minute, .Second, .Nanosecond], fromDate: date, toDate: NSDate(), options: [])
let hour = components.hour //3
let minute = components.minute //30
Per duncan's and rmaddy's suggestions use NSDateComponentsFormatter
I created a function for you! I hope you like it. And this is super easy to implement and very customizable.
func totime(time: Double) -> (String) {
var timex = time
var fancytime: String = "a while"
if time < 61 {
fancytime = "\(timex)s"
} else if time < 3601 {
timex = timex/60
timex = round(timex)
fancytime = "\(timex)m"
} else if time < 86401 {
timex = timex/3600
timex = round(timex)
fancytime = "\(timex)h"
} else if Double(time) < 3.15576E+07 {
timex = timex/86400
timex = round(timex)
fancytime = "\(timex)d"
} else {
fancytime = "more than one year"
}
fancytime = fancytime.stringByReplacingOccurrencesOfString(".0", withString: "")
return fancytime
}
Tested, and it works flawlessly:
print(totime(90000)) // prints "1d"
print(totime(900)) // prints "15m"
print(totime(13500)) // prints "4h"
Just call it with totime(Double).
Hello I have a method that returns an array of times for each day.
prayTimesDate(date: NSDate, latitide : Double, longitude : Double, timeZone : Double) -> NSMutableArray
I need to iterate through a whole year or maybe a date range to get an array of times for each day in a whole year. I found alot of references in ruby and python on how to do this but I couldn't find anything for swift or objective-c. Is there any built in methods in swift that will accomplish this? If not can someone help me out as I am still new in programming. Any input is greatly appreciated.
This is the objective-c code for the method I'm linking to my swift project
- (NSMutableArray *)prayerTimesDate:(NSDate *)date latitude:(double)latitude longitude:(double)longitude andTimezone:(double)timezone
{
unsigned unitFlags = NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay;
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:unitFlags fromDate:date];
NSInteger year = [components year];
NSInteger month = [components month];
NSInteger day = [components day];
return [self getDatePrayerTimesForYear:year month:month day:day latitude:latitude longitude:longitude andtimeZone:timezone];
}
Assuming your prayerTimesDate: method is already returning the expected result, you can loop through each day of the year while repeatedly call prayerTimesDate: to get an array containing the prayer times for each day, ex:
func yearlyPrayerDatesFromCurrentDate (latitude:Double, longitude:Double, timezone:Double) -> NSMutableArray {
// Set "date" to equal the current day
var date:NSDate! = NSDate()
// Increment "date" by one year to calculate the ending
// date for the loop
let gregorian:NSCalendar! = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian)
let dateComponents = NSDateComponents()
dateComponents.year = 1
let endingDate:NSDate! = gregorian.dateByAddingComponents(dateComponents, toDate: date, options: nil)
// Create an array to hold *all* the returned
// results for the year
var datesArray = NSMutableArray()
// Loop through each date until the ending date is
// reached
while date.compare(endingDate) != NSComparisonResult.OrderedDescending {
// Call your prayerTimesDate: method on the current
// date to get that date's prayer times and add the
// times from the returned array to the datesArray
datesArray.addObjectsFromArray(prayerTimesDate(date, latitude: latitude, longitude: longitude, andTimezone: timezone))
// increment the date by 1 day
let dateComponents = NSDateComponents()
dateComponents.day = 1
date = gregorian.dateByAddingComponents(dateComponents, toDate: date, options: nil)
}
return datesArray
}
Here is another example for a period over 14 days (without NSCalendar):
let ti:NSTimeInterval = 24*60*60 //one day
let dateFrom = NSDate() //Now
let dateTo = dateFrom.dateByAddingTimeInterval(24*60*60*14) //14 Days later
var nextDate = NSDate()
var endDate = dateTo.dateByAddingTimeInterval(ti)
while nextDate.compare(endDate) == NSComparisonResult.OrderedAscending
{
print("nextDate:", nextDate)
nextDate = nextDate.dateByAddingTimeInterval(ti)
}
Create an NSDateComponents instance for 1 day and NSDate objects for each time on the first day. Now you can iterate over the number of days you want (or until you hit then end date) and then you can use dateByAddingComponents:toDate:options: of the calendar to get the new date for each day.
From Apple doc: To compute a sequence of dates, use the enumerateDatesStartingAfterDate:matchingComponents:options:usingBlock: method instead of calling this method ( - nextDateAfterDate:matchingComponents:options: ) in a loop with the previous loop iteration's result.
As I got, it will iterate all dates that matched with "matchingComponents" till you finish iteration with "stop.memory = true"
//: Playground - noun: a place where people can play
import UIKit
let calendar = NSCalendar.currentCalendar()
let startDate = calendar.startOfDayForDate(NSDate())
let finishDate = calendar.dateByAddingUnit(.Day, value: 10, toDate: startDate, options: [])
let dayComponent = NSDateComponents()
dayComponent.hour = 1
calendar.enumerateDatesStartingAfterDate(startDate, matchingComponents: dayComponent, options: [.MatchStrictly]) { (date, exactMatch, stop) in
print(date)
if date!.compare(finishDate!) == NSComparisonResult.OrderedDescending {
// .memory gets at the value of an UnsafeMutablePointer
stop.memory = true
}
}
I came across a situation where I needed to restrict a UIDatePicker's selected hour, but still allow free selection of the day. This would be useful if you wanted to allow a user to select a date/time during set business hours. I found something that was close to what I was wanting to do by alerting the user that their selection was bad, but didn't actually change the date on the picker, so I wanted to share my solution Q&A-style.
This particular example will not allow selection of times before 7:00am or after 9:59pm. Selection of an "invalid" time will immediately slide the UIDatePicker back to the closest valid time on the respective end of the spectrum (for example, selection of 10:02pm will immediately slide back to 9:59pm)
- (void)datePickerChanged
{
NSDateComponents *components = [[NSCalendar currentCalendar] components:NSYearCalendarUnit|NSMonthCalendarUnit|NSDayCalendarUnit|NSHourCalendarUnit|NSMinuteCalendarUnit fromDate:datePicker.date];
if([components hour] < 7)
{
[components setHour:7];
[components setMinute:0];
[datePicker setDate:[[NSCalendar currentCalendar] dateFromComponents:components]];
}
else if([components hour] > 21)
{
[components setHour:21];
[components setMinute:59];
[datePicker setDate:[[NSCalendar currentCalendar] dateFromComponents:components]];
}
}
Edit: As #DuncanC suggested in the comments, feedback to the user should probably be included, such as a label saying "Only times between 7:00am and 9:59pm can be used"
In Swift2.0:
func datePickerChanged() {
let components = NSCalendar.currentCalendar().components(
[NSCalendarUnit.Year, NSCalendarUnit.Month, NSCalendarUnit.Day, NSCalendarUnit.WeekOfYear, NSCalendarUnit.Hour, NSCalendarUnit.Minute, NSCalendarUnit.Second, NSCalendarUnit.Weekday, NSCalendarUnit.WeekdayOrdinal, NSCalendarUnit.WeekOfYear],
fromDate: datePickerInstance.date)
if components.hour < 7 {
components.hour = 7
components.minute = 0
datePickerInstance.setDate(NSCalendar.currentCalendar().dateFromComponents(components)!, animated: true)
}
else if components.hour > 21 {
components.hour = 21
components.minute = 59
datePickerInstance.setDate(NSCalendar.currentCalendar().dateFromComponents(components)!, animated: true)
}
else {
print("Everything is good.")
}
}
If you want to actually limit the hours that are displayed, I built a custom picker for that purpose. It's a subclass of UIPickerView and it replicates the functionality of UIDatePicker in countDownTimer mode, while adding support to set maxTimeInterval.
You use it like this:
GSTimeIntervalPicker *picker = [[GSTimeIntervalPicker alloc] init];
picker.maxTimeInterval = (3600 * 3); // set the limit
picker.minuteInterval = 5; // the step. Default is 1 min.
picker.timeInterval = (3600 * 1.5); // 1 h 30 minutes
picker.onTimeIntervalChanged = ^(NSTimeInterval newTimeInterval) {
// Use the value
};
Available on GitHub under MIT license. Blog post here.
In Swift 4:
func datePickerChanged() {
var components = Calendar.current.dateComponents([.hour, .minute, .month, .year, .day], from: datePicker.date)
if components.hour! < 7 {
components.hour = 7
components.minute = 0
datePicker.setDate(Calendar.current.date(from: components)!, animated: true)
}
else if components.hour! > 21 {
components.hour = 21
components.minute = 59
datePicker.setDate(Calendar.current.date(from: components)!, animated: true)
}
else {
print("Everything is fine!")
}
}