Want to display API data to labels (Swift, Alamofire) - ios

Question

I am using Alamofire to call the Riot API and I want to display the information that it has called. I have the get request working, I just don't know how to link to a label in the application. I have included screenshots of the code!
Code
Response
It is just a simple app I am creating!
func callAlamo(url: String){
Alamofire.request(url).responseJSON(completionHandler: {
response in
self.pasrseData(JSONData: response.data!)
})
}
func parseData(JSONData: Data){
do {
var readableJSON = try JSONSerialization.jsonObject(with: JSONData, options: .mutableContainers) as? JSONStandard
print(readableJSON)
}
catch {
print(error)
}
}

Answer 1

No need to serialize since responseJSONfrom Alamofire has done it. Since I don't know what is inside of your JSON object, let's say that you get a return of age and name:
struct InfoModel { // this struct will decompose our JSON object from the response that we get
var age:Int
var name:String
init(json:Dictionary<String,Any>?) {
guard let dict = json,
let age = dict["age"] as? Int,
let name = dict["name"] as? String
else {fatalError() }
self.age = age
self.name = name
}
}
func parse(url: String, completion:#escaping (InfoModel)-> Void) {
Alamofire.request(url).responseJSON {response in
// get the JSON dictionary
if let JSON = response.result.value {
// no need to decompose your object since your struct does it inside of its initializer
completion(InfoModel(json: JSON as? Dictionary<String, Any>))
}
}
}
// call this function anywhere
parse(url: "") { (m:InfoModel) in
print("age= \(m.age), name= \(m.name)")
// now populate your label
labelOne.text = "\(m.age)"
labelTwo.text = name
}

Answer 2

You set the text property of the label in the completion block, basically:
func callAlamo(url: String){
Alamofire.request(url).responseJSON(completionHandler: {
response in
// here we say get me a non optional data (otherwise don't do the if)
if let data = response.data {
// here we are saying if you can't get me a value (i.e. not nil) for:
// json (note the try? will give nil if there is an error)
// name, we get the name out of the json dictionary
// then go to the else block, where we exit the function
// Happy case where we values for json and name we now have non optional variables W00t
guard
let json = try? self.parseData(JSONData: data),
let name = json["name"] as? String
else {
print("name does not exist in json: \(json)")
return
}
// Time to set the label
self.name.text = name
}
})
}
// Changed this to return JSON as a dictionary (it looks like what you printed was a dictionary)
// I also changed this so it throws the error and doesn't deal with it.
// It probably doesn't know what to do if it can't read json something
// else should handle the error higher up the stack
func parseData(JSONData: Data) throws -> [String: Any]? {
return try JSONSerialization.jsonObject(with:
JSONData, options: .mutableContainers) as? [String: Any]
}
NB: This is untested if your having problems and I'll go for a tested solution.
Edit: Answering how to get another property.
The way we got "name" was this chunk of code:
guard
let json = try? self.parseData(JSONData: data),
let name = json["name"] as? String
else {
print("name does not exist in json: \(json)")
return
}
To get another property out we could do this:
guard
let json = try? self.parseData(JSONData: data),
let name = json["name"] as? String,
let summonerLevel = json["summonerLevel"] as? Int
else {
print("name does not exist in json: \(json)")
return
}
Then to display summonerLevel we do the same as with name (although we have an int not a String)
// Time to set the label
self.name.text = name
// (you will have to create this new label)
self.summonerLevelLabel.text = "Level: \(summonerLevel)"