I have a huge array full of a bunch of hashes. What I need to do is single out one index hash from the array that meets a specific criteria. (doing this due to an rspec test, but having trouble singling out one of them)
My array is like this
[
{
"name" => "jon doe",
"team" => "team2",
"price" => 2000,
"eligibility_settings" => {}
},
{
"name" => "jonny doe",
"team" => "team1",
"value" => 2000,
"eligibility_settings" => {
"player_gender" => male,
"player_max_age" => 26,
"player_min_age" => 23,
"established_union_only" => true
}
},
{
"name" => "jonni doe",
"team" => "team3",
"price" => 2000,
"eligibility_settings" => {}
},
]
I need to single out the second one, based on its eligibility settings. I just took three of them from my array, have lots more, so simple active record methods like (hash.second) won't work in this instance.
I've tried things like
players.team.map(&:hash).find{ |x| x[ 'eligibility_settings?' ] == true}
However when I try this, I get a nil response. (which is odd)
I've also looked into using the ruby detect method, which hasn't gotten me anywhere either
Players.team.map(&:hash).['hash.seligibiltiy_settings'].detect { true }
Would anybody have any idea what to do with this one?
Notes
players.team.map(&:hash).find{ |x| x[ 'eligibility_settings?' ] == true}
Players.team.map(&:hash).['hash.seligibiltiy_settings'].detect { true }
Is is players or Players ?
Why is it plural?
If you can call map on team, it probably should be plural
Why do you convert to a hash?
eligibility_settings? isn't a key in your hash. eligibility_settings is
eligibility_settings can be a hash, but it cannot be true
If you want to check if it isn't empty, use !h['eligibility_settings'].empty?
Possible solution
You could use :
data = [
{
'name' => 'jon doe',
'team' => 'team2',
'price' => 2000,
'eligibility_settings' => {}
},
{
'name' => 'jonny doe',
'team' => 'team1',
'value' => 2000,
'eligibility_settings' => {
'player_gender' => 'male',
'player_max_age' => 26,
'player_min_age' => 23,
'established_union_only' => true
}
},
{
'name' => 'jonni doe',
'team' => 'team3',
'price' => 2000,
'eligibility_settings' => {}
}
]
p data.find { |h| !h['eligibility_settings'].empty? }
# {"name"=>"jonny doe", "team"=>"team1", "value"=>2000, "eligibility_settings"=>{"player_gender"=>"male", "player_max_age"=>26, "player_min_age"=>23, "established_union_only"=>true}}
If h['eligibility_settings'] can be nil, you can use :
data.find { |h| !h['eligibility_settings'].blank? }
or
data.find { |h| h['eligibility_settings'].present? }
Related
I have two queries I am running and iterating over both and my final hash is seen below. But, I want to have format on how the data is being stored in the hash that I'm creating or format it after I'm done creating it. But I am not sure how to achieve the desired format where the names fall under the same id as show below
desired format of example data:
[
{
id: 1,
accepted: false,
trans: 10234
names: [
{ name: "Joe", amount: "$1,698.00" },
{ name: "Smith", amount: "$674.24" },
]
},
{
id: 2,
accepted: true,
trans: 10234,
names: [
{ name: "Joe", amount: "$1,698.00" },
{ name: "Smith", amount: "$674.24" },
]
}
]
current format I have
[
{
:id => 1,
:accepted => false,
:trans => 8,
:name => "Smith",
:amount => 36.0
},
{
:id => 1,
:amount => false,
:trans => 8,
:name => "Joe",
:amount => 6.0
},
{
:id => 3,
:accepted => false,
:trans => 8,
:name => "Tom",
:amount => 34.0
},
{
:id => 3,
:accepted => false,
:trans=> 8,
:name => "Martha",
:amount => 4.0
}
],
[
{
:id => 2,
:accepted => true,
:trans => 7,
:name => "Bob",
:amount => 35.0
},
{
:id => 2,
:accepted => true,
:trans => 7,
:name => "John",
:amount => 5.0
}
]
logic for creating hash
imports = ListImports.limit(20).order(created_at: :DESC)
groups = imports.map{|import| ListImportGroup.where(list_import_id: import.id)}
pub_hash_true = []
pub_hash_false = []
hash = []
imports.map do |import|
hash << {
id: import.id,
trans: import.trans,
accepted: import.amount
}
end
hash.each do |import|
groups.flatten.each do |group|
accepted = import[:accepted]
num_transactions = import[:trans]
if accepted == false
pub_hash_false << {id: import[:id], accepted: accepted, trans: num_transactions, name: group.name, amount: group.amount}
else
pub_hash_true << {id: import[:id], accepted: accepted, trans: num_transactions, name: group.name, amount: group.amount}
end
end
end
# Note: You didn't specify what is the association between `ListImport` and `ListImportGroup`.
# However, I'm fairly sure you could be fetching this data via a JOIN query like below,
# rather than making up to 20 additional database calls to fetch the associated records.
imports = ListImports.limit(20).order(created_at: :DESC).includes(:list_import_group)
result = imports.map do |import|
{
id: import.id,
trans: import.trans,
accepted: import.amount,
names: import.list_import_groups.pluck(:name, :amount)
}
end
And if you do actually need to filter for imports where accepted is true or false, you could do something like this instead of building separate arrays manually:
accepted_imports = result.select { |import| import[:accepted] }
# and
rejected_imports = result.reject { |import| import[:accepted] }
# or even:
accepted_imports, rejected_imports = result.partition { |import| import[:accepted] }
You didn't specify the exact correspondence between the desired and current formats.
But I assume
For the entries with the same id, the values of accepted and trans are identical.
the desired amount for Joe in the current format is identical in the corresponding amount in the desired amount. (In your example, the former is 6.0 whereas the latter is "$1,698.00", which does not make sense.)
Then, the following would do the conversion. The array ahout is in the desired format.
# Let us assume "a1" is the original array in the "current format"
hout = {}
a1.flatten.map{|h|
h.slice(*(%i(id trans name amount accepted))).values
}.each{ |a|
hout[a[0]] = {id: a[0], accepted: a[4], trans: a[1], names: []} if !hout.key? a[0]
hout[a[0]][:names].push(
{name: a[2], amount: "$"+helper.number_with_precision(a[3], precision: 2, delimiter: ',')}
)
}
ahout = hout.values
You may want to sort ahout, if you like.
Note that I am assuming you are using Rails 5+. Otherwise, the method helper may not work. In that case, you can use sprintf or whatever formatting method.
I would like to transform this
def some_process(k,v)
return "#{v}_#{k}"
end
a_hash = {
"i_love_hashes" => {
"thing" => 20,
"other_thing" => "0",
"yet_another_thing" => "i disagree",
"_peculiar_thing" => [
{"count" => 30,
"name" => "freddie"},
{"count" => 15,
"name" => "johhno"},
{"count" => 12,
"name" => "mohammed"},
]
},
"as_do_i" => {
"thing" => 10,
"other_thing" => "2",
"yet_another_thing" => "i strongly agree",
"_peculiar_thing" => [
{"count" => 10,
"name" => "frodo"},
{"count" => 4,
"name" => "bilbo"},
{"count" => 2,
"name" => "elizabeth"},
]
}
}
into this
{
"i_love_hashes"=>{
"thing"=>20,
"other_thing"=>"0",
"yet_another_thing"=>"i disagree",
"_peculiar_thing"=> [
{"count"=>30, "name"=>"freddie", :sinister_name=>"freddie_i_love_hashes"},
{"count"=>15, "name"=>"johhno", :sinister_name=>"johhno_i_love_hashes"},
{"count"=>12, "name"=>"mohammed", :sinister_name=>"mohammed_i_love_hashes"}
]},
"as_do_i"=>{
"thing"=>10,
"other_thing"=>"2",
"yet_another_thing"=>"i strongly agree",
"_peculiar_thing"=>[
{"count"=>10, "name"=>"frodo", :sinister_name=>"frodo_as_do_i"},
{"count"=>4, "name"=>"bilbo", :sinister_name=>"bilbo_as_do_i"},
{"count"=>2, "name"=>"elizabeth", :sinister_name=>"elizabeth_as_do_i"}
]
}
}
this is the code I am currently using to achieve this
a_hash.each_with_object({}) do |(k,v),o|
o.merge!({k =>
v.each_with_object({}) do |(a,b),g|
g.merge!({ a =>
(b.is_a?(Array) ? b.collect {|x| x.merge({sinister_name: (some_process k, x["name"])})} : b)
})
end
})
end
Ignoring the specific details of what is being returned by "some_process" (what is important is that it depends on the outer most key and the inner name values, in this example), are there any alternatives that would be considered more elegant?
Why not do a recursive function?
def add_siniter(hash)
hash[:siniter_name] = "#{hash['name']}_i_love_hashes"
hash
end
def format_hash(item)
case item
when Hash then item.keys.each{|key| format_hash(item[key])}
when Array then item.map!{|h| add_siniter(h)}
end
end
format_hash(a_hash)
1) How can I grab all songs with more than 50 likes? The result set should return an array of songs instead of the whole document.
2) How can I return the results of a specific song id instead of the whole document?
So far I've come across this concept of virtual collections for embedded objects. However, it hasn't been implemented since. Although, on the same link, someone suggests using the aggregation framework for such a thing. Is this a viable solution?
I have the following document structure:
document = {
'date' => Time.now.utc.strftime('%Y%m%d'),
'songs' => {
'1' => {
'views' => {
'non_uniques' => 2000,
'uniques' => 203
},
'countries' => {
'us' => 123,
'uk' => 11
},
'likes' => 123,
'comments' => 123
},
'2' => {
'views' => {
'non_uniques' => 2000,
'uniques' => 203
},
'countries' => {
'us' => 123,
'uk' => 11
},
'likes' => 123,
'comments' => 123
}
},
'sign_ins' => {
'non_uniques' => 2000,
'uniques' => 203
}
}
Expected output (as requested)
For question 1), somewhere within the lines of:
['1' => {
'views' => {
'non_uniques' => 2000,
'uniques' => 203
},
'countries' => {
'us' => 123,
'uk' => 11
},
'likes' => 123,
'comments' => 123
},
'2' => {
'views' => {
'non_uniques' => 2000,
'uniques' => 203
},
'countries' => {
'us' => 123,
'uk' => 11
},
'likes' => 123,
'comments' => 123
}]
For 2):
'1' => {
'views' => {
'non_uniques' => 2000,
'uniques' => 203
},
'countries' => {
'us' => 123,
'uk' => 11
},
'likes' => 123,
'comments' => 123
}
Use aggregation framework like this:
db.songs.aggregate({$unwind:"$songs"},{$match:{"songs.likes":{$gt:50}}})
Now you can add other stages like {$group} if you want things back in one doc, or $project to change the field names, etc.
Change the '=>' delimiter in the document. Then you will have a JSON file
document = JSON.parse(document)
You will get a hash. Then check if likes > 50 in the hash
document[].each do |song|
song[].each do |id|
if id[likes].to_i > 50
#Do what you want to do
end
end
end
Hope that helps
Try:
songs_arr = []
document["songs"].keys.each do |key|
songs_arr << "insert songs here" if document["songs"][key]["likes"] > 50
end
I have an array like this:
['one','three','two','four']
I have a array of hash like this:
[{'three' => {..some data here..} }, {'two' => {..some data here..} }, {:total => some_total }] # etc...
I want to sort the array of hashes by the first array. I know I can do:
array_of_hashes.sort_by{|k,v| k.to_s} to sort them and it will sort by the key
( and the .to_s to convert :total to a string )
How can I make this happen?
Edit:
I was incorrect about how this is setup, it is actually like this:
{'one' => {:total => 1, :some_other_value => 5}, 'two' => {:total => 2, :some_other_value => 3} }
If I need to put this in a new question, just let me know and I will do that.
Thank you
similar to ctcherry answer, but using sort_by.
sort_arr = ['one','three','two','four']
hash_arr = [{'three' => {..some data here..} }, {'two' => {..some data here..} }]
hash_arr.sort_by { |h| sort_arr.index(h.keys.first) }
The index method of Array is your friend in this case:
sort_list = ['one','three','two','four']
data_list = [{'three' => { :test => 3 } }, {'two' => { :test => 2 } }, {'one' => { :test => 1 } }, {'four' => { :test => 4 } }]
puts data_list.sort { |a,b|
sort_list.index(a.keys.first) <=> sort_list.index(b.keys.first)
}.inspect
Resulting in, the same order as the source array:
[{"one"=>{:test=>1}}, {"three"=>{:test=>3}}, {"two"=>{:test=>2}}, {"four"=>{:test=>4}}]
I am using Ruby on Rails 3 and I would like to "trasform" the following array so that I can use my custom logic to access its data.
This is the original array from which I have to build a new one
[
{
"account" => {
"id" => 45,
"name" => "Test_name",
"..." => ..."
}
},
{
"other" => {
"sub_other" => {...}
}
}
]
I would like to trasform the above array so that I can do in my controller something like
array_name[45]
# => {
"name" => "Test_name",
"..." => ..."
}
but only for the account hashs. The other hash should remain untouched.
How can I proceed to build the new array?
If I understand your requirements correctly, I think you are better off constructing a hash from account id to account data. Perhaps something like this will work:
arr = [
{
"account" => {
"id" => 45,
"name" => "Test_name",
"..." => "..."
}
},
{
"other" => {
"sub_other" => "..."
}
}
]
account_hashes = arr.select {|item| item.keys.first == "account"}
answer = account_hashes.inject({}) do |acc, item|
acc[item["account"].delete("id")] = item["account"]
acc
end