local t = "{{2173,1},{2160,5}}"
print(#t) -- 19?? wrong
How to convert to appear in numbers?
local t = {{2173,1},{2160,5}}
print(#t) -- 2 correct
You can run the string through load or loadstring (depending on your Lua version), which will return the table you are looking for:
local t = "{{2173,1},{2160,5}}"
t = (loadstring or load)("return "..t)()
print(#t) -- 2
Here is an ad hoc solution for the input you gave:
local s = "{{2173,1},{2160,5}}"
local t = {}
local n = 0
for a,b in s:gmatch("(%d+),(%d+)") do
n = n + 1
t[n] = {a,b}
end
for k,v in ipairs(t) do print(k,v[1],v[2]) end
Related
So I want to take an input like R U R' U' and turn it into a table that contains
R
U
R'
U'
I haven't found an example of code that worked. I have tried this solution from codegrepper, and it didn't work. I have not come up with anything else in my head but my general program, which is supposed to take an input like R and find its place in a table. If R is 1, then it will take the value 1 from another table, which will have the r^ as value 1. Then it will do this with the rest and print it when it is done. So if there is an optimization with this that could make it all quicker than I would like to see it. Thanks and goodbye.
function split(str, pat)
local t = {}
local fpat = "(.-)" .. pat
local last_end = 1
local s, e, cap = str:find(fpat, 1)
while s do
if s ~= 1 or cap ~= "" then table.insert(t, cap) end
last_end = e + 1
s, e, cap = str:find(fpat, last_end)
end
if last_end <= #str then
cap = str:sub(last_end)
table.insert(t, cap)
end
return t
end
then split it with split(var," ")
local myString = "R U R' U'"
local myTable = {}
for e in string.gmatch(myString, "%S+") do
table.insert(myTable, e)
end
Lua Users Wiki
s:gmatch(pattern)
This returns a pattern finding iterator. The iterator will search
through the string passed looking for instances of the pattern you
passed.
First you need to match all the space-separated parts. You can do this using gmatch. Then you can insert these parts as keys in a hash table, the value being the one-indexed index of the occurrence:
local str = "R U R' U'"
local index = 1
local last_occurrence = {}
for match in str:gmatch"%S+" do
last_occurrence[match] = index
index = index + 1
end
Now you can use your "other table" to obtain the value in constant time:
local other_table = {"r^"}
local value = other_table[last_occurrence.R] -- "r^"
Sounds like a "let me google it for you" question, but somehow I can't find an answer. The Lua # operator only counts entries with integer keys, and so does table.getn:
tbl = {}
tbl["test"] = 47
tbl[1] = 48
print(#tbl, table.getn(tbl)) -- prints "1 1"
count = 0
for _ in pairs(tbl) do count = count + 1 end
print(count) -- prints "2"
How do I get the number of all entries without counting them?
You already have the solution in the question -- the only way is to iterate the whole table with pairs(..).
function tablelength(T)
local count = 0
for _ in pairs(T) do count = count + 1 end
return count
end
Also, notice that the "#" operator's definition is a bit more complicated than that. Let me illustrate that by taking this table:
t = {1,2,3}
t[5] = 1
t[9] = 1
According to the manual, any of 3, 5 and 9 are valid results for #t. The only sane way to use it is with arrays of one contiguous part without nil values.
You can set up a meta-table to track the number of entries, this may be faster than iteration if this information is a needed frequently.
The easiest way that I know of to get the number of entries in a table is with '#'. #tableName gets the number of entries as long as they are numbered:
tbl={
[1]
[2]
[3]
[4]
[5]
}
print(#tbl)--prints the highest number in the table: 5
Sadly, if they are not numbered, it won't work.
There's one way, but it might be disappointing: use an additional variable (or one of the table's field) for storing the count, and increase it every time you make an insertion.
count = 0
tbl = {}
tbl["test"] = 47
count = count + 1
tbl[1] = 48
count = count + 1
print(count) -- prints "2"
There's no other way, the # operator will only work on array-like tables with consecutive keys.
function GetTableLng(tbl)
local getN = 0
for n in pairs(tbl) do
getN = getN + 1
end
return getN
end
You're right. There are no other way to get length of table
You could use penlight library. This has a function size which gives the actual size of the table.
It has implemented many of the function that we may need while programming and missing in Lua.
Here is the sample for using it.
> tablex = require "pl.tablex"
> a = {}
> a[2] = 2
> a[3] = 3
> a['blah'] = 24
> #a
0
> tablex.size(a)
3
local function CountedTable(x)
assert(type(x) == 'table', 'bad parameter #1: must be table')
local new_t = {}
local mt = {}
-- `all` will represent the number of both
local all = 0
for k, v in pairs(x) do
all = all + 1
end
mt.__newindex = function(t, k, v)
if v == nil then
if rawget(x, k) ~= nil then
all = all - 1
end
else
if rawget(x, k) == nil then
all = all + 1
end
end
rawset(x, k, v)
end
mt.__index = function(t, k)
if k == 'totalCount' then return all
else return rawget(x, k) end
end
return setmetatable(new_t, mt)
end
local bar = CountedTable { x = 23, y = 43, z = 334, [true] = true }
assert(bar.totalCount == 4)
assert(bar.x == 23)
bar.x = nil
assert(bar.totalCount == 3)
bar.x = nil
assert(bar.totalCount == 3)
bar.x = 24
bar.x = 25
assert(bar.x == 25)
assert(bar.totalCount == 4)
I stumbled upon this thread and want to post another option. I'm using Luad generated from a block controller, but it essentially works by checking values in the table, then incrementing which value is being checked by 1. Eventually, the table will run out, and the value at that index will be Nil.
So subtract 1 from the index that returned a nil, and that's the size of the table.
I have a global Variable for TableSize that is set to the result of this count.
function Check_Table_Size()
local Count = 1
local CurrentVal = (CueNames[tonumber(Count)])
local repeating = true
print(Count)
while repeating == true do
if CurrentVal ~= nil then
Count = Count + 1
CurrentVal = CueNames[tonumber(Count)]
else
repeating = false
TableSize = Count - 1
end
end
print(TableSize)
end
seems when the elements of the table is added by insert method, getn will return correctly. Otherwise, we have to count all elements
mytable = {}
element1 = {version = 1.1}
element2 = {version = 1.2}
table.insert(mytable, element1)
table.insert(mytable, element2)
print(table.getn(mytable))
It will print 2 correctly
I have a table in Lua:
p = {'sachin', 'sachin', 'dravid', 'Dhoni', 'yuvraj', 'kohli'}
I want to count frequency of each name in table .
test1 = {sachin=2, dravid=1, Dhoni=1, yuvraj=1, kohli=1}
I tried this program with lot of for loops .Please see my code
> function exec(ele,p)
count = 0
for k,v in pairs(p) do
if ele == p[k] then
count = count +1
end
end
return count
end
> new_table = {}
> for k,v in pairs(p) do
new_table[v] = exec(v,p)
end
>
> for k,v in pairs(new_table) do
print(k,v)
end
dhone 1
yuvraj 1
kohli 1
sachin 2
dravid 1
I want to do this more efficient way. How can I achieve this?
You can count the frequency like this:
function tally(t)
local freq = {}
for _, v in ipairs(t) do
freq[v] = (freq[v] or 0) + 1
end
return freq
end
And here's another demo example.
Using metatable may be a little unnecessary for this simple case, just showing another option:
local mt = {__index = function() return 0 end}
local newtable = {}
setmetatable(newtable, mt)
for _, v in pairs(p) do
newtable[v] = newtable[v] + 1
end
The metamethod __index above gives the table 0 as the default value.
Is there a way to use the arg 2 value of table.concat to represent the current table index?
eg:
t = {}
t[1] = "a"
t[2] = "b"
t[3] = "c"
X = table.concat(t,"\n")
desired output of table concat (X):
"1 a\n2 b\n3 c\n"
Simple answer : no.
table.concat is something really basic, and really fast.
So you should do it in a loop anyhow.
If you want to avoid excessive string concatenation you can do:
function concatIndexed(tab,template)
template = template or '%d %s\n'
local tt = {}
for k,v in ipairs(tab) do
tt[#tt+1]=template:format(k,v)
end
return table.concat(tt)
end
X = concatIndexed(t) -- and optionally specify a certain per item format
Y = concatIndexed(t,'custom format %3d %s\n')
I don't think so: how would you tell it that the separator between keys and values is supposed to be a space, for example?
You can write a general mapping function to do what you'd like:
function map2(t, func)
local out = {}
for k, v in pairs(t) do
out[k] = func(k, v)
end
return out
end
function joinbyspace(k, v)
return k .. ' ' .. v
end
X = table.concat(map2(t, joinbyspace), "\n")
No. But there is a work around:
local n = 0
local function next_line_no()
n = n + 1
return n..' '
end
X = table.concat(t,'\0'):gsub('%f[%Z]',next_line_no):gsub('%z','\n')
function Util_Concat(tab, seperator)
if seperator == nil then return table.concat(tab) end
local buffer = {}
for i, v in ipairs(tab) do
buffer[#buffer + 1] = v
if i < #tab then
buffer[#buffer + 1] = seperator
end
end
return table.concat(buffer)
end
usage tab is where the table input is and seperator be both nil or string (if it nil it act like ordinary table.concat)
print(Util_Concat({"Hello", "World"}, "_"))
--Prints
--Hello_world
Sounds like a "let me google it for you" question, but somehow I can't find an answer. The Lua # operator only counts entries with integer keys, and so does table.getn:
tbl = {}
tbl["test"] = 47
tbl[1] = 48
print(#tbl, table.getn(tbl)) -- prints "1 1"
count = 0
for _ in pairs(tbl) do count = count + 1 end
print(count) -- prints "2"
How do I get the number of all entries without counting them?
You already have the solution in the question -- the only way is to iterate the whole table with pairs(..).
function tablelength(T)
local count = 0
for _ in pairs(T) do count = count + 1 end
return count
end
Also, notice that the "#" operator's definition is a bit more complicated than that. Let me illustrate that by taking this table:
t = {1,2,3}
t[5] = 1
t[9] = 1
According to the manual, any of 3, 5 and 9 are valid results for #t. The only sane way to use it is with arrays of one contiguous part without nil values.
You can set up a meta-table to track the number of entries, this may be faster than iteration if this information is a needed frequently.
The easiest way that I know of to get the number of entries in a table is with '#'. #tableName gets the number of entries as long as they are numbered:
tbl={
[1]
[2]
[3]
[4]
[5]
}
print(#tbl)--prints the highest number in the table: 5
Sadly, if they are not numbered, it won't work.
There's one way, but it might be disappointing: use an additional variable (or one of the table's field) for storing the count, and increase it every time you make an insertion.
count = 0
tbl = {}
tbl["test"] = 47
count = count + 1
tbl[1] = 48
count = count + 1
print(count) -- prints "2"
There's no other way, the # operator will only work on array-like tables with consecutive keys.
function GetTableLng(tbl)
local getN = 0
for n in pairs(tbl) do
getN = getN + 1
end
return getN
end
You're right. There are no other way to get length of table
You could use penlight library. This has a function size which gives the actual size of the table.
It has implemented many of the function that we may need while programming and missing in Lua.
Here is the sample for using it.
> tablex = require "pl.tablex"
> a = {}
> a[2] = 2
> a[3] = 3
> a['blah'] = 24
> #a
0
> tablex.size(a)
3
local function CountedTable(x)
assert(type(x) == 'table', 'bad parameter #1: must be table')
local new_t = {}
local mt = {}
-- `all` will represent the number of both
local all = 0
for k, v in pairs(x) do
all = all + 1
end
mt.__newindex = function(t, k, v)
if v == nil then
if rawget(x, k) ~= nil then
all = all - 1
end
else
if rawget(x, k) == nil then
all = all + 1
end
end
rawset(x, k, v)
end
mt.__index = function(t, k)
if k == 'totalCount' then return all
else return rawget(x, k) end
end
return setmetatable(new_t, mt)
end
local bar = CountedTable { x = 23, y = 43, z = 334, [true] = true }
assert(bar.totalCount == 4)
assert(bar.x == 23)
bar.x = nil
assert(bar.totalCount == 3)
bar.x = nil
assert(bar.totalCount == 3)
bar.x = 24
bar.x = 25
assert(bar.x == 25)
assert(bar.totalCount == 4)
I stumbled upon this thread and want to post another option. I'm using Luad generated from a block controller, but it essentially works by checking values in the table, then incrementing which value is being checked by 1. Eventually, the table will run out, and the value at that index will be Nil.
So subtract 1 from the index that returned a nil, and that's the size of the table.
I have a global Variable for TableSize that is set to the result of this count.
function Check_Table_Size()
local Count = 1
local CurrentVal = (CueNames[tonumber(Count)])
local repeating = true
print(Count)
while repeating == true do
if CurrentVal ~= nil then
Count = Count + 1
CurrentVal = CueNames[tonumber(Count)]
else
repeating = false
TableSize = Count - 1
end
end
print(TableSize)
end
seems when the elements of the table is added by insert method, getn will return correctly. Otherwise, we have to count all elements
mytable = {}
element1 = {version = 1.1}
element2 = {version = 1.2}
table.insert(mytable, element1)
table.insert(mytable, element2)
print(table.getn(mytable))
It will print 2 correctly