Opening app's notification settings in the settings app - ios

Question

In the case that a user may accidentally declines to receive notifications and wants to turn notifications later, how can I use an NSURL to open the IOS Settings App to my app's notification page where they can select Allow Notifications?

Answer 1

Updated 8 Dec, 2021:
This method will open Settings > Your App. It will show all available privacy toggles like camera, photos, notifications, cellular data, etc.
After a comment from #Mischa below, tested and updated the answer to this (more succinct):
if let appSettings = URL(string: UIApplication.openSettingsURLString), UIApplication.shared.canOpenURL(appSettings) {
UIApplication.shared.open(appSettings)
}
Previous answer:
I found the answer to this question (albeit helpful) has a bit too much assumed logic. Here is a plain and simple Swift 5 implementation if anyone else stumbles upon this question:
if let bundleIdentifier = Bundle.main.bundleIdentifier, let appSettings = URL(string: UIApplication.openSettingsURLString + bundleIdentifier) {
if UIApplication.shared.canOpenURL(appSettings) {
UIApplication.shared.open(appSettings)
}
}

Answer 2

For Swift 3, use UIApplicationOpenSettingsURLString to go to settings for your app where it shows the Notifications status and "Cellular Data"
let settingsButton = NSLocalizedString("Settings", comment: "")
let cancelButton = NSLocalizedString("Cancel", comment: "")
let message = NSLocalizedString("Your need to give a permission from notification settings.", comment: "")
let goToSettingsAlert = UIAlertController(title: "", message: message, preferredStyle: UIAlertControllerStyle.alert)
goToSettingsAlert.addAction(UIAlertAction(title: settingsButton, style: .destructive, handler: { (action: UIAlertAction) in
DispatchQueue.main.async {
guard let settingsUrl = URL(string: UIApplicationOpenSettingsURLString) else {
return
}
if UIApplication.shared.canOpenURL(settingsUrl) {
if #available(iOS 10.0, *) {
UIApplication.shared.open(settingsUrl, completionHandler: { (success) in
print("Settings opened: \(success)") // Prints true
})
} else {
UIApplication.shared.openURL(settingsUrl as URL)
}
}
}
}))
logoutUserAlert.addAction(UIAlertAction(title: cancelButton, style: .cancel, handler: nil))

Answer 3

Swift 5:
if let url = URL(string: UIApplication.openSettingsURLString) {
UIApplication.shared.open(url)
}

Answer 4

This should keep you covered for all iOS versions, including iOS 15 and iOS 16.
extension UIApplication {
private static let notificationSettingsURLString: String? = {
if #available(iOS 16, *) {
return UIApplication.openNotificationSettingsURLString
}
if #available(iOS 15.4, *) {
return UIApplicationOpenNotificationSettingsURLString
}
if #available(iOS 8.0, *) {
// just opens settings
return UIApplication.openSettingsURLString
}
// lol bruh
return nil
}()
private static let appNotificationSettingsURL = URL(
string: notificationSettingsURLString ?? ""
)
func openAppNotificationSettings() -> Bool {
guard
let url = UIApplication.appNotificationSettingsURL,
self.canOpen(url) else { return false }
return self.open(url)
}
}
Usage:
Button {
let opened = UIApplication.shared.openAppNotificationSettings()
if !opened {
print("lol fail")
}
} label: {
Text("Notifications")
}

Answer 5

UPDATE: This will be rejected by Apple.
To open notifications part of settings use this
UIApplication.shared.open(URL(string:"App-Prefs:root=NOTIFICATIONS_ID")!, options: [:], completionHandler: nil)

Answer 6

Since iOS 15.4 we can deeplink to the notif settings screen directly using UIApplicationOpenNotificationSettingsURLString:
https://developer.apple.com/documentation/uikit/uiapplicationopennotificationsettingsurlstring?language=objc