I am trying to read a value from a view in aps.net mvc: I am aware that this seems like a very basic issue, however, i could not find any solution for this, so i am turning to you: In my case, it seems as if the parameter playlistModel.Model.Name is never sent, or at least is null.
My controller:
[HttpPost]
[ValidateAntiForgeryToken]
public ActionResult Create(PlaylistViewModelDetails playlistModel)
{
if (!String.IsNullOrEmpty(playlistModel.Model.Name))
{
//this is never called due to playlistModel.Model.Name being null.
return RedirectToAction("Index");
}
return View(playlistModel);
}
#model Orpheus.Models.ViewModels.PlaylistViewModelDetails
#using (Html.BeginForm())
{
#Html.AntiForgeryToken()
<div class="form-horizontal">
<hr />
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
<div class="form-group">
#Html.LabelFor(model => model.Model.Name, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.Model.Name, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.Model.Name, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Erstellen" class="btn btn-default" />
</div>
</div>
</div>
}
public class PlaylistViewModelDetails
{
public PlaylistModel Model = new PlaylistModel(); //a seperate class containing a string value, which must be read from the form
}
Thank you for helping me to solve this issue!
Your PlaylistViewModelDetails contains only a field for Model. The DefaultModelBinder only binds properties, not fields.
Change your model to
public class PlaylistViewModelDetails
{
public PlaylistModel Model { get; set; }
}
and add a parameter-less constructor if you want to initialize PlaylistModel
public PlaylistViewModelDetails()
{
Model = new PlaylistModel();
}
Note also Name in PlaylistModel also need to be a property.
Related
ANSWERED
See answers section below
I've been struggling for hours with this problem and I haven't found anything that relates, so apologies if this post is a duplicate.
I'll start by constructing a problem related to my own.
Let's say we create a ViewModel:
public class XmlViewModel(){
[Required]
public string Code { get; set; }
public string XML { get; set; }
}
and a constructor method which loads the View and as well as another that gets called when the submit is registered on the View.
public class Extractor{
public ActionResult Index()
{
XmlViewModel xmlVM = new XmlViewModel ()
{
XML = "Sample XML";
};
return View(xmlVM);
}
public ActionResult GetXml(XmlViewModel xmlVM){
xmlVM.XML = GetXMLByCode();
return View ("Index", xmlVM)
}
}
Then the view Index as below
#model Project.ViewModel.XmlViewModel
#{
ViewBag.Title = "Index";
}
#using (Html.BeginForm("GetXml", "Extractor", Model))
{
#Html.AntiForgeryToken()
<div class="form-horizontal">
<hr />
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
<div class="form-group">
#Html.LabelFor(model => model.Code, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.Code, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.Code, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.XML, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-9">
<pre id="XML">#Html.Raw(Html.Encode(Model.XML))</pre>
</div>
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Generate XML" class="btn btn-default"/>
</div>
</div>
</div>
}
So in this scenario I'm starting the page with:
When the user clicks Submit using a XML Code, I want the Code to be run against some collection of XML, then that returned XML replaces the "SampleXML"
Problem is when the form gets submitted again(Twice) (Now with the XML field holding a few hundred characters) it overloads the Query and returns this:
Because yep you guessed it, the XML fills up the Request with the XML from the previous Form result.
So my question is, is there any way to clear the ViewModel Property so it isn't passed in the Query, or some attribute to add that will tell the ViewModel to not pass the property through the Html.BeginForm()?
If possible I would like to stay away from passing the ViewModel properties individually as the actual problem's ViewModel is more complicated and it would be troublesome going down that route.
After my suggestions, if you are still getting header to large, I can help diagnose.
Add an xml file to your project. Add tons of xml to it. Right click to get properties. For build action, change to embedded resource.
Where I have WebApplication2.XMLFile1.xml, you should have your assembly name dot then your file name. You can right click on your project, and see properties to get assembly name.
Here is my code
namespace WebApplication2.Controllers
{
public class XmlViewModel
{
[Required]
public string Code { get; set; }
public string XML { get; set; }
}
public class HomeController : Controller
{
public static string GetXMLByCode()
{
var assembly = Assembly.GetExecutingAssembly();
var resourceName = "WebApplication2.XMLFile1.xml";
string result = String.Empty;
using (Stream stream = assembly.GetManifestResourceStream(resourceName))
using (StreamReader reader = new StreamReader(stream))
{
result = reader.ReadToEnd();
}
return result;
}
public ActionResult GetXml(XmlViewModel xmlVM)
{
xmlVM.XML = GetXMLByCode();
return View("Index9", xmlVM);
}
public ActionResult Index9()
{
XmlViewModel xmlVM = new XmlViewModel { XML = "Sample XML" };
return View(xmlVM);
}
here is my view
#model WebApplication2.Controllers.XmlViewModel
#{
ViewBag.Title = "Index9";
Layout = "~/Views/Shared/_Layout.cshtml";
}
#using (Html.BeginForm("GetXml", "Home", Model))
{
#Html.AntiForgeryToken()
<div class="form-horizontal">
<hr />
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
<div class="form-group">
#Html.LabelFor(model => model.Code, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.Code, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.Code, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.XML, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-9">
<pre id="XML">#Html.Raw(Html.Encode(Model.XML))</pre>
</div>
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Generate XML" class="btn btn-default" />
</div>
</div>
</div>
}
ANSWERED
I eventually figured it out by doing the following in the view:
#{
ViewBag.Title = "Index";
ViewBag.XML= XmlViewModel.XML;
XmlViewModel.XML = "";
}
---
<div class="form-group">
#Html.LabelFor(model => model.XML, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-9">
<pre id="XML">#Html.Raw(Html.Encode(ViewBag.XML))</pre>
</div>
</div>
Now when the view is loaded, the Viewbag will hold the XML being returned and I can safely empty the model data before returning it to the Html.BeginForm()
Keeping for anyone in the same situation
Upon POST of an ActionController I am receiving the great ole' object reference not set to an instance of an object error.
Basically I need the ID of the userRequest to be saved WITH the requestResponse. (Foreign Key here)
Here is the code.
ViewModel:
public class RequestResponseViewModel
{
public Models.Request userRequest { get; set; }
public Models.RequestResponse requestResponse { get; set; }
}
View: In debug here there is value in model.userRequest.ID
#model UserRequests.ViewModels.RequestResponseViewModel
#{
ViewBag.Title = "Create";
}
<h2>Admin Response to Request</h2>
#using (Html.BeginForm())
{
#Html.AntiForgeryToken()
<div class="form-horizontal">
<hr />
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
<div class="form-group">
#Html.LabelFor(model => model.requestResponse.Response,
htmlAttributes: new { #class = "control-label col-md-1" })
<div class="col-md-10">
#Html.TextAreaFor(model => model.requestResponse.Response, new {
#class = "form-control", #rows = 5 })
#Html.ValidationMessageFor(model =>
model.requestResponse.Response, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.userRequest.ID, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-2">
#Html.DisplayFor(model => model.userRequest.ID)
#Html.ValidationMessageFor(model => model.userRequest.ID, "", new { #class = "text-danger" })
</div>
#Html.LabelFor(model => model.requestResponse.Author, htmlAttributes: new { #class = "control-label col-md-1" })
<div class="col-md-3">
#Html.EditorFor(model => model.requestResponse.Author, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.requestResponse.Author, "", new { #class = "text-danger" })
</div>
#Html.LabelFor(model => model.requestResponse.CreateDate, htmlAttributes: new { #class = "control-label col-md-1" })
<div class="col-md-3">
<h5>#DateTime.Now</h5>
#Html.ValidationMessageFor(model => model.requestResponse.CreateDate, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
<div class="col-md-offset-1">
<button type="reset" class="btn btn-default">Cancel</button>
<input type="submit" value="Create" class="btn btn-success" />
</div>
</div>
</div>
<hr />
<h3 class="text-success">Original Request</h3>
<div class="row">
<div class="col-md-10">
<h4>#Html.DisplayFor(model => model.userRequest.Title)</h4>
</div>
</div>
<div class="row">
<div class="col-md-10">
<h4>#Html.DisplayFor(model => model.userRequest.Description)</h4>
</div>
</div>
}
<div>
#Html.ActionLink("Back to Browse", "Browse","Change")
</div>
Get ActionResult:
public ActionResult Create(int id)
{
UserRequestContextDataContext db = new UserRequestContextDataContext();
var request = (from m in db.Requests
where m.ID == id
select new Models.Request()
{
ID = m.ID,
Title = m.Title,
Description = m.Description,
BusinessUnit = m.BusinessUnit,
Author = m.Author,
ModuleName = m.MenuItem,
RequestStatus = 2,
SubmitDate = m.SubmitDate,
Type = m.Type,
UrgencyNum = m.UrgencyLevel
}).FirstOrDefault();
var reqResponse = new Models.RequestResponse();
var viewModel = new RequestResponseViewModel
{
userRequest = request,
requestResponse = reqResponse
};
return View(viewModel);
}
The "viewModel" here has everything I need. It's lost somewhere between the ActionResults..
And Finally the Post ActionResult:
[HttpPost]
public ActionResult Create(RequestResponseViewModel _requestResponseViewModel)
{
try
{
if (ModelState.IsValid)
{
using (UserRequestContextDataContext db = new UserRequestContextDataContext())
{
RequestResponse reqRes = new RequestResponse();
reqRes.Response = _requestResponseViewModel.requestResponse.Response.ToString();
reqRes.RequestID = _requestResponseViewModel.userRequest.ID;
reqRes.Author = _requestResponseViewModel.requestResponse.Author.ToString();
reqRes.CreateDate = DateTime.Now;
db.RequestResponses.InsertOnSubmit(reqRes);
db.SubmitChanges();
}
}
return RedirectToAction("Browse","Change");
}
catch (Exception ex)
{
return View("Error", new HandleErrorInfo(ex, "Change", "Create"));
}
}
Using debug mode the userRequest object is NULL in the view model parameter of the POST method but requestResponse is FINE and populated as should.
Searching on this, it seemed most had issues with the naming convention in the view model but I've made sure there are no discrepancies there.
If there is a more clear way to do this workflow please mention.
#Html.DisplayFor does not create an HTML input element, but a simple string literal (for most types, some exceptions are listed in the docs: https://msdn.microsoft.com/en-us/library/ee407420(v=vs.118).aspx#Anchor_1).
So when you press submit, your browser will not send the ID back to the server because it sends only form data (e.g. data from input, textare, select fields). Using your browsers developer tools (F12) you can examine what is actually send to the server.
You can add a hidden input field using #Html.HiddenFor(model => model.userRequest.ID) or use a custom display template for the ID to automatically add a hidden input field. You could further use UIHint attributes to automatically select a display template. Both approaches are thoroughly documented (e.g. http://www.codeguru.com/csharp/.net/net_asp/mvc/using-display-templates-and-editor-templates-in-asp.net-mvc.htm).
Another reason the object could be NULL in the POST is due to forgetting to add the setters { get; set; } in your view model:
public Orders orders; --> missing { get; set; }
public class OrderViewModel
{
public Orders orders { get; set; }
public List<VendorJobTitleView> Jobs { get; set; }
public List<ManagerView> Managers { get; set; }
}
I have a simple contact form that is using a model for it's fields, everything seems to work but the ViewBag message gets changed regardless if there are validation errors or not, user validation prevents this but I also need the HttpPost action to set the message based on if the the form was filled correctly.
I tried using if(ModelState.IsValid) but it doesn't seem to work. I realize I can probably manually check each variable in the home to see if it's empty, but that won't really tell me if it's valid or the post was returned with errors, is there a build in method for this?
ContactFormModel.cs
namespace TestApplication.Models
{
public class ContactFormModel
{
[Required]
[Display(Name = "Name")]
public string name { get; set; }
[Required]
[Display(Name = "Phone")]
public string phone { get; set; }
[Required]
[Display(Name = "Message")]
public string message { get; set; }
}
}
HomeController.cs
[HttpPost]
public ActionResult Contact(ContactFormModel contactForm)
{
ViewBag.Message = "Thank you. Your message has been sent.";
return View();
}
Contact.cshtml
#model TestApplication.Models.ContactFormModel
#{
ViewBag.Title = "Contact";
}
<h2>#ViewBag.Title.</h2>
<h3>#ViewBag.Message</h3>
<p>Use this area to provide additional information.</p>
#*#if (!IsPost)
{
#Html.EditorForModel(Model)
}*#
#using (Html.BeginForm())
{
#Html.AntiForgeryToken()
<div class="form-horizontal">
<hr />
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
<div class="form-group">
#Html.LabelFor(model => model.name, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.name, "", new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.name, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.phone, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.phone, "", new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.phone, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.message, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.TextAreaFor(model => model.message, new { #class = "form-control" })
#Html.ValidationMessageFor(model => model.message, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Create" class="btn btn-default" />
</div>
</div>
</div>
}
The pattern for doing what you want is to check ModelState.IsValid. If it's valid continue processing, if not return the view with the existing model contents to give the user a chance to correct their error(s).
[HttpPost]
public ActionResult Contact(ContactFormModel contactForm)
{
if (ModelState.IsValid)
{
ViewBag.Message = "Thank you. Your message has been sent.";
return View();
}
else
{
return View(contactForm);
}
}
Having said that, you should consider using a PRG (post-redirect-get) pattern. By returning the same view in the HttpPost version of the method you open yourself up to repeated posting of the data. If the user hits Refresh in their browser it will repost the data they just posted (after popping up a dialog that most non-technical users will never understand). You must have a HttpGet version that delivers the view in the first place, you should redirect to that on success. You'll have to switch to using TempData instead of ViewBag because the ViewBag won't survive the redirect.
[HttpPost]
public ActionResult Contact(ContactFormModel contactForm)
{
if (ModelState.IsValid)
{
TempData.Message = "Thank you. Your message has been sent.";
// Assumes there is a Get version of the Contact action method
return RedirectToAction("Contact");
}
else
{
return View(contactForm);
}
}
Hit a strange issue where my model is not binding and shows up on the controller as null.
I have a form doing a httppost. My breakpoint in the controller is hit and the parameter I expect to be my model is null.
Looking at some example code on another page that works, I copied and pasted it and the only difference was the name of the parameter was 'model' instead of message.
View
#model Site.Models.ContactMessage
#{
ViewBag.Title = "Index";
}
<h2>Index</h2>
#using (Html.BeginForm())
{
#Html.AntiForgeryToken()
<div class="form-horizontal">
<h4>ContactMessage</h4>
<hr />
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
<div class="form-group">
#Html.LabelFor(model => model.Message, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.Message, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.Message, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.To, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.To, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.To, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Save" class="btn btn-default" />
</div>
</div>
</div>
}
<div>
#Html.ActionLink("Back to List", "Index")
</div>
Controller
public ActionResult Contact()
{
return View();
}
[HttpPost]
public ActionResult Contact(ContactMessage message)
{
var m = message;
return View();
}
and it worked. I thought I must have entirely missed something about naming convention. Found you can use Bind, from reading a heap of other posts, to change the prefix like;
public ActionResult Contact([Bind(Prefix = "model")] ContactMessage message)
but that didn't work, still null. Going to rename it to model so it works and I can move on but would like to know why it's not binding if not called model.
public ActionResult Contact(ContactMessage message)
Changed back to this as above but still returns a null.
Interestingly, if I open up another MVC app, that one has whatever parameter names I want and works fine. It's using an older version of MVC 5 (not updated it yet but I will do that and see if anything happens. I don't expect it will.)
Your problem is that you model contains a property named Message and you also have a parameter named message The DefaultModelBinder reads the form values which will include message = "someTextValue" and searches for model properties that have the name message. It finds the one in you model and sets it value (all OK so far) but then it finds another one (your parameter) and tries to set the value of a complex object string value (in effect ContactMessage message = "someTextValue";) which fails so the model becomes null
Forgive the newbie ASP.NET MVC question. I am used to tutorials where Code First is used with the Entity Framework. Here, this is not the case. I have a form that I want the user to fill out. When it has been filled out, I want to use EF to write the values to an existing database. I can't figure out how to "trap" the values in the view so I can write my EF code. I used a model and I redirected the BeginForm to an "Edit" action method but I don't know how to get my filled in class. Here is the HomeController methods:
[HttpGet]
public ActionResult Trial()
{
UserAccount account = new UserAccount();
return View(account);
}
public ActionResult Edit()
{
}
Here is the model class:
public class UserAccount
{
public int AccountID { get; set; }
public string AccountName { get; set; }
public string RegistrationCode { get; set; }
public DateTime Created { get; set; }
}
}
Here is the View the wizard generated. When I hit the "Create" button, I want to go to the "Edit" action menu or someplace I can use EF to write to the existing database table. How do I do this?
#model AlphaFrontEndService.Models.UserAccount
#{
ViewBag.Title = "Trial";
}
<h2>Trial</h2>
#using (Html.BeginForm("Edit", "Home"))
{
#Html.AntiForgeryToken()
<div class="form-horizontal">
<h4>UserAccount</h4>
<hr />
#Html.ValidationSummary(true)
<div class="form-group">
#Html.LabelFor(model => model.AccountID, new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.AccountID)
#Html.ValidationMessageFor(model => model.AccountID)
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.AccountName, new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.AccountName)
#Html.ValidationMessageFor(model => model.AccountName)
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.RegistrationCode, new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.RegistrationCode)
#Html.ValidationMessageFor(model => model.RegistrationCode)
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.Created, new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.Created)
#Html.ValidationMessageFor(model => model.Created)
</div>
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Create" class="btn btn-default" />
</div>
</div>
</div>
}
<div>
#Html.ActionLink("Back to List", "Index")
</div>
You need a POST action for Trial method like below:
[HttpPost]
public ActionResult Trial(UserAccount model)
{
if (ModelState.IsValid)
{
//Store the form data into your database
}
return View(model);
}
Then in your view, add a submit button element inside the form, also instead of Edit, you just need to use Trial for the postback.
#using (Html.BeginForm("Trial", "Home")) {
//
<input type="submit" value="Submit"/>
}
Note: You don't need to create other Edit action method if you don't have some other reasons.
If you don't know how to save the data to your database, below is an example:
Create your DbContext class
public class MyDbContext : DbContext
{
public MyDbContext()
: base("name=YourDbConnection")
{
}
public DbSet<UserAccount> UserAccounts { get; set; }
}
Then the action method will looks like:
public class HomeController : Controller
{
//
[HttpPost]
public ActionResult Trial(UserAccount model)
{
if (ModelState.IsValid)
{
using (var db = new MyDbContext())
{
db.UserAccounts.Add(model);
db.SaveChanges();
return RedirectToAction("Index");
}
}
return View(model);
}
}