Can a URL from Firebase turn to enum Media? - Swift - ios

In my Firebase database, I have a 'link' with some URL of a video as a value.
I'm trying to call it it via:
enum Media {
static let videoURL = "linkLabel.text = posts[selectedIndexPath].link"
}
Without success. If I call it just as a label text, it is fine. However, I also try the following:
static let videoURL = URL(string: "linkLabel.text = posts[selectedIndexPath].link")
As well as trying to call from my super.viewDidload() like:
videoVRView.load(from: URL(string: "\(linkLabel.text = posts[selectedIndexPath].link)"))
Anybody would know how to achieve this correctly? It will be amazing! Thanks!
----- EDIT:
I got it work by videoVRView.load(from: URL(string: "\(posts[selectedIndexPath].link)"))

Related

iOS swift extracting permalink from deeplink URL

I am implementing Firebase dynamic links in my iOS project. It is working fine and it is opening my iOS Home screen properly. But now I would like to extract values from url and open appropriate screen based on url.
for example:
https://www.dd.com/forums/hot-deals-online/topics/smart-tv-carniva
in this url I would like to get 'hot-deals-online' and 'smart-tv-carniva' permalink which I will pass to view controller to open that screen on the app
can someone suggest me best approach for this.
Shortest is to access path of URLComponents object:
let url = "https://www.dd.com/forums/hot-deals-online/topics/smart-tv-carniva"
if let comps = URLComponents(string: url) {
var elements = comps.path.split(separator: "/").map(String.init)
// ["forums", "hot-deals-online", "topics", "smart-tv-carniva"]
// To build an url back, example:
var url = URL(string: comps.host!)!
url.appendPathComponent(elements[0])
url.appendPathComponent(elements[1])
// Result: www.dd.com/forums/hot-deals-online
}
P.S. calling .map(String.init) makes in-place conversion from array of substrings to normal String array.

WebView (not WKWebView) calling Localized HTML file

A Mac app requires that a HTML file be called in a WebView (the legacy type, not the newer WKWebView) in a localized form to present the user with some content.
As I side note, I realize that WebView should not be used today, and WKWebView is preferred, however this is a legacy app that currently needs support.
I've used a similar method for the iOS version, however it does not seem to be working. The HTML files are simply called "Term.HTML" and are placed in each localization folder alongside the localized string and all other localized content. This is the code I tried to use:
NSString *htmlFile = [[NSBundle mainBundle] pathForResource:NSLocalizedString(#"fileTerm", nil) ofType:#"html"];
htmlString = [NSString stringWithContentsOfFile:htmlFile encoding:NSUTF8StringEncoding error:nil];
[termsView takeStringURLFrom:htmlString];
Where my localized strings file each contain a line that says:
"fileTerm" = "Term";
This is what links the declaration of the first line to the actual file. It works in iOS. However, when running the app and the view containing the WebView attempt to the run, XCode will automatically create a breakpoint on the third line when I actually attempt to give the HTML file to "termsView" which is my WebView. After skipping this breakpoint, and forcing the app to run, the whole view containing the WebView will simply not appear. I would be thankful if anyone knew why this was or if there was a better way to do this? Thank you everyone!
may be someone needs in SWift: I solved this problem with saving 3 html file for every language, and then in ViewController class checked current app language. And called up the html file for current language
func loadHtmlFile() {
let preferredLanguage = NSLocale.preferredLanguages[0]
if preferredLanguage == "kz" {
let url = Bundle.main.url(forResource: "aboutUs_kz", withExtension:"html")
let request = URLRequest(url: url!)
webView.load(request)
}
if preferredLanguage == "ru" {
let url = Bundle.main.url(forResource: "aboutUs_ru", withExtension:"html")
let request = URLRequest(url: url!)
webView.load(request)
}
if preferredLanguage == "en" {
let url = Bundle.main.url(forResource: "aboutUs_en", withExtension:"html")
let request = URLRequest(url: url!)
webView.load(request)
}
}
in viewDidLoad()
override func viewDidLoad() {
super.viewDidLoad()
loadHtmlFile()
}

Choose specific url without writing a lot of if statement

I'm working on an horoscope application now I have a problem after user selected is zodiac how can I know what php url to show him for example:
there is 12 zodiac's so how can I give him his horoscope for this url for example
NSURL: "blablabla_horscope.com/libra/today_horoscope"
I mean I don't want to write in Xcode twelve options of url, and start making if statements for example "if this user and then use here is NSUserDefaults with his choosed zodiac"
since then I will have to start making a list of a lot of if statement and it will make my app work slow and it's a bad idea so I have thinking about making some kinda of php file, that will handle all that after the user registered in the background but where to start for that?
I'm currently working on Swift, core-data, php.
let urlString = "http://www.blablabla/?sign=libra&time=today"
let url = NSURL (string: urlString)
let dataURL = try? NSData(contentsOfURL: url!, options: [])
let result: String = String(data: dataURL!, encoding: NSUTF8StringEncoding)!
print("the result is %#", result)
Set your constant for the sign type prior to setting your urlString.
let sign = "libra"
or
let sign = "cancer"
etc...
and then you can:
let urlString = "http://www.blablabla/?sign=\(sign)&time=today"
Late

Open WhatsApp conversation using Abid doesn't work

I'm trying to open whatsapp conversation/chat for particular contact.
Instead of opening the desired chat it only opens the app.
No idea whats wrong :
let URLString = "whatsapp://send?abid=\(ID);text=lOL;"
UIApplication.sharedApplication().openURL(NSURL(string: URLString)!)
URLString value : whatsapp://send?abid=414;text=lOL
Any suggestions?
Update your URL like this:
whatsapp://send?abid=\(ID)&text=lOL
Source from HERE.
Try this and check if the UIApplication and open the URL.
let whatsAppURL: NSURL = NSURL(string: "whatsapp://send?abid=\(ID)&text=lOL")
if UIApplication.sharedApplication().canOpenURL(whatsAppURL){
UIApplication.sharedApplication().openURL(whatsAppURL)
}

'NSURLRequest?' does not have a member named 'URL' - Swift

Hi I am really new to coding in Swift, and am trying to follow the codes in this book: http://www.apress.com/9781484202098. Learn iOS 8 App Development 2nd Edition by James Bucanek
In particular, I am working through Chapter 3 - building a URL shortening app, but despite having copied the code exactly, I am getting an error on the code in Page 76:
if let toShorten = webView.request.URL.absoluteString {
which states 'NSURLRequest?' does not have a member named 'URL'.
I have tried googling an answer, but unfortunately have not come across anything. Any response I can find seems to suggest that my code ought to be working (e.g. How to get url which I hit on UIWebView?). This seems to have the closest answer SWIFT: Why I can't get the current URL loaded in UIWebView? but the solution does not appear to work for me. If I add a ? after the request, it will then at least build it, but I then have a nil variable returned.
I am using Xcode v6.1.1. Here is the piece of code that is coming up with the error in ViewController.swift:
let GoDaddyAccountKey = "0123456789abcdef0123456789abcdef" //this is replaced by my actual account key in my own code
var shortenURLConnection: NSURLConnection?
var shortURLData: NSMutableData?
#IBAction func shortenURL( AnyObject ) {
if let toShorten = webView.request?.URL.absoluteString { // ? now added
let encodedURL = toShorten.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)
let urlString = "http://api.x.co/Squeeze.svc/text/\(GoDaddyAccountKey)?url=\(encodedURL)"
shortURLData = NSMutableData()
if let firstrequest = NSURL(string: urlString) //added if here and removed !
let request = NSURLRequest(URL:firstrequest)
shortenURLConnection = NSURLConnection(request:request, delegate:self)
shortenButton.enabled = false
}
}
}
If you have any suggestions on how I can fix this, I would really appreciate it!
Update:
Following suggestions from Ashley below, I have amended my code so that it is no longer bringing up the error (see comments above). However, it is now no longer running. This appears to be because the urlString is being created as http://api.x.co/Squeeze.svc/text/d558979bb9b84eddb76d8c8dd9740ce3?url=Optional("http://www.apple.com/"). The problem is therefore the Optional() that is included and thus makes it an invalid URL. Does anyone have a suggestion on how to remove this please?
request is an optional property on UIWebView:
var request: NSURLRequest? { get }
also stringByAddingPercentEscapesUsingEncoding returns an optional:
func stringByAddingPercentEscapesUsingEncoding(_ encoding: UInt) -> String?
What you need is to make user of optional binding in a few places:
if let toShorten = webView.request?.URL.absoluteString {
if let encodedURL = toShorten.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding) {
let urlString = "http://api.x.co/Squeeze.svc/text/\(GoDaddyAccountKey)?url=\(encodedURL)"
shortURLData = NSMutableData()
if let firstrequest = NSURL(string: urlString) { // If a method can return a nil, don't force unwrap it
let request = NSURLRequest(URL:first request)
shortenURLConnection = NSURLConnection(request:request, delegate:self)
shortenButton.enabled = false
}
}
}
See Apple's docs on optional chaining for details
See Apple's docs for NSURL class

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