I have NSString strings that represent Product name Quantity Price
I need to align columns of these values like this
Productname Qty Price
PLAIN T-SHIRT 5 50.00
BLACK DENIM 1 29.99
BLUE DENIM 3 29.99
STRIPED DRESS 1 49.99
BLACK BOOTS 2 35.99
How ever I try using
+(NSString *) get_TOT:(NSString *)tot_STR : (int) length_range
{
NSString *tmp_TT;
NSUInteger length = tot_STR.length;
NSRange range;
tmp_TT = [NSString stringWithFormat:#" %d %f",Qty,pricc];
if (length <= 33)
{
range = NSMakeRange(33-length, length);
tmp_TT = [tmp_TT stringByReplacingCharactersInRange:range withString:tot_STR];
}
else
{
tmp_TT = [tmp_TT substringToIndex:33];
}
return tmp_TT;
}
I am not sure what is going wrong here
Thanks in advance
Woah! Adding hardcoded blank spaces to get the desired UI would be a very bad way of doing it.
You should use NSAttributedStrings to get the center-alignment.
Related
In iOS I am using two strings to combine and to form a single string. But the combined string must be of 16 characters . So if two strings are small and if we combine both and if it is less than 16 characters I must add few more characters to make it to 16 characters. How to achieve this?
NSString *combined = [NSString stringWithFormat:#"%#%#", stringURL, stringSearch];
This is the code I am using. So if I combine and it is less than 16 characters how to calculate it and add more characters to make it 16 characters?
Something like below
NSString *combined = [NSString stringWithFormat:#"%#%#", stringURL, stringSearch];
if (combined.length < 16)
{
NSString *newCombined = [NSString stringWithFormat:#"%#%#", combined, #"Some new string"];
}
You can use substringWithRange: method from NSString. You can take the below code as an example and modify it as per your requirements.
if (combined.length > 25)
{
NSString *beginning = [combined substringWithRange:NSMakeRange(0, 15)];
NSString *fromEnd = [combined substringWithRange:NSMakeRange(startPoint, combined.length-startPoint)];
}
You could make use of stringWithFormat - basically of printf if you want to pad with just a single char. Below I give some examples which I have constructed to illustrate, so it won't run out the box, but you only need to comment out the ones you do not want to make it work.
// To get 50 spaces
NSString * s50 = [NSString stringWithFormat:#"%*s", 50, ""];
// Pad with these characters, select only 1
// This will pad with spaces
char * pad = "";
// This will pad with minuses - you need enough to fill the whole field
char * pad = "-------------------------------------------------------";
// Some string
NSString * s = #"Hi there";
// Here back and front are just int's. They must be, but they can be calculated,
// e.g. you could have this to pad to 50
int back = 50 - s.length; if ( back < 0 ) back = 0;
// Pad s at the back
int back = 20;
NSString * sBack = [NSString stringWithFormat:#"%#%*s", s, back, pad];
// Pad s in front
int front = 10;
NSString * sFront = [NSString stringWithFormat:#"%*s%#", front, pad, s];
// Pad s both sides
NSString * sBoth = [NSString stringWithFormat:#"%*s%#%*s", front, pad, s, back, pad];
Note that the amounts here are parameterised. I use e.g. 50 in the first line but that could just as well be n as long as n is an int and you can use that to then perform calculations, store it in n and pad. There is an example in the code.
Here is a sample of the output
2020-11-04 08:16:22.908828+0200 FormatSpecifiers[768:15293] [Hi there-------------------------------------------------------]
2020-11-04 08:16:22.908931+0200 FormatSpecifiers[768:15293] [-------------------------------------------------------Hi there]
2020-11-04 08:16:22.908992+0200 FormatSpecifiers[768:15293] [-------------------------------------------------------Hi there-------------------------------------------------------]
I just show how to pad the combined string. To combine the string of course just use stringByAppendingString e.g.
NSString * s = [a stringByAppendingString:b];
and then you can do calcs based on s.length e.g. as shown in the example.
I am making a game that requires me to use very large numbers. I believe I am able to store very large numbers with NSDecimal. However, when displaying the numbers to users I would like to be able to convert the large number to a succinct string that uses characters to signify the value eg. 100,000 -> 100k 1,000,000 -> 1.00M 4,200,000,000 -> 4.20B and so forth going up to extremely large numbers. Is there any built in method for doing so or would I have to use a bunch of
NSDecimalCompare statements to determine the size of the number and convert?
I am hoping to use objective c for the application.
I know that I can use NSString *string = NSDecimalString(&NSDecimal, _usLocale); to convert to a string could I then do some type of comparison on this string to get the result I'm looking for?
Use this method to convert your number into a smaller format just as you need:
-(NSString*) suffixNumber:(NSNumber*)number
{
if (!number)
return #"";
long long num = [number longLongValue];
int s = ( (num < 0) ? -1 : (num > 0) ? 1 : 0 );
NSString* sign = (s == -1 ? #"-" : #"" );
num = llabs(num);
if (num < 1000)
return [NSString stringWithFormat:#"%#%lld",sign,num];
int exp = (int) (log(num) / 3.f); //log(1000));
NSArray* units = #[#"K",#"M",#"G",#"T",#"P",#"E"];
return [NSString stringWithFormat:#"%#%.1f%#",sign, (num / pow(1000, exp)), [units objectAtIndex:(exp-1)]];
}
Some sample examples:
NSLog(#"%#",[self suffixNumber:#99999]); // 100.0K
NSLog(#"%#",[self suffixNumber:#5109999]); // 5.1M
Source
Solved my issue: Can only be used if you know that your NSDecimal that you are trying to format will only be a whole number without decimals so make sure you round when doing any math on the NSDecimals.
-(NSString *)returnFormattedString:(NSDecimal)nsDecimalToFormat{
NSMutableArray *formatArray = [NSMutableArray arrayWithObjects:#"%.2f",#"%.1f",#"%.0f",nil];
NSMutableArray *suffixes = [NSMutableArray arrayWithObjects:#"k",#"M",#"B",#"T",#"Qa",#"Qi",#"Sx",#"Sp",#"Oc",#"No",#"De",#"Ud",#"Dud",#"Tde",#"Qde",#"Qid",#"Sxd",#"Spd",#"Ocd",#"Nvd",#"Vi",#"Uvi",#"Dvi",#"Tvi", nil];
int dick = [suffixes count];
NSLog(#"count %i",dick);
NSString *string = NSDecimalString(&nsDecimalToFormat, _usLocale);
NSString *formatedString;
NSUInteger characterCount = [string length];
if (characterCount > 3) {
NSString *trimmedString=[string substringToIndex:3];
float a;
a = 100.00/(pow(10, (characterCount - 4)%3));
int remainder = (characterCount-4)%3;
int suffixIndex = (characterCount + 3 - 1)/3 - 2;
NSLog(#"%i",suffixIndex);
if(suffixIndex < [suffixes count]){
NSString *formatSpecifier = [formatArray[remainder] stringByAppendingString:suffixes[suffixIndex]];
formatedString= [NSString stringWithFormat:formatSpecifier, [trimmedString floatValue] / a];
}
else {
formatedString = #"too Big";
}
}
else{
formatedString = string;
}
return formatedString;
}
I have to count how many decimal digits are there in a double in Xcode 5. I know that I must convert my double in a NSString, but can you explain me how could I exactly do? Thanks
A significant problem is that a double has a fractional part which has no defined length. If you know you want, say, 3 fractional digits, you could do:
[[NSString stringWithFormat:#"%1.3f", theDoubleNumber] length]
There are more elegant ways, using modulo arithmetic or logarithms, but how elegant do you want to be?
A good method could be to take your double value and, for each iteration, increment a counter, multiply your value by ten, and constantly check if the left decimal part is really near from zero.
This could be a solution (referring to a previous code made by Graham Perks):
int countDigits(double num) {
int rv = 0;
const double insignificantDigit = 8;
double intpart, fracpart;
fracpart = modf(num, &intpart);
while ((fabs(fracpart) > 0.000000001f) && (rv < insignificantDigit))
{
num *= 10;
fracpart = modf(num, &intpart);
rv++;
}
return rv;
}
You could wrap the double in an instance of NSNumber and get an NSString representation from the NSNumber instance. From there, calculating the number of digits after the decimal could be done.
One possible way would be to implement a method that takes a double as an argument and returns an integer that represents the number of decimal places -
- (NSUInteger)decimalPlacesForDouble:(double)number {
// wrap double value in an instance of NSNumber
NSNumber *num = [NSNumber numberWithDouble:number];
// next make it a string
NSString *resultString = [num stringValue];
NSLog(#"result string is %#",resultString);
// scan to find how many chars we're not interested in
NSScanner *theScanner = [NSScanner scannerWithString:resultString];
NSString *decimalPoint = #".";
NSString *unwanted = nil;
[theScanner scanUpToString:decimalPoint intoString:&unwanted];
NSLog(#"unwanted is %#", unwanted);
// the number of decimals will be string length - unwanted length - 1
NSUInteger numDecimalPlaces = (([resultString length] - [unwanted length]) > 0) ? [resultString length] - [unwanted length] - 1 : 0;
return numDecimalPlaces;
}
Test the method with some code like this -
// test by changing double value here...
double testDouble = 1876.9999999999;
NSLog(#"number of decimals is %lu", (unsigned long)[self decimalPlacesForDouble:testDouble]);
results -
result string is 1876.9999999999
unwanted is 1876
number of decimals is 10
Depending on the value of the double, NSNumber may do some 'rounding trickery' so this method may or may not suit your requirements. It should be tested first with an approximate range of values that your implementation expects to determine if this approach is appropriate.
I have a .CSV File below that is already put into a nice format rather than a solid list of values.
How would i be able to read individual values from this list … for example 'Time of 5 & 6" and return the number?
I know how would retrieve this from a normal .csv file that is listed, however not from one that has a weird layout like this one. Any ideas?
Thank
If the column titles (such as "Time 4" and "Time of 5 & 6") are consistent, you could separate each line and then by commas, look for the index of the column title, and then grab the same column in the next line.
I haven't tested this, but I think it should work. Assuming your file is read in as a string:
NSArray *componentsByLine = [myFile componentsSeparatedByCharactersInSet:[NSCharacterSet newlineCharacterSet]];
int firstIndex = 0;
int secondIndex = 0;
BOOL found = NO;
for(firstIndex = 0; firstIndex < componentsByLine.count; firstIndex++)
{
NSArray *componentsByComma = [[componentsByLine objectAtIndex:firstIndex] componentsSeparatedByString:#","];
for(secondIndex = 0; secondIndex < componentsByComma.count; secondIndex++)
{
if([[componentsByComma objectAtIndex:secondIndex] isEqualToString:#"Time of 5 & 6"])
{
found = YES;
break;
}
}
if(found)
break;
}
float requestedTime = [[[[componentsByLine objectAtIndex:firstIndex+1] componentsSeparatedByString:#","] objectAtIndex:secondIndex] floatValue];
I have some data in an NSString, separated by colons:
#"John:Doe:1970:Male:Dodge:Durango"
I need to limit the total length of this string to 100 characters. But I also need to ensure the correct number of colons are present.
What would be a reasonable to way to truncate the string but also add the extra colons so I can parse it into the correct number of fields on the other side?
For example, if my limit was 18, you would end up with something like this:
#"John:Doe:1970:Ma::"
Here's an updated version of my own latest pass at this. Uses #blinkenlights algorithm:
+ (NSUInteger)occurrencesOfSubstring:(NSString *)substring inString:(NSString *)string {
// http://stackoverflow.com/a/5310084/878969
return [string length] - [[string stringByReplacingOccurrencesOfString:substring withString:#""] length] / [substring length];
}
+ (NSString *)truncateString:(NSString *)string toLength:(NSUInteger)length butKeepDelmiter:(NSString *)delimiter {
if (string.length <= length)
return string;
NSAssert(delimiter.length == 1, #"Expected delimiter to be a string containing a single character");
int numDelimitersInOriginal = [[self class] occurrencesOfSubstring:delimiter inString:string];
NSMutableString *truncatedString = [[string substringToIndex:length] mutableCopy];
int numDelimitersInTruncated = [[self class] occurrencesOfSubstring:delimiter inString:truncatedString];
int numDelimitersToAdd = numDelimitersInOriginal - numDelimitersInTruncated;
int index = length - 1;
while (numDelimitersToAdd > 0) { // edge case not handled here
NSRange nextRange = NSMakeRange(index, 1);
index -= 1;
NSString *rangeSubstring = [truncatedString substringWithRange:nextRange];
if ([rangeSubstring isEqualToString:delimiter])
continue;
[truncatedString replaceCharactersInRange:nextRange withString:delimiter];
numDelimitersToAdd -= 1;
}
return truncatedString;
}
Note that I don't think this solution handles the edge case from CRD where the number of delimiters is less than the limit.
The reason I need the correct number of colons is the code on the server will split on colon and expect to get 5 strings back.
You can assume the components of the colon separated string do not themselves contain colons.
Your current algorithm will not produce the correct result when one or more of the characters among the last colonsToAdd is a colon.
You can use this approach instead:
Cut the string at 100 characters, and store the characters in an NSMutableString
Count the number of colons, and subtract that number from the number that you need
Starting at the back of the string, replace non-colon characters with colons until you have the right number of colons.
I tend towards #dasblinkenlight, it's just an algorithm after all, but here's some code. Few modern shorthands - used an old compiler. ARC assumed. Won't claim it's efficient, or beautiful, but it does work and handles edge cases (repeated colons, too many fields for limit):
- (NSString *)abbreviate:(NSString *)input limit:(NSUInteger)limit
{
NSMutableArray *fields = [[input componentsSeparatedByString:#":"] mutableCopy];
NSUInteger colonCount = fields.count - 1;
if (colonCount >= limit)
return [#"" stringByPaddingToLength:limit withString:#":" startingAtIndex:0];
NSUInteger nonColonsRemaining = limit - colonCount;
for (NSUInteger ix = 0; ix <= colonCount; ix++)
{
if (nonColonsRemaining > 0)
{
NSString *fieldValue = [fields objectAtIndex:ix];
NSUInteger fieldLength = fieldValue.length;
if (fieldLength <= nonColonsRemaining)
nonColonsRemaining -= fieldLength;
else
{
[fields replaceObjectAtIndex:ix withObject:[fieldValue substringToIndex:nonColonsRemaining]];
nonColonsRemaining = 0;
}
}
else
[fields replaceObjectAtIndex:ix withObject:#""];
}
return [fields componentsJoinedByString:#":"];
}