Show two UIAlertController objects continuously using completion block - ios

Question

I'm trying to show two UIAlertController's instances continuously, which is like this code block below.
func showAlerts() {
let alertA = UIAlertController(title: "Alert A", message: "This is alert a...", preferredStyle: .alert)
let alertB = UIAlertController(title: "Alert B", message: "This is alert b...", preferredStyle: .alert)
let alertButton1 = UIAlertAction(title: "OK", style: .default, handler: nil)
let alertButton2 = UIAlertAction(title: "Cancel", style: .cancel, handler: nil)
alertA.addAction(alertButton1)
alertA.addAction(alertButton2)
alertB.addAction(alertButton1)
alertB.addAction(alertButton2)
self.present(alertA, animated: true) {
self.present(alertB, animated: true, completion: {
debugPrint("alerts are all shown")
})
}
}
I expect this code to show each alert continuously, which means alertB shows after alertA. But alertB doesn't appear as I expect, with warnings on console saying;
Warning: Attempt to present <UIAlertController: 0x7f7ffde0ace0> on <ContinuousUIAlertController_Experiment.ViewController: 0x7f7ffdd092d0> which is already presenting <UIAlertController: 0x7f7ffde09f90>
If I remember correctly, multiple UIAlertController objects cannot be existed at the same time. So I somehow understand what the warning above tells.
So, then, how can I implement continuous alert showing using completion of UIViewController::present(_:animated:completion:) or with nearly the same logic? (I prefer not to use UIAlertAction's handler)
If there is a solution, please let me know.
I'm struggling with this problem for a few days and I've not addressed yet.

Answer 1

You can't show 2 uialettcontrol at 1time.
But you can show 2nd uialettcontrol on 1st one's uialeraction.
For example
let alertController = UIAlertController(title: "iOScreator", message:
"Hello, world!", preferredStyle: UIAlertControllerStyle.Alert)
alertController.addAction(UIAlertAction(title: "Dismiss", style: UIAlertActionStyle.Destructive,handler: { action in
self.pressed()
}))
func pressed()
{
print("you pressed")
}
On pressed event you can write code for 2nd uialettcontrol.