This question already has answers here:
Post an HTML Table to ADO.NET DataTable
(2 answers)
Closed 6 years ago.
i would like to get the list of checkboxes to the controller.
foreach (var item in Model.Billeder)
{
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
<div class="form-group">
#Html.LabelFor(ModelItem => item.Overskrift, htmlAttributes: new { #class = "control-label col-md-2" }) #Html.DisplayFor(model => item.Overskrift)
<div class="col-md-10">
<div class="checkbox">
#Html.EditorFor(ModelItem => item.Emailbool)
#Html.ValidationMessageFor(ModelItem => item.Emailbool, "", new { #class = "text-danger" })
</div>
</div>
</div>
}
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Send" class="btn btn-default" />
</div>
</div>
in tilbud i have a
public virtual ICollection<Billed> Billeder { get; set; }
i would like for it to come into the controller so i can sort them
public ActionResult MailTilbud(Tilbud tb)
The for-each loop wouldn't work because the checkbox element name wouldn't be properly created with index which would cause it to be not posted back in controller, so change it to use for loop :
for (int i=0 i <Model.Billeder.Count; i++)
{
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
<div class="form-group">
#Html.LabelFor(ModelItem => Model.Billeder[i].Overskrift, htmlAttributes: new { #class = "control-label col-md-2" })
#Html.DisplayFor(model => Model.Billeder[i].Overskrift)
<div class="col-md-10">
<div class="checkbox">
#Html.EditorFor(ModelItem => Model.Billeder[i].Emailbool)
#Html.ValidationMessageFor(ModelItem => Model.Billeder[i].Emailbool, "", new { #class = "text-danger" })
</div>
</div>
</div>
}
and you would need to modify your model to have IList<T>, as ICollection<T> does not have indexing support.
public virtual IList<Billed> Billeder { get; set; }
and if the above property is in your model which is mapped to a table using Entity Framework, then you would need to create ViewModel class specific to view instead of modifying the DTO model.
Related
I cannot figure out why my view only passes back a NULL for a model to my controller.
This is for an Edit Post method. I checked other controllers with Edit Post methods that are structured the same way as this one and they work fine. It seems to be just this view and controller.
Here is my view:
#model Non_P21_Quote_System_v1._0.Models.gl_code
#{
ViewBag.Title = "Edit";
Layout = "~/Views/Shared/_Layout.cshtml";
}
<h2>Edit</h2>
#if (TempData["Message"] != null)
{
<div style="color:green">
#TempData["Message"]
</div><br />
}
#if (ViewBag.error != null)
{
<div style="color:red">
<h3>#ViewBag.error</h3>
</div><br />
}
#using (Html.BeginForm())
{
#Html.AntiForgeryToken()
<div class="form-horizontal">
<h4>gl_code</h4>
<hr />
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
#Html.HiddenFor(model => model.ID)
<div class="form-group">
#Html.LabelFor(model => model.GL_code, "GL Code", htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.GL_code, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.GL_code, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.GL_description, "Gl Description", htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.GL_description, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.GL_description, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.expense_type_ID, "Expense", htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.DropDownList("expense_type_ID", null, htmlAttributes: new { #class = "form-control" })
#Html.ValidationMessageFor(model => model.expense_type_ID, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.eag, "Employee Account Group", htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.DropDownList("eag", null, htmlAttributes: new { #class = "form-control" })
#Html.ValidationMessageFor(model => model.eag, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Save" class="btn btn-default" />
</div>
</div>
</div>
}
<div>
#Html.ActionLink("Back to List", "gl_Index")
</div>
#section Scripts {
#Scripts.Render("~/bundles/jqueryval")
}
Here is my controller method:
[HttpPost]
[ValidateAntiForgeryToken]
public async Task<ActionResult> Edit([Bind(Include = "ID,GL_code,GL_description,expense_type_ID,eag")] gl_code gl_code)
{
if (ModelState.IsValid)
{
db.Entry(gl_code).State = EntityState.Modified;
await db.SaveChangesAsync();
return RedirectToAction("gl_Index");
}
ViewBag.eag = new SelectList(db.employee_account_group, "ID", "eag_name");
ViewBag.expense_type_ID = new SelectList(db.expense_type, "ID", "type", gl_code.expense_type_ID);
return View(gl_code);
}
When I debug it, I see the model being passed in is of value NULL. I am seeing this on the controller side at the the parameters part of the Edit method.
Its null because your model contains a property named gl_code and you have also named the parameter for your model gl_code in the POST method.
Change the name of one or the other and the model will bind correctly.
What is happening internally is that the form submits a name/value pair for each successful form control, in your case gl_code=someValue. The DefaultModelBinder first initializes a new instance of your model. It then reads the form values and finds a match for the property in your model and sets it to someValue. But it also finds a match in the method parameters and tries set the value of the parameter to someValue, which fails (because you cannot do gl_code gl_code = "someValue";) and the model becomes null.
It appears you have a property on your view model called gl_code. In your controller, you also refer to the view model as gl_code.
Try changing this.
public async Task<ActionResult> Edit(gl_code gl_code)
To
public async Task<ActionResult> Edit(gl_code model)
I have a view that contains 2 partial views.
#model ListViewModel
....
#{
Html.RenderPartial("EditCartItemsPartical");
Html.RenderPartial("ShowProductINFO", Model.Products);
}
and I just want to create a from with the first partial, and a list with the second.
The partial views
EditCartItemsPartical.cshtml
#model TestNewATM3._0.Models.CartItem
#using (Html.BeginForm())
{
#Html.AntiForgeryToken()
<div class="form-horizontal">
<div class="form-group">
#Html.LabelFor(model => model.CartId, "CartId", htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.CartId, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.CartId, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.ProductId, "ProductId", htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.ProductId, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.ProductId, "", new { #class = "text-danger" })
</div>
</div>
.... // more control for CartItem
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Create" class="btn btn-default" />
</div>
</div>
</div>
}
ShowProductINFO.cshtml
#model IEnumerable<TestNewATM3._0.Models.AllProduct2>
<p>#Html.ActionLink("Create New", "Create")</p>
<table class="table">
<tr>
<th>ID</th>
<th>#Html.DisplayNameFor(model => model.Title)</th>
</tr>
#foreach (var item in Model) {
<tr>
<td>#Html.DisplayFor(model => item.Id)</td>
<td>#Html.DisplayFor(modelItem => item.Title)</td>
</tr>
}
</table>
And in my controller I got this.
public ActionResult Edit()
{
var db = ApplicationDbContext.Create();
var list = new ListViewModel
{
Products = db.AllProduct2s.ToList(),
Users = db.Users.ToList(),
Cart = db.Carts.ToList(),
CartItem = db.CartItems.ToList()
};
return View(list);
}
But the problem is that I cant show both partial at the same time because if I send the list in my view, then my first partial gets a problem cause it want a #model TestNewATM3.0.Models.CartItem. but if I don't sent the list My list wont show because I don't send it.
So how do i show a normal partial form view and a List partial view at the same time?
I'm having a little difficulty understanding your examples (i.e you have an edit view with create buttons), it looks like your trying to create a view to edit the cart.
Note: I would suggest renaming the CartItem property of your model to CartItems for clarity, but I'll use the current property names for the examples below.
You could render the partial view for each of the items in the list like so,
but this approach more is more than a little messy:
foreach(var cartItem in Models.CartItem){
Html.RenderPartial("EditCartItemsPartical", cartItem);
}
A simpler and more performant approach would be to edit the first view so it takes a collection of cart items
Like so
#model IEnumerable<TestNewATM3._0.Models.CartItem>
#using (Html.BeginForm())
{
#Html.AntiForgeryToken()
<div class="form-horizontal">
#foreach(var modelItem in Model.CartItem){
<h4>CartItem</h4>
<hr />
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
<div class="form-group">
#Html.LabelFor(model => modelItem.CartId, "CartId", htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => modelItem.CartId, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => modelItem.CartId, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.ProductId, "ProductId", htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => modelItem.ProductId, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => modelItem.ProductId, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.Aantal, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => modelItem.Aantal, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => modelItem.Aantal, "", new { #class = "text-danger" })
</div>
</div>
}
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Save" class="btn btn-default" />
</div>
</div>
</div>
}
Of course this will require you to change the server side code to receive a collection of cart items, but from the user's perspective not having to post a form back multiple times, to complete your changes is going to result in a better experience.
disclaimer: I changed the above view in notepad, might need to adjust a bit before it works perfectly
I hope this helps.
I have this code in my controller:
public ActionResult Search(String searchstring)
{
var number = from n in db.UCountInfoes
select n;
if (!String.IsNullOrEmpty(searchstring))
{
number = number.Where(i => i.IDNumber.Equals(searchstring));
}
return View(number);
}
and on my .cshtml page i have this which i use to search:
<div class="form-group">
#Html.LabelFor(model => model.ID_Number, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.ID_Number, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.ID_Number, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" name="SearchButton" value="Search" class="btn btn-inverse" />
</div>
</div>
After clicking the search button i want to return the records found on another .cshtml page.
return RedirectToAction("Action Name", "Your Controller Name", number);
Instead of return View you can use the above method.
Here Action Name is the View Name you want to show the results into.
This question already has answers here:
how to create a view with multiple models mvc 4?
(2 answers)
Closed 7 years ago.
I've been trying to dissect an automated MVC view & controller, and modify it so that i can insert information from a form in the view, on to two separate database tables (Entity framework database first).
here's what i have so far. it works if i reference either of the namespaces at the top on their own, but not together?
#model manage.mysite.DataModels.Property_Type
#model manage.mysite.DataModels.Room_Type
#{
ViewBag.Title = "Create";
}
<h2>Create</h2>
#using (Html.BeginForm())
{
<div class="form-horizontal">
<h4>Property_Type</h4>
<hr />
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
<div class="form-group">
#Html.LabelFor(model => model.PropertyType, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.PropertyType, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.PropertyType, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.RoomType, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.RoomType, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.RoomType, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Create" class="btn btn-default" />
</div>
</div>
</div>
}
It is not possible to reference several models in a View.
However, you can create composite model, which has the two other models as properties.
As such:
using manage.mysite.DataModels;
namespace manage.mysite.ViewModels
{
public class FooViewModel
{
public Property_Type PropertyType { get; set; }
public Room_Type RoomType { get; set; }
}
}
And then serve this model instead.
#model manage.mysite.ViewModels.FooViewModel
#{
ViewBag.Title = "Create";
}
<h2>Create</h2>
#using (Html.BeginForm())
{
<div class="form-horizontal">
<h4>Property_Type</h4>
<hr />
#Html.ValidationSummary(true, "", new { #class = "text-danger" })
<div class="form-group">
#Html.LabelFor(model => model.PropertyType.PropertyType, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.PropertyType.PropertyType, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.PropertyType.PropertyType, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
#Html.LabelFor(model => model.RoomType.RoomType, htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.EditorFor(model => model.RoomType.RoomType, new { htmlAttributes = new { #class = "form-control" } })
#Html.ValidationMessageFor(model => model.RoomType.RoomType, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Create" class="btn btn-default" />
</div>
</div>
</div>
}
See also:
MVC Multiple Models in One View
how to create a view with multiple models mvc 4?
Which is the best way to use multiple models with sames properties and using a unique view?
The checkbox is not displaying in page. I tried many solutions in google. Nothing worked. Here s the code:
#model project.gamestatus
#using (Html.BeginForm("Create", "Calculator", FormMethod.Post, new { id = "frmID" }))
{
//other codes
<div class="form-group">
#Html.Label("Show on Screen", htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.CheckBoxFor(m => m.display_status)
#Html.ValidationMessageFor(model => model.display_status, "", new { #class = "text-danger" })
</div>
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Create" class="btn btn-info" />
</div>
</div>
}
Only if the checkbox is shown in page i can proceed with validation. In my view there is no checkbox
First of all, you need to ensure that the display_status model is of boolean type and assigned the display name to it along with any validation.
[Display(Name="CheckBox Display Name")]
[Required]
public bool display_status { get; set; }
Also, #Html.CheckBoxFor do not support the label of checkbox. Therefore, you can have the label of the checkbox using #Html.LabelFor as follow:
<div class="form-group">
#Html.Label("Show on Screen", htmlAttributes: new { #class = "control-label col-md-2" })
<div class="col-md-10">
#Html.CheckBoxFor(m => m.display_status)
#Html.LabelFor(m => m.display_status)
#Html.ValidationMessageFor(m => m.display_status, "", new { #class = "text-danger" })
</div>
</div>
though its a very old post but I undergo this issue todat, but when I inspected I found that the CSS property opacity was set to 0 so changing it to 1 will solve the issue
#Html.EditorFor(model => model.Active, new { htmlAttributes = new { style = "opacity: 1" } })
I fixed the problem by setting the height to 20px explicitly. When I examined the page, it was being set to 20%:
#Html.CheckBoxFor(m => m.ExistingUser, new { style="height:20px" })