How to send JSON response to another view in Swift 3 - ios

Question

I have a problem with sending a JSON response from UITableView into another UITableView.
I want to send the Products array like in the code below into another UITableViewController based on the selected row on the TableView, but when I log the value in didSelectRowAt it returns nil.
So here's the JSON return.
{
"error_description": [],
"results": [
{
"id": 2,
"name": "Ernser, Kilback and Kreiger LLC",
"address": "48788 Adaline Ville 7634 Bertram Shoal",
"contact_person": "Coralie Schaden",
"mobile_number": "[phone]",
"image": {
"url": null,
"thumb": {
"url": null
},
"medium": {
"url": null
},
"small": {
"url": null
},
"icon": {
"url": null
}
},
"registered_at": "2017-01-10T04:16:52.621Z",
"products": [
{
"id": 21,
"name": "Fantastic Rubber Car",
"image": {
"url": null,
"thumb": {
"url": null
},
"medium": {
"url": null
},
"small": {
"url": null
},
"icon": {
"url": null
}
},
"points": 0,
"merchant_id": 2,
"created_at": "2017-01-10T04:16:52.630Z",
"updated_at": "2017-01-10T04:16:52.636Z"
},
{
"id": 22,
"name": "Mediocre Plastic Shirt",
"image": {
"url": null,
"thumb": {
"url": null
},
"medium": {
"url": null
},
"small": {
"url": null
},
"icon": {
"url": null
}
},
"points": 15,
"merchant_id": 2,
"created_at": "2017-01-10T04:16:52.819Z",
"updated_at": "2017-01-10T04:16:52.827Z"
},
]
}
This is a part of my code for getting the response.
I used the Alamofire
var merchantModel: Merchant!
var merchantArr = [Merchant]()
var productArr = [Product]()
var productModel : Product?
.....
case .success:
let json = JSON(data: response.data!)
for result in json["results"].arrayValue{
guard let merchantID = result["id"].number, let merchantName = result["name"].string, let merchantAddress = result["address"].string, let contactPerson = result["contact_person"].string, let mobilenumber = result["mobile_number"].string else{
return
}
self.merchantModel = Merchant(merchantID: merchantID, merchantName: merchantName, merchantAddress: merchantAddress, contactPerson: contactPerson, mobileNumber: mobilenumber, merchantImage: contactPerson)
let isSuccessfulSave = NSKeyedArchiver.archiveRootObject(self.merchantModel!, toFile: Merchant.ArchiveURL.path)
if !isSuccessfulSave {
print("Failed to save sender...")
}
for prodArr in result["products"].arrayValue{
print("prodArr:\(prodArr)")
guard let prodID = prodArr["id"].number, let prodName = prodArr["name"].string,
let points = prodArr["points"].number else{
return
}
self.productModel = Product(productID: prodID, productName: prodName, productPoints: points)
}
self.merchantArr.append(self.merchantModel!)
self.productArr.append(self.productModel!)
self.merchantModel.loadMerchant()
self.tableView.reloadData()
}

Answer 1

Swift is not javascript, and JSON is not the simplest way to handle the data in this language.
You'd probably prefer to transform your JSON data into Foundation objects, manipulate them, create UITableView with them... And when you'll need to have the JSON format again, you transform those Foundation objects back to JSON.
There are a lot of ways to achieve that, and some amazing third-party libraries to do it very easily. However for a start I encourage you to have a look at Apple's resources :
NSJSONSerialization
Working with JSON in Swift