Related
I am working on a multi-label classification problem. My gt labels are of shape 14 x 10 x 128, where 14 is the batch_size, 10 is the sequence_length, and 128 is the vector with values 1 if the item in sequence belongs to the object and 0 otherwise.
My output is also of same shape: 14 x 10 x 128. Since, my input sequence was of varying length I had to pad it to make it of fixed length 10. I'm trying to find the loss of the model as follows:
total_loss = 0.0
unpadded_seq_lengths = [3, 4, 5, 7, 9, 3, 2, 8, 5, 3, 5, 7, 7, ...] # true lengths of sequences
optimizer = torch.optim.Adam(model.parameters(), lr=1e-3)
criterion = nn.BCEWithLogitsLoss()
for data in training_dataloader:
optimizer.zero_grad()
# shape of input 14 x 10 x 128
output = model(data)
batch_loss = 0.0
for batch_idx, sequence in enumerate(output):
# sequence shape is 10 x 128
true_seq_len = unpadded_seq_lengths[batch_idx]
# only keep unpadded gt and predicted labels since we don't want loss to be influenced by padded values
predicted_labels = sequence[:true_seq_len, :] # for example, 3 x 128
gt_labels = gt_labels_padded[batch_idx, :true_seq_len, :] # same shape as above, gt_labels_padded has shape 14 x 10 x 128
# loop through unpadded predicted and gt labels and calculate loss
for item_idx, predicted_labels_seq_item in enumerate(predicted_labels):
# predicted_labels_seq_item and gt_labels_seq_item are 1D vectors of length 128
gt_labels_seq_item = gt_labels[item_idx]
current_loss = criterion(predicted_labels_seq_item, gt_labels_seq_item)
total_loss += current_loss
batch_loss += current_loss
batch_loss.backward()
optimizer.step()
Can anybody please check to see if I'm calculating loss correctly. Thanks
Update:
Is this the correct approach for calculating accuracy metrics?
# batch size: 14
# seq length: 10
for epoch in range(10):
TP = FP = TN = FN = 0.
for x, y, mask in tr_dl:
# mask shape: (10,)
out = model(x) # out shape: (14, 10, 128)
y_pred = (torch.sigmoid(out) >= 0.5).float().type(torch.int64) # consider all predictions above 0.5 as 1, rest 0
y_pred = y_pred[mask] # y_pred shape: (14, 10, 10, 128)
y_labels = y[mask] # y_labels shape: (14, 10, 10, 128)
# do I flatten y_pred and y_labels?
y_pred = y_pred.flatten()
y_labels = y_labels.flatten()
for idx, prediction in enumerate(y_pred):
if prediction == 1 and y_labels[idx] == 1:
# calculate IOU (overlap of prediction and gt bounding box)
iou = 0.78 # assume we get this iou value for objects at idx
if iou >= 0.5:
TP += 1
else:
FP += 1
elif prediction == 1 and y_labels[idx] == 0:
FP += 1
elif prediction == 0 and y_labels[idx] == 1:
FN += 1
else:
TN += 1
EPOCH_ACC = (TP + TN) / (TP + TN + FP + FN)
It is usually recommended to stick with batch-wise operations and avoid going into single-element processing steps while in the main training loop. One way to handle this case is to make your dataset return padded inputs and labels with additionally a mask that will come useful for loss computation. In other words, to compute the loss term with sequences of varying sizes, we will use a mask instead of doing individual slices.
Dataset
The way to proceed is to make sure you build the mask in the dataset and not in the inference loop. Here I am showing a minimal implementation that you should be able to transfer to your dataset without much hassle:
class Dataset(data.Dataset):
def __init__(self):
super().__init__()
def __len__(self):
return 100
def __getitem__(self, index):
i = random.randint(5, SEQ_LEN) # for demo puporse, generate x with random length
x = torch.rand(i, EMB_SIZE)
y = torch.randint(0, N_CLASSES, (i, EMB_SIZE))
# pad data to fit in batch
pad = torch.zeros(SEQ_LEN-len(x), EMB_SIZE)
x_padded = torch.cat((pad, x))
y_padded = torch.cat((pad, y))
# construct tensor to mask loss
mask = torch.cat((torch.zeros(SEQ_LEN-len(x)), torch.ones(len(x))))
return x_padded, y_padded, mask
Essentially in the __getitem__, we not only pad the input x and target y with zero values, we also construct a simple mask containing the positions of the padded values in the currently processed element.
Notice how:
x_padded, shaped (SEQ_LEN, EMB_SIZE)
y_padded, shaped (SEQ_LEN, N_CLASSES)
mask, shaped (SEQ_LEN,)
are all three tensors which are shape invariant across the dataset, yet mask contains the padding information necessary for us to compute the loss function appropriately.
Inference
The loss you've used nn.BCEWithLogitsLoss, is the correct one since it's a multi-dimensional loss used for binary classification. In other words, you can use it here in this multi-label classification task, considering each one of the 128 logits as an individual binary prediction. Do not use nn.CrossEntropyLoss) as suggested elsewhere, since the softmax will push a single logit (i.e. class), which is the behaviour required for single-label classification tasks.
Therefore, in the training loop, we simply have to apply the mask to our loss.
for x, y, mask in dl:
y_pred = model(x)
loss = mask*bce(y_pred, y)
# backpropagation, loss postprocessing, logs, etc.
This is what you need for the first part of the question, there are already loss functions implemented in tensorflow: https://medium.com/#aadityaura_26777/the-loss-function-for-multi-label-and-multi-class-f68f95cae525. Yours is just tf.nn.weighted_cross_entropy_with_logits, but you need to set the weight.
The second part of the question is not straightforward, because there's conditioning on the IOU, generally, when you do machine learning, you should heavily depend on matrix multiplication, in your case, you probably need to pre-calculate the IOU -> 1 or 0 as a vector, then multiply with the y_pred , element-wise, this will give you the modified y_pred . After that, you can use any accuracy available function to calculate the final result.
if you can use the CROSSENTROPYLOSS instead of BCEWithLogitsLoss there is something called ignore_index. you can use it to exclude your padded sequences. the difference between the 2 losses is the activation function used (softmax vs sigmoid). but I think you can still use the CROSSENTROPYLOSSfor binary classification as well.
I'm currently working on implementing a neural CRF as a project for school and am looking around for repos to reference.
I encountered this one the other day and have been completely stumped by the implementation of the forward algorithm.
T = feats.shape[1]
batch_size = feats.shape[0]
# alpha_recursion,forward, alpha(zt)=p(zt,bar_x_1:t)
log_alpha = torch.Tensor(batch_size, 1, self.num_labels).fill_(-10000.).to(self.device)
# normal_alpha_0 : alpha[0]=Ot[0]*self.PIs
# self.start_label has all of the score. it is log,0 is p=1
log_alpha[:, 0, self.start_label_id] = 0
# feats: sentances -> word embedding -> lstm -> MLP -> feats
# feats is the probability of emission, feat.shape=(1,tag_size)
for t in range(1, T):
log_alpha = (log_sum_exp_batch(self.transitions + log_alpha, axis=-1) + feats[:, t]).unsqueeze(1)
# log_prob of all barX
log_prob_all_barX = log_sum_exp_batch(log_alpha)
return log_prob_all_barX
From my understanding, the forward algorithm and its log alpha should be the log of the following where s_m is the scoring function - transition score from previous to current tag + emission score of neural hidden state/feature:
it seems to me that the code should be something more akin to log_alpha = log_sum_exp(transition_score + feat_score + log_alpha) if the log is applied.
I am trying to implement gradient descent algorithm to minimize a cost function for multiple linear algorithm. I am using the concepts explained in the machine learning class by Andrew Ng. I am using Octave. However when I try to execute the code it seems to fail to provide the solution as my theta values computes to "NaN". I have attached the cost function code and the gradient descent code. Can someone please help.
Cost function :
function J = computeCostMulti(X, y, theta)
m = length(y); % number of training examples
J = 0;
h=(X*theta);
s= sum((h-y).^2);
J= s/(2*m);
Gradient Descent Code:
function [theta, J_history] = gradientDescentMulti(X, y, theta, alpha, num_iters)
m = length(y); % number of training examples
J_history = zeros(num_iters, 1);
for iter = 1:num_iters
a= X*theta -y;
b = alpha*(X'*a);
theta = theta - (b/m);
J_history(iter) = computeCostMulti(X, y, theta);
end
I implemented this algorithm in GNU Octave and I separated this into 2 different functions, first you need to define a gradient function
function [thetaNew] = compute_gradient (X, y, theta, m)
thetaNew = (X'*(X*theta'-y))*1/m;
end
then to compute the gradient descent algorithm use a different function
function [theta] = gd (X, y, alpha, num_iters)
theta = zeros(1,columns(X));
for iter = 1:num_iters,
theta = theta - alpha*compute_gradient(X,y,theta,rows(y))';
end
end
Edit 1
This algorithm works for both multiple linear regression (multiple independent variable) and linear regression of 1 independent variable, I tested this with this dataset
age height weight
41 62 115
21 62 140
31 62 125
21 64 125
31 64 145
41 64 135
41 72 165
31 72 190
21 72 175
31 66 150
31 66 155
21 64 140
For this example we want to predict
predicted weight = theta0 + theta1*age + theta2*height
I used these input values for alpha and num_iters
alpha=0.00037
num_iters=3000000
The output of runing gradient descent for this experiment is as follows:
theta =
-170.10392 -0.40601 4.99799
So the equation is
predicted weight = -170.10392 - .406*age + 4.997*height
This is almost absolute minimum of the gradient, since the true results for
this problem if using PSPP (open source alternative of SPSS) are
predicted weight = -175.17 - .40*age + 5.07*height
Hope this helps to confirm the gradient descent algorithm works same for multiple linear regression and standard linear regression
I did found the bug and it was not either in the logic of the cost function or gradient descent function. But indeed in the feature normilization logic and I was accidentally returning the wrong varible and hence it was cauing the output to be "NaN"
It is dumb mistake :
What I was doing previously
mu= mean(a);
sigma = std(a);
b=(X.-mu);
X= b./sigma;
Instead what I shoul be doing
function [X_norm, mu, sigma] = featureNormalize(X)
%FEATURENORMALIZE Normalizes the features in X
% FEATURENORMALIZE(X) returns a normalized version of X where
% the mean value of each feature is 0 and the standard deviation
% is 1. This is often a good preprocessing step to do when
% working with learning algorithms.
% You need to set these values correctly
X_norm = X;
mu = zeros(1, size(X, 2));
sigma = zeros(1, size(X, 2));
% ====================== YOUR CODE HERE ======================
mu= mean(X);
sigma = std(X);
a=(X.-mu);
X_norm= a./sigma;
% ============================================================
end
So clearly I should be using X_norm insated of X and that is what cauing the code to give wrong output
I am building a neural network to learn to recognize handwritten digits from MNIST. I have confirmed that backpropagation calculates the gradients perfectly (gradient checking gives error < 10 ^ -10).
It appears that no matter how I train the weights, the cost function always tends towards around 3.24-3.25 (never below that, just approaching from above) and the training/test set accuracy is very low (around 11% for the test set). It appears that the h values in the end are all very close to 0.1 and to each other.
I cannot find why my program cannot produce better results. I was wondering if anyone could maybe take a look at my code and please tell me any reasons for this occurring. Thank you so much for all your help, I really appreciate it!
Here is my Python code:
import numpy as np
import math
from tensorflow.examples.tutorials.mnist import input_data
# Neural network has four layers
# The input layer has 784 nodes
# The two hidden layers each have 5 nodes
# The output layer has 10 nodes
num_layer = 4
num_node = [784,5,5,10]
num_output_node = 10
# 30000 training sets are used
# 10000 test sets are used
# Can be adjusted
Ntrain = 30000
Ntest = 10000
# Sigmoid Function
def g(X):
return 1/(1 + np.exp(-X))
# Forwardpropagation
def h(W,X):
a = X
for l in range(num_layer - 1):
a = np.insert(a,0,1)
z = np.dot(a,W[l])
a = g(z)
return a
# Cost Function
def J(y, W, X, Lambda):
cost = 0
for i in range(Ntrain):
H = h(W,X[i])
for k in range(num_output_node):
cost = cost + y[i][k] * math.log(H[k]) + (1-y[i][k]) * math.log(1-H[k])
regularization = 0
for l in range(num_layer - 1):
for i in range(num_node[l]):
for j in range(num_node[l+1]):
regularization = regularization + W[l][i+1][j] ** 2
return (-1/Ntrain * cost + Lambda / (2*Ntrain) * regularization)
# Backpropagation - confirmed to be correct
# Algorithm based on https://www.coursera.org/learn/machine-learning/lecture/1z9WW/backpropagation-algorithm
# Returns D, the value of the gradient
def BackPropagation(y, W, X, Lambda):
delta = np.empty(num_layer-1, dtype = object)
for l in range(num_layer - 1):
delta[l] = np.zeros((num_node[l]+1,num_node[l+1]))
for i in range(Ntrain):
A = np.empty(num_layer-1, dtype = object)
a = X[i]
for l in range(num_layer - 1):
A[l] = a
a = np.insert(a,0,1)
z = np.dot(a,W[l])
a = g(z)
diff = a - y[i]
delta[num_layer-2] = delta[num_layer-2] + np.outer(np.insert(A[num_layer-2],0,1),diff)
for l in range(num_layer-2):
index = num_layer-2-l
diff = np.multiply(np.dot(np.array([W[index][k+1] for k in range(num_node[index])]), diff), np.multiply(A[index], 1-A[index]))
delta[index-1] = delta[index-1] + np.outer(np.insert(A[index-1],0,1),diff)
D = np.empty(num_layer-1, dtype = object)
for l in range(num_layer - 1):
D[l] = np.zeros((num_node[l]+1,num_node[l+1]))
for l in range(num_layer-1):
for i in range(num_node[l]+1):
if i == 0:
for j in range(num_node[l+1]):
D[l][i][j] = 1/Ntrain * delta[l][i][j]
else:
for j in range(num_node[l+1]):
D[l][i][j] = 1/Ntrain * (delta[l][i][j] + Lambda * W[l][i][j])
return D
# Neural network - this is where the learning/adjusting of weights occur
# W is the weights
# learn is the learning rate
# iterations is the number of iterations we pass over the training set
# Lambda is the regularization parameter
def NeuralNetwork(y, X, learn, iterations, Lambda):
W = np.empty(num_layer-1, dtype = object)
for l in range(num_layer - 1):
W[l] = np.random.rand(num_node[l]+1,num_node[l+1])/100
for k in range(iterations):
print(J(y, W, X, Lambda))
D = BackPropagation(y, W, X, Lambda)
for l in range(num_layer-1):
W[l] = W[l] - learn * D[l]
print(J(y, W, X, Lambda))
return W
mnist = input_data.read_data_sets("MNIST_data/", one_hot=True)
# Training data, read from MNIST
inputpix = []
output = []
for i in range(Ntrain):
inputpix.append(2 * np.array(mnist.train.images[i]) - 1)
output.append(np.array(mnist.train.labels[i]))
np.savetxt('input.txt', inputpix, delimiter=' ')
np.savetxt('output.txt', output, delimiter=' ')
# Train the weights
finalweights = NeuralNetwork(output, inputpix, 2, 5, 1)
# Test data
inputtestpix = []
outputtest = []
for i in range(Ntest):
inputtestpix.append(2 * np.array(mnist.test.images[i]) - 1)
outputtest.append(np.array(mnist.test.labels[i]))
np.savetxt('inputtest.txt', inputtestpix, delimiter=' ')
np.savetxt('outputtest.txt', outputtest, delimiter=' ')
# Determine the accuracy of the training data
count = 0
for i in range(Ntrain):
H = h(finalweights,inputpix[i])
print(H)
for j in range(num_output_node):
if H[j] == np.amax(H) and output[i][j] == 1:
count = count + 1
print(count/Ntrain)
# Determine the accuracy of the test data
count = 0
for i in range(Ntest):
H = h(finalweights,inputtestpix[i])
print(H)
for j in range(num_output_node):
if H[j] == np.amax(H) and outputtest[i][j] == 1:
count = count + 1
print(count/Ntest)
Your network is tiny, 5 neurons make it basically a linear model. Increase it to 256 per layer.
Notice, that trivial linear model has 768 * 10 + 10 (biases) parameters, adding up to 7690 floats. Your neural network on the other hand has 768 * 5 + 5 + 5 * 5 + 5 + 5 * 10 + 10 = 3845 + 30 + 60 = 3935. In other words despite being nonlinear neural network, it is actualy a simpler model than a trivial logistic regression applied to this problem. And logistic regression obtains around 11% error on its own, thus you cannot really expect to beat it. Of course this is not a strict argument, but should give you some intuition for why it should not work.
Second issue is related to other hyperparameters, you seem to be using:
huge learning rate (is it 2?) it should be more of order 0.0001
very little training iterations (are you just executing 5 epochs?)
your regularization parameter is huge (it is set to 1), so your network is heavily penalised for learning anything, again - change it to something order of magnitude smaller
The NN architecture is most likely under-fitting. Maybe, the learning rate is high/low. Or there are most issues with the regularization parameter.
I'm currently trying to build a simple model for predicting time series. The goal would be to train the model with a sequence so that the model is able to predict future values.
I'm using tensorflow and lstm cells to do so. The model is trained with truncated backpropagation through time. My question is how to structure the data for training.
For example let's assume we want to learn the given sequence:
[1,2,3,4,5,6,7,8,9,10,11,...]
And we unroll the network for num_steps=4.
Option 1
input data label
1,2,3,4 2,3,4,5
5,6,7,8 6,7,8,9
9,10,11,12 10,11,12,13
...
Option 2
input data label
1,2,3,4 2,3,4,5
2,3,4,5 3,4,5,6
3,4,5,6 4,5,6,7
...
Option 3
input data label
1,2,3,4 5
2,3,4,5 6
3,4,5,6 7
...
Option 4
input data label
1,2,3,4 5
5,6,7,8 9
9,10,11,12 13
...
Any help would be appreciated.
I'm just about to learn LSTMs in TensorFlow and try to implement an example which (luckily) tries to predict some time-series / number-series genereated by a simple math-fuction.
But I'm using a different way to structure the data for training, motivated by Unsupervised Learning of Video Representations using LSTMs:
LSTM Future Predictor Model
Option 5:
input data label
1,2,3,4 5,6,7,8
2,3,4,5 6,7,8,9
3,4,5,6 7,8,9,10
...
Beside this paper, I (tried) to take inspiration by the given TensorFlow RNN examples. My current complete solution looks like this:
import math
import random
import numpy as np
import tensorflow as tf
LSTM_SIZE = 64
LSTM_LAYERS = 2
BATCH_SIZE = 16
NUM_T_STEPS = 4
MAX_STEPS = 1000
LAMBDA_REG = 5e-4
def ground_truth_func(i, j, t):
return i * math.pow(t, 2) + j
def get_batch(batch_size):
seq = np.zeros([batch_size, NUM_T_STEPS, 1], dtype=np.float32)
tgt = np.zeros([batch_size, NUM_T_STEPS], dtype=np.float32)
for b in xrange(batch_size):
i = float(random.randint(-25, 25))
j = float(random.randint(-100, 100))
for t in xrange(NUM_T_STEPS):
value = ground_truth_func(i, j, t)
seq[b, t, 0] = value
for t in xrange(NUM_T_STEPS):
tgt[b, t] = ground_truth_func(i, j, t + NUM_T_STEPS)
return seq, tgt
# Placeholder for the inputs in a given iteration
sequence = tf.placeholder(tf.float32, [BATCH_SIZE, NUM_T_STEPS, 1])
target = tf.placeholder(tf.float32, [BATCH_SIZE, NUM_T_STEPS])
fc1_weight = tf.get_variable('w1', [LSTM_SIZE, 1], initializer=tf.random_normal_initializer(mean=0.0, stddev=1.0))
fc1_bias = tf.get_variable('b1', [1], initializer=tf.constant_initializer(0.1))
# ENCODER
with tf.variable_scope('ENC_LSTM'):
lstm = tf.nn.rnn_cell.LSTMCell(LSTM_SIZE)
multi_lstm = tf.nn.rnn_cell.MultiRNNCell([lstm] * LSTM_LAYERS)
initial_state = multi_lstm.zero_state(BATCH_SIZE, tf.float32)
state = initial_state
for t_step in xrange(NUM_T_STEPS):
if t_step > 0:
tf.get_variable_scope().reuse_variables()
# state value is updated after processing each batch of sequences
output, state = multi_lstm(sequence[:, t_step, :], state)
learned_representation = state
# DECODER
with tf.variable_scope('DEC_LSTM'):
lstm = tf.nn.rnn_cell.LSTMCell(LSTM_SIZE)
multi_lstm = tf.nn.rnn_cell.MultiRNNCell([lstm] * LSTM_LAYERS)
state = learned_representation
logits_stacked = None
loss = 0.0
for t_step in xrange(NUM_T_STEPS):
if t_step > 0:
tf.get_variable_scope().reuse_variables()
# state value is updated after processing each batch of sequences
output, state = multi_lstm(sequence[:, t_step, :], state)
# output can be used to make next number prediction
logits = tf.matmul(output, fc1_weight) + fc1_bias
if logits_stacked is None:
logits_stacked = logits
else:
logits_stacked = tf.concat(1, [logits_stacked, logits])
loss += tf.reduce_sum(tf.square(logits - target[:, t_step])) / BATCH_SIZE
reg_loss = loss + LAMBDA_REG * (tf.nn.l2_loss(fc1_weight) + tf.nn.l2_loss(fc1_bias))
train = tf.train.AdamOptimizer().minimize(reg_loss)
with tf.Session() as sess:
sess.run(tf.initialize_all_variables())
total_loss = 0.0
for step in xrange(MAX_STEPS):
seq_batch, target_batch = get_batch(BATCH_SIZE)
feed = {sequence: seq_batch, target: target_batch}
_, current_loss = sess.run([train, reg_loss], feed)
if step % 10 == 0:
print("#{}: {}".format(step, current_loss))
total_loss += current_loss
print('Total loss:', total_loss)
print('### SIMPLE EVAL: ###')
seq_batch, target_batch = get_batch(BATCH_SIZE)
feed = {sequence: seq_batch, target: target_batch}
prediction = sess.run([logits_stacked], feed)
for b in xrange(BATCH_SIZE):
print("{} -> {})".format(str(seq_batch[b, :, 0]), target_batch[b, :]))
print(" `-> Prediction: {}".format(prediction[0][b]))
Sample output of this looks like this:
### SIMPLE EVAL: ###
# [input seq] -> [target prediction]
# `-> Prediction: [model prediction]
[ 33. 53. 113. 213.] -> [ 353. 533. 753. 1013.])
`-> Prediction: [ 19.74548721 28.3149128 33.11489105 35.06603241]
[ -17. -32. -77. -152.] -> [-257. -392. -557. -752.])
`-> Prediction: [-16.38951683 -24.3657589 -29.49801064 -31.58583832]
[ -7. -4. 5. 20.] -> [ 41. 68. 101. 140.])
`-> Prediction: [ 14.14126873 22.74848557 31.29668617 36.73633194]
...
The model is a LSTM-autoencoder having 2 layers each.
Unfortunately, as you can see in the results, this model does not learn the sequence properly. I might be the case that I'm just doing a bad mistake somewhere, or that 1000-10000 training steps is just way to few for a LSTM. As I said, I'm also just starting to understand/use LSTMs properly.
But hopefully this can give you some inspiration regarding the implementation.
After reading several LSTM introduction blogs e.g. Jakob Aungiers', option 3 seems to be the right one for stateless LSTM.
If your LSTMs need to remember data longer ago than your num_steps, your can train in a stateful way - for a Keras example see Philippe Remy's blog post "Stateful LSTM in Keras". Philippe does not show an example for batch size greater than one, however. I guess that in your case a batch size of four with stateful LSTM could be used with the following data (written as input -> label):
batch #0:
1,2,3,4 -> 5
2,3,4,5 -> 6
3,4,5,6 -> 7
4,5,6,7 -> 8
batch #1:
5,6,7,8 -> 9
6,7,8,9 -> 10
7,8,9,10 -> 11
8,9,10,11 -> 12
batch #2:
9,10,11,12 -> 13
...
By this, the state of e.g. the 2nd sample in batch #0 is correctly reused to continue training with the 2nd sample of batch #1.
This is somehow similar to your option 4, however you are not using all available labels there.
Update:
In extension to my suggestion where batch_size equals the num_steps, Alexis Huet gives an answer for the case of batch_size being a divisor of num_steps, which can be used for larger num_steps. He describes it nicely on his blog.
I believe Option 1 is closest to the reference implementation in /tensorflow/models/rnn/ptb/reader.py
def ptb_iterator(raw_data, batch_size, num_steps):
"""Iterate on the raw PTB data.
This generates batch_size pointers into the raw PTB data, and allows
minibatch iteration along these pointers.
Args:
raw_data: one of the raw data outputs from ptb_raw_data.
batch_size: int, the batch size.
num_steps: int, the number of unrolls.
Yields:
Pairs of the batched data, each a matrix of shape [batch_size, num_steps].
The second element of the tuple is the same data time-shifted to the
right by one.
Raises:
ValueError: if batch_size or num_steps are too high.
"""
raw_data = np.array(raw_data, dtype=np.int32)
data_len = len(raw_data)
batch_len = data_len // batch_size
data = np.zeros([batch_size, batch_len], dtype=np.int32)
for i in range(batch_size):
data[i] = raw_data[batch_len * i:batch_len * (i + 1)]
epoch_size = (batch_len - 1) // num_steps
if epoch_size == 0:
raise ValueError("epoch_size == 0, decrease batch_size or num_steps")
for i in range(epoch_size):
x = data[:, i*num_steps:(i+1)*num_steps]
y = data[:, i*num_steps+1:(i+1)*num_steps+1]
yield (x, y)
However, another Option is to select a pointer into your data array randomly for each training sequence.