attempt to call method 'random' (a nil value) in Lua - lua

Question

Below is my code
require 'dpnn'
require 'cunn'
local deviceNumber = tonumber(os.getenv("CUDA_CARD_NR"))
cutorch.setDevice(deviceNumber)
local module = nn.Sequential():cuda()
module:add(nn.Linear(2,1):cuda())
module:add(nn.Sigmoid():cuda())
criterion = nn.BCECriterion():cuda() -- Binary Cross Entorpy Criteria
local targets = torch.CudaTensor(10):random(0,1)
local inputs = torch.CudaTensor(10,2):uniform(-1,1)
function trainEpoch(module,criterion,inputs,targets)
for i=1,inputs:size(1) do
local idx = math.random(1,inputs:size(1))
local input, target = inputs[idx], targets:narrow(1,idx,1)
-- forward
local output= module:forward(input)
local loss= criterion:forward(output,target)
-- backward
local gradOutput = criterion:backward(output,target)
module:zeroGradParameters()
local gradInput = module:backward(input,gradOutput)
--update
module:updateGradParameters(0.9) -- momentum
module:updateParameters(0.1) -- W = W -0.1*dL/dW
end
end
for i=1,100 do
trainEpoch(module,criterion,inputs,targets)
end
I am running above using the following command
CUDA_CARD_NR=1 luajit feedforwad.lua
It gives the following error
luajit: feedforwad.lua:13: attempt to call method 'random' (a nil value)
stack traceback:
feedforwad.lua:13: in main chunk
[C]: at 0x004064f0
I know that there is some error in the line
local targets = torch.CudaTensor(10):random(0,1)
But I am not able to figure out.

Answer 1

luajit: feedforwad.lua:13: attempt to call method 'random' (a nil
value)
Is not "some error" and you should not have problems to figure out what is wrong because the error message tells you exactly what is wrong.
You tried to call the a method named random which happens to be a nil value.
This means that there is no function with that name and therefor you can't call it.
According to the reference documentation (which you should have checked befor coming here) the function is actually named rand