F# currying - calling with two parameters - f#

I have problem, that can be reduced to following example:
let func a b c = printf "%s %s %s" a b c
let partial = func "a"
let something_that_returns_two_parameters = "b", "c" // what to write here?
something_that_returns_two_parameters |> partial // what to write here?
My expected result is func being called with "a" "b" "c".
I can edit last two lines.
Is this achievable in some way?

You need to apply the tuple using the ||> operator:
something_that_returns_two_parameters ||> partial
This operator applies each component of the tuple to the function.
See F# operators for reference.

Related

MIX seqbuilder [CustomOperation] attribute method AND vanilla yield IN a single seq expression

This code runs fine except if I uncomment the last line in my custom seq expression :
type T (i: int) =
member x.i = i
override x.ToString() =
sprintf "T is %A " x.i
type TBuilder() =
member x.Yield (()) = Seq.empty
[<CustomOperation("test")>]
member x.Test1 (source : seq<_>, i: int) : seq<T> =
printfn "Calling Test1 with i= %d" i |> ignore
seq { yield! source
yield T(i) }
let t = TBuilder()
let mytest =
t {
test 42
test 43
// yield T(44) // if uncommented, it does not compile
}
If yield T(44) line is uncommented, I get an compiler error like so :
Error This control construct may only be used if the computation expression builder defines a 'For' method.
My question : Is there a way to mix
my [CustomOperation] test (from method Test1) that yields T objects
with
a vanilla yield, for example yield T(44) or any other seq related syntax
inside a unique seq expression BUT without defining any 'For' method ?
Reference : DSL in Action for F# (Chapter 7) by Anh-Dung Phan on github.
Thanks.
Short answer: no. If you change your operators so that they preserve variable bindings (via MaintainsVariableSpace=true or MaintainsVariableSpaceUsingBind=true arguments to the [<CustomOperator>] attribute constructor) then you won't need For but you'll need Bind instead.
What do you expect the computation expression you've written to mean? If you look at how the F# spec specifies the translation for computation expressions, anything of the form
bldr {
op1 x
op2 y
yield z
}
will turn into something like
bldr.For(bldr.Op2(bldr.Op1(bldr.Yield(), x), y), fun () -> b.Yield(z))
so you clearly need a For method and also your Yield method needs to do something different; at the very least it needs to be able to take arguments of arbitrary types (e.g. in the above example it needs to work on an argument of type unit and also on an argument of whatever type the value z has).

F# creating smaller tuple using Seq.map

I have written this F# code:
let tuples = [|("A",1,0);("A",2,3);("A",3,6)|]
let tupleSubset =
tuples
|> Seq.map(fun values ->
values.[0],
values.[2])
printfn "%A" tupleSubset
I am getting: The operator 'expr.[idx]' has been used on an object of indeterminate type based on information prior to this program point. Consider adding further type constraints
Can anyone tell me what I am doing wrong?
A simple way around the error you are getting would be the following:
let tuples = [|("A",1,0); ("A",2,3); ("A",3,6)|]
let tupleSubset = tuples |> Seq.map (fun (a, b, c) -> a, b)
printfn "%A" tupleSubset
As to why you are getting the error: note that the kind of index dereferencing you are attempting with values.[0] and values.[1] works for arrays, dictionaries, etc., but not for tuples, whereas each values has the type string * int * int.
Since you don't need the third element of the tuple, you can even choose not to bind it to a symbol, by writing the second line as follows:
let tupleSubset = tuples |> Seq.map (fun (a, b, _) -> a, b)
The explanation of Shredderoy is correct, accessing an element by its index is reserved to arrays, which are contiguous blocks of memory.
For tuple, if you want to access the values of a tuple in F# the general method is to pattern match
let tuple = a,b,c
let (x,y,z) = tuple
In the case of pair, the function fst and snd also give a similar access
PS : In you initial array, you dont need to use parenthesis, as the compiler recognizes the , as a tuple

Trying to understand F# active patterns, why can I do this:

I have a Dictionary over which I initially iterated thusly:
myDictionary |> Seq.iter (fun kvp -> doSomething kvp.Key kvp.Value)
Later, I discovered that I could make use of the KeyValue active pattern, and do this:
myDictionary |> Seq.iter (fun (KeyValue (k, v)) -> doSomething k v)
Knowing that active patterns aren't some form of preprocessor directive, how am I able to substitute the kvp argument in the lambda for a function that decomposes it?
Functions arguments call always be destructured using pattern matching. For instance:
let getSingleton = fun [x] -> x
let getFirst = fun (a,b) -> a
let failIfNotOne = fun 1 -> ()
let failIfNeitherOne = fun (x,1 | 1,x) -> ()
Semantically, fun<pat>-><body> is roughly equivalent to
fun x -> match x with |<pat>-><body>
| _ -> raise MatchFailureException(...)
I think the answer from #kvb covers in enough details why you can use patterns in the arguments of fun. This is not an ad-hoc feature - in F#, you can use patterns anywhere where you can bind a variable. To show some of the examples by #kvb in another contexts:
// When declaring normal functions
let foo [it] = it // Return the value from a singleton list
let fst (a, b) = a // Return first element of a pair
// When assigning value to a pattern using let
let [it] = list
let (a, b) = pair
Similarly, you can use patterns when writing fun. The match construct is a bit more powerful, because you can specify multiple clauses.
Now, active patterns are not really that magical. They are just normal functions with special names. The compiler searches for active patterns in scope when it finds a named pattern. For example, the pattern you're using is just a function:
val (|KeyValue|) : KeyValuePair<'a,'b> -> 'a * 'b
The pattern turns a KevValuePair object into a normal F# tuple that is then matched by a nested pattern (k, v) (which assigns the first element to k and the second to v). The compiler essentially translates your code to:
myDictionary |> Seq.iter (fun _arg0 ->
let _arg1 = (|KeyValue|) _arg0
let (k, v) = _arg1
doSomething k v )

Enumerator and disposing in F#

I am trying to draw lessons on the following behaviour from an example I simplified :
let groupedEnum (input: 'a seq) =
using (input.GetEnumerator()) (fun en ->
Seq.unfold(fun _ ->
if en.MoveNext() then
Some(en.Current, ())
else None) ()
)
//WORKS
let c = groupedEnum ("11111122334569999" |> List.ofSeq ) |> List.ofSeq
//BOOM !! System.NullReferenceException
let c = groupedEnum ("11111122334569999" ) |> List.ofSeq
Is the enumerator "en" disposed of independently of it being captured ? (I guess it is but is there anything to say / materials to read on this behaviour beside this msdn doc on ressources)
Why is it working if the sequence is transformed to a list first ?
Edit : this is just a toy example to illustrate a behaviour, not to be followed.
There are very few good reasons to manipulate enumerators directly.
The using function disposes the enumerator as soon as the lambda function returns. However, the lambda function creates a lazy sequence using Seq.unfold and the lazy sequence accesses the enumerator after the sequence is returned from groupedEnum.
You could either fully evaluate the whole sequence inside using (by adding List.ofSeq there) or you need to call Dispose when the end of the generated sequence is reached:
let groupedEnum (input: 'a seq) =
let en = input.GetEnumerator()
Seq.unfold(fun _ ->
if en.MoveNext() then
Some(en.Current, ())
else
en.Dispose()
None)
Exception handling becomes quite difficult in this case, but I guess that one way to do it would be to wrap the body in try .. with and call Dispose if an exception happens (and then return None).
If you use sequence expressions instead, then the meaning of use changes and it automatically disposes the enumerator after the end of sequence is reached (not when the lazy sequence is returned). So using sequence expressions might be a better choice because the hard work is done for you:
let groupedEnum (input: 'a seq) = seq {
use en = input.GetEnumerator()
let rec loop () = seq {
if en.MoveNext() then
yield en.Current
yield! loop () }
yield! loop () }
EDIT And why does it work in your first example? The enumerator returned by F# list type simply ignores Dispose and continues working, while if you call Dispose on an enumerator returned by a string, the enumerator cannot be used again. (This is arguably a bit odd behaviour of the F# list type.)

F# curried function

Anyone have a decent example, preferably practical/useful, they could post demonstrating the concept?
(Edit: a small Ocaml FP Koan to start things off)
The Koan of Currying (A koan about food, that is not about food)
A student came to Jacques Garrigue and said, "I do not understand what currying is good for." Jacques replied, "Tell me your favorite meal and your favorite dessert". The puzzled student replied that he liked okonomiyaki and kanten, but while his favorite restaurant served great okonomiyaki, their kanten always gave him a stomach ache the following morning. So Jacques took the student to eat at a restaurant that served okonomiyaki every bit as good as the student's favorite, then took him across town to a shop that made excellent kanten where the student happily applied the remainder of his appetite. The student was sated, but he was not enlightened ... until the next morning when he woke up and his stomach felt fine.
My examples will cover using it for the reuse and encapsulation of code. This is fairly obvious once you look at these and should give you a concrete, simple example that you can think of applying in numerous situations.
We want to do a map over a tree. This function could be curried and applied to each node if it needs more then one argument -- since we'd be applying the one at the node as it's final argument. It doesn't have to be curried, but writing another function (assuming this function is being used in other instances with other variables) would be a waste.
type 'a tree = E of 'a | N of 'a * 'a tree * 'a tree
let rec tree_map f tree = match tree with
| N(x,left,right) -> N(f x, tree_map f left, tree_map f right)
| E(x) -> E(f x)
let sample_tree = N(1,E(3),E(4)
let multiply x y = x * y
let sample_tree2 = tree_map (multiply 3) sample_tree
but this is the same as:
let sample_tree2 = tree_map (fun x -> x * 3) sample_tree
So this simple case isn't convincing. It really is though, and powerful once you use the language more and naturally come across these situations. The other example with some code reuse as currying. A recurrence relation to create prime numbers. Awful lot of similarity in there:
let rec f_recurrence f a seed n =
match n with
| a -> seed
| _ -> let prev = f_recurrence f a seed (n-1) in
prev + (f n prev)
let rowland = f_recurrence gcd 1 7
let cloitre = f_recurrence lcm 1 1
let rowland_prime n = (rowland (n+1)) - (rowland n)
let cloitre_prime n = ((cloitre (n+1))/(cloitre n)) - 1
Ok, now rowland and cloitre are curried functions, since they have free variables, and we can get any index of it's sequence without knowing or worrying about f_recurrence.
While the previous examples answered the question, here are two simpler examples of how Currying can be beneficial for F# programming.
open System.IO
let appendFile (fileName : string) (text : string) =
let file = new StreamWriter(fileName, true)
file.WriteLine(text)
file.Close()
// Call it normally
appendFile #"D:\Log.txt" "Processing Event X..."
// If you curry the function, you don't need to keep specifying the
// log file name.
let curriedAppendFile = appendFile #"D:\Log.txt"
// Adds data to "Log.txt"
curriedAppendFile "Processing Event Y..."
And don't forget you can curry the Printf family of function! In the curried version, notice the distinct lack of a lambda.
// Non curried, Prints 1 2 3
List.iter (fun i -> printf "%d " i) [1 .. 3];;
// Curried, Prints 1 2 3
List.iter (printfn "%d ") [1 .. 3];;
Currying describes the process of transforming a function with multiple arguments into a chain of single-argument functions. Example in C#, for a three-argument function:
Func<T1, Func<T2, Func<T3, T4>>> Curry<T1, T2, T3, T4>(Func<T1, T2, T3, T4> f)
{
return a => b => c => f(a, b, c);
}
void UseACurriedFunction()
{
var curryCompare = Curry<string, string, bool, int>(String.Compare);
var a = "SomeString";
var b = "SOMESTRING";
Console.WriteLine(String.Compare(a, b, true));
Console.WriteLine(curryCompare(a)(b)(true));
//partial application
var compareAWithB = curryCompare(a)(b);
Console.WriteLine(compareAWithB(true));
Console.WriteLine(compareAWithB(false));
}
Now, the boolean argument is probably not the argument you'd most likely want to leave open with a partial application. This is one reason why the order of arguments in F# functions can seem a little odd at first. Let's define a different C# curry function:
Func<T3, Func<T2, Func<T1, T4>>> BackwardsCurry<T1, T2, T3, T4>(Func<T1, T2, T3, T4> f)
{
return a => b => c => f(c, b, a);
}
Now, we can do something a little more useful:
void UseADifferentlyCurriedFunction()
{
var curryCompare = BackwardsCurry<string, string, bool, int>(String.Compare);
var caseSensitiveCompare = curryCompare(false);
var caseInsensitiveCompare = curryCompare(true);
var format = Curry<string, string, string, string>(String.Format)("Results of comparing {0} with {1}:");
var strings = new[] {"Hello", "HELLO", "Greetings", "GREETINGS"};
foreach (var s in strings)
{
var caseSensitiveCompareWithS = caseSensitiveCompare(s);
var caseInsensitiveCompareWithS = caseInsensitiveCompare(s);
var formatWithS = format(s);
foreach (var t in strings)
{
Console.WriteLine(formatWithS(t));
Console.WriteLine(caseSensitiveCompareWithS(t));
Console.WriteLine(caseInsensitiveCompareWithS(t));
}
}
}
Why are these examples in C#? Because in F#, function declarations are curried by default. You don't usually need to curry functions; they're already curried. The major exception to this is framework methods and other overloaded functions, which take a tuple containing their multiple arguments. You therefore might want to curry such functions, and, in fact, I came upon this question when I was looking for a library function that would do this. I suppose it is missing (if indeed it is) because it's pretty trivial to implement:
let curry f a b c = f(a, b, c)
//overload resolution failure: there are two overloads with three arguments.
//let curryCompare = curry String.Compare
//This one might be more useful; it works because there's only one 3-argument overload
let backCurry f a b c = f(c, b, a)
let intParse = backCurry Int32.Parse
let intParseCurrentCultureAnyStyle = intParse CultureInfo.CurrentCulture NumberStyles.Any
let myInt = intParseCurrentCultureAnyStyle "23"
let myOtherInt = intParseCurrentCultureAnyStyle "42"
To get around the failure with String.Compare, since as far as I can tell there's no way to specify which 3-argument overload to pick, you can use a non-general solution:
let curryCompare s1 s2 (b:bool) = String.Compare(s1, s2, b)
let backwardsCurryCompare (b:bool) s1 s2 = String.Compare(s1, s2, b)
I won't go into detail about the uses of partial function application in F# because the other answers have covered that already.
It's a fairly simple process. Take a function, bind one of its arguments and return a new function. For example:
let concatStrings left right = left + right
let makeCommandPrompt= appendString "c:\> "
Now by currying the simple concatStrings function, you can easily add a DOS style command prompt to the front of any string! Really useful!
Okay, not really. A more useful case I find is when I want to have a make a function that returns me data in a stream like manner.
let readDWORD array i = array[i] | array[i + 1] << 8 | array[i + 2] << 16 |
array[i + 3] << 24 //I've actually used this function in Python.
The convenient part about it is that rather than creating an entire class for this sort of thing, calling the constructor, calling obj.readDWORD(), you just have a function that can't be mutated out from under you.
You know you can map a function over a list? For example, mapping a function to add one to each element of a list:
> List.map ((+) 1) [1; 2; 3];;
val it : int list = [2; 3; 4]
This is actually already using currying because the (+) operator was used to create a function to add one to its argument but you can squeeze a little more out of this example by altering it to map the same function of a list of lists:
> List.map (List.map ((+) 1)) [[1; 2]; [3]];;
val it : int list = [[2; 3]; [4]]
Without currying you could not partially apply these functions and would have to write something like this instead:
> List.map((fun xs -> List.map((fun n -> n + 1), xs)), [[1; 2]; [3]]);;
val it : int list = [[2; 3]; [4]]
I gave a good example of simulating currying in C# on my blog. The gist is that you can create a function that is closed over a parameter (in my example create a function for calculating the sales tax closed over the value of a given municipality)out of an existing multi-parameter function.
What is appealing here is instead of having to make a separate function specifically for calculating sales tax in Cook County, you can create (and reuse) the function dynamically at runtime.

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