I want to read the text file into json. i have a text file with three lines.
While i tried to read using json .It returns all the 3 lines into one string.
Here is my code for your reference :
[System.Web.Mvc.HttpPost]
public JsonResult upload(HttpPostedFileBase file)
{
bool result = false;
StringBuilder strbuild = new StringBuilder();
try
{
if (file.ContentLength == 0)
throw new Exception("Zero length file!");
else
{
var fileName = Path.GetFileName(file.FileName);
var filePath = Path.Combine(Server.MapPath("~/Downloads"), fileName);
file.SaveAs(filePath);
if (!string.IsNullOrEmpty(filePath))
{
using (StreamReader sr = new StreamReader(Path.Combine(Server.MapPath("~/Downloads"), fileName)))
{
while (sr.Peek() >= 0)
{
strbuild.AppendFormat(sr.ReadLine());
}
}
}
}
}
catch (Exception)
{
result = false;
}
return new JsonResult()
{
Data = strbuild.ToString()
};
}
My Result is :
"HD-M-16-H-000001*1001*1 HD-M-16-H-000001*1001 HD-M-16-H-000001 15 JUL 201614 JUL 20170816ACHEONG SIEW FUNG 12345678I 22 DEC 1960SPO F- 15 JUL 201615 JUL 2016 HD-M-16-H-000001*1001*2 HD-M-16-H-000001*1001 HD-M-16-H-000001 15 JUL 201614 JUL 20170816AREBECCA SIOW SIQIN S1234567E 04 FEB 1995C O F- 15 JUL 201615 JUL 2016 HD-M-16-H-000001*1001*3 HD-M-16-H-000001*1001 HD-M-16-H-000001 15 JUL 201614 JUL 20170816ASAMANTHA SIOW SIHUI S1234567J 18 NOV 1993C O F- 15 JUL 201615 JUL 2016 "
My Text File is :
line 1:
HD-M-16-H-000001*1001*1 HD-M-16-H-000001*1001 HD-M-16-H-000001 15 JUL 201614 JUL 20170816ACHEONG SIEW FUNG 12345678I 22 DEC 1960SPO F- 15 JUL 201615 JUL 2016
line 2 :
HD-M-16-H-000001*1001*2 HD-M-16-H-000001*1001 HD-M-16-H-000001 15 JUL 201614 JUL 20170816AREBECCA SIOW SIQIN S1234567E 04 FEB 1995C O F- 15 JUL 201615 JUL 2016
Line 3:
HD-M-16-H-000001*1001*3 HD-M-16-H-000001*1001 HD-M-16-H-000001 15 JUL 201614 JUL 20170816ASAMANTHA SIOW SIHUI S1234567J 18 NOV 1993C O F- 15 JUL 201615 JUL 2016
So how can i show the json result with 3 (String) lines ?
Thanks in advance !!!
I have an array of hashes like this:
[{Mon, 09 May 2016 14:49:17 UTC +00:00=>12},
{Sun, 17 Apr 2016 14:08:40 UTC +00:00=>30},
{Sun, 16 Apr 2016 14:08:40 UTC +00:00=>18},
{Sun, 15 Apr 2016 14:03:33 UTC +00:00=>21}]
How can I sum the previous value from the oldest date to the current date, my expected output will be:
[{Mon, 09 May 2016 14:49:17 UTC +00:00=>81},
{Sun, 17 Apr 2016 14:08:40 UTC +00:00=>69},
{Sun, 16 Apr 2016 14:08:40 UTC +00:00=>39},
{Sun, 15 Apr 2016 14:03:33 UTC +00:00=>21}]
Thanks!
Assuming that the key of every hash in your array is a DateTime object, you can get what your want with this:
balance = [
{DateTime.parse('Mon, 09 May 2016 14:49:17 UTC +00:00')=>12},
{DateTime.parse('Sun, 17 Apr 2016 14:08:40 UTC +00:00')=>30},
{DateTime.parse('Sun, 16 Apr 2016 14:08:40 UTC +00:00')=>18},
{DateTime.parse('Sun, 15 Apr 2016 14:03:33 UTC +00:00')=>21}
] # => your original array
# Get expected array.
balance.map{ |h|
{
h.keys.first => balance.select{ |e|
e.keys.first <= h.keys.first }.map{ |s|
s[s.keys.first] }.reduce(:+)
}
}
I split the code in lines in order to improve readability.
Another approach would be to sort the array first and then use the map function to keep a running total to collect the required data.
# sort the balances by date
balance = balance.sort {|a, b| a.keys.first <=> b.keys.first }
# get running total and collect for each date
total = 0
balance.map do |entry|
date, value = entry.first
total += value
{date => total}
end
I assume your array is in lastest-to-earliest date order and looks something like arr below:
a = [{ "Mon, 09 May 2016 14:49:17 UTC +00:00"=>12 },
{ "Sun, 17 Apr 2016 14:08:40 UTC +00:00"=>30 },
{ "Sun, 16 Apr 2016 14:08:40 UTC +00:00"=>18 },
{ "Sun, 15 Apr 2016 14:03:33 UTC +00:00"=>21 }]
require 'date'
arr = a.map do |h|
(d, v) = h.to_a.first
{ DateTime.parse(d) => v }
end
#=> [{#<DateTime: 2016-05-09T14:49:17+00:00 ((2457518j,53357s,0n),+0s,2299161j)>=>12},
# {#<DateTime: 2016-04-17T14:08:40+00:00 ((2457496j,50920s,0n),+0s,2299161j)>=>30},
# {#<DateTime: 2016-04-16T14:08:40+00:00 ((2457495j,50920s,0n),+0s,2299161j)>=>18},
# {#<DateTime: 2016-04-15T14:03:33+00:00 ((2457494j,50613s,0n),+0s,2299161j)>=>21}]
We can then compute the required array as follows.
cumv = 0
arr.reverse.
map { |h| h.to_a.first }.
each_with_object([]) do |(d,v),a|
cumv += v
a << { d => cumv }
end.
reverse
#=> [{#<DateTime: 2016-05-09T14:49:17+00:00 ((2457518j,53357s,0n),+0s,2299161j)>=>81},
# {#<DateTime: 2016-04-17T14:08:40+00:00 ((2457496j,50920s,0n),+0s,2299161j)>=>69},
# {#<DateTime: 2016-04-16T14:08:40+00:00 ((2457495j,50920s,0n),+0s,2299161j)>=>39},
# {#<DateTime: 2016-04-15T14:03:33+00:00 ((2457494j,50613s,0n),+0s,2299161j)>=>21}]
I have a build log which I want to extract some content from. I want to extract [xxxxcontentxxxx] out of the log file given the system name, if any.
Input.txt:
150755: CMDLINE=omake System1
150758: Subsystem Start: Tue Dec 22 03:33:06 2015 1450726386
[xxxxcontentxxxx]
151251: Subsystem End: Tue Dec 22 03:35:00 2015 1450726500
151255: CMDLINE=omake System2
151258: Subsystem Start: Tue Dec 22 03:35:00 2015 1450726500
151668: Subsystem End: Tue Dec 22 03:36:28 2015 1450726588
151672: CMDLINE=omake System3
151675: Subsystem Start: Tue Dec 22 03:36:29 2015 1450726589
[xxxxcontentxxxx]
152020: Subsystem End: Tue Dec 22 03:38:14 2015 1450726694
152024: CMDLINE=omake System4
152027: Subsystem Start: Tue Dec 22 03:38:15 2015 1450726695
[xxxxcontentxxxx]
152294: Subsystem End: Tue Dec 22 03:39:12 2015 1450726752
152298: CMDLINE=omake System5
152301: Subsystem Start: Tue Dec 22 03:39:12 2015 1450726752
[xxxxcontentxxxx]
152558: Subsystem End: Tue Dec 22 03:40:18 2015 1450726818
For example, I want to extract for System2, System3 and System4. The output should be saved to a file in the following format:
Note: System2 is skipped because it does not contain [xxxxcontentxxxx]
Output.txt:
151672: CMDLINE=omake System3
151675: Subsystem Start: Tue Dec 22 03:36:29 2015 1450726589
[xxxxcontentxxxx]
152020: Subsystem End: Tue Dec 22 03:38:14 2015 1450726694
152024: CMDLINE=omake System4
152027: Subsystem Start: Tue Dec 22 03:38:15 2015 1450726695
[xxxxcontentxxxx]
152294: Subsystem End: Tue Dec 22 03:39:12 2015 1450726752
How can I achieve this with PowerShell?
Here is something I have. Certainly, there is a more elegant way of achieving this:
$reader = [System.IO.File]::OpenText("C:\log.txt")
try {
$startPrinting = $false
for (;;) {
$line = $reader.ReadLine()
if ($line -eq $null) { break }
if ($line.Split(' ').Contains("System2") -or
$line.Split(' ').Contains("System3") -or
$line.Split(' ').Contains("System4")
) {
$startPrinting = $true
}
if ($startPrinting) {
Write-Host $line
}
if ($line.split(' ').Contains('End:')) {
$startPrinting = $false
}
}
} finally {
$reader.Close()
}
You could for instance use a switch statement, like this:
$systems = 'System2', 'System3', 'System4'
$reader = [IO.File]::OpenText('.\Documents\test.txt')
while ($line = $reader.ReadLine()) {
switch -regex ($line) {
'CMDLINE=omake (\S+)' {
$systemName = $matches[1]
$msg = #($line)
}
'Subsystem End' {
if ($systems -contains $systemName) {
if ($msg.Count -gt 3) {
$msg -join "`r`n"
} else {
"Note: $systemName is skipped because it doesn't have content."
}
}
}
default { $msg += $line }
}
}
$reader.Close()
This is, of course, entirely unpolished as it assumes that your input file will always start with a CMDLINE line and end with a Subsystem End line. But it should give you the general idea.
My network only achieve around 80%, but the reported best score is around 85% accuracy. I m using same input data and same initalization. I dont know whats wrong, so I try to check my gradients and implemented what is recommended for gradient checking: http://ufldl.stanford.edu/tutorial/supervised/DebuggingGradientChecking/
But i m not sure, if my implementation is correct:
public void gradientchecking(double[] theta){
System.out.println("Gradient Checking started");
//costfunction returns cost and gradients
IPair<Double, double[]> org = costfunction(theta);
double[] theta_pos = new double[theta.length];
double[] theta_neg = new double[theta.length];
for (int i = 0; i < theta.length; i++) {
theta_pos[i]= theta[i];
theta_neg[i]=theta[i];
}
double mu = 1e-5;
for (int k = 0; k < 20; k++) {
theta_pos[k] = theta_pos[k] + mu;
theta_neg[k] = theta_neg[k] - mu;
IPair<Double, double[]> pos = costfunction(theta_pos);
IPair<Double, double[]> neg = costfunction(theta_neg);
System.out.println("Org: "+org.getSecond()[k] +" check:"+ ((pos.getSecond()[k]-neg.getSecond()[k])/(2*mu)));
//System.out.println("Org: "+org.getSecond()[k] +"check:"+ ((pos.getSecond()[k]-neg.getSecond()[k])/(2*mu)));
theta_pos[k] = theta_pos[k] - mu;
theta_neg[k] = theta_neg[k] + mu;
}
}
}
I got the following result after a freshly initialized theta:
Gradient Checking started
Cost: 1.1287071297725055 | Wrong: 124 | start: Thu Jul 30 22:57:08 CEST 2015 |end: Thu Jul 30 22:57:18 CEST 2015
Cost: 1.128707130295382 | Wrong: 124 | start: Thu Jul 30 22:57:18 CEST 2015 |end: Thu Jul 30 22:57:28 CEST 2015
Cost: 1.1287071292496391 | Wrong: 124 | start: Thu Jul 30 22:57:28 CEST 2015 |end: Thu Jul 30 22:57:38 CEST 2015
Org: 5.2287135944026004E-5 check:1.0184607936733826E-4
Cost: 1.1287071299252593 | Wrong: 124 | start: Thu Jul 30 22:57:38 CEST 2015 |end: Thu Jul 30 22:57:47 CEST 2015
Cost: 1.1287071296197628 | Wrong: 124 | start: Thu Jul 30 22:57:47 CEST 2015 |end: Thu Jul 30 22:57:56 CEST 2015
Org: 1.5274823511207024E-5 check:1.141254586229615E-4
Cost: 1.1287071299063134 | Wrong: 124 | start: Thu Jul 30 22:57:56 CEST 2015 |end: Thu Jul 30 22:58:05 CEST 2015
Cost: 1.1287071296387077 | Wrong: 124 | start: Thu Jul 30 22:58:05 CEST 2015 |end: Thu Jul 30 22:58:14 CEST 2015
Org: 1.3380293717695182E-5 check:1.0008639478696018E-4
Cost: 1.1287071297943114 | Wrong: 124 | start: Thu Jul 30 22:58:14 CEST 2015 |end: Thu Jul 30 22:58:23 CEST 2015
Cost: 1.1287071297507094 | Wrong: 124 | start: Thu Jul 30 22:58:23 CEST 2015 |end: Thu Jul 30 22:58:32 CEST 2015
Org: 2.1800899147740388E-6 check:9.980780136716263E-5
that indicates that my gradient calculation has an error, or the gradientchecking() method. I m not sure, can somebody help me?
In Java arrays are reference types.
int[] arr = { 8,7,6,5,4,3,2,1,8};
int[] b = arr;
b [0] = -10;
for (int i:arr) {
System.out.print (' ');
System.out.print (i);
}
outputs -10 7 6 5 4 3 2 1 8
So i mean that you incorrectly creating arrays
double[] theta_pos = theta;
double[] theta_neg = theta;
they are just references to theta, and by changing their contents you change theta also, +mu-mu = 0. Use clone() methods while copying array.
double[] theta_pos = theta.clone();
double[] theta_neg = theta.clone();
But remember that clone may not work as you expecting in some cases, with simple(non-reference) types it works ideal. Look at this
Does calling clone() on an array also clone its contents?
Have any library solution to parse as follow file list string
0x001d8f60 "-rw------- 1 root root 000000000 Jun 30 2014 YS_LIANG
drw------- 1 root root 000000000 Jun 30 2014 2014-05-08 [][][] - [][][][]
drw------- 1 root root 000000000 Jun 30 2014 FTPClient-WinCE
drw------- 1 root root 000000000 Jun 30 2014 GRAPHIC
drw------- 1 root root 000000000 Jun 30 2014 S8521 V1.6.17
drw------- 1 root root 000000000 Jun 30 2014 S8521V1.7.0
drw------- 1 root root 000000000 Jun 30 2014 Storage Card2
drw------- 1 root root 000000000 Jun 30 2014 UltraEdit 18.20.0.1021
drw------- 1 root root 000000000 Jun 30 2014 usb wireless driver
drw------- 1 root root 000000000 Jun 30 2014 Windows7 ActiveSync
-rw------- 1 root root 101384240 Jun 28 2013 avira_free_antivirus_zhtw.exe
-rw------- 1 root root 000564736 Jun 21 2011 ComTest.exe
-rw------- 1 root root 000000189 Feb 10 2014 ComTest.INI
-rw------- 1 root root 006465536 May 5 2014 DR12AsyncSocket.exe
-r"
Thanks
ok, I got the solution.
while(true)
{
nNewLineIdx = strRespFileList.Find(_T("\r\n"));
if(nNewLineIdx == -1)
{
break;
}
// TODO : Save in CStringArray
}
// Parse CString line of CStringArray
for(int loop=0; loop<CStringArray.GetCount();loop++)
{
int strLineLen = CStringArray.GetAt(loop).GetLength();
int nSerchLoc = 0;
int nStep = 0;
while(nSerchLoc < strLineLen)
{
CString strTok = CStringArray.GetAt(loop).Tokenize(_T(" "), nSerchLoc);
// TODO : Save cut information
}
}