why just the last input is storage? - printing

Question

import java.util.Scanner;
public class error{
private static class punto{
int x, y;
}
private static class lados{
punto inicio = new punto();
public lados(punto inicio1){
inicio=inicio1;
}
public punto getInicio(){
return inicio;
}
public void setInicio(punto inicio){
this.inicio = inicio;
}
}
public static void main(String[]args){
Scanner leer = new Scanner(System.in);
punto inicio = new punto();
lados arreglo[] = new lados[100];
for(int i=0; i<3; i++){
inicio.x = leer.nextInt();
inicio.y = leer.nextInt();
arreglo[i] = new lados(inicio);
}
for(int i=0; i<3; i++){
System.out.println(arreglo[i].getInicio().x);
System.out.println(arreglo[i].getInicio().y);
}
}
}
what am I doing wrong?
I want to storage ponits(x,y) in an index on an array
but just the last input is storaged in all index...
maybe there is other way to do what I want to do, if someone share it I'd love it.
input:
1
2
3
4
5
6
output:
5
6
5
6
5
6
expected output:
1
2
3
4
5
6

Answer 1

You use the same inicio instance in all lados instances you are creating :
for(int i=0; i<3; i++){
inicio.x = leer.nextInt();
inicio.y = leer.nextInt();
arreglo[i] = new lados(inicio);
}
You should create a new instance of punto for each lados if you want that the information to not be overwritten at each iteration.
Try that :
for(int i=0; i<3; i++){
inicio = new punto()
inicio.x = leer.nextInt();
inicio.y = leer.nextInt();
arreglo[i] = new lados(inicio);
}
By convention, classes should begin by an uppercase letter : Punto, Lados, etc...