I'm trying to upload a file using TIdHTTP. The problem is the access token gets changed when the request is sent to the server.
The access token that I'm using is fJNhDM6TlcpeVmD8h3jFuPJS71sxwZB8bZBXajTRB5TNAcRa6PNXfv4J7mPxIvMdMhjy7oKdTLbsRYthpBCCqGVkj4vlojJ4BRBkLAVIBJ1DZAnMZD
The API returns
HTTP/1.1 400 Bad Request
OAuth "invalid_token" "Malformed access token fJNhDM6TlcpeVmD8h3jFu=\r\nPJS71sxwZB8bZBXajTRB5TNAcRa6PNXfv4J7mPxIvMdMhjy7oKdTLbsRYthpBCCqGVkj4v=\r\nlojJ4BRBkLAVIBJ1DZAnMZD"
There is =\r\n added to my token twice.
My code is:
function TFoo.Post(const AToken, guID, AMessage, AImageFileName: string): Boolean;
var
lParam : TIdMultipartFormDataStream;
begin
Result := False;
if not FileExists(AImageFileName) then begin
LastError := 'File not found ' + AImageFileName;
Exit;
end;
ProxyCheck;
lParam := TIdMultipartFormDataStream.Create;
try
lParam.AddFormField('message', AMessage);
lParam.AddFormField('access_token', AToken);
lParam.AddFile('source', AImageFileName);
idHTTP.Request.ContentType := 'application/x-www-form-urlencoded';
try
idHTTP.Post( UrlAPI + guID + '/photos', lParam);
Result := True;
except;
LastError := idHTTP.ResponseText + sLineBreak + idHTTP.Response.WWWAuthenticate.Text;
end;
finally
lParam.Free;
end;
end;
What am I missing here ?
By default, AddFormField() sets the TIdFormDataField.ContentTransfer property to MIME's quoted-printable format. That is where the extra =\r\n is coming from. It is a "soft" line break being inserted by quoted-printable every 76 characters. Any server that supports quoted-printable would remove "soft" line breaks during decoding. But maybe your server does not.
If you want to disable the quoted-printable behavior, you can set the ContentTransfer property to either:
a blank string:
lParam.AddFormField('access_token', AToken).ContentTransfer := '';
'7bit' (since it does not contain any non-ASCII characters):
lParam.AddFormField('access_token', AToken).ContentTransfer := '7bit';
'8bit' or binary:
lParam.AddFormField('access_token', AToken).ContentTransfer := '8bit';
lParam.AddFormField('access_token', AToken).ContentTransfer := 'binary';
In this case, I would suggest #1.
On a side note, do not set the HTTP content type when posting a TIdMultipartFormDataStream. Not only are you using the wrong media type to begin with (it should be multipart/form-data instead), but the TIdMultipartFormDataStream version of Post() will simply overwrite it anyway.
function TFoo.Post(const AToken, guID, AMessage, AImageFileName: string): Boolean;
var
lParam : TIdMultipartFormDataStream;
begin
Result := False;
if not FileExists(AImageFileName) then begin
LastError := 'File not found ' + AImageFileName;
Exit;
end;
ProxyCheck;
lParam := TIdMultipartFormDataStream.Create;
try
lParam.AddFormField('message', AMessage);
lParam.AddFormField('access_token', AToken).ContentTransfer := '';
lParam.AddFile('source', AImageFileName);
try
idHTTP.Post(UrlAPI + guID + '/photos', lParam);
Result := True;
except;
LastError := idHTTP.ResponseText + sLineBreak + idHTTP.Response.WWWAuthenticate.Text;
end;
finally
lParam.Free;
end;
end;
Related
I am using Delphi XE8 and I am sendig a PUT message via idHttp.
Http.Request.CustomHeaders.Clear;
Http.Request.BasicAuthentication := false;
http.Request.Method := 'PUT';
Http.Request.Accept := '*/*';
Http.Request.ContentType := 'application/json';
http.Request.CustomHeaders.AddValue('apiKey','T_API23207_169');
http.Request.CustomHeaders.AddValue('transactionId','20200924_015');
http.Request.CustomHeaders.AddValue('usziID','1');
Http.Request.AcceptEncoding := '*';
http.Request.CharSet := 'utf-8';
kuldes_header.Text := http.Request.CustomHeaders.Text;
http.Intercept := IdLogEvent1;
IdLogEvent1.Active := true;
jsonToSend := TStringStream.create(json_adat.Text,system.sysUtils.TEncoding.UTF8);
kuldes_body.Lines.LoadFromStream(jsonToSend);
try
try
send_text := http.Put('http://10.109.132.24:8090/rest/usziIroda/1',jsonToSend);
resp := http.ResponseText;
code := http.ResponseCode;
jsonToSend.Position := 0;
except
on E: EIdHTTPProtocolException do
begin
code := e.ErrorCode;
error_message := e.ErrorMessage;
end;
end;
hiba_kod.Lines.Add(IntToStr(code));
valasz_uzenet.Text := send_text;
hiba_uzenet.Text := error_message; enter code here
The returned error message has strange characters:
"Megadott tranzakció azonosÃtóval már történt API hÃvás"
But it should be like this:
"Megadott tranzakció azonosítóval már történt API hívás"
How can I convert the returned message to normal string?
Thank you!
The result you showed - Megadott tranzakció azonosÃtóval már történt API hÃvás - is the UTF-8 encoded form of Megadott tranzakció azonosítóval már történt API hívás being misinterpreted in Latin-1/ISO-8859-1. Which most likely means that the response did not specify a UTF-8 charset in its Content-Type header (since you have an Intercept assigned, you can easily verify this for yourself), so Indy would fall back to a default charset instead.
The original UTF-8 bytes have been decoded and lost before you can access the response data in send_text or error_message. However, since ISO-8859-1 basically has a 1:1 relationship between byte values and Unicode codepoint values, what you can try doing in this specific situation is copy the ErrorMessage's Char values as-is to a RawByteString(65001) or UTF8String, and then let the RTL decode that as UTF-8 back into a proper UTF-16 (Unicode)String, eg:
function DecodeISO88591AsUTF8(const S: string): string;
var
utf8: UTF8String;
I: Integer;
begin
SetLength(utf8, Length(S));
for I := Low(S) to High(S) do
utf8[I] := AnsiChar(S[I]);
Result := string(utf8);
end;
...
error_message := e.ErrorMessage;
//if not TextIsSame(http.Response.CharSet, 'utf-8') then
if TextIsSame(http.Response.CharSet, 'ISO-8859-1') then
error_message := DecodeISO88591AsUTF8(error_message);
Alternatively, you can instead call the overloaded version of TIdHTTP.Put() that fills a response TStream instead of returning a decoded String, and then you can decode the original raw bytes however you want. Just be sure to enable the hoNoProtocolErrorException and hoWantProtocolErrorContent flags in the TIdHTTP.HTTPOptions property so that any error response is stored in the TStream, then you don't need a try/except to handle the EIdHTTPProtocolException separately.
http.HTTPOptions := http.HTTPOptions + [hoNoProtocolErrorException, hoWantProtocolErrorContent];
...
RespStrm := TMemoryStream.Create;
try
http.Put('http://10.109.132.24:8090/rest/usziIroda/1', jsonToSend, RespStrm);
resp := http.ResponseText;
code := http.ResponseCode;
jsonToSend.Position := 0;
RespStrm.Position := 0;
if (code div 100) = 2 then
begin
send_text := decode RespStrm as needed...;
end else
begin
error_message := decode RespStrm as needed...;
end;
finally
RespStrm.Free;
end;
...
My goal is to be able to convert TMemoryStream to string. I have this code to get the data into the TMemoryStream:
var
idHttp : TIdHTTPEx;
url : string;
slTemp : TStringList;
memoryStream : TMemoryStream;
begin
try
idHttp := TIdHTTPEx.Create(nil);
slTemp := TStringList.Create;
memoryStream := TMemoryStream.Create;
try
url := GetURL;
SetParams(slTemp);
idHttp.Request.Accept := 'application/json, text/javascript, */*; q=0.01';
idHttp.Request.AcceptEncoding := 'gzip, deflate, br';
idHttp.Request.AcceptLanguage := 'en-US,en;q=0.9';
idHttp.Request.CacheControl := 'no-cache';
idHttp.Request.Connection := 'keep-alive';
idHttp.Request.ContentLength := 16;
idHttp.Request.ContentType := 'application/x-www-form-urlencoded; charset=UTF-8';
idHttp.Post(url, slTemp, memoryStream);
Result := MemoryStreamToString(memoryStream);
finally
memoryStream.Free;
slTemp.Free;
idHttp.Free;
end;
except on E : Exception do
begin
Result := 'e:' + E.Message;
end;
end;
end;
And this is my code to convert it to a string:
function MemoryStreamToString(MemoryStream : TMemoryStream): string;
var
StringStream: TStringStream;
begin
Result:='';
StringStream:= TStringStream.Create('', TEncoding.UTF8);
try
MemoryStream.Position := 0;
StringStream.CopyFrom(MemoryStream, MemoryStream.Size);
Result:= StringStream.DataString;
Result := Result;
finally
FreeAndNil(StringStream);
end;
end;
My function works fine in most of the conversion but not this. I checked these links: link1, link2 but they are different than my situation. I tried link3 too but still fail.
Any idea how to solve the problem?
You don't need to decode the raw data manually. Just let TIdHTTP do it for you. The Post() method has an overload that returns a decoded string:
Result := idHttp.Post(url, slTemp);
Also, you need to get rid of this line completely:
idHttp.Request.AcceptEncoding := 'gzip, deflate, br';
Otherwise TIdHTTP will not be able to decode the response correctly if the server decides to send a compressed response. You are manually giving the server permission to do so, but you are not setting up the TIdHTTP.Compressor property so TIdHTTP can handle decompression. Do not set the AcceptEncoding manually unless you are willing and able to manually detect and decode a response that has been actually been encoded in one of the formats you specify. Otherwise, just let TIdHTTP manage the AcceptEncoding property internally based on its actual capabilites.
i want to send emoji with indy 9.00.10 on delphi 7. i use tnt VCL Controls .
i found this url http://apps.timwhitlock.info/emoji/tables/unicode for unicode and bytes code.
how to convert this codes to delphi Constants for Send with indy.
i use this delphi code for send message to telegram bot:
procedure TBotThread.SendMessage(ChatID:String; Text : WideString;
parse_mode:string;disable_notification:boolean);
Var
Stream: TStringStream;
Params: TIdMultipartFormDataStream;
//Text : WideString;
msg : WideString;
Src : string;
LHandler: TIdSSLIOHandlerSocket;
begin
try
try
if FShowBotLink then
Text := Text + LineBreak + FBotUser;
msg := '/sendmessage';
Stream := TStringStream.Create('');
Params := TIdMultipartFormDataStream.Create;
Params.AddFormField('chat_id',ChatID);
if parse_mode <> '' then
Params.AddFormField('parse_mode',parse_mode);
if disable_notification then
Params.AddFormField('disable_notification','true')
else
Params.AddFormField('disable_notification','false');
Params.AddFormField('disable_web_page_preview','true');
Params.AddFormField('text',UTF8Encode(Text));
LHandler := TIdSSLIOHandlerSocket.Create(nil);
FidHttpSend.ReadTimeout := 30000;
FidHttpSend.IOHandler:=LHandler;
LHandler.SSLOptions.Method := sslvTLSv1;
LHandler.SSLOptions.Mode := sslmUnassigned;
FidHttpSend.HandleRedirects := true;
FidHttpSend.Post(BaseUrl + API + msg, Params, Stream);
finally
Params.Free;
Stream.Free;
ENd;
except
on E: EIdHTTPProtocolException do
begin
if E.ReplyErrorCode = 403 then
begin
WriteToLog('Bot was blocked by the user');
end;
end;
end;
end;
bytes sample for emojies:
AERIAL_TRAMWAY = '\xf0\x9f\x9a\xa1';
AIRPLANE = '\xe2\x9c\x88';
ALARM_CLOCK = '\xe2\x8f\xb0';
ALIEN_MONSTER = '\xf0\x9f\x91\xbe';
sorry for bad english!!!
The Telegram Bot API supports several forms of input:
We support GET and POST HTTP methods. We support four ways of passing parameters in Bot API requests:
URL query string
application/x-www-form-urlencoded
application/json (except for uploading files)
multipart/form-data (use to upload files)
You are using the last option.
Indy 9 does not support Delphi 2009+ or Unicode. All uses of string are assumed to be AnsiString, which is the case in Delphi 7. Any AnsiString you add to TIdMultipartFormDataStream or TStrings, even a UTF-8 encoded one, will be transmitted as-is by TIdHTTP. However, there is no option to specify to the server that the string data is actually using UTF-8 as a charset. But, according to the docs:
All queries must be made using UTF-8.
So not specifying an explicit charset might not be problem.
If you still have problems with multipart/form-data, then consider using application/x-www-form-urlencoded (use TIdHTTP.Post(TStrings)) or application/json (use TIdHTTP.Post(TStream)) instead:
procedure TBotThread.SendMessage(ChatID: String; Text: WideString; parse_mode: string; disable_notification: boolean);
var
Params: TStringList;
LHandler: TIdSSLIOHandlerSocket;
begin
if FShowBotLink then
Text := Text + LineBreak + FBotUser;
Params := TStringList.Create;
try
Params.Add('chat_id=' + UTF8Encode(ChatID));
if parse_mode <> '' then
Params.Add('parse_mode=' + UTF8Encode(parse_mode));
if disable_notification then
Params.Add('disable_notification=true')
else
Params.Add('disable_notification=false');
Params.Add('disable_web_page_preview=true');
Params.Add('text=' + UTF8Encode(Text));
LHandler := TIdSSLIOHandlerSocket.Create(nil);
try
LHandler.SSLOptions.Method := sslvTLSv1;
LHandler.SSLOptions.Mode := sslmClient;
FidHttpSend.HandleRedirects := true;
FidHttpSend.ReadTimeout := 30000;
FidHttpSend.IOHandler := LHandler;
try
try
FidHttpSend.Post(BaseUrl + API + '/sendmessage', Params, TStream(nil));
except
on E: EIdHTTPProtocolException do
begin
if E.ReplyErrorCode = 403 then
begin
WriteToLog('Bot was blocked by the user');
end;
end;
end;
finally
FidHttpSend.IOHandler := nil;
end;
finally
LHandler.Free;
end;
finally
Params.Free;
end;
end;
procedure TBotThread.SendMessage(ChatID: String; Text: WideString; parse_mode: string; disable_notification: boolean);
var
Params: TStringStream;
LHandler: TIdSSLIOHandlerSocket;
function JsonEncode(const wStr: WideString): string;
var
I: Integer;
Ch: WideChar;
begin
// JSON uses UTF-16 text, so no need to encode to UTF-8...
Result := '';
for I := 1 to Length(wStr) do
begin
Ch := wStr[i];
case Ch of
#8: Result := Result + '\b';
#9: Result := Result + '\t';
#10: Result := Result + '\n';
#12: Result := Result + '\f';
#13: Result := Result + '\r';
'"': Result := Result + '\"';
'\': Result := Result + '\\';
'/': Result := Result + '\/';
else
if (Ord(Ch) >= 32) and (Ord(Ch) <= 126) then
Result := Result + AnsiChar(Ord(wStr[i]))
else
Result := Result + '\u' + IntToHex(Ord(wStr[i]), 4);
end;
end;
end;
begin
if FShowBotLink then
Text := Text + LineBreak + FBotUser;
Params := TStringStream.Create('');
try
Params.WriteString('{');
Params.WriteString('chat_id: "' + JsonEncode(ChatID) + '",');
if parse_mode <> '' then
Params.WriteString('parse_mode: "' + JsonEncode(parse_mode) + '",')
if disable_notification then
Params.WriteString('disable_notification: True,')
else
Params.WriteString('disable_notification: False,');
Params.WriteString('disable_web_page_preview: True,');
Params.WriteString('text: "' + JsonEncode(Text) + '"');
Params.WriteString('}');
Params.Position := 0;
LHandler := TIdSSLIOHandlerSocket.Create(nil);
try
LHandler.SSLOptions.Method := sslvTLSv1;
LHandler.SSLOptions.Mode := sslmClient;
FidHttpSend.HandleRedirects := true;
FidHttpSend.ReadTimeout := 30000;
FidHttpSend.IOHandler := LHandler;
try
try
FidHttpSend.Request.ContentType := 'application/json';
FidHttpSend.Post(BaseUrl + API + '/sendmessage', Params, TStream(nil));
except
on E: EIdHTTPProtocolException do
begin
if E.ReplyErrorCode = 403 then
begin
WriteToLog('Bot was blocked by the user');
end;
end;
end;
finally
FidHttpSend.IOHandler := nil;
end;
finally
LHandler.Free;
end;
finally
Params.Free;
end;
end;
That being said, your function's Text parameter is a WideString, which uses UTF-16, so you should be able to send any Unicode text, including emojis. If you are trying to generate text in your code, just make sure you UTF-16 encode any non-ASCII characters correctly. For example, codepoint U+1F601 GRINNING FACE WITH SMILING EYES is wide chars $D83D $DE01 in UTF-16:
var
Text: WideString;
Text := 'hi ' + #$D83D#$DE01; // 'hi 😁'
SendMessage('#channel', Text, 'Markup', False);
Alternatively, you can use HTML in your text messages, so you can encode non-ASCII characters using numerical HTML entities. According to the docs:
All numerical HTML entities are supported.
Codepoint U+1F601 is numeric entity $#128513; in HTML:
var
Text: WideString;
Text := 'hi $#128513;'; // 'hi 😁'
SendMessage('#channel', Text, 'HTML', False);
I am sending alright files (doc, pdf, xls) with english filenames but when I am sending files with greek filenames I am getting on server side ????????? characters for filename & the error message Socket Error 10053, software caused connection abort. Is there a solution for this kind of problem.
Code:
procedure TForm1.LoadFileButtonClick(Sender: TObject);
begin
OpenDialog1.Filter := 'All Files (*.*)';
OpenDialog1.FilterIndex := 1;
if OpenDialog1.Execute then
begin
Edit1.Text := ExtractFileName(OpenDialog1.FileName);
Edit3.Text := OpenDialog1.FileName;
Fstream := TFileStream.Create(OpenDialog1.FileName, fmopenread);
Edit2.Text := inttostr(Fstream.Size);
Fstream.Position := 0;
FreeandNil(FStream);
//Fstream.Free;
end;
end;
procedure TForm1.SendFileButtonClick(Sender: TObject);
var
IncommingText: string;
begin
if (opendialog1.filename<>'') and (CheckBox1.Checked = True) then begin
IdTCPClient1.iohandler.writeln(edit1.text + '#' + edit2.text + ';' + edit3.text + ',');
Sleep(2000);
try
IdTCPClient1.IOHandler.largestream:=true;
Fstream := TFileStream.Create(OpenDialog1.FileName, fmopenread);
IdTCPClient1.IOHandler.Write(Fstream, 0 ,true);
finally
Fstream.Position := 0;
FreeandNil(FStream);
//Fstream.Free;
memo1.Lines.Add('File Sent');
IncommingText := IdTCPClient1.iohandler.readln;
if IncommingText = 'DONE!' then begin
Memo1.Lines.Add('File ' +Edit1.Text +' ' +Edit2.Text +' was received successfully by the Server');
//APPLICATION.ProcessMessages;
end else begin Memo1.Lines.Add('File ' +Edit1.Text +' was not received by the Server'); end;
end; //try - finally
end else begin
showmessage('Please choose a file Or Try to connect to the Server');
end;
end;
Indy's default text encoding is ASCII (because the majority of Internet protocols are still largely ASCII based, unless they define extra extensions to support Unicode). That is why you are getting ? for non-ASCII characters. To send non-ASCII characters, you need to tell Indy which text encoding to use that is compatible with the characters you are exchanging. UTF-8 is usually the best choice for that. There are three ways you can do that:
set the global GIdDefaultTextEncoding variable in the IdGlobal unit. It is set to encASCII by default, you can set it to encUTF8 instead:
procedure TForm1.FormCreate(Sender: TObject);
begin
GIdDefaultTextEncoding := encUTF8;
end;
set the TIdIOHandler.DefStringEncoding property to TIdTextEncoding.UTF8 (or IndyTextEncoding_UTF8 if you are using Indy 10.6+):
procedure TForm1.IdTCPClient1Connected(Sender: TObject);
begin
IdTCPClient1.IOHandler.DefStringEncoding := TIdTextEncoding.UTF8;
// or:
// IdTCPClient1.IOHandler.DefStringEncoding := IndyTextEncoding_UTF8;
end;
pass TIdTextEncoding.UTF8 (or IndyTextEncoding_UTF8) directly to the AByteEncoding parameter of WriteLn():
IdTCPClient1.IOHandler.WriteLn(..., TIdTextEncoding.UTF8);
// or:
// IdTCPClient1.IOHandler.WriteLn(..., IndyTextEncoding_UTF8);
Keep in mind that you are using an Ansi version of Delphi, where string maps to AnsiString, and thus Indy has to perform an additional Ansi-to-Unicode conversion of AnsiString data before it can then apply the specified text encoding to produce the bytes it transmits. Typically, Indy uses the OS's default Ansi encoding to handle that initial conversion (so if your AnsiString data is Greek encoded, and your OS is set to Greek, you will be fine), however you can use the TIdIOHandler.DefAnsiEncoding property, or the ASrcEncoding parameter of WriteLn(), if you need to specify that your AnsiString data is using a different encoding.
As for your socket error, without seeing a call stack leading up to the error, or at least which line of your code is raising it, that is difficult to troubleshoot. My guess is that it is related to you calling ReadLn() inside of the finally block regardless of whether WriteLn() or Write() actually succeeded. That code needs to be moved out of the finally block, it does not belong there.
Try something more like this instead:
procedure TForm1.LoadFileButtonClick(Sender: TObject);
begin
OpenDialog1.Filter := 'All Files (*.*)';
OpenDialog1.FilterIndex := 1;
if OpenDialog1.Execute then
begin
Edit1.Text := ExtractFileName(OpenDialog1.FileName);
Edit3.Text := OpenDialog1.FileName;
// Indy has its own FileSizeByName() function...
Edit2.Text := IntToStr(FileSizeByName(OpenDialog1.FileName));
end;
end;
procedure TForm1.SendFileButtonClick(Sender: TObject);
var
IncommingText: string;
Strm: TFileStream;
begin
if not CheckBox1.Checked then
begin
ShowMessage('Please connect to the Server');
Exit;
end;
if OpenDialog1.FileName = '' then
begin
ShowMessage('Please choose a file');
Exit;
end;
Strm := TFileStream.Create(OpenDialog1.FileName, fmOpenRead);
try
IdTCPClient1.IOHandler.WriteLn(Edit1.Text + '#' + Edit2.Text + ';' + Edit3.Text + ',', TIdTextEncoding.UTF8);
IdTCPClient1.IOHandler.LargeStream := True;
IdTCPClient1.IOHandler.Write(Strm, 0 , True);
finally
Strm.Free;
end;
Memo1.Lines.Add('File Sent');
IncommingText := IdTCPClient1.IOHandler.ReadLn;
if IncommingText = 'DONE!' then begin
Memo1.Lines.Add('File ' + Edit1.Text + ' ' + Edit2.Text + ' was received successfully by the Server');
//APPLICATION.ProcessMessages;
end else
begin
Memo1.Lines.Add('File ' + Edit1.Text + ' was not received by the Server');
end;
end;
Lastly, just an FYI, you are setting the AWriteByteCount parameter of Write() to True, so it is going to transmit the stream size (as an Int64 because of LargeStream=True) before then sending the TStream data, so putting the file size in the WriteLn() data is redundant.
I'm making requests to the webaddress to get XML files throught the HTTPS connection. But this connection works like 50%. In most cases it fails. Usual error is "socket error #10060". Or "Error connecting with SSL. EOF was observed that violates the protocol". What I'm doing wrong?
function SendRequest(parameters: string): IXMLDocument;
var
sPostData: TStringList;
sHttpSocket: TIdHTTP;
sshSocketHandler: TIdSSLIOHandlerSocketOpenSSL;
resStream: TStringStream;
xDoc: IXMLDocument;
begin
sPostData := TStringList.Create;
try
sPostData.Add('add some parameter to post' + '&');
sPostData.Add('add some parameter to post' + '&');
sPostData.Add('add some parameter to post' + '&');
sPostData.Add(parameters);
sHttpSocket := TIdHTTP.Create;
sshSocketHandler := TIdSSLIOHandlerSocketOpenSSL.Create;
sHttpSocket.IOHandler := sshSocketHandler;
sHttpSocket.Request.ContentType := 'application/x-www-form-urlencoded';
sHttpSocket.Request.Method := 'POST';
resStream := TStringStream.Create;
sHttpSocket.Post(Self.sUrl, sPostData, resStream);
xDoc := CreateXMLDoc;
xDoc.LoadFromStream(resStream);
Result := xDoc;
resStream.Free;
sHttpSocket.Free;
sshSocketHandler.Free;
sPostData.Free;
except on E: Exception do
begin
TCommon.ErrorLog('errorLog.txt', DateTimeToStr(Now) + ' ' + E.Message);
end
end;
end;
Maybe I can do this in another way, that works like 100%, when internet connection is available?
Regards,
evilone
An "EOF" error suggests you are connnecting to a server that is not actually using SSL to begin with, or the SSL data may be corrupted.
Besides that, why are you including explicit '&' characters between your post data parameters? Don't do that, Indy will just encode them and send its own '&' characters. Also, consider using TMemoryStream instead of TStringStream to ensure IXMLDocumect.LoadFromStream() is loading the server's original raw XML data as-is, and not an altered version that the RTL/VCL produces due to Unicode handling (TStringStream is TEncoding-enabled).
Edit: Given the URL you provided, an example of calling verifyUser() would look like this:
const
ERPLYAccountCode = '...';
function verifyUser(const user, pass: string; const sessionLength: Integer = 3600): IXMLDocument;
var
sPostData: TStringList;
sHttpSocket: TIdHTTP;
sshSocketHandler: TIdSSLIOHandlerSocketOpenSSL;
resStream: TMemoryStream;
xDoc: IXMLDocument;
begin
Result := nil;
try
resStream := TMemoryStream.Create;
try
sPostData := TStringList.Create;
try
sPostData.Add('clientCode=' + ERPLYAccountCode);
sPostData.Add('request=verifyUser');
sPostData.Add('version=1.0');
sPostData.Add('responseType=XML');
sPostData.Add('responseMode=normal');
sPostData.Add('username=' + user);
sPostData.Add('password=' + pass);
sPostData.Add('sessionLength=' + IntToStr(sessionLength));
sHttpSocket := TIdHTTP.Create;
try
sshSocketHandler := TIdSSLIOHandlerSocketOpenSSL.Create(sHttpSocket);
sHttpSocket.IOHandler := sshSocketHandler;
sHttpSocket.Request.ContentType := 'application/x-www-form-urlencoded';
sHttpSocket.Post('https://www.erply.net/api/', sPostData, resStream);
finally
sHttpSocket.Free;
end;
finally
sPostData.Free;
end;
resStream.Position := 0;
xDoc := CreateXMLDoc;
xDoc.LoadFromStream(resStream);
Result := xDoc;
finally
resStream.Free;
end;
except
on E: Exception do
begin
TCommon.ErrorLog('errorLog.txt', DateTimeToStr(Now) + ' ' + E.Message);
end;
end;
end;