This should be easy but I am struggling on that.
I googled already but nothing seems to work.
(I am using wxMaxima 15.08.1 on Windows)
My example code looks like this:
kill (all);
numer:true;
sigma_z: 1000.0$ /*[N/mm²]*/
sigma_b_zul : simga_z*0.7;
sigma_b_zul : simga_z*0.7, numer;
sigma_b_zul : simga_z*0.7, numer:true;
float(sigma_b_zul);
the output is every time:
0.7 simga_z
the next cell looks like:
d_d: 1000$ /*dfd*/
sigma_g_f_d: d_d * 0.7;
the result is:
7.0E+2
I am completely clueless why maxima behaves like this. Can anyone help?
The variable you define is
sigma_z: 1000.0$ /*[N/mm²]*/
but then you call
simga_z*0.7;
Please, notice the difference between sigma_z and simga_z.
Related
due to using nginx lua (kong gateway)
would like to replace
from
{"body":"\r\n \"username\": \"sampleUser\",\r\n \"password\": \"samplePassword\",\r\n"}
to
{"body":"\r\n \"username\": \"sampleUser\",\r\n \"password\": \"***REDACTED***\",\r\n"}
from
username=sampleUser&password=samplePassword
to
username=sampleUser&password=***REDACTED***
from
"password" : "krghfkghkfghf"
to
"password" : "***REDACTED***"
i did try on sample https://stackoverflow.com/a/16638937/712063
local function replacePass(configstr, newpass)
return configstr:gsub("(%[\"password\"%]%s*=%s*)%b\"\"", "%1\"" .. newpass .. "\"")
end
it does not work, any recommended reference ?
maybe something like this:
local t = {
[[{"body":"\r\n \"username\": \"sampleUser\",\r\n \"password\": \"samplePassword\",\r\n"} ]],
[[username=sampleUser&password=samplePassword]],
[["password" : "krghfkghkfghf"]]
}
local newpass ="***REDACTED***"
for k,example in pairs(t) do
res = example:gsub('(password[\\" :]+)(.-)([\\"]+)',"%1"..newpass.."%3")
res = res:gsub("(password=).+","%1"..newpass)
print(res)
end
out:
{"body":"\r\n \"username\": \"sampleUser\",\r\n \"password\": \"***REDACTED***\",\r\n"}
username=sampleUser&password=***REDACTED***
"password" : "***REDACTED***"
There's several things wrong with that at first sight.
1. You only check for =
In your test data you seem to have cases with key = value as well as key : value but your pattern only checks for =; replace that with [=:] for a simple fix.
2. You can't balance quotation marks
I don't know how you expect this to work, but [[%b""]] just finds the shortest possible string between two " characters, just as [[".-"]] would. If that's your intention, then there's nothing wrong with writing it using %b though.
3. Just don't
As I don't know the context, I can't say if this really is a bad idea or not, but it does seem like a very brittle solution. If this is an option, I would recommend considering the alternative and going with something more robust.
As for what a better alternative could look like, I can't say without knowledge of your requirements. Maybe normalizing the data into a Lua table and replacing the password key in a uniform way? This would make sure that the data is either sanitized, or errors during parsing.
Beyond that, it would help if you told us how it doesn't work. It's easy to miss bugs when reading someone elses code, but knowing how the code misbehaves can help a lot with actually spotting the problem.
EDIT:
4. You didn't even remove the brackets
You didn't even remove the [] from that other stack overflow answer. Obviously that doesn't work without any modifications.
I know the pseudo code.
It goes something like this:
if f(x): g(x)*h(x) then u:g(x) and v:h(x)
for i:0 thru n do block
( binomial(n,i)*diff(u,x,i)*diff(v,x,n-i), i:i+1);
I'm not able to actually execute the code. I get some thing I don't need. Please
help me.
Thankyou
kill(all)$
y:x^4*log(x);
u:log(x);
v:x^4;
n:4;
lsum(binomial(n,i)*diff(u,x,n-i)*diff(v,x,i),i,[0,1,2,3,4]);
I am having some issue with ezSearch (Umbraco) and it is very similar to this one
http://our.umbraco.org/projects/website-utilities/ezsearch/bugs-feedback-suggestions/48460-Search-error-when-searching-for-test-keyword?p=0#comment176864
Here is the screenshot of error
http://our.umbraco.org/media/upload/e08b702e-b738-42a4-81d8-382a4400b96a/error.jpg
Can anyone hep me with this please?
Thank you,
Adi
I'm using ezSearch, and from reading the ezSearch.cshtml this looks like a bug if the query passed to the macro is " ". That is to say, if the search is empty, it works ok, but if the search is an actual quoted space then the line in the cshtml: (line 60 in my version)
// Check the search term isn't empty
if(!string.IsNullOrWhiteSpace(model.SearchTerm))
{
// Tokenize the search term
model.SearchTerms = Tokenize(model.SearchTerm);
...
etc.
...
}
ends up with a bad set of tokens in model.SearchTerms.
it's a bit of a hack, but i think putting this before that if statement will help.
model.SearchTerm = model.SearchTerm.Replace("\"","").Replace(" ","").Replace("'","");
..hope that helps.
'ingie.
So, I’m having an issue while trying to split strings into tables (players into teams). When there are two players only, it works like a charm, but when there are 3+ players, this pops up: “Init Error : transformice.lua:7: bad argument: table expected, got nil”. Everything seems to be ok, I really don’t know what’s wrong. Can you guys please help me? Thanks! Here is my code:
ps = {"Player1","Player2","Player3","Player4"}
local teams={{},{},{}}
--[[for name,player in pairs(tfm.get.room.playerList) do
table.insert(ps,name)
end]]
table.sort(ps,function() return math.random()>0.5 end)
for i,player in ipairs(ps) do
table.insert(teams[i%#teams],player)
end
Lua arrays start at index 1, not 0. In the case of when you have 3 players this line:
table.insert(teams[i%#teams],player)
Would evaluate to:
table.insert(teams[3%3],player)
Which then would end up being:
table.insert(teams[0],player)
And teams[0] would be nil. You should be able to write it as:
table.insert(teams[i%#teams+1],player)
instead.
I'm trying to get a handle on how OOP is done in Lua, and I thought I had a simple way to do it but it isn't working and I'm just not seeing the reason. Here's what I'm trying:
Person = { };
function Person:newPerson(inName)
print(inName);
p = { };
p.myName = inName;
function p:sayHello()
print ("Hello, my name is " .. self.myName);
end
return p;
end
Frank = Person.newPerson("Frank");
Frank:sayHello();
FYI, I'm working with the Corona SDK, although I am assuming that doesn't make a difference (except that's where print() comes from I believe). In any case, the part that's killing me is that inName is nil as reported by print(inName)... therefore, myName is obviously set to nil so calls to sayHello() fail (although they work fine if I hardcode a value for myName, which leads me to think the basic structure I'm trying is sound, but I've got to be missing something simple). It looks, as far as I can tell, like the value of inName is not being set when newPerson() is called, but I can't for the life of me figure out why; I don't see why it's not just like any other function call.
Any help would be appreciated. Thanks!
Remember that this:
function Person:newPerson(inName)
Is equivalent to this:
function Person.newPerson(self, inName)
Therefore, when you do this:
Person.newPerson("Frank");
You are passing one parameter to a function that expects two. You probably don't want newPerson to be created with :.
Try
Frank = Person:newPerson("Frank");