I have Dictionary and I am adding to tableView.
let myArray = [["name": "First element", "foo": "bar","GroupID":"1"], ["name": "First element", "foo": "bar","GroupID":"1"],["name": "Second element", "foo": "bar","GroupID":"2"], ["name": "Second element", "foo": "bar","GroupID":"2"]]
In this dictionary I have key GroupID.
Is it possible that I can get dictionary data whose GroupID = %#?
I want to filter data based on grouping
Suppose I have four data, and group id is same in two data. I want to delete all data whose GroupID is same from dictionary.
If groupid == 1 than data will be deleted from dictionary whose GroupID == 1 and tableview will reload data.
I am doing this because I want to delete group data.
You can use filter on your Array to remove those dictionaries from your array, check this example
var subitems: [[String:String]] = [
["groupid": "1", "b": "2"],
["groupid": "3", "b": "4"],
["groupid": "1", "b": "6"]
]
var filteredSubitems = subitems.filter{
$0["groupid"] != "1" // change with your groupid
}
print(filteredSubitems)
Here is a simple way to do it:
var index = 0
for element in myArray {
if element["GroupID"] == "1" {
myArray.remove(at: 0)
index += 1
} else {
index += 1
}
}
print(myArray):
It prints out:
[["name": "Second element", "GroupID": "2", "foo": "bar"], ["name":
"Second element", "GroupID": "2", "foo": "bar"]]
Good luck!
Related
Create a NSDictionary having country names as keys and the state of country as values and I want to display state corresponding to a country into another tableView
First of all it is not a good idea to use NSDictionary in swift, you can use Dictionary, in your case it can be [String: [String]].
You can create a Dictionary in swift like this:
var countries = [
"country 1": "state one",
"country 2": "state 2"
]
To access the value just do like this: let state = countries["country 1"]
UPDATE
to make it with an array of states it is the same.
var countries = [
"country 1": [
"state 1",
"state2","state3",
"state4"
],
"country 2": [
"otherstate 1",
"otherstate",
"otherstate",
"otherstate"
]
]
access array of values:
let states = countries["country 1"] as! [String]
for state in states {
print(state)
}
Here I need to get the index of particular array in which the key value pair item.defaultShipping == "true" then I need to the get the index of particular array and to pass in model class so that in order to get corresponding data so that it should be passed in another Api but when I tried below method it showing an error that Contexual type 'Any' cannot be used within dictionary literal in let parameters below line can anyone help me how to resolve this issue ?
here is my code
var i = 0
for item in customerShippingAddressModel {
if item.defaultShipping == "true" {
}
i += 1
}
let arr = customerShippingAddressModel[i]
let parameters : [String: Any] = ["address":
[ "region": "\(arr.region.region)",
"region_code": "\(arr.region.regionCode)",
"region_id": "\(arr.region.regionId)",
"country_id": "\(arr.countryId)",
"company": "\(arr.company)",
"telephone": "\(arr.telephone)",
"postcode": "\(arr.postCode)",
"city": "\(arr.city)",
"firstname": "\(arr.firstName)",
"lastname": "\(arr.lastName)",
"email": "\(arr.email)",
"prefix": "",
"sameAsBilling": 1,
"street": ["0": "\((arr.customerStreet[0])!)",
"1": "\((arr.customerStreet[1])!)"]]]
print(parameters)
Since Swift 3 you can use enumerated() which will allow you to have the index and the value as the following:
for (index, item) in customerShippingAddressModel.enumerated() {
if item.defaultShipping == "true" {
// you can get the item and index value here.
}
}
I 'm having an array of dictionary like so...
[
{
"id" : "3",
"sellingPrice" : "520",
"quantity" : "15"
},
{
"id" : "5",
"sellingPrice" : "499",
"quantity" : "-1"
},
{
"id" : "8",
"sellingPrice" : "500",
"quantity" : "79"
}
]
Now I want to add to the dictionary another key called remaining_balance with a value of 420,499 & 500 respectively. How can I achieve this..? Hope somebody can help...
It seems like you want to add a value to your dictionary that is an array:
var arrDict = Array<Dictionary<String,Any>>() //Your array
arrDict.append(["id":"3","sellingPrice":"520","quantity":"13"])
arrDict.append(["id":"5","sellingPrice":"43","quantity":"32"])
arrDict.append(["id":"8","sellingPrice":"43","quantity":"33"])
let arrValue = ["420","499","500"] //Your remaining value in array
print("Before ",arrDict)
for (index,dict) in arrDict.enumerated() {
var dictCopy = dict //assign to var variable
dictCopy["remaining_balance"] = arrValue[index]
arrDict[index] = dictCopy //Replace at index with new dictionary
}
print("After ",arrDict)
EDIT
If you are able keep an index of an array it would be possible,
Assuming that you have the index of an array
var dictCopy = arrDict[index]
dictCopy["remaining_balance"] = "666" //Your calculated value
arrDict[index] = dictCopy //Replace at index with new dictionary
var newKV = [["remaining_balance": "420"],["remaining_balance": "490"],["remaining_balance": "500"]]
let array = [["id":"3", "sellingPrice":"520", "quantity":"15"], ["id":"5", "sellingPrice":"520", "quantity":"15"], ["id":"8", "sellingPrice":"520", "quantity":"15"]]
let newArray = array.enumerated().map { (index : Int, value: [String: String]) -> [String: String] in
var dic = value
dic.merge(newKV[index]) { (_, new) -> String in
new
}
return dic
}
You could achieve it by mapping your array:
var myArray = [["id": "3", "sellingPrice": "520", "quantity" : "15"], ["id": "5", "sellingPrice": "499", "quantity" : "-1"], ["id": "8", "sellingPrice": "500", "quantity" : "79"]]
print(myArray)
/*
[["id": "3", "sellingPrice": "520", "quantity": "15"],
["id": "5", "sellingPrice": "499", "quantity": "-1"],
["id": "8", "sellingPrice": "500", "quantity": "79"]]
*/
print("___________________")
var remainingBalanceDesriedValue = 420
myArray = myArray.map { (dict: [String: String]) -> [String: String] in
var copyDict = dict
copyDict["remaining_balance"] = "\(remainingBalanceDesriedValue)"
remainingBalanceDesriedValue = (remainingBalanceDesriedValue == 420) ? 499 : (remainingBalanceDesriedValue == 499) ? 500 : 420
return copyDict
}
print(myArray)
/*
[["sellingPrice": "520", "quantity": "15", "id": "3", "remaining_balance": "420"],
["sellingPrice": "499", "quantity": "-1", "id": "5", "remaining_balance": "499"],
["sellingPrice": "500", "quantity": "79", "id": "8", "remaining_balance": "500"]]
*/
Let's assume you have an array of dictionaries like so:
var arrayOfDictionaries = [
[
"id": 3,
"sellingPrice": 520,
"quantity": 15
]
]
It is important that arrayOfDictionaries is not a let constant, otherwise it is considered immutable and you can not call append on it.
Now you init a new dictionary like:
let newDictionary = [
"id": 10,
"remaining_balance": 420,
"quantity": 15
]
Now add the newDictionary like
arrayOfDictionaries.append(newDictionary)
If the order is important
If the order is important there are a couple of ways to go about that.
When calling append the new value (in this case the new dictionary) will always be inserted at the bottom of the array.
If for some reason you can not call append in the correct order you could use insert, which inserts your dictionary at a specific position.
Yet another way is to append the values wildly and after you are done, call sort on the array.
Improvement Tips
Notice that for the values I did not use strings, as you only have numbers like "id" : 30.
Also, if you want the second key to be called remaining_balance you should call the first key selling_price instead of sellingPrice. Because of conistency.
Alternative approach
As far as I have understood you are trying to implement some software that is responsibly for selling some products.
I think you are tackling this problem from a completely wrong side.
I think you should read about database relationships. Selling products actually is a very common problem.
Maybe this will help you. I would offer a possible solution myself, but I think this misses the point of your question.
If you decide to use the database approach, you won't necessarily have to use a database. You can take the approach and implement it using simple structs/classes/arrays.
I noticed this question lacks an extension answer, yes.. I'm gonna be that guy, so here it is. This could be made more generic by supporting other types of dictionaries, feel free to pitch in ;)
Inspiration from #eason's answer.
var newKV = [["remaining_balance": "420"],["remaining_balance": "490"],["remaining_balance": "500"]]
var array = [["id":"3", "sellingPrice":"520", "quantity":"15"], ["id":"5", "sellingPrice":"520", "quantity":"15"], ["id":"8", "sellingPrice":"520", "quantity":"15"]]
extension Array where Element == [String: String] {
enum UniquingKeysStrategy {
case old
case new
}
mutating func merge(with target: Array<Element>, uniquingKeysWith: UniquingKeysStrategy = .new) {
self = self.merged(with: target)
}
func merged(with target: Array<Element>, uniquingKeysWith strategy: UniquingKeysStrategy = .new) -> Array<Element> {
let base = self.count > target.count ? self : target
let data = self.count > target.count ? target : self
return data.enumerated().reduce(into: base, {
result, data in
result[data.offset]
.merge(data.element, uniquingKeysWith: {
old, new in
if strategy == .new { return new }
return old
})
})
}
}
let mergedArrays = newKV.merged(with: array, uniquingKeysWith: .old)
array.merge(with: newKV)
Happy Coding :)
I have an array of dictionary. I need to sort that array. The sorting shouldnt be like ascending or descending but it should be based on an another array contents.
EX: Lets say I have an array nammed array_unsorted and that array contains a lot of dictionary objects like d1, d2, d3, d4 etc. Each of the dictionary object has a key called key1 and each dictionary object has different value for that key such as Kammy, Maddy, Jessy. Lets say I have anohter sorted array which Maddy, Kammy, Jessy. Now the dictionary should be sorted in a way that the first element should the dictionary object in which the value for key1 should beMaddy`.
I cannot use SortDescriptor, because this will sort as an ascending or descending order based on the key passed to it.
I have tried my solution but I am ended up using so many nested loops. I feel like the solution I made so so pathetic that I dont even want to post the code here.
Any help would be so much appreciated.
EDIT: There can be multiple sorting arrays but as of now I am considering only one sorting array and then I can write the code for multiple sorting arrays.
How about this:
Create a new, empty dictionary with a String key, and a value of type Dictionary. Call it sourceItemsDict.
Loop through the dictionaries in your source array, and add each entry to your new dictionary, using your sort key as the dictionary key, and put the array entry as the value.
Create a new, empty array of dictionaries for your sorted results. call it sortedArray.
Now loop through your array that has the desired order in it. Fetch the item with that key from sourceItemsDict and append it to the end of sortedArray.
That should do it, and it should perform in O(n) time.
Try this:
func sort<T: Equatable>(arrayOfDict arr: [[String: T]], by key: String, order: [T]) -> [[String: T]] {
return arr.sorted {
guard let value0 = $0[key], let value1 = $1[key] else {
return false
}
guard let index0 = order.index(of: value0), let index1 = order.index(of: value1) else {
return false
}
return index0 < index1
}
}
let array_unsorted = [
["name": "Kammy", "city": "New York"],
["name": "Maddy", "city": "Cupertino"],
["name": "Jessy", "city": "Mountain View"]
]
let sortedByName = sort(arrayOfDict: array_unsorted, by: "name", order: ["Maddy", "Kammy", "Jessy"])
let sortedByCity = sort(arrayOfDict: array_unsorted, by: "city", order: ["Cupertino", "Mountain View", "New York"])
print(sortedByName)
print(sortedByCity)
Your question leaves a couple of unresolved scenarios:
1: What if the key is missing from a dictionary?
let array_unsorted = [
["name": "Kammy", "city": "New York"],
["city": "Las Vegas"],
["name": "Maddy", "city": "Cupertino"],
["name": "Jessy", "city": "Mountain View"]
]
let sortedByName = sort(arrayOfDict: array_unsorted, by: "name", order: ["Maddy", "Kammy", "Jessy"])
Should Las Vegas appear at the beginning or end of the sorted array?
2: What if you don't specify an order for a value?
let array_unsorted = [
["name": "Amy"],
["name": "Kammy", "city": "New York"],
["name": "Maddy", "city": "Cupertino"],
["name": "Jessy", "city": "Mountain View"]
]
let sortedByName = sort(arrayOfDict: array_unsorted, by: "name", order: ["Maddy", "Kammy", "Jessy"])
Now where should Amy be placed?
Check out this example:
let dic1 = ["name" : "a"]
let dic2 = ["name" : "b"]
let dic3 = ["name" : "c"]
let dic4 = ["name" : "d"]
let dic5 = ["name" : "e"]
let unsorted_array = [dic2,dic5,dic1,dic4,dic3]
func sortArrayByName(_ array:[[String:String]])->[[String:String]]{
var sortedArray:[[String:String]] = [[String:String]]()
var sortingOrder:[String] = [String]()
for eachDic in array{
if let name = eachDic["name"]{
sortingOrder.append(name)
sortingOrder.sort() // sorting logic here
if sortedArray.isEmpty{
sortedArray.append(eachDic)
} else {
let index = sortingOrder.index(of: name)!
sortedArray.insert(eachDic, at: index)
}
}
}
return sortedArray
}
let sorted_array = sortArrayByName(unsorted_array)
I have 3 lists:
a = ["John", "Archie", "Levi"]
b = ["13", "20"]
c = ["m", "m", "m", "m"]
I want to merge this into one list with dictionaries:
result = [
{"name": "John", "age": "13", "gender": "m"},
{"name": "Archie", "age": "20", "gender": "m"},
{"name": "Levi", "age": "", "gender": "m"},
{"name": "", "age": "", "gender": "m"},
]
Ok, this is pretty normal computer science problem. Here is an outline of how to go about solving it:
First, identify the inputs and the desired outputs. You've done that.
Note any edge cases you need to handle
Next, map out the logic flow using pseudo-code.
Convert from pseudo-code to real code.
Test and debug.
For step 2, your data suggests that you want to handle cases where you have different numbers of elements in each source array. it looks like you want to create a dictionary for all the 0 elements in each array, then a dictionary for the 1 elements, etc. When you run out of elements for a given array, it looks like you want to skip that key in your resulting dictionary entry.
Now to pseudo-code:
Find the array with the maximum number of elements. Make this your output_count (the number of items in your output array.)
Create an output array large enough for output_count entries.
Loop from 0 to output_count - 1.
create a dictionary variable
for each input array, if there are enough elements, add a key/value pair
for that array's key and the value at the current index. Otherwise skip
that key.
add the new dictionary to the end of your output array.
That should be enough to get you started. Now see if you can convert that pseudo-code to actual code, test it, and debug it. Report back here with your actual code, and feel free to ask for help if you get stuck getting your code working.
Try like this:
let a = ["John", "Archie", "Levi"]
let b = ["13", "20"]
let c = ["m", "m", "m", "m"]
var dicArray:[[String:String]] = []
for index in 0..<max(a.count,b.count,c.count) {
dicArray.append([:])
dicArray[index]["name"] = index < a.count ? a[index] : ""
dicArray[index]["age"] = index < b.count ? b[index] : ""
dicArray[index]["gender"] = index < c.count ? c[index] : ""
}
dicArray // [["gender": "m", "age": "13", "name": "John"], ["gender": "m", "age": "20", "name": "Archie"], ["gender": "m", "age": "", "name": "Levi"], ["gender": "m", "age": "", "name": ""]]
Here is my take. I first create the array, and then use enumerate() and forEach to process each array and add them to the array of dictionaries:
let a = ["John", "Archie", "Levi"]
let b = ["13", "20"]
let c = ["m", "m", "m", "m"]
let count = max(a.count, b.count, c.count)
var result = Array(count: count, repeatedValue: ["name":"", "age":"", "gender":""])
a.enumerate().forEach { idx, val in result[idx]["name"] = val }
b.enumerate().forEach { idx, val in result[idx]["age"] = val }
c.enumerate().forEach { idx, val in result[idx]["gender"] = val }
print(result)
[["gender": "m", "age": "13", "name": "John"], ["gender": "m", "age":
"20", "name": "Archie"], ["gender": "m", "age": "", "name": "Levi"],
["gender": "m", "age": "", "name": ""]]
This should do the job
let maxLength = max(a.count, b.count, c.count)
let paddedA = a + [String](count: maxLength-a.count, repeatedValue: "")
let paddedB = b + [String](count: maxLength-b.count, repeatedValue: "")
let paddedC = c + [String](count: maxLength-c.count, repeatedValue: "")
let res = zip(paddedA, zip(paddedB, paddedC)).map {
["name": $0.0, "age": $0.1.0, "gender": $0.1.1]
}
Output
[["gender": "m", "age": "13", "name": "John"], ["gender": "m", "age": "20", "name": "Archie"], ["gender": "m", "age": "", "name": "Levi"], ["gender": "m", "age": "", "name": ""]]