I'm working on a macOS application. I need to syntax-highlight text that is placed over TextView (NSTextView) with a list of selected words. For simplicity, I'm actually testing the same feature on the iPhone Simulator. Anyway, a list of words to highlight comes as a form of an array. The following is what I have.
func HighlightText {
let tagArray = ["let","var","case"]
let style = NSParagraphStyle.defaultParagraphStyle().mutableCopy() as! NSMutableParagraphStyle
style.alignment = NSTextAlignment.Left
let words = textView.string!.componentsSeparatedByString(" ") // textView.text (UITextView) or textView.string (NSTextView)
let attStr = NSMutableAttributedString()
for i in 0..<words.count {
let word = words[i]
if HasElements.containsElements(tagArray,text: word,ignore: true) {
let attr = [
NSForegroundColorAttributeName: syntaxcolor,
NSParagraphStyleAttributeName: style,
]
let str = (i != words.count-1) ? NSAttributedString(string: word.stringByAppendingString(" "), attributes: attr) : NSAttributedString(string: word, attributes: attr)
attStr.appendAttributedString(str)
} else {
let attr = [
NSForegroundColorAttributeName: NSColor.blackColor(),
NSParagraphStyleAttributeName: style,
]
let str = (i != words.count-1) ? NSAttributedString(string: word.stringByAppendingString(" "), attributes: attr) : NSAttributedString(string: word, attributes: attr)
attStr.appendAttributedString(str)
}
}
textView.textStorage?.setAttributedString(attStr)
}
class HasElements {
static func containsElements(array:Array<String>,text:String,ignore:Bool) -> Bool {
var has = false
for str in array {
if str == text {
has = true
}
}
return has
}
}
The simple methodology here is to separate the entire string of text into words with a white space (" ") and puts each word in an array (words). The containsElements function simply tells whether or not the selected word contains one of the keywords in the array (tagArray). If it returns true, the word is put in an NSMutableAttributedString with a highlight color. Otherwise, it's put in the same attributed string with a plain color.
The problem with this simple methodology is that a separated word puts the last word and /n and the next word together. For example, if I have a string like
let base = 3
let power = 10
var answer = 1
, only the first 'let' will be highlighted as the code puts 3 and the next let together like '3\nlet.' If I separate any word containing \n with a fast enumeration, the code won't detect each new paragraph well. I appreciate any advice to make it better. Just FYI, I'm going to leave this topic open to both macOS and iOS.
Muchos thankos
Couple different options. String has a function called componentsSeparatedByCharactersInSet that allows you to separate by a character set you define. Unfortunately this won't work since you want to separate by \n which is more than one character.
You could split the words twice.
let firstSplit = textView.text!.componentsSeparatedByString(" ")
var words = [String]()
for word in firstSplit {
let secondSplit = word.componentsSeparatedByString("\n")
words.appendContentsOf(secondSplit)
}
But then you wouldn't have any sense of the line breaks.. You'd need to re add them back in.
Finally, the easiest hack is simply:
let newString = textView.text!.stringByReplacingOccurrencesOfString("\n", withString: "\n ")
let words = newString.componentsSeparatedByString(" ")
So basically you add your own spaces.
Related
I know how to remove first character from a word in swift like this:
var data = "CITY Singapore"
data.removeFirst()
print(data)//ITY Singapore
what i want is to remove the first word and space so the result is "Singapore".
How can i remove the first word and leading space in swift?
You can try
let data = "CITY Singapore"
let res = data.components(separatedBy: " ").dropFirst().joined(separator: " ")
print(res)
Or
let res = data[data.range(of: " ")!.upperBound...] // may crash for no " " inside the string
Or you can go with this too
let strData = "CITY Singapore"
if let data = strData.components(separatedBy: " ").dropFirst().first {
// do with data
}
else {
// fallback
}
This is a Regular Expression solution, the benefit is to modify the string in place.
The pattern searches from the beginning of the string to the first space character
var data = "CITY Singapore"
if let range = data.range(of: "^\\S+\\s", options: .regularExpression) {
data.removeSubrange(range)
}
You can use String's enumerateSubstrings in range method (Foundation) using byWords option and remove the first enclosing range. You need also to stop enumeration after removing the range at the first occurrence:
var string = "CITY Singapore"
string.enumerateSubstrings(in: string.startIndex..., options: .byWords) { (_, _, enclosingRange, stop) in
string.removeSubrange(enclosingRange)
stop = true
}
string // "Singapore"
I have a UILabel with text "hello world, hello". There are 2 hello words.
And I want to replace the only 'bold hello' to 'thanks' without bold.
I use this code:
uiLabel1.text = "hello world, hello"
let target = "hello"
let replace = "thanks"
uiLabel1.text.replacingOccurrences(of: target, with: replace, options:
NSString.CompareOptions.literal, range: nil)
And the result is: "thanks world, thanks"
The result I want: "hello world, thanks"
Okay, so there's probably an easier way to do this...
So, I went through the API (like super quick) and looked for something like lastIndexOf, which lead me on a little trail to String#range(of:options), which allows you to search backwards, hmmm, interesting.
This returns a Range<String.Index> ... okay, so how can I use that?! Hmm, maybe String#replacingOccurrences(of:with:options:range:) 🤔
So, crack open a play ground and...
var str = "hello world, hello"
let lastIndexOf = str.range(of: "hello", options: .backwards)
str = str.replacingOccurrences(of: "hello", with: "thanks", options: .caseInsensitive, range: lastIndexOf)
str now equals "hello world, thanks"
Hi #MadProgrammer, your code is to replace the last hello word to thanks, right? But my question is to replace hello with the bold attribute, it may in the first, middle or at the end of a string.
Okay, so clearly we're missing some context...
Assuming, now, you're using a NSAttributedString, it becomes slightly more complicated
Building the string itself is not hard, figuring out how to find string components by attribute, a little more difficult.
Lucky for us, we have the Internet. So, the following is based on ideas I got from:
NSAttributedString by example
Detect whether a font is bold/italic on iOS?
One of the important things to remember when trying to solve an issue, you'll be lucky to find a single answer which does it all, instead, you need to break your issue down and focus on solving individual elements, and be prepared to go back to the start 😉
So, once again, unto the play ground...
import UIKit
var str = "hello world, "
//let lastIndexOf = str.range(of: "hello", options: .backwards)
//str = str.replacingOccurrences(of: "hello", with: "thanks", options: .caseInsensitive, range: lastIndexOf)
extension UIFont {
var isBold: Bool {
return fontDescriptor.symbolicTraits.contains(.traitBold)
}
var isItalic: Bool {
return fontDescriptor.symbolicTraits.contains(.traitItalic)
}
}
// Just so I can see that the style ;)
let fontSize = CGFloat(24.0)
let boldAttrs = [
NSAttributedString.Key.font: UIFont.boldSystemFont(ofSize: fontSize),
NSAttributedString.Key.foregroundColor: UIColor.white // Playground
]
// Playground only
let plainAttrs = [
NSAttributedString.Key.foregroundColor: UIColor.white // Playground
]
let boldText = NSMutableAttributedString(string: "hello", attributes: boldAttrs)
let styledText = NSMutableAttributedString(string: str, attributes: plainAttrs)
let someMoreBoldText = NSMutableAttributedString(string: "not to be replaced", attributes: boldAttrs)
// Attributes can be combined with their appear together ;)
styledText.append(boldText)
styledText.append(NSMutableAttributedString(string: " ", attributes: plainAttrs))
styledText.append(someMoreBoldText)
styledText.append(NSMutableAttributedString(string: " ", attributes: plainAttrs))
styledText.append(boldText)
styledText.enumerateAttribute(NSAttributedString.Key.font, in: NSRange(0..<styledText.length)) { (value, range, stop) in
guard let font = value as? UIFont, font.isBold else {
return;
}
let subText = styledText.attributedSubstring(from: range)
guard subText.string == "hello" else {
return
}
styledText.replaceCharacters(in: range, with: "thanks")
}
styledText
Which outputs...
The important things for me are:
The style has not be changed
Only the individual "hello" values, which are bolded, have been changed
Here is the code. But actually this is hardcoded. If the target enclosed in between <b></b>, it will work.
var text = "hello world, <b>hello</b>"
let target = "hello"
let replace = "thanks"
text = text.replacingOccurrences(of: "<b>\(target)</b>", with: replace, options: .literal, range: nil) //hello world, thanks
I have JSON file with text and label. In JSON file I want to add this characters <b> or <i> to some words. For example:
"this is my text <b>bold<b> or <i>italic<i>"
And before when I show text in label I want to analyse my text and if some words have this characters <b> or <i> I want to make this word bold or italic in the text of the label. How to do it? Or there are another way to make bold text from JSON?
UPDATE:
Yours code:
/* Set Tagged Text & Fonts */
let taggedTextString = myText.text
let tagFont = UIFont.boldSystemFont(ofSize: 17.0)
let normalFont = UIFont.systemFont(ofSize: 17.0)
/* You can simply assign the AttributedText to the modified String, which may return nil. */
textLabel.attributedText = taggedTextString.modifyFontWithTags(openingTag: "<tag>", closingTag: "</tag>", taggedFont: tagFont, unTaggedFont: normalFont)
My code:
var attributedString = NSMutableAttributedString(string: myText.text)
let paragraphStyle = NSMutableParagraphStyle()
paragraphStyle.lineSpacing = 5
attributedString.addAttribute(NSAttributedStringKey.paragraphStyle, value:paragraphStyle, range:NSMakeRange(0, attributedString.length))
textLabel.attributedText = attributedString;
Is this code the best way to union your and my code?
for i in stride(from: 0, to: allTagsSplitArray.count, by: 1) {
finalAttrStr.append(NSMutableAttributedString(string: allTagsSplitArray[i], attributes: [kCTFontAttributeName as NSAttributedStringKey : i % 2 == 0 ? untaggedTextFont : taggedTextFont]))
// my code
finalAttrStr.addAttribute(NSAttributedStringKey.paragraphStyle, value:paragraphStyle, range:NSMakeRange(0, finalAttrStr.length))
}
The simplest way I seem to have accomplished this is by running through the string and scanning for your key tags - <b>, <i>, etc.
To make things easier (and more reusable), we should make an extension of our String or NSAttributedString classes. For this example, I've extended the String class, and and I return a NSAttributedString:
func modifyFontWithTags(openingTag: String, closingTag: String, taggedFont: UIFont?, unTaggedFont: UIFont?) -> NSMutableAttributedString? {
/* Make sure we have everything we need. */
guard let taggedTextFont = taggedFont,
let untaggedTextFont = unTaggedFont,
!self.isEmpty,
self.contains(openingTag),
self.contains(closingTag) else { return nil }
/* Split the string up using our closing tag. */
let closingTagSplitArray = self.components(separatedBy: closingTag)
/* Make a placeholder array. */
var allTagsSplitArray = [String]()
/* Iterate through our split array. */
for item in closingTagSplitArray {
if item.contains(openingTag) {
/* Strip the opening tag & append. */
allTagsSplitArray.append(contentsOf: item.components(separatedBy: openingTag))
} else {
/* Just append. */
allTagsSplitArray.append(item)
}
}
/* Instantiate our attributed string. */
let finalAttrStr = NSMutableAttributedString()
for i in stride(from: 0, to: allTagsSplitArray.count, by: 1) {
/* Add our font to every-other item in the array (the tagged portions). */
finalAttrStr.append(NSMutableAttributedString(string: allTagsSplitArray[i], attributes: [NSFontAttributeName : i % 2 == 0 ? untaggedTextFont : taggedTextFont]))
}
return finalAttrStr
}
Note: In this example, I take in an UIFont parameter, but you can modify this function to take in whatever attribute types you want.
I have a UILabel that has max-lines of 2, and a word wrapping property. This is done in storyboard.
I need to add a '...' after the last wrapped word on those labels that end up being word wrapped.
Is this possible? I have tried some solutions from around the internet, but they seem to have not worked. Those include:
Testing label if it has been truncated, and appending '...' to those that have been.
Programmatically using attributed text to hijack storyboard.
Tried using Truncate Tail - Unable to use this because it cuts the word off like so "Highli...".
I think I understand what you are trying to do. This is a bit sloppy, but it should work
extension UILabel {
func truncateAndFitText()
{
if let string = self.text
{
let words = string.components(separatedBy: " ")
var lastString = ""
var tempString = ""
for word in words
{
(tempString == "") ? tempString.append(word) : tempString.append(" \(word)")
let size: CGSize = tempString.size(attributes: [NSFontAttributeName: self.font])
if (size.width > (self.bounds.size.width * CGFloat(self.numberOfLines)))
{
lastString.append("...")
break
}
else
{
lastString = tempString
}
}
self.text = lastString
}
}
}
and then use it like
myLabel.truncateAndFitText
for example I have a String text like : "I have to go to the kitchen"
and If I searched this text using the 'av' phrase I want a way that return me the whole word 'have'
how I can do this in swift
There is very nice solution with filter in swift.You can use rangeOfString method of String with filter to get only filtered string having "av"
var s = "I have to go to the kitchen"
//will return "have"
let abc:[String] = s.componentsSeparatedByString(" ").filter({ $0.rangeOfString("av", options: NSStringCompareOptions.CaseInsensitiveSearch, range: nil, locale: nil) != nil } )
There is an API for that, enumerateSubstrings(in:options:using:)
The byWords option returns all words in the closure
let string = "I have to go to the kitchen"
var found : String?
string.enumerateSubstrings(in: string.startIndex..., options: .byWords) { substring, _, _, stop in
if let word = substring, word.contains("av") {
found = word
stop = true
}
}
print(found ?? "not found")
Split your string into array by space char (" "), and return component that contains your 'av' string.
let words = stringYouWantToSearchIn.componentsSeparatedByString(" ")
for word in words
{
var range = word.rangeOfString(lastWord)
if (range != nil)
{
//you got what do you want in 'word variable'
break
}
}