Hello I am trying to get some data from a text file and put it into a table.
Im not sure how to add more then one pattern while also doing what I want, I know this pattern by its self %a+ finds letters and %b{} finds brackets, but I am not sure how to combine them together so that I find the letters as a key and the brackets as a value and have them be put into a table that I could use.
text file :
left = {{0,63},{16,63},{32,63},{48,63}}
right = {{0,21},{16,21},{32,21},{48,21}}
up = {{0,42},{16,42},{32,42},{48,42}}
down = {{0,0},{16,0},{32,0},{48,0}}
code:
local function get_animations(file_path)
local animation_table = {}
local file = io.open(file_path,"r")
local contents = file:read("*a")
for k, v in string.gmatch(contents, ("(%a+)=(%b{})")) do -- A gets words and %b{} finds brackets
animation_table[k] = v
print("key : " .. k.. " Value : ".. v)
end
file:close()
end
get_animations("Sprites/Player/MainPlayer.txt")
This is valid Lua code, why not simply execute it?
left = {{0,63},{16,63},{32,63},{48,63}}
right = {{0,21},{16,21},{32,21},{48,21}}
up = {{0,42},{16,42},{32,42},{48,42}}
down = {{0,0},{16,0},{32,0},{48,0}}
If you don't want the data in globals, use the string library to turn it into
return {
left = {{0,63},{16,63},{32,63},{48,63}},
right = {{0,21},{16,21},{32,21},{48,21}},
up = {{0,42},{16,42},{32,42},{48,42}},
down = {{0,0},{16,0},{32,0},{48,0}},
}
befor you execute it.
If you insist on parsing that file you can use a something like this for each line:
local line = "left = {{0,63},{16,63},{32,63},{48,63}}"
print(line:match("^%w+"))
for num1, num2 in a:gmatch("(%d+),(%d+)") do
print(num1, num2)
end
This should be enough to get you started. Of course you wouldn't print those values but put them into a table.
I have something like
str = "What a wonderful string //011// this is"
I have to replace the //011// with something like convertToRoman(011) and then get
str = "What a wonderful string XI this is"
However, the conversion into roman numbers is no problem here.
It is also possible that the string str didn't has a //...//. In this case it should simply return the same string.
function convertSTR(str)
if not string.find(str,"//") then
return str
else
replace //...// with convertToRoman(...)
end
return str
end
I know that I can use string.find to get the complete \\...\\ sequence. Is there an easier solution with pattern matching or something similiar?
string.gsub accepts a function as a replacement. So, this should work
new = str:gsub("//(.-)//", convertToRoman)
I like LPEG, therefore here is a solution with LPEG:
local lpeg = require"lpeg"
local C, Ct, P, R = lpeg.C, lpeg.Ct, lpeg.P, lpeg.R
local convert = function(x)
return "ROMAN"
end
local slashed = P"//" * (R("09")^1 / convert) * P"//"
local other = C((1 - slashed)^0)
local grammar = Ct(other * (slashed * other)^0)
print(table.concat(grammar:match("What a wonderful string //011// this is"),""))
Via an enterpreise service consumer I connect to a webservice, which returns me some data, and also url's.
However, I tried all methods of the mentioned class above and NO METHOD seems to convert the unicode-characters inside my url into the proper readable characters.... ( in this case '=' and ';' ) ...
The only method, which runs properly is "is_valid_url", which returns false, when I pass url's like this:
http://not_publish-workflow-dev.hq.not_publish.com/lc/content/forms/af/not_publish/request-datson-internal/v01/request-datson-internal.html?taskId\u003d105862\u0026wcmmode\u003ddisabled
What am I missing?
It seems that this format is for json values. Usually = and & don't need to be written with the \u prefix. To decode all \u characters, you may use this code:
DATA(json_value) = `http://not_publish-workflow-dev.hq.not_publish.com/lc`
&& `/content/forms/af/not_publish/request-datson-internal/v01`
&& `/request-datson-internal.html?taskId\u003d105862\u0026wcmmode\u003ddisabled`.
FIND ALL OCCURRENCES OF REGEX '\\u....' IN json_value RESULTS DATA(matches).
SORT matches BY offset DESCENDING.
LOOP AT matches ASSIGNING FIELD-SYMBOL(<match>).
DATA hex2 TYPE x LENGTH 2.
hex2 = to_upper( substring( val = json_value+<match>-offset(<match>-length) off = 2 ) ).
DATA(uchar) = cl_abap_conv_in_ce=>uccp( hex2 ).
REPLACE SECTION OFFSET <match>-offset LENGTH <match>-length OF json_value WITH uchar.
ENDLOOP.
ASSERT json_value = `http://not_publish-workflow-dev.hq.not_publish.com/lc`
&& `/content/forms/af/not_publish/request-datson-internal/v01`
&& `/request-datson-internal.html?taskId=105862&wcmmode=disabled`.
I hate to answer my own questions, but anyway, I found an own solution, via manually replacing those unicodes. It is similar to Sandra's idea, but able to convert ANY unicode.
I share it here, just in case, any person might also need it.
DATA: lt_res_tab TYPE match_result_tab.
DATA(valid_url) = url.
FIND ALL OCCURRENCES OF REGEX '\\u.{4}' IN valid_url RESULTS lt_res_tab.
WHILE lines( lt_res_tab ) > 0.
DATA(match) = substring( val = valid_url off = lt_res_tab[ 1 ]-offset len = lt_res_tab[ 1 ]-length ).
DATA(hex_unicode) = to_upper( match+2 ).
DATA(char) = cl_abap_conv_in_ce=>uccp( uccp = hex_unicode ).
valid_url = replace( val = valid_url off = lt_res_tab[ 1 ]-offset len = lt_res_tab[ 1 ]-length with = char ).
FIND ALL OCCURRENCES OF REGEX '\\u.{4}' IN valid_url RESULTS lt_res_tab.
ENDWHILE.
WRITE / url.
WRITE / valid_url.
I have a lua string in Chinese, such as
str = '这是一个中文字符串' -- in English: 'this is a Chinese string'
Now I would like to iterate the string above, to get the following result:
str[1] = '这'
str[2] = '是'
str[3] = '一'
str[4] = '个'
str[5] = '中'
str[6] = '文'
str[7] = '字'
str[8] = '符'
str[9] = '串'
and also output 9 for the length of the string.
Any ideas?
Something like this should work if you are using utf8 module from Lua 5.3 or luautf8, which works with LuaJIT:
local str = '这是一个中文字符串'
local tbl = {}
for p, c in utf8.codes(str) do
table.insert(tbl, utf8.char(c))
end
print(#tbl) -- prints 9
I haven't used non-english characters in lua before and my emulator just puts them in as '?' but something along the lines of this might work:
convert = function ( str )
local temp = {}
for c in str:gmatch('.') do
table.insert(temp, c)
end
return temp
end
This is a simple function that utilizes string.gmatch() to separate the string into individual characters and save them into a table. It would be used like this:
t = convert('abcd')
Which would make 't' a table containing a, b, c and d.
t[1] = a
t[2] = b
...
I am not sure if this will work for the Chinese characters but it is worth a shot.
I'm programming User Defined Views in a Rails app. I have a table called uvcondtions that contains the column(field_name), condition(condition), and compared to (ucompare) to information.
For example:
Field_name = description
ucondition = like
ucompare = Truck
Gets turned into where table_name.description like "Truck"
It's working great for most PG SQL conditions. The in condition doesn't work.
If I have this in the uvconditions record:
field_name = id
uvcondition = in
uvcompare = (1,3)
I get this error:
PG::Error: ERROR: syntax error at or near " '(1,3)' "
LINE 1: ...sts" WHERE "worequests"."tenant_id" = 1 AND (id in '(1,3)')
This is the statements that create the where clause:
uvc = uvcondition.ucompare if uvcondition.ucondition == 'in'
#worequests = Worequest.where( uvcondition.field_name + " " + uvcondition.ucondition + " ?", uvc )
Is there any way to remove the quotes around uvc ??
Thanks for the help!
The error is occuring because uvc is actually a string:
uvc = "(1,3)"
Which misleads Rails to sanitize this string before using it in the SQL query (puttin the extra quotes). Instead of this behavior, Rails should create a list of possible values, made from an Array.
Make uvc a Ruby array and it should solve your problem:
uvc = [1, 3]
#worequests = Worequest.where(uvcondition.field_name + " " + uvcondition.ucondition + " ?", uvc)