Show Location string using latitude and longitude - ios

Question

I am using this method to show the string of location using current location latitude and longitude but it is showing differently
NSString *urlString = [NSString stringWithFormat:#"http://maps.googleapis.com/maps/api/geocode/json?latlng=%f,%f&sensor=false",location.coordinate.latitude, location.coordinate.longitude];
NSError* error;
NSString *locationString = [NSString stringWithContentsOfURL:[NSURL URLWithString:urlString] encoding:NSASCIIStringEncoding error:&error];
NSData *data = [locationString dataUsingEncoding:NSUTF8StringEncoding];
id json = [NSJSONSerialization JSONObjectWithData:data options:0 error:nil];
NSDictionary *dic = [[json objectForKey:#"results"] objectAtIndex:0];
NSArray* arr = [dic objectForKey:#"address_components"];
//Iterate each result of address components - find locality and country
NSString *cityName;
NSString *countryName;
for (NSDictionary* d in arr)
{
NSArray* typesArr = [d objectForKey:#"types"];
NSString* firstType = [typesArr objectAtIndex:0];
if([firstType isEqualToString:#"locality"])
cityName = [d objectForKey:#"long_name"];
if([firstType isEqualToString:#"country"])
countryName = [d objectForKey:#"long_name"];
}
NSString* locationFinal = [NSString stringWithFormat:#"%#,%#",cityName,countryName];
NSLog(#"Final Location %# ",locationFinal);
but final location is showing this type :-
Final Location नठदिलà¥à¤²à¥,India
Why it is showing this type? Can anyone know about this.

Answer 1

Please supply the language with the API params. If language is not supplied, the geocoder attempts to use the preferred language as specified in the Accept-Language header, or the native language of the domain from which the request is sent.
So please replace the code as with the language parameter as like this.
NSString *urlString = [NSString stringWithFormat:#"http://maps.googleapis.com/maps/api/geocode/json?latlng=%f,%f&sensor=false&language=en",location.coordinate.latitude, location.coordinate.longitude];
and try again.

Answer 2

I believe that is an uninitialzed variable which is pointing into random memory.
Try:
NSString *cityName = nil;
NSString *countryName = nil;
Short-circuit your for loop:
for (NSDictionary* d in arr)
{
// Add this after the existing code:
if (cityName && countryName)
break;
}
and check for errors before presenting the results:
if (cityName && countryName) {
NSString* locationFinal = [NSString stringWithFormat:#"%#,%#",cityName,countryName];
NSLog(#"Final Location %# ",locationFinal);
} else {
NSLog(#"Failed to find location");
}
Finally your JSON-processing code does no error-checking at all. That's a mistake.