I'm trying to replace a string that holds double backslash to a string with only single backslash, for example:
\\This\\Is\\Not\\Working
To:
\This\Is\Not\Working
Using:
str = [str stringByReplacingOccurrencesOfString:#"\\\\" withString#"\\"];
But for some reason, The string remains the same (with the double backslash) every single time. What am i doing wrong here?
Sadly, I misinterpreted the console log output. the string was fine, the debugger just showed the single slash as a doubled one. (For escaping purposes i'd imagine).
The below lines of code is fine:
NSString *str=#"\\This\\Is\\Not\\Working";
str = [str stringByReplacingOccurrencesOfString:#"\\\\" withString#"\\"];
Just check value by NSLog or by printing, because in debug console slash is represented as double slash.
Check image for more clear understanding:
NSString *Str = #"\\This\\Is\\Not\\Working";
NSLog(#"%#",Str);// print:-\This\Is\Not\Working
Str = [Str stringByReplacingOccurrencesOfString:#"\\\\" withString:#"\\"];// in this no replace occurres
NSLog(#"%#",Str); // print:-\This\Is\Not\Working
NSString *Str1 = #"\\\\This\\\\Is\\\\Not\\\\Working";
NSLog(#"%#",Str1);// print:-\\This\\Is\\Not\\Working
Str1 = [Str1 stringByReplacingOccurrencesOfString:#"\\\\" withString:#"\\"];
NSLog(#"%#",Str1);// print:-\This\Is\Not\Working
Try this:
NSString *str = #"\\This\\Is\\Not\\Working";
str = [str stringByReplacingOccurrencesOfString:#"\\" withString:#"\\\\"];
NSLog(#"%#", [str stringByReplacingOccurrencesOfString:#"\\\\" withString:#"\\"]);
1st Line is your user input.
2nd Line converts the double back-slashed user input string into four back-slashed string
3rd line simply replaces four back slashes with two back slashes which results in printing single back slash
Related
I'm trying to replace single slash to triple slash in Objective-C. I'm unable to do conversion.
Example:
NSString *string = "pW`-={}|[]456\";
string = [string stringByReplacingOccurrencesOfString:#"\\\" withString:#"\"];
I want to output: pW`-={}|[]456\\
Every back-slash in Objective-C string literal should be presented with two back-slashes (first one is escaping back-slash), otherwise it will not even compile, so
If you want convert this
pW`-={}|[]456\
into this
pW`-={}|[]456\\\
it needs to call
string = [string stringByReplacingOccurrencesOfString:#"\\" withString:#"\\\\\\"];
if vice-versa, then correspondingly
string = [string stringByReplacingOccurrencesOfString:#"\\\\\\" withString:#"\\"];
My problem is, i want to trim away some characters from my string. My string contains xml. So i need to trim characters from an xml opening tag upto its closing tag. How can i do it?
Eg: My string contains the following xml codes.
<CategoriesResponse xmlns="https://abc.defg.com/hijk">
<MainCategories>
<CatID xsi:type="xsd:int">178</CatID>
<CatID xsi:type="xsd:int">150</CatID>
<CatID xsi:type="xsd:int">77</CatID>
<CatID xsi:type="xsd:int">33</CatID>
<CatID xsi:type="xsd:int">179</CatID>
</MainCategories>
<SubCategories>
//some needed elements should not be trimmed.
</SubCategories>
i need to trim from the opening tag <MainCategories> to closing tag </MainCategories>.
How to do it?? So here my starting character will be <MainCategories and ending character will be /MainCategories>
Try this
NSString *str = #"<CategoriesResponse xmlns=\"https://abc.defg.com/hijk\"><MainCategories><CatID xsi:type=\"xsd:int\">178</CatID><CatID xsi:type=\"xsd:int\">150</CatID><CatID xsi:type=\"xsd:int\">77</CatID><CatID xsi:type=\"xsd:int\">33</CatID><CatID xsi:type=\"xsd:int\">179</CatID></MainCategories><SubCategories></SubCategories>";
NSRange startRange = [str rangeOfString:#"<MainCategories>"];
NSRange endRange = [str rangeOfString:#"</MainCategories>"];
NSString *replacedString = [str stringByReplacingCharactersInRange:NSMakeRange(startRange.location, (endRange.location+endRange.length)-startRange.location) withString:#""];
NSLog(#"%#",replacedString);
Hope this helps.
Try below code:
NSString *strXml=#"<CategoriesResponse xmlns=\"https://abc.defg.com/hijk\"><MainCategories><CatID xsi:type=\"xsd:int\">178</CatID><CatID xsi:type=\"xsd:int\">150</CatID><CatID xsi:type=\"xsd:int\">77</CatID><CatID xsi:type=\"xsd:int\">33</CatID><CatID xsi:type=\"xsd:int\">179</CatID></MainCategories><SubCategories></SubCategories>";
strXml=[strXml stringByReplacingOccurrencesOfString:#"<MainCategories>" withString:#"<MainCategories"];
strXml=[strXml stringByReplacingOccurrencesOfString:#"</MainCategories>" withString:#"/MainCategories>"];
NSLog(#"%#",strXml);
Hope it will help :)
I have a strange problem encoding my String
For example:
NSString *str = #"\u0e09\u0e31\u0e19\u0e23\u0e31\u0e01\u0e04\u0e38\u0e13";
NSString *utf = [str stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSLog("utf: %#", utf);
This worked perfectly in log
utf: ฉันรักคุณ
But, when I try using my string that I parsed from JSON with the same string:
//str is string parse from JSON
NSString *str = [spaces stringByReplacingOccurrencesOfString:#"U" withString:#"u"];
NSLog("str: %#, str);
NSString *utf = [str stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSLog("utf: %#", utf);
This didn't work in log
str: \u0e09\u0e31\u0e19\u0e23\u0e31\u0e01\u0e04\u0e38\u0e13
utf: \u0e09\u0e31\u0e19\u0e23\u0e31\u0e01\u0e04\u0e38\u0e13
I have been finding the answer for hours but still have no clue
Any would be very much appreciated! Thanks!
The string returned by JSON is actually different - it contains escaped backslashes (for each "\" you see when printing out the JSON string, what it actually contains is #"\").
In contrast, your manually created string already consists of "ฉันรักคุณ" from the beginning. You do not insert backslash characters - instead, #"\u0e09" (et. al.) is a single code point.
You could replace this line
NSString *utf = [str stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
with this line
NSString *utf = str;
and your example output would not change. The stringByReplacingPercentEscapesUsingEncoding: refers to a different kind of escaping. See here about percent encoding.
What you need to actually do, is parse the string for string representations of unicode code points. Here is a link to one potential solution: Using Objective C/Cocoa to unescape unicode characters. However, I would advise you to check out the JSON library you are using (if you are using one) - it's likely that they provide some way to handle this for you transparently. E.g. JSONkit does.
I am reading a line of code in from a source file on disk and the line is a string, and it is of a string that contains HTML code in it:
line = #"format = #"<td width=\"%#\">";"
I need to remove the escaped characters from the html string. So any place that there is a '\"', I need to replace it with ''. I tried this:
[line stringByReplacingOccurrencesOfString:#"\\""" withString:#""];
But it only removed the '\' character, not the accompanying '"'. How can I remove the escaped '"' from this string?
EDIT: The key part of this problem is that I need to figure out a way to identify the location of the first #", and the closing " of the string declaration, and ignore/remove everything else. If there is a better way to accomplish this I am all ears.
[s stringByReplacingOccurrencesOfString:#"\\\"" withString:#""]
The replacement string there is a slash, which has to be escaped in the literal replacement string using another slash, followed by a quote, which also has to be escaped in the literal by a slash.
Try use this:
NSString *unfilteredString = #"!##$%^&*()_+|abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString:#"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"] invertedSet];
NSString *resultString = [[unfilteredString componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:#""];
NSLog (#"Result: %#", resultString);
I am making an app where there is a requirement to store ASCII art into a database. I store the strings in the below format.
"___________\n |---------|-O\n/___________\\n|______________|\n\____________/"
When I retrieve the data and display it in a label, I want the newline characters and backslashes to be parsed so as to display the real shape of the ASCII art.
How should I parse this kind of strings?
NSString has a method to do what you want, which is to replace a litteral \n, with a newline character (which is symbolized as \n). In a c-format string you can use a double slash to let the library know the second slach is a real one and not an escape symbol. So this should work assuming you have been able to load your data from sqlite into an NSString:
newString = [yourStringFromSQLite stringByReplacingOccurrencesOfString:#"\\n" withString:#"\n"];
If you are using \n just for creating new lines then instead of that just keep space while inserting value in database and set following properties for label ->
1)keep width just to fit first word.
2)linebreakmode to wordwrap (so as width will not be available it will wrap next word to new line)
3)set no. of lines to 0
Hope this will help.
try to use the scanner for remove the html entities
- (NSString *)flattenHTML:(NSString *)html trimWhiteSpace:(BOOL)trim {
NSScanner *theScanner;
NSString *text = nil;
theScanner = [NSScanner scannerWithString:html];
while ([theScanner isAtEnd] == NO) {
[theScanner scanUpToString:#"<" intoString:NULL] ;
[theScanner scanUpToString:#">" intoString:&text] ;
html = [html stringByReplacingOccurrencesOfString:[ NSString stringWithFormat:#"%#>", text] withString:#" "];
}
return trim ? [html stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]] : html;
}
and call this method where your trimmed string need to display