I have tried to use extended function to separate these values but the problem is that I am able to separate only one value.
https://isu.ifmo.ru/docs/XMLP/help/en_US/htmfiles/B25951_01/T421739T421827.htm
You will have to use some text processing functions on each of the parameter. Say, if $name is the parameter which contains the comma separated data, then
<?xdofx:Instr($name,',',1)?> will give you the position of the comma in the text.
Then <?xdofx:substr($name,1, Instr($name,',',1)-1)?> will return the text before the comma.
And. <?xdofx:substr($name,Instr($name,',',1)+1, length($name))?> will return the text after the comma
first,last
6
first
last
Related
I would like to improve this filter so that it can remove a variable text contained in parentheses, as well as the parentheses themselves.
Like this :
Example
The starting point of my formula is :
=filter(C3:C;ISBLANK(B3:B))
I thought a "Substitute" could do the trick but I failed to use it properly, and I don't know if this function can be applied to variable text ?
Thanks in advance for your answers !
Try with this formula that removes every text in between brackets:
=INDEX(REGEXREPLACE(FILTER(C3:C;ISBLANK(B3:B)),"\(+.\) ",""))
you can use the SUBSTITUTE function in combination with a filter function. Here's how:
Select the cells you want to filter and remove the text contained in parentheses.
In a new column next to the data you want to filter, use the SUBSTITUTE function to remove the text contained in parentheses. The syntax for the SUBSTITUTE function is:
=SUBSTITUTE(A1, "(" & ")", "")
where A1 is the cell containing the data you want to filter and "(" & ")" is the text contained in parentheses that you want to remove.
Filter the data using the new column that contains the filtered text.
To remove the original data and keep only the filtered data, you can copy the filtered data and paste it over the original data, or delete the original data and keep only the filtered data.
Try with REGEXEXTRACT.
=FILTER(REGEXEXTRACT(C3:C;"\)(.*)");ISBLANK(B3:B))
Thank you for your answers ; unfortunately the formulas return errors when I apply them :
=SUBSTITUTE(A1, "(" & ")", "")
and
=INDEX(REGEXREPLACE(FILTER(C3:C;ISBLANK(B3:B)),"\(+.\) ",""))
gives this (In this two cases the error is not identified)
This formula has a different result:
=FILTER(REGEXEXTRACT(C3:C;"\)(.*)");ISBLANK(B3:B))
it gives that (Here the text variable has been deleted as desired, but the rest of the data is no longer filtered correctly)
I have a field where I need to extract the text between two characters.
I've found regexextract and I got it to work when there is one character but I can't for the life get it to work with multiple characters.
2020-02: Test Course (QAS)
I need to extract text after : and before (
So it would just return "Test Course"
TYIA
If it's for just one cell (say A2):
=IFERROR(TRIM(REGEXEXTRACT(A2,":([^\(]+)")))
This will return what you want regardless of spaces after the colon or before the opening parenthesis. If no match is found, null will be returned.
If it's to process an entire range (say, A2:A), place the following in, say, B2 of an otherwise empty Col B:
=ArrayFormula(IF(A2:A="",,IFERROR(TRIM(REGEXEXTRACT(A2:A,":([^\(]+)")),A2:A)))
This will return what you want regardless of spaces after the colon or before the opening parenthesis. If no match is found, the original string will be returned.
In both cases, the REGEX string...
:([^\(]+)
... means "a grouping of any number of characters that aren't an opening parenthesis and which follows a colon."
One way to do that would be with the INDEX() and SPLIT() functions like this:
=TRIM(INDEX(SPLIT(A2,":("),2)
Split splits the text into 3 parts using the : and (, then INDEX chooses the second part.
The TRIM() just gets rid of the spaces.
I'm trying to use regex to extract information from a large text file on google sheets, but within the regex, I'm using quotation marks, and instead of treating everything like the text I want to use, the quotation marks make it so that the regex splits into many different parts. Is there some character I can add to prevent this?
As an example, say I used =REGEXEXTRACT("name"="",""name"="(\w+)"")
It would basically split this into:
REGEXEXTRACT(
"name"
=
""
,
""
name
"="
(\w+)
"")
and would return a formula parse error.
Is there any way I can cancel out certain quotation marks?
Solution:
You can escape double quotes by... another double quote!
So if your first formula argument is name"=" and your second formula argument is "name"="(\w+)", you would use:
=REGEXEXTRACT("name""=""","""name""=""(\w+)""")
Output: (note that I used concatenate to show the expressions)
I am using the following formula to extract the substring venue01 from column C, the problem is that when value string in column C is shorter it only extracts the value 1 I need it to extract anything straight after the - (dash) no matter the length of the value text in column c
={"VenueID";ARRAYFORMULA(IF(ISBLANK(A2:A),"",RIGHT(C2:C,SEARCH("-",C2:C)-21)))}
There is a much simpler solution using regular expressions.
=REGEXEXTRACT(A1,".*-(.*)")
In case you are no familiar with Regular Expressions what this means is, get me every string of characters ((.*)) after a dash (-).
Example
Reference
REGEXTRACT
Test regular expressions
Cheat sheet for regular expressions
To answer bomberjackets question in the comment of Raserhin:
To select the part of the string before the "-"
=REGEXEXTRACT(A1,"(.*)-.*")
EXAMPLE
example of code
Adding to your original formula. I think if you'd use RIGHT and inside it reverse the order of the string with ARRAY then that may work.
=Right(A1,FIND("-",JOIN("",ARRAYFORMULA(MID(A1,LEN(A1)-ROW(INDIRECT("1:"&LEN(A1)))+1,1))))-1)
It takes string from the right side up to X number of characters.
Number of character is fetched from reversing the text, then finding
the dash "-".
It adds one more +1 of the text as it will take out so it accounts
for the dash itself, if no +1 is added, it will show the dash on
the extracted string.
The REGEX on the other answer works great too, however, you can control a number of character to over or under trim. E.g. if there is a space after the dash and you would like to always account for one more char.
I have a column in open office like this:
abc-23
abc-32
abc-1
Now, I need to get only the sum of the numbers 23, 32 and 1 using a formula and regular expressions in calc.
How do I do that?
I tried
=SUMIF(F7:F16,"([:digit:].)$")
But somehow this does not work.
Starting with LibreOffice 6.4, you can use the newly added REGEX function to generically extract all numbers from a cell / text using a regular expression:
=REGEX(A1;"[^[:digit:]]";"";"g")
Replace A1 with the cell-reference you want to extract numbers from.
Explanation of REGEX function arguments:
Arguments are separated by a semicolon ;
A1: Value to extract numbers from. Can be a cell-reference (like A1) or a quoted text value (like "123abc"). The following regular expression will be applied to this cell / text.
"[^[:digit:]]": Match every character which is not a decimal digit. See also list of regular expressions in LibreOffice
The outer square brackets [] encapsulate the list of characters to search for
^ adds a NOT, meaning that every character not included in the search list is matched
[:digit:] represents any decimal digit
"": replace matching characters (every non-digit) with nothing = remove them
"g": replace all matches (don't stop after the first non-digit character)
Unfortunately Libre-Office only supports regex in find/replace and in search.
If this is a once-only deal, I would copy column A to column to B, then use [data] [text to columns] in B and use the - as a separator, leaving you with all the text in column B and the numbers in column C.
Alternatively, you could use =Right(A1,find("-",A1,1)+1) in column B, then sum Column C.
I think that this is not exactly what do you want, but maybe it can help you or others.
It is all about substring (in Calc called [MID][1] function):
First: Choose your cell (for example with "abc-23" content).
Secondly: Enter the start length ("british" --> start length 4 = tish).
After that: To print all remaining text, you can use the [LEN][2] function (known as length) with your cell ("abc-23") in parameter.
Code now looks like this:
D15="abc-23"
=MID(D15; 5; LEN(D15))
And the output is: 23
When you edit numbers (in this example 23), no problem. However, if you change anything before (text "abc-"), the algorithm collapses because the start length is defined to "5".
Paste the string in a cell, open search and replace dialog (ctrl + f) extended search option mark regular expression search for ([\s,0-9])([^0-9\s])+ and replace it with $1
adjust regex to your needs
I didn't figure out how to do this in OpenOffice/LibreOffice directly. After frustrations in searching online and trying various formulas, I realised my sheet was a simple CSV format, so I opened it up in vim and used vim's built-in sed-like feature to find/replace the text in vim command mode:
:%s/abc-//g
This only worked for me because there were no other columns with this matching text. If there are other columns with the same text, then the solution would be a bit more complex.
If your sheet is not a CSV, you could copy the column out to a text file and use vim to find/replace, and then paste the data back into the spreadsheet. For me, this was a lot less frustrating than trying to figure this out in LibreOffice...
I won't bother with a solution without knowing if there really is interest, but, you could write a macro to do this. Extract all the numbers and then implement the sum by checking for contained numbers in the text.