rails each method reset in controller workaround - ruby-on-rails

So i have this in my controller at the moment:
popular = Impression.select('impressionable_id, count(impressionable_id) as total').group('impressionable_id').order('total desc')
popular.each do |popevents|
#events = Event.where(id: popevents.impressionable_id)
end
Basically all this is doing is selecting the most popular events that are saved in the impressions table and getting all the event information.
So in my view i have this:
<% #events.each do |e| %>
<pre>
<%= e.eventname %>
</pre>
<% end %>
I was expecting to see around 4-5 event names here, However i'm only seeing 1. I'm guessing its because the #events is getting reset?
What would be the work around for this?
Sam

Yes, you could do something like:
#events = popular.flat_map do |popevents|
Event.where(id: popevents.impressionable_id)
end
And it would give you the full list of events. But this is very inefficient; as it is going to run a single query for each id.
A better way would be:
#events = Event.where(id: popular.map(&:impressionable_id))
which would do it all in one query.

Related

Linking to the latest post from home page in a Rails application

I'm building a Rails app where I have individual entries called films. I would like to display the latest entry's link on the homepage (separate controller) and I'm struggling to make it work.
My films_controller.rb is as follows (excerpt):
def show
#film = Film.find(params[:id])
end
My home_controller.rb only has the following:
def index
end
And my view file (index.html.erb) has the following:
<%= link_to #film.last.filmTitle, film_path(#film) %>
I'm getting the following error:
Couldn't find Film with 'id'=#<Film::ActiveRecord_Relation:0x007fc93f2d1fd0>
With the #film.find(params[:id]) highlighted.
Thanks!
The last method:
Find the last record (or last N records if a parameter is supplied). If no order is defined it will order by primary key.
source
You can add a #last_film instance variable in your index controller and use it in the view.
def index
#films = Film.all
#last_film = Film.last
end
and in your index.html.erb
<%= link_to #last_film.filmTitle, film_path(#last_film) %>
The index method need something, currently, it didn't connect with ActiveRecord like model or table, that's why
Couldn't find Film with 'id'=#<Film::ActiveRecord_Relation:0x007fc93f2d1fd0>
So if you need to show recent posts in the index then you could something like this
def index
#films = Film.limit(10).order(created_at: :desc) #=> or you can use id
end
it will show last 10 records, for this in the index.html.erb like this
<% #films.each do |film| %>
<%= link_to film.filmTitle, film_path(film) %>
<% end %>
In the other hand if you need to show only one post which is the last then you should modify this query like this like limit(10) to limit(1) or you can use use the last method like this
def index
#film = Film.last
#or
##films = Film.limit(1).order(created_at: :desc) #=> or you can use id
end
if you use this #film = Film.last then your index file will like this
<%= link_to #film.filmTitle, film_path(#film) %>
otherwise, you need to use each method which describes before.

How do I use a button to update the order of a filtered category?

I am new to Rails, but slowly making progress. I can't quite wrap my head around how to achieve my next task.
I have a controller (IdeasController) with an index that looks like this:
def index
if params[:round].blank? && params[:challenge].blank?
#ideas = Idea.all.order(params[:sort])
# #ideas = Idea.all.order(created_at: :desc, cached_votes_up: :desc)
end
if params[:round].present?
#round_id = Round.find_by(name: params[:round]).id
#ideas = Idea.where(round_id: #round_id).order("created_at DESC")
end
if params[:challenge].present?
#challenge_id = Challenge.find_by(name: params[:challenge]).id
#ideas = Idea.where(challenge_id: #challenge_id).order("created_at DESC")
end
end
I am updating the view and filtering by category with the above :round and :challenge with the code below in my index.html.erb:
<%= link_to "All", ideas_path %>
<% Round.all.each do |round| %>
<%= link_to round.name, ideas_path(round: round.name) %>
<% end %>
<% Challenge.all.each do |challenge| %>
<%= link_to challenge.name, ideas_path(challenge: challenge.name) %>
<% end %>
Now, my problem is that I want to create a button that orders by created_at DESC or ASC. I want the button to essentially be a toggle. I also want another button to order by cached_weighted_average DESC or ASC. This is from acts_as_votable so I can sort by vote counts.
The problem I am running into is that I can create a link or button that orders by created_at or cached_weighted_average, but it replaces all of the URL that was previously filtered by :round or :challenge. For example, if a user clicks "Round 1" and sees all ideas marked for "Round 1" and then they click the link to order by cached_weighted_average, the URL replaces:
/ideas?round=Round+1
With this:
/ideas?sort=cached_weighted_average+ASC
What I want is:
/ideas?round=Round+1&?sort=cached_weighted_average+ASC
I know this is a very new question, but everything I have tried has failed so far. It feels like I am missing something very easy. What I noticed I can do easily is inside the controller I can do something like:
if params[:round].present?
#round_id = Round.find_by(name: params[:round]).id
#ideas = Idea.where(round_id: #round_id).order("cached_weighted_average DESC")
end
Which is perfect. This button just needs to switch between cached_weighted_average DESC and created_at DESC.
Any help is appreciated, thanks.
passing multiple parameters is one way to handle:
<%= link_to object.name, object_path(first: something, second: something_else) %>
then alter your conditionals to contemplate presence of multiple params.
to differentiate between round and challenge when attempting to allow the user to choose how they'd like to sort you could use the same name and then pass it different values.
something like:
params["round_or_challenge"]
this would change your conditional to something like:
if params["round_or_challenge"] == "round" && params["asc_or_desc"] == "asc"
# query
elsif params["round_or_challenge"] == "challenge"
# query
end
or whatever. it's basically the same...just pass the values you need. you can also pass the existing parameters from the view the same way you access them in the controller.
Thanks for the response, #toddmetheny. I didn't implement your solution, but your solution helped me understand passing multiple parameters a bit more.
I ended up creating a helper, sortable. I also used the url_for to append at the end of whatever the current URL might be. I liked this approach because it meant I could sort on any parameter. I'm not sure that it's the best solution, but it works.
def sortable (name, sort)
link_to name, url_for(params.merge(sort: sort))
end

Ruby on Rails each iteration error when one record

I am stuck on what seems should have a very simple solution, but I can not find anything that will work! I am iterating results from a table on the index page (which returns a list of states). This works without any problems when multiple records are returned. However, when a single record is returned, I get an error: undefined method 'each' for #
I know it is causing the error when only one record is returned, but I can not find any documentation on how to handle this, especially in the case that 1 or 0 records could be returned.
Code in controller:
#states = State.find(params[:id])
Code in index page:
<ul>
<% #states.each do |state| %>
<li>
<%= state.state_name %>
</li>
<% end %>
</ul>
Because you're using find, when you send multiple ids in the params, multiple records are matched; when you send a single id, a single instance is returned.
To ensure that each time, you get an ActiveRecord::Relation object that you can call each on, change your controller code to the following:
#states = State.where(id: params[:id]) # index action
You mentioned that it is the index view, so the above change should solve your problem.
If it's the show view, then you need to stick with find and change your view to display only one state.
You need to check if it responds to .each, which is the prime given for knowing if something implements the enumerable module.
if #states.respond_to?(:each)
# iteration goes here
else
# single handling goes here
Ofcourse you can also use the .where option in your query which returns always a collection
#states = State.where(id: params[:id])
Scenario 1:-
When record is queried in controller as:
#states = State.find(params[:id])
Then in view it should be like that:
<p><%= #states.state_name %></p>
Scenario 2:-
When record is queried in controller as:
#states = State.all
Then in view it should be like that:
<ul>
<% #states.each do |state| %>
<li>
<%= state.state_name %>
</li>
<% end %>
</ul>
Note:- In first scenario it is only one object but in second scenario it is a collection of object or a array of object. And only array are iterated.

How can I limit the number of records to load in view???

This code shows all the records of CommunityTopic that belongs to current Community.
How can I limit the numbers to 10 records to display here?
<ul>
<% #community.community_topics.each do |topic| %>
<li>
<%= link_to topic.title, community_topic_path(#community, topic) %>
<%= link_to topic.user.user_profile.nickname, community_topic_path(#community, topic) %>
</li>
<% end %>
</ul>
Use the limit method:
<% #community.community_topics.limit(10).each do |topic| %>
This will only supply the first 10 elements of the collection to the block. If you want to be more sophisticated, you could use something like will_paginate.
In general, such data fetching should take place in the controller. So instead of having a #community variable where the view gets the data from, have a #community_topics as well, which is prefilled with the data you want to render.
You shouldn't usually do this in the view, but rather in the controller. You can use limit as #Fermaref proposed, or you can use a paginator to help you out such as will_paginate or kaminari.
To move this to the controller, try something like this:
def some_action
#community = Community.find(params[:id])
#community_topics = #community.community_topics.order(:some_attribute).limit(10)
end
Then just use #community_topics in your view. One advantage here is that you can now move this logic to a private method for reuse if needed. You can also functionally test that #community_topics limits to 10 rows.
Use 8.3 reorder
The reorder method overrides the default scope order. For example:
#categories = Category.includes(:subcategories).where(active: true).references(:subcategories).order(name: :asc).reorder('categories.name ASC', 'subcategories.name ASC')
http://guides.rubyonrails.org/active_record_querying.html

Rails 3 & Kaminari pagination problem

Ok so I have decided to use Kaminari for pagination in a rails 3 project. I have followed the video from RailsCasts http://railscasts.com/episodes/254-pagination-with-kaminari
All goes well up until the point or running the server.
controllers/stories_controller.rb
def index
#stories = Story.all
#pages = Story.page(params[:page]).per(3)
#stories = Story.search(params[:search])
end
views/stories/index.html.erb
<%= paginate #pages %>
When i start the server the index page in question displays all the stories from the DB and renders the pagination view showing (1 2 Next > Last ยป). What am I missing to get the pagination working?
I still can not understand your code. Why do you assign Story.all to #stories in the 1st line and overwrite the variable in the 3rd line?
Anyways, #stories will display "all the stories from the DB" because you're not calling the pagination method (.per) on #stories. The pagination links will show you the paginated counts because you're calling per method on #page variable and passing it to the helper.
I mean, you need to call .per on the relation before passing it to <%= paginate %> helper.
It's quite simple.
I guess you want to get results from your search, right?
Try
#stories = Story.search(params[:search]).page(params[:page]).per(3)
and something like:
<% #stories.each do |story| %>
<%= render story %>
<% end %>
<%= paginate #stories %>
in your view

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