How to return multiple values in swift - ios

Question

I'm starter in swift.
I create tableview and get data from jsonFile to show text and picture.
Then I want to add searchBar on tableview but have problem.
import UIKit
class EpisodesTableViewController: UITableViewController
{
var episodes = [Episode]()
var names = [Episode]()
let searchController = UISearchController(searchResultsController: nil)
var filteredNames = [Episode]()
func filterContentForSearchText(searchText: String) {
filteredNames = self.names.filter { name in
return name.title!.lowercaseString.containsString(searchText.lowercaseString)
}
tableView.reloadData()
}
override func viewDidLoad()
{
super.viewDidLoad()
searchController.searchResultsUpdater = self
searchController.dimsBackgroundDuringPresentation = false
definesPresentationContext = true
tableView.tableHeaderView = searchController.searchBar
tableView.setContentOffset(CGPoint(x: 0, y: searchController.searchBar.frame.size.height), animated: false)
tableView.estimatedRowHeight = tableView.rowHeight
tableView.rowHeight = UITableViewAutomaticDimension
tableView.separatorStyle = .None
self.episodes = Episode.downloadAllEpisodes()
self.tableView.reloadData()
}
override func preferredStatusBarStyle() -> UIStatusBarStyle {
return .LightContent
}
// MARK: - Table view data source
override func numberOfSectionsInTableView(tableView: UITableView) -> Int
{
return 1
}
override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int
{
if searchController.active && searchController.searchBar.text != ""{
return filteredNames.count
}else{
return names.count
}
return episodes.count
}
override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell
{
let cell = tableView.dequeueReusableCellWithIdentifier("Episode Cell", forIndexPath: indexPath) as! EpisodeTableViewCell
let episode = self.episodes[indexPath.row]
let data: Episode
if searchController.active && searchController.searchBar.text != "" {
data = filteredNames[indexPath.row]
}
else {
data = names[indexPath.row]
}
let titleName = data.title!
cell.episode = episode
cell.textLabel?.text = titleName
return cell
}
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if segue.identifier == "SendData"{
if let detailPage = segue.destinationViewController as? detailEpisodeViewController {
if let indexpath = tableView.indexPathForSelectedRow {
let episode = episodes[indexpath.row]
detailPage.episode = episode
}
}
}
}
}
extension EpisodesTableViewController: UISearchResultsUpdating {
func updateSearchResultsForSearchController(searchController: UISearchController) {
filterContentForSearchText(searchController.searchBar.text!)
}
}
this my code.
override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int
{
if searchController.active && searchController.searchBar.text != ""{
return filteredNames.count
}else{
return names.count
}
return episodes.count
}
When I return filteredNames and names interface just show seachbar. If I return filtered names and episodes show error index out of range.
I don't know How to fix that.

Answer 1

If you want to return two values just return a touple like so:
return (DataType, DataType)
so this could be
func returnTouple() -> (String, AnyObject) {
return ("Hello World", 1)
}
then you would access it like so:
let (myString, myObject) = returnTouple()
and myString == "Hello World"
You could also access both throught .0 and .1 like returnTouple().0 == "Hello World"
Next,
override func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
if searchController.active && searchController.searchBar.text != "" {
return filteredNames.count
} else {
return names.count
}
return episodes.count
}
This function shouldn't work. You have an if {} else {} with a return statement in both sections. Unless you said if {} else if {} this makes the thrid return statement impossible to hit so it shouldn't be there.