I have a linked list pretty printer which takes the input from command prompt.
E.g., print xyz
My code is something like below:
class Randomcalss:
def __init__(self, val):
self.val = int(val)
def to_string(self):
return "printing linked list:"
def children(self):
for field in self.val.type.fields():
key = field.name
val = self.val[key]
yield key,val.dereference()
It does work as expected, and prints:
printing linked list:= {head = {next = 0x625590, prev = 0x623c70}}
But if I want to traverse the linked list and proceed further what do I do.
Because every time I try to access head['next'] it says head is a string and string indices must be integers.
Cant I do something like self.val[key] to access next node of head too?
You can do val.dereference()['next'] and this will give you address of next member of the list. You can cast the value obtained(if required) and traverse further.
Related
Question:
How can I add the ability to search for items in my custom column Help Text?
FooAdmin View
Code:
Here is a simplified version of the code that I am working with:
models.py (yes this is how the models need to be set up)
class HelpText(models.Model):
help_text = models.CharField(max_length=1000)
def __str__(self):
return self.help_text
class Foo(models.Model):
job_name = models.CharField(max_length=200, blank=False, null=False)
env = models.CharField(max_length=200, blank=False, null=False)
def __str__(self):
return self.job_name
class FooHelpText(models.Model):
foo = models.OneToOneField(Foo, on_delete=models.DO_NOTHING)
help_text = models.ForeignKey(HelpText, on_delete=models.DO_NOTHING)
def __str__(self):
return str(self.help_text)
admin.py
class FooHelpTextInline(admin.TabularInline):
model = models.FooHelpText
#admin.register(models.Foo)
class FooAdmin(admin.ModelAdmin):
search_fields = ['env', 'job_name',]
list_display = ['pk', 'job_name', 'env', '_get_help_text', ]
inlines = [FooHelpTextInline]
def _get_help_text(self, obj):
return obj.foohelptext.help_text
Current behavior:
The current code above allows me to see the associated help_text in a column on FooAdmin. However, I am not able to search by anything in that column.
Not the answer I am looking for:
I know if it was the other way around where the help_text was a ForeignKey on Foo I could do something like foo__help_text, but that is not how my models are set up (and can not change).
Desired behavior:
Use the search box to search for help text (not just env and job_name).
Possible Solution (that I need help with):
I suspect that get_search_results might be what I need, but I don't understand how to implement it for my use case.
UPDATE:
The closest I can get is searching for a number(aka a specific PK that I know exists) and getting that search result. But the query doesn't really make sense. And obviously that is not the desired functionality of a search.
def get_search_results(self, request, queryset, search_term):
queryset, use_distinct = super().get_search_results(request, queryset, search_term)
try:
search_term_as_int = int(search_term)
except ValueError:
pass
else:
queryset |= models.Foo.objects.select_related(
'foohelptext').filter(fooshelptext=search_term_as_int)
return queryset, use_distinct
I just don't understand the Python |= (bitwise OR operator) and why it has to be an integer.
Much easier than I thought. No need for get_search_results.
Simply needed to add it as foohelptext__help_text__help_text as an other item in the search fields.
Why this works:
def m = [[1,11], [2,22], [3,33]]
println(m.collectEntries())
output: [1:11, 2:22, 3:33]
But this doesn't work:
def m = [[Name:sub, Value:23234], [Name:zoneinfo, Value:Europe/London]]
println(m.collectEntries())
output:
groovy.lang.MissingPropertyException: No such property: sub for class
I want to process that map so that I get a list of key value pairs like this:
["Name:sub" :"Value:23234", "Name:zoneinfo": "Value:Europe/London"]
where Name:sub is the key and Value:23234 is the value.
Reference https://stackoverflow.com/a/34899177/9992516
In the second example sub and zoneinfo are being read as variable names, not strings, and you need to quote them.
def m = [[Name:'sub', Value:23234], [Name:'zoneinfo', Value:'Europe/London']]
println m.collectEntries{ ["Name:${it.Name}", "Value:${it.Value}"] }
It cannot find sub field in your class, probably you want to have a string "sub"?
Basically, map entry can be declared in two ways:
Name: 'sub'
and
'Name': 'sub'
For the key it is assumed that is is a String, even if it is not wrapped by quotes.
But for the value it is mandatory to wrap in quotes. Otherwise, it is treated as a variable (or field)
Given your desired results:
["Name:sub" :"Value:23234", "Name:zoneinfo": "Value:Europe/London"]
What you actually need to do is quote the entire item in each pair:
def m = [["Name:sub", "Value:23234"], ["Name:zoneinfo", "Value:Europe/London"]]
I need to translate a message key using a Hashmap using the Grails standard internationalization method.
I receive an Enum and a map with the binding, which are going to be replaced in the text.
The Enum indicates, which key is going to be recovered. The bindings have the values to replace on the translation.
messageSource.getMessage("mail.layout.subject.${templateName}",ARGS,"",locale)
The problem is that I need to pass the map to the args like an array, not like a map, but I don't know the order of the args.
My question is, if there are any ways to create a tranlation key like:
mail.layout.subject.ENUM1=Blablabl {name} bablablabl {age}
Instead of
mail.layout.subject.ENUM1=Blablabl {0} bablablabl {1}
Finally I did it with brute force. May be is not the best answer but I coudln't find any one better.
Basically I get the translation with te message resources and then I work with it finding my custom expresions.
def messageSource = grailsApplication.getMainContext().getBean('messageSource')
def subject = messageSource.getMessage("mail.layout.subject.NOTIFICATION",null,"",locale)
An example of subject resource
mail.layout.subject.NOTIFICATION=The user {friend.name} is friend of {user}
An example bindings:
def bindings = [friend:[name:"Jhon",surname:"Smith"],user:"David"]
With this senteces I replace my expresions with the value of the bindings
Pattern pattern = Pattern.compile("\\{[^}]+\\}")
def res = subject.replaceAll(pattern,{
def expresion = it[1..it.size()-2] // removes brackets
def fields = expresion.split("\\.");
def res = bindings
fields.each{
println(it)
res = res."${it}"
}
return res
})
After the proces the subject becomes like: "The user Jhon is friend of David"
The example use a HashMap of HashMaps, but it also works with object because grails/groovy handles the object like HashMaps and viceversa
This is much cleaner. :)
import groovy.text.SimpleTemplateEngine
def text = 'Dear "$firstname $lastname",So nice to meet you in ${city.name}.See you in ${month},${signed}'
def binding = ["firstname":"Sam", "lastname":"Pullara", "city":["name":"San Francisco", "id":"28"], "month":"December", "signed":"Groovy-Dev"]
def engine = new SimpleTemplateEngine()
template = engine.createTemplate(text).make(binding)
I'm new to this python/biopyhton stuff, so am struggling to work out why the following code, pretty much lifted straight out of the Biopython Cookbook, isn't doing what I'd expect.
I'd have thought it'd end up with the interpreter display two list containing the same number, but all i get is one list and then a message saying TypeError: 'generator' object is not subscriptable.
I'm guessing something is going wrong with the Medline.parse step and the result of the efetch isn't being processed in a way that allows subsequent interation to extract the PMID values. Or, the efetch isn't returning anything.
Any pointers at to what I'm doing wrong?
Thanks
from Bio import Medline
from Bio import Entrez
Entrez.email = 'A.N.Other#example.com'
handle = Entrez.esearch(db="pubmed", term="biopython")
record = Entrez.read(handle)
print(record['IdList'])
items = record['IdList']
handle2 = Entrez.efetch(db="pubmed", id=items, rettype="medline", retmode="text")
records = Medline.parse(handle2)
for r in records:
print(records['PMID'])
You're trying to print records['PMID'] which is a generator. I think you meant to do print(r['PMID']) which will print the 'PMID' entry in the current record dictionary object for each iteration. This is confirmed by the example given in the Bio.Medline.parse() documentation.
My question is just an extension of this thread [Question]http://stackoverflow.com/questions/851636/default-filter-in-django-admin .
from myproject.myapp.mymodels import fieldC
class Poll(models.Model):
fieldA = models.CharField(max_length=80, choices=CHOICES.MyCHOICES)
fieldB = models.ForeignKey(fieldC)
admin.py
list_display = ('fieldB__fieldc1')
Now my list filter shows four criteria All, A ,B ,C .
What I want is if the superuser is logged in ,the filter should show all four criteria All,A,B,C and if the user is other than superuser filter should only show All, A, B.
How can i acheive this ?
Here is my actual piece of admin.py
def changelist_view(self, request, extra_context=None):
referer = request.META.get('HTTP_REFERER', '')
test = referer.split(request.META['PATH_INFO'])
if test[-1] and not test[-1].startswith('?'):
if not request.GET.has_key('patient__patient_type__exact'):
q = request.GET.copy()
q['patient__patient_type__exact'] = 'Real'
request.GET = q
request.META['QUERY_STRING'] = request.GET.urlencode()
if not request.user.is_superuser:
q['patient__patient_type__exact'] = 'Real'
return super(VisitAdmin, self).changelist_view(request, extra_context)
Thanks in advance
I think the new FilterSpec API in Django 1.4 gives you exactly what you need here. Check out the docs on list_filter. In 1.4 you can now make custom list filters that subclass django.contrib.admin.SimpleListFilter and give you the power to write custom lookup and queryset code, and since the request is passed in you can do a simple conditional with is_superuser.
if request.user.is_superuser:
# pass one set of lookups
else:
# pass a different set
read the example code in the docs carefully and I think it will all be clear.