swift switch statement cases have different and shared things to do - ios

Question

i have code like this
switch thing {
case thisThing:
do thing #1
do thing #2
case thatThing:
do thing #2
do thing #3
case anotherThing:
do thing #4
default:
default
}
So, EVERY case has something that ONLY IT does. Some cases also do the same things as one or more other cases.
Is there a way to accomplish this if I don't want any repetitive code?
OR, is there a much more efficient way of doing this without switch statements at all?? I mean, I could, for example, use if statements, but like switch statements, I can't think of a way to accomplish what I want without using repetitive code.
also, this example might be more clear than the above
myFavoriteNumbers = []
myLeastFavoriteNumbers = []
switch myNumber {
case 1:
print("my number is number 1") // do this only for case 1
myFavoriteNumbers += [1] // do this for case 1 and case 2
case 2:
print("this is number 2") // do this only for case 2
myFavoriteNumbers += [2] // do this for case 1 and case 2
case 3:
print("I don't like number 3") // do this only for case 3
myLeastFavoriteNumbers += [3] // do this for case 3 and case 4
case 4:
print("Number Four") // do this only for case 4
myLeastFavoriteNumbers += [4] // do this for case 3 and case 4
default:
print("Default")
}

Answer 1

You can use an initial separate pattern matching statement (comparable to a single case independent from the switch statement) that covers the actions that are unique for any (valid) number, and let the switch statement follow with cases that handle actions that are common for several numbers. With this you separate the unique and common logic action, where the latter is simply implemented as usual cases for any pattern matching switch implementation.
E.g., for your example
var myFavoriteNumbers: [Int] = []
var myLeastFavoriteNumbers: [Int] = []
let myNumberDescriptions = ["my number is number 1",
"this is number 2", "I don't like number 3", "Number Four"]
let myNumber = 1
/* unique action:
perform a unique action (given a valid number)
and thereafter proceed to common cases */
if 1...myNumberDescriptions.count ~= myNumber {
print(myNumberDescriptions[myNumber-1])
}
/* common cases */
switch myNumber {
/* common case: is a favourite number */
case 1...2: myFavoriteNumbers += [myNumber]
/* common case: is a least favourite number */
case 3...4: myLeastFavoriteNumbers += [myNumber]
default:
print("Default")
}
In case the action that is unique to any number is more complex, use the same approach as above, but use more advanced logic (e.g. an event handler) for the unique action "case".

Answer 2

You could nest switch statements that switch on the same value, like this:
switch myNumber {
case 1...2:
myFavoriteNumbers += [myNumber] // do this for case 1 and case 2
switch myNumber {
case 1:
print("my number is number 1") // do this only for case 1
default:
print("this is number 2") // do this only for case 2
}
case 3...4:
myLeastFavoriteNumbers += [myNumber] // do this for case 3 and case 4
switch myNumber {
case 3:
print("I don't like number 3") // do this only for case 3
default:
print("Number Four") // do this only for case 4
}
default:
print("Default")
}
Not the most elegant bit of code you'll ever see, but it achieves what you want to achieve without the repetition.

Answer 3

Fallthrough comes to mind as an obvious solution, but as somebody here already said it does not work in a way that would be helpful.
I don't have any silver bullet for you but I think I would go about this in such a way:
create one switch statement which only covers separate logic
create a second switch statement which combines common logic
switch thing {
case thisThing:
do thing #1
case thatThing:
do thing #4
case anotherThing:
do thing #5
default: ()
}
switch thing {
case thisThing, thatThing:
do thing #2
default: ()
}
It would work when your logic does not depend on the order of function calls (which it should not, if it does it may be a sign to improve your code design). To me it looks clean, however it's still not ideal..