Control multiple tableviews in a single view - ios

Question

I have a table view nested in a collection view and i'm returning 3 (possibly more in the future) collection view cells and I was wondering if it is possible to present different content in each one of the collection cells? I attached a few screenshots to better understand what I am taking about. Thanks.
func numberOfSectionsInTableView(tableView: UITableView) -> Int {
// #warning Incomplete implementation, return the number of sections
return 3
}
func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
// #warning Incomplete implementation, return the number of rows
return 1
}
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCellWithIdentifier("cell", forIndexPath: indexPath) as! UITableViewCell
// Configure the cell...
cell.textLabel?.text = "Homeroom"
cell.detailTextLabel?.text = "8:15 AM - 9:00 AM"
cell.selectionStyle = .None
return cell
}

Answer 1

Yes you can. You need set a property for every tableView you have and in delegate method compare it like below
class Some: UIViewController {
var firstTableView: UITableView
var secondTableView: UITableView
override func viewDidLoad() {
firstTableView = YOUR_FIRST
secondTableView = YOUR_Second
}
func numberOfSectionsInTableView(tableView: UITableView) -> Int {
if tableView == firstTableView {
return 2;
}
else if tableView == secondTableView {
return 1;
}
return 3
}
func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
// #warning Incomplete implementation, return the number of rows
if tableView == firstTableView {
return 2;
}
else if tableView == secondTableView {
return 1;
}
}
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
var cell = tableView.dequeueReusableCellWithIdentifier("cell", forIndexPath: indexPath) as! UITableViewCell
if tableView == firstTableView {
cell = tableView.dequeueReusableCellWithIdentifier("cellOfFirstTableView", forIndexPath: indexPath) as! UITableViewCell
}
else if tableView == secondTableView {
cell = tableView.dequeueReusableCellWithIdentifier("cellOfSecondTableView", forIndexPath: indexPath) as! UITableViewCell
}
// Configure the cell...
if tableView == firstTableView {
cell.textLabel?.text = "Homeroom"
cell.detailTextLabel?.text = "8:15 AM - 9:00 AM"
cell.selectionStyle = .None
}
else if tableView == secondTableView {
cell.textLabel?.text = "Homeroom"
cell.detailTextLabel?.text = "8:15 AM - 9:00 AM"
cell.selectionStyle = .None
}
return cell
}
}

Answer 2

You can use UITableViewDelegate / UITableViewDataSource methods with if else conditions or some thing similar
eg.
func tableView(tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
if tableView == table1 { // table1 is a global var for the table
} else if tableView == table2 {
}
}
But I think it will be very clear if you use separate controller class for each table so you can easily manage the code.
But this depends on what type of data you have. If data is completely unrelated you can just use 3 different controllers.
Or if you can reuse data and codes among 3 tables then you can decide if you wanna use 3 different controllers or to use i class with above method.
eg.
let table1Controller = Table1Controller(dataList1)
let table2Controller = Table2Controller(dataList2)
let table3Controller = Table3Controller(dataList3)
table1.delegate = table1Controller
table1.dataSource = table1Controller
table2.delegate = table2Controller
table2.dataSource = table2Controller
table3.delegate = table3Controller
table3.dataSource = table3Controller