here's the function:
$('.popoutlink').on('click', function() {
var box = $('#' + $(this).data('box'));
box.siblings().hide();
box.toggle("slide", { direction: "left" }, 500);
box.siblings().hide();
});
the two siblings.hide statements are because I'm in the middle of trying to figure out why I'm left with two slideouts on screen if I click on two buttons in rapid succession.
The html is:
<div class="col-md-2">
<div class="popoutlink" data-box="p1">1</div>
<div class="popoutlink" data-box="p2">2</div>
<div class="popoutlink" data-box="p3">3</div>
<div class="popoutlink" data-box="p4">4</div>
<div class="popoutlink" data-box="p5">5</div>
</div>
<div class="col-md-10 bb" style="height: 400px;">
<div class="popout" id="p1"><h1>panel 1</h1></div>
<div class="popout" id="p2">
<h1>panel 2</h1>
</div>
If I click on two buttons quickly then two windows are left on screen. I would like the siblings to hide before the selected div appears.
I have tried using promise.done():
box.siblings().hide(200).promise().done(function(){
box.toggle("slide", { direction: "left" }, 500);
});
to no effect. Adding box.toggle to hide as a callback:
box.siblings().hide(200, function(){
box.toggle("slide", { direction: "left" }, 500);
});
was very funny but not useful.
How do I get the siblings to go away reliably before I show the selected div no matter how quickly I click the buttons?
You see it here just click on the numbered boxes quickly
Thanks
If I understand your question, this should help:
https://jsfiddle.net/Twisty/3mbh5p0r/
jQuery UI
$(function() {
$('.popoutlink').on('click', function() {
var box = $('#' + $(this).data('box'));
$(".popout").hide();
//box.siblings().hide();
box.toggle("slide", {
direction: "left"
}, 500);
//box.siblings().hide();
});
});
When any of the "links" are clicked, they are all hidden and then only the one whom was clicked is toggled.
Update
A little more testing of .hide() versus .css("display", "none") revealed that changing the CSS was a faster method. This page talks about how it's immediate but I found that it wasn't as fast.
The matched elements will be hidden immediately, with no animation.
This is roughly equivalent to calling .css( "display", "none" ),
except that the value of the display property is saved in jQuery's
data cache so that display can later be restored to its initial value.
If an element has a display value of inline and is hidden then shown,
it will once again be displayed inline.
And:
Note that .hide() is fired immediately and will override the animation
queue if no duration or a duration of 0 is specified.
I did try using the callback, which made it worse. The callback should be triggered when the hide animation is complete, yet it added the element of animating the hide operation. Even when the speed was 0, it was slower.
So I advise this:
$(function() {
$('.popoutlink').on('click', function() {
$(".popout").css("display", "none");
$('#' + $(this).data('box')).show("fast");
});
});
Related
I am using JQuery UI sliders in a mobile survey application. I can correctly capture the slider value if the label is clicked or the handle is moved to the label. My problem is that if the user does not click on a label/move the slider. I want to record the initial value of the slider. Here is the html where the slider goes:
<div class="well-lg">
<b>#Html.DisplayFor(model => model.QuestionsText)</b><div id="mySlideOutput"></div>
<br />
<div id="mySlideOutput"></div> // testing output of slider value
<br />
#*Include ID of EvaluationQuestion in ID of slider*#
<div id="slider-#(Model.ID)"></div>
#Html.Hidden("QR-" + #Model.ID)
</div>
Here is the Jquery code:
<script>
var items = ['Very Exceptional Results', 'Above Standard', 'Standard', 'Results Not Acceptable', 'Less Than Standard', 'N/A'];
#*var sliderDefault = $("#slider-#(Model.ID)"),
initialValue = 1;*#
// commented out code that was used to make sure the value is being populated at certain states
//NOTE: Needs to be changed to populate slider item labels from database.
$("#slider-#(Model.ID)").slider({
value: initialValue,
min: 1,
max: 6,
//step: 1,
slide: function (event, ui) {
$("#QR-#(Model.ID)").val(ui.value);
$('#mySlideOutput').html('ui-value = ' + ui.value);
},
#*stop: function(event, ui) {
$("#QR-#(Model.ID)").val(ui.value);
//alert(ui.value);
},*#
#*start: function(event, ui) {
$("#QR-#(Model.ID)").val(ui.value);
alert(ui.value);
}*#
});
$("#slider-#(Model.ID)").slider("pips", { rest: "label", labels: items });
I would like the initial value to populate the db if the slider is not moved to another option. Any suggestions? I appreciate the help.
$("#slider-#(Model.ID)").slider("value");
This will just return the value of the slider at any time it is called... whether you want to call this function at run time, or just before page unload is up to you.
I have a simple webapp consisting of a main page that contains a grid with 3 columns.
<div data-role="content">
<div class="ui-grid-b" id="main">
</div>
</div>
At runtime this grid is expanded with new rows by clicking a button.
$(document).on('pageinit', '#page-home', function() {
$('button').on('click', function() {
var table = $('#main');
var blocka = $('<div class="ui-block-a">One</div>');
var blockb = $('<div class="ui-block-b">Two</div>');
var blockc = $('<div class="ui-block-c">Three</div>');
blocka.appendTo(table);
blockb.appendTo(table);
blockc.appendTo(table);
});
});
Now I have the problem that if there are more rows added (let's say 10) then the last rows run out of screen.
Is there a simple way to automatically scroll to the last row everytime a new one is created?
I know that I can get the element by calling table.find('.ui-block-a:last') but I don't know how to scroll to the found element.
Thanks in advance!
As suggested in this answer: How to go to a specific element on page?
Add the following after blockc.appendTo(table) in your click handler:
$('html, body').animate({
scrollTop: blocka.offset().top + 'px'
}, 'fast');
Here is fiddle demo: http://jsfiddle.net/ezanker/5ap48/
I have a list like so:
<ol id="page_items">
<li>
<label for="page_body_1">Content Area 1</label>
<textarea name="page_body_1" class="page_content_area" rows="10"></textarea>
</li>
<li>
<label for="page_body_2">Content Area 2</label>
<textarea name="page_body_2" class="page_content_area" rows="10"></textarea>
</li>
</ol>
When the page loads, #page_items turns into a tinyMCE editor. What I want is for the element that defines whether or not the li elements are being sorted to be the <label> but no other child elements of li. So the only element that starts the sort is the label.
Here's my jQuery:
$(document).ready(function(){
$("#page_items").sortable({
activate: function(event, ui) {
var EditorID = ui.item.find('textarea').attr('id');
if ( EditorID ){
tinyMCE.execCommand("mceRemoveControl", false, EditorID);
$('#'+EditorID).hide();
}
},
stop: function(event, ui) {
var EditorID = ui.item.find('textarea').attr('id');
if ( EditorID ){
$('#'+EditorID).show();
tinyMCE.execCommand("mceAddControl", false, EditorID);
delete EditorID;
}
}
});
});
In case anyone is wondering, I'm disabling the tinyMCE because in FireFox, moving an iFrame around the DOM clears it's contents and doesn't allow focus back on it.
Is there a way to cancel the sortable if the element clicked isn't the label?
If anyone has any code clean-up suggestions they are also welcome!
Thanks.
This turned out to be a sortable option that I didn't see before (I looked... oh I looked). The handle option is what I need. This initializes a sortable with the handle option specified.
Simply...
$(document).ready(function(){
$("#page_items").sortable({
handle: 'label'
});
});
I am using Jquery UI tabs, and have it set to toggle the opacity with each slide change. I'm wondering if there's a way to apply the opacity toggle to only a single element within each tab, instead of the entire tab. My understanding of jQuery is pretty basic, so bear with me.
So, If I have something like this:
<div id="tabs">
<ul id="tabs-nav><li></li></ul>
<div id="tab-1">
<img />
<p />
</div>
<div id="tab-2">
<img />
<p />
</div>
...etc
</div>
How could I set it so that only the <img> has an effect applied, and the rest just switches normally?
Here are the basics of the call I have for UI tabs:
var $tabs = $('#slides').tabs({fx: { opacity: 'toggle' } });
$(".ui-tabs-panel").each(function(i){
//stuff to create previous/next links
});
$('.next-tab, .prev-tab').click(function() {
$tabs.tabs('select', $(this).attr("rel"));
return false;
});
UPDATE: So this is what I ended up with based on karim79's suggestions, and it seems to work. I added this after the original code I showed above (and removed {fx: { opacity: 'toggle' } } from my original code):
$( "#slides" ).bind( "tabsselect", function(event, ui) {
$(ui.panel).find("img").fadeOut().fadeIn();
});
I'm going to explain my logic, because like I said, my understanding is basic, so I'd love to know if my rationale is off!
I removed karim79's coniditional statement, because I want this to apply to ALL of the tabs. Am I correct in understanding that an if(ui.index == 2) would only apply to the third tab?
Then, I changed the .css("opacity", 0.6) to .fadeOut().fadeIn() because the .css opacity was only succeeding in making all of the slides semi-transparent, but not fading anything in or out.
Would this be an acceptable way of doing this or is it somehow hackish?
This should do it:
$( ".selector" ).bind( "tabsselect", function(event, ui) {
if(ui.index == 2) { // or whatever index you're interested in
$(ui.panel).find("img").css("opacity", 0.6);
}
});
i want to detect to see if an element was dragged out of container.
for example:
<div id="container">
<img src="xxx.png" />
</div>
if i am drag that img element out of the div. i will remove
the img element, but i do not know how to detect when the img is out of div.
i am use jquery drag and drop library.
There is an easy way to do this.
Set child to draggable
Set parent to droppable
Set a flag which if true on drag stop removes the element
Unset this flag in the parents on drop function
child dragged out of parent == child not dropped into parent
So when you move the child around in the parent nothing happens (removeMe flag is unset) and it moves back to original position.
If you drag the child outside of the parent the removeMe flag isn't unset and the drag stop method removes the child.
javascript
$("#draggable").draggable({
start: function(event, ui) {
// flag to indicate that we want to remove element on drag stop
ui.helper.removeMe = true;
},
stop: function(event, ui) {
// remove draggable if flag is still true
// which means it wasn't unset on drop into parent
// so dragging stopped outside of parent
if (ui.helper.removeMe) {
ui.helper.remove();
}
},
// move back if dropped into a droppable
revert: 'valid'
});
$("#droppable").droppable({
drop: function(event, ui) {
// unset removeMe flag as child is still inside parent
ui.helper.removeMe = false;
}
});
html
<div id="droppable">
<p id="draggable">Drag me!</p>
</div>
thank your provides a solution.
I have found an other solution without need an outer div for this problem.
I am use "distance" option to detect how long mouse has moved, then use
"stop" option to remove element.
$(".droppable").droppable({
drop: function(event, ui) {
var obj = $(ui.draggable).clone();
obj.draggable({
distance: 100,//used to measure how far my mouse moved.
helper: 'clone',
opacity : 0.35,
stop: function(event, ui) {
$(this).remove();//remove this element.
}
}
);//obj.draggable
}//drop
})
you need to add a div outside of your container
<div id="droppableDiv">
<div id="container">
<img src="xxx.png" />
</div>
</div>
and then make it droppable by adding a function similar to:
$("#droppableDiv").droppable ({
drop: function() { alert('dropped'); }
});
instead of the alert('dropped'); part you could add a little bit of code that removes the img element from the container div.
here is a example that does some other thing but makes use of droppable and draggable objects, maybe it can help you understand how it works!
hope this helps
-Fortes