iOS Swift access string in array - ios

Question

I set up an array like this:
let modelArray = [
"Casual": ["health": 17, "weapon": 8, "crafting": 15, "social": 30],
"Soldier": ["health": 25, "weapon": 32, "crafting": 8, "social": 5],
"Doctor": ["health": 35, "weapon": 5, "crafting": 15, "social": 15],
"Dorothy": ["health": 15, "weapon": 15, "crafting": 20, "social": 20],
"Asian": ["health": 13, "weapon": 5, "crafting": 7, "social": 45],
"Police": ["health": 23, "weapon": 22, "crafting": 5, "social": 20]
]
How do I access the String (for example "Casual") value when looping?
for (index, model) in character.modelArray.enumerate()
{
print("\(index) carries: \(model[0]")
}
This gives me Type '(String, Dictionary)' has no subscript members

Answer 1

As Josh points out, your modelArray object is a dictionary of dictionaries. (let modelArray : [String: [String:Int]] is the full type information).
The dictionary within can't be subscripted using an Int, only a String.
Here's a version of your code, which will get some the health stat of each character:
for statDictionary in characters.modelArray {
let health = statDictionary["health"]
print(health)
}
further suggestion
Storing data like this in a dictionary is fine for some purposes, but you may find a cleaner, safer API can be made by creating structs (or classes) for holding this state information.
struct CharacterStats {
let health : Int
let weaponNumber : Int
// etc.
}
Then enumerating would be even simpler and require no loose string keys (which could be mistyped).
for stat in characters {
let health = stat.health
}

Answer 2

Just my point of view.
A dictionary of dictionaries is ugly
Create a model type
struct Model {
let name: String
let health: Int
let weapon: Int
let crafting: Int
let social: Int
}
and then your array
let models = [
Model(name: "Casual", health: 17, weapon: 8, crafting: 15, social: 30),
Model(name: "Soldier", health: 25, weapon: 32, crafting: 8, social: 5),
Model(name: "Doctor", health: 35, weapon: 5, crafting: 15, social: 15),
Model(name: "Dorothy", health: 15, weapon: 15, crafting: 20, social: 20),
Model(name: "Asian", health: 13, weapon: 5, crafting: 7, social: 45),
Model(name: "Police", health: 23, weapon: 22, crafting: 5, social: 20),
]
Looping
Now you can simply
for model in models {
print(model.name)
}
Update: Searching
if let doctor = models.filter({ $0.name == "Doctor" }).first {
print(doctor.health)
}