sql server 2008 r2 pivot - stored-procedures

Would it be possible to provide Example:
Basic: With data and columns predefined
More advanced: With dynamic data and column predefined
Expert usage of: With dynamic data and dynamic columns
Thank you

Basic Examples:
USE AdventureWorks2008R2;
GO
SELECT DaysToManufacture, AVG(StandardCost) AS AverageCost
FROM Production.Product
GROUP BY DaysToManufacture;
More Advanced Examples
-- Pivot table with one row and five columns
SELECT 'AverageCost' AS Cost_Sorted_By_Production_Days,
[0], [1], [2], [3], [4]
FROM
(SELECT DaysToManufacture, StandardCost
FROM Production.Product) AS SourceTable
PIVOT
(
AVG(StandardCost)
FOR DaysToManufacture IN ([0], [1], [2], [3], [4])
) AS PivotTable;
Expert Examples:
USE AdventureWorks2008R2;
GO
SELECT VendorID, [250] AS Emp1, [251] AS Emp2, [256] AS Emp3, [257] AS Emp4, [260] AS Emp5
FROM
(SELECT PurchaseOrderID, EmployeeID, VendorID
FROM Purchasing.PurchaseOrderHeader) p
PIVOT
(
COUNT (PurchaseOrderID)
FOR EmployeeID IN
( [250], [251], [256], [257], [260] )
) AS pvt
ORDER BY pvt.VendorID;
Hope it helps

Related

Google Sheets - GROUP BY and ORDER BY on different column

I got a table in this format
Name Datum
A 01.01.2019
B 17.03.2020
C 18.03.2020
C 01.04.2020
I get this table output from this query:
=QUERY(Anrufe!$1:$1000;"Select A,B where A is not null ORDER BY B ASC label A 'Name', B 'Datum'")
I am trying to change the query, so that it performs a group by. This is what it should look like
Name Datum count
A 01.01.2019 1
B 17.03.2020 1
C 01.04.2020 2
But when i add a group by and add a aggregation function to the select it still throws an error.
=QUERY(Anrufe!$1:$1000;"Select A,B, min(B) where A is not null group by A ORDER BY B ASC label A 'Name', B 'Datum'")
I want the query to choose the youngest Date, that is in the column B. But it seems that the QUERY-Parser forces me to add the column B to the group by. This results in the same problem, that i manually have to count the records with the same names.
Anyone has any idea how to solve that?
Already checked those links:
Google sheets query order by SUM
Google Sheets Query: Possible to Group / Order by without Select?
Google Sheets query - Multiple “where” conditions with “group by” and “order by”
I got this message (CANNOT_GROUP_WITHOUT_AGG) from a simple query
I think you want this:
=QUERY(Anrufe!$1:$1000,"Select A,min(B),count(A) where A is not null group by A ORDER BY min(B) ASC label A 'Name', min(B) 'Datum'")

Find records with ID in array of IDS and keep the order of records matching that of IDs [duplicate]

I have a simple SQL query in PostgreSQL 8.3 that grabs a bunch of comments. I provide a sorted list of values to the IN construct in the WHERE clause:
SELECT * FROM comments WHERE (comments.id IN (1,3,2,4));
This returns comments in an arbitrary order which in my happens to be ids like 1,2,3,4.
I want the resulting rows sorted like the list in the IN construct: (1,3,2,4).
How to achieve that?
You can do it quite easily with (introduced in PostgreSQL 8.2) VALUES (), ().
Syntax will be like this:
select c.*
from comments c
join (
values
(1,1),
(3,2),
(2,3),
(4,4)
) as x (id, ordering) on c.id = x.id
order by x.ordering
In Postgres 9.4 or later, this is simplest and fastest:
SELECT c.*
FROM comments c
JOIN unnest('{1,3,2,4}'::int[]) WITH ORDINALITY t(id, ord) USING (id)
ORDER BY t.ord;
WITH ORDINALITY was introduced with in Postgres 9.4.
No need for a subquery, we can use the set-returning function like a table directly. (A.k.a. "table-function".)
A string literal to hand in the array instead of an ARRAY constructor may be easier to implement with some clients.
For convenience (optionally), copy the column name we are joining to ("id" in the example), so we can join with a short USING clause to only get a single instance of the join column in the result.
Works with any input type. If your key column is of type text, provide something like '{foo,bar,baz}'::text[].
Detailed explanation:
PostgreSQL unnest() with element number
Just because it is so difficult to find and it has to be spread: in mySQL this can be done much simpler, but I don't know if it works in other SQL.
SELECT * FROM `comments`
WHERE `comments`.`id` IN ('12','5','3','17')
ORDER BY FIELD(`comments`.`id`,'12','5','3','17')
With Postgres 9.4 this can be done a bit shorter:
select c.*
from comments c
join (
select *
from unnest(array[43,47,42]) with ordinality
) as x (id, ordering) on c.id = x.id
order by x.ordering;
Or a bit more compact without a derived table:
select c.*
from comments c
join unnest(array[43,47,42]) with ordinality as x (id, ordering)
on c.id = x.id
order by x.ordering
Removing the need to manually assign/maintain a position to each value.
With Postgres 9.6 this can be done using array_position():
with x (id_list) as (
values (array[42,48,43])
)
select c.*
from comments c, x
where id = any (x.id_list)
order by array_position(x.id_list, c.id);
The CTE is used so that the list of values only needs to be specified once. If that is not important this can also be written as:
select c.*
from comments c
where id in (42,48,43)
order by array_position(array[42,48,43], c.id);
I think this way is better :
SELECT * FROM "comments" WHERE ("comments"."id" IN (1,3,2,4))
ORDER BY id=1 DESC, id=3 DESC, id=2 DESC, id=4 DESC
Another way to do it in Postgres would be to use the idx function.
SELECT *
FROM comments
ORDER BY idx(array[1,3,2,4], comments.id)
Don't forget to create the idx function first, as described here: http://wiki.postgresql.org/wiki/Array_Index
In Postgresql:
select *
from comments
where id in (1,3,2,4)
order by position(id::text in '1,3,2,4')
On researching this some more I found this solution:
SELECT * FROM "comments" WHERE ("comments"."id" IN (1,3,2,4))
ORDER BY CASE "comments"."id"
WHEN 1 THEN 1
WHEN 3 THEN 2
WHEN 2 THEN 3
WHEN 4 THEN 4
END
However this seems rather verbose and might have performance issues with large datasets.
Can anyone comment on these issues?
To do this, I think you should probably have an additional "ORDER" table which defines the mapping of IDs to order (effectively doing what your response to your own question said), which you can then use as an additional column on your select which you can then sort on.
In that way, you explicitly describe the ordering you desire in the database, where it should be.
sans SEQUENCE, works only on 8.4:
select * from comments c
join
(
select id, row_number() over() as id_sorter
from (select unnest(ARRAY[1,3,2,4]) as id) as y
) x on x.id = c.id
order by x.id_sorter
SELECT * FROM "comments" JOIN (
SELECT 1 as "id",1 as "order" UNION ALL
SELECT 3,2 UNION ALL SELECT 2,3 UNION ALL SELECT 4,4
) j ON "comments"."id" = j."id" ORDER BY j.ORDER
or if you prefer evil over good:
SELECT * FROM "comments" WHERE ("comments"."id" IN (1,3,2,4))
ORDER BY POSITION(','+"comments"."id"+',' IN ',1,3,2,4,')
And here's another solution that works and uses a constant table (http://www.postgresql.org/docs/8.3/interactive/sql-values.html):
SELECT * FROM comments AS c,
(VALUES (1,1),(3,2),(2,3),(4,4) ) AS t (ord_id,ord)
WHERE (c.id IN (1,3,2,4)) AND (c.id = t.ord_id)
ORDER BY ord
But again I'm not sure that this is performant.
I've got a bunch of answers now. Can I get some voting and comments so I know which is the winner!
Thanks All :-)
create sequence serial start 1;
select * from comments c
join (select unnest(ARRAY[1,3,2,4]) as id, nextval('serial') as id_sorter) x
on x.id = c.id
order by x.id_sorter;
drop sequence serial;
[EDIT]
unnest is not yet built-in in 8.3, but you can create one yourself(the beauty of any*):
create function unnest(anyarray) returns setof anyelement
language sql as
$$
select $1[i] from generate_series(array_lower($1,1),array_upper($1,1)) i;
$$;
that function can work in any type:
select unnest(array['John','Paul','George','Ringo']) as beatle
select unnest(array[1,3,2,4]) as id
Slight improvement over the version that uses a sequence I think:
CREATE OR REPLACE FUNCTION in_sort(anyarray, out id anyelement, out ordinal int)
LANGUAGE SQL AS
$$
SELECT $1[i], i FROM generate_series(array_lower($1,1),array_upper($1,1)) i;
$$;
SELECT
*
FROM
comments c
INNER JOIN (SELECT * FROM in_sort(ARRAY[1,3,2,4])) AS in_sort
USING (id)
ORDER BY in_sort.ordinal;
select * from comments where comments.id in
(select unnest(ids) from bbs where id=19795)
order by array_position((select ids from bbs where id=19795),comments.id)
here, [bbs] is the main table that has a field called ids,
and, ids is the array that store the comments.id .
passed in postgresql 9.6
Lets get a visual impression about what was already said. For example you have a table with some tasks:
SELECT a.id,a.status,a.description FROM minicloud_tasks as a ORDER BY random();
id | status | description
----+------------+------------------
4 | processing | work on postgres
6 | deleted | need some rest
3 | pending | garden party
5 | completed | work on html
And you want to order the list of tasks by its status.
The status is a list of string values:
(processing, pending, completed, deleted)
The trick is to give each status value an interger and order the list numerical:
SELECT a.id,a.status,a.description FROM minicloud_tasks AS a
JOIN (
VALUES ('processing', 1), ('pending', 2), ('completed', 3), ('deleted', 4)
) AS b (status, id) ON (a.status = b.status)
ORDER BY b.id ASC;
Which leads to:
id | status | description
----+------------+------------------
4 | processing | work on postgres
3 | pending | garden party
5 | completed | work on html
6 | deleted | need some rest
Credit #user80168
I agree with all other posters that say "don't do that" or "SQL isn't good at that". If you want to sort by some facet of comments then add another integer column to one of your tables to hold your sort criteria and sort by that value. eg "ORDER BY comments.sort DESC " If you want to sort these in a different order every time then... SQL won't be for you in this case.

Use computed columns in related table in power query on SQLITE via odbc

In power query ( version included with exel 2016, PC ), is it possible to refer to a computed column of a related table?
Say I have an sqlite database as follow
PRAGMA foreign_keys=OFF;
BEGIN TRANSACTION;
CREATE TABLE products (
iddb INTEGER NOT NULL,
px FLOAT,
PRIMARY KEY (iddb)
);
INSERT INTO "products" VALUES(0,0.0);
INSERT INTO "products" VALUES(1,1.1);
INSERT INTO "products" VALUES(2,2.2);
INSERT INTO "products" VALUES(3,3.3);
INSERT INTO "products" VALUES(4,4.4);
CREATE TABLE sales (
iddb INTEGER NOT NULL,
quantity INTEGER,
product_iddb INTEGER,
PRIMARY KEY (iddb),
FOREIGN KEY(product_iddb) REFERENCES products (iddb)
);
INSERT INTO "sales" VALUES(0,0,0);
INSERT INTO "sales" VALUES(1,1,1);
INSERT INTO "sales" VALUES(2,2,2);
INSERT INTO "sales" VALUES(3,3,3);
INSERT INTO "sales" VALUES(4,4,4);
INSERT INTO "sales" VALUES(5,5,0);
INSERT INTO "sales" VALUES(6,6,1);
INSERT INTO "sales" VALUES(7,7,2);
INSERT INTO "sales" VALUES(8,8,3);
INSERT INTO "sales" VALUES(9,9,4);
COMMIT;
basically we have products ( iddb, px ) and sales of those products ( iddb, quantity, product_iddb )
I load this data in power query by:
A. creating an ODBC data source using SQLITE3 driver : testDSN
B. in excel : data / new query , feeding this connection string Provider=MSDASQL.1;Persist Security Info=False;DSN=testDSN;
Now in power query I add a computed column, say px10 = px * 10 to the product table.
In the sales table, I can expand the product table into product.px, but not product.px10 . Shouldn't it be doable? ( in this simplified example I could expand first product.px and then create the px10 column in the sales table, but then any new table needinng px10 from product would require me to repeat the work... )
Any inputs appreciated.
I would add a Merge step from the sales query to connect it to the product query (which will include your calculated column). Then I would expand the Table returned to get your px10 column.
This is instead of expanding the Value column representing the product SQL table, which gets generated using the SQL foreign key.
You will have to come back and add any further columns added to the product query to the expansion list, but at least the column definition is only in one place.
In functional programming you don't modify existing values, only create new values. When you add the new column to product it creates a new table, and doesn't modify the product table that shows up in related tables. Adding a new column over product can't show up in Odbc's tables unless you apply that transformation to all related tables.
What you could do is generalize the "add a computed column" into a function that takes a table or record and adds the extra field. Then just apply that over each table in your database.
Here's an example against Northwind in SQL Server
let
Source = Sql.Database(".", "Northwind_Copy"),
AddAColumn = (data) => if data is table then Table.AddColumn(data, "UnitPrice10x", each [UnitPrice] * 10)
else if data is record then Record.AddField(data, "UnitPrice10x", data[UnitPrice] * 10)
else data,
TransformedSource = Table.TransformColumns(Source, {"Data", (data) => if data is table then Table.TransformColumns(data, {"Products", AddAColumn}, null, MissingField.Ignore) else data}),
OrderDetails = TransformedSource{[Schema="dbo",Item="Order Details"]}[Data],
#"Expanded Products" = Table.ExpandRecordColumn(OrderDetails, "Products", {"UnitPrice", "UnitPrice10x"}, {"Products.UnitPrice", "Products.UnitPrice10x"})
in
#"Expanded Products"

SQL Join based on three keys

Database is Teradata
I have two table which I am trying to join. Following are the table structures. When I join these table I expect to get two rows as output but getting 4 rows.what is reason for this behavior. Join based on three keys should uniquely identify a row but still getting 4 rows as output. Any help is appreciated.
TableA
Weekkey|segment|type|users
201501|1|A|100
201501|1|B|100
TableB
Weekkey|segment|type|revenue
201501|1|A|200
201501|1|B|200
when I join these two table using the following query i get the following result
select a.* ,b.user
from tablea a left join tableb b on a.weekkey=b.weekkey
and a.segment=b.segment
and a.type=b.type
Weekkey|segment|type|revenue|users
201501|1|A|200|100
201501|1|B|200|100
201501|1|A|200|100
201501|1|B|200|100
Using sql server, here is ddl and sample data along with the query you posted. The output you state you are getting doesn't happen here.
create table #tablea
(
Weekkey int
, segment int
, type char(1)
, users int
)
insert #tablea
select 201501, 1, 'A', 100 union all
select 201501, 1, 'B', 100
create table #TableB
(
Weekkey int
, segment int
, type char(1)
, revenue int
)
insert #TableB
select 201501, 1, 'A', 200 union all
select 201501, 1, 'B', 200
select a.*
, b.revenue
from #tablea a
left join #tableb b on a.weekkey = b.weekkey
and a.segment = b.segment
and a.type = b.type
drop table #tablea
drop table #TableB

SQLite select query. Get row with array

I coder for iOS and I use SQLite for my data storage.
For now i have two tables in my database. This is table_1 and table_2 (it's easier for understanding)
About struct:
table_1 contain id field (int type) and some_value field (text type)
table_2 contain id field (int type) and table_1_id field (int type)
My question is next: how to select all row from table_1 via array table_1_id field table_2, and this is must SELECT with ORDER BY. I mean order by array.
For example:
if table_2 -> table_1_id contain value 5, 1, 10, 3, 15, 2
the result of output must be in this order.
For now my query is simple:
SELECT * FROM table_1 WHERE id IN (5, 1, 10, 3, 15, 2)
but the select not return order for this query it return data order by 1, 2, 3, 5, 10, 15.
I think I make relation between my table and make SELECT from table_2 uses ORDER BY, but I don't know how to do this correct.
Thanks in advance!
(Very important for me return this order - 5, 1, 10, 3, 15, 2)
I find some result in stackoverflow
link
This is work for me:
SELECT * FROM "comments" WHERE ("comments"."id" IN (1,3,2,4)) ORDER
BY id=1 DESC, ID=3 DESC, id=2 DESC, ID=4 DESC
This is hard code but I create this query string programmatically in cycle and this work great.

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