Please check the attached image How To count the number of rows in a Web Table with multiple pages In Selenium Web Driver? As per filter, the data displayed in a table with 15 rows on first page among 25 pages with 350 rows. I am not getting the total number of rows. Please help.
//To locate table.
WebElement mytable = driver.findElement(By.xpath(".//*[#id='list']"));
//To locate rows of table.
List<WebElement> rows_table = mytable.findElements(By.tagName("tr"));
//To calculate no of rows In table.
int rows_count = rows_table.size();
rows_count=rows_count-1;
//Loop will execute till the last row of table.
//for (int row=0; row<rows_count; row++)
System.out.println("Number Of Rows = "+rows_count);
}
Related
I have a data set with 900 000 rows. There's a column "event_id". I want to create a table of occurences of event_id.
occured once = 63K
occured twice = 114K
occured thrice = 54k
and so on.
How can I do this in Tableau?
step_1 = drag event_id to rows
step_2 = drag filename.csv(count) to TEXT.
//Sample sheet here
Hi,
I am using formulas to calculate an array N:R. Once calculated, I want to determine the last row of the array with a non-empty cell (the empty cells are not blank).
What I can do so far:
Return the last non-empty cell of a column
=INDEX(FILTER(O:O,O:O<>""), ROWS(FILTER(O:O,O:O<>"")))
or the row of the filter selection (in my case 25 in the filter selection vs 38 in the sheet)
=ROWS(FILTER(O:O,O:O<>""))
What I haven't figured out is how to:
Do this search for the whole array and not just one row at a time
Return the row of the last non-empty cell in the array
Cheers
For a formulaic approach, you can try
=max(filter(row(N2:N), MMULT(N(N2:R<>""), transpose(column(N2:R2)^0))>0))
This custom function will do it. Sometimes scripts are way easier than some of the bizarre formulas that arise (IMHO). It just loops through the data row by row and notes the row number if it finds data ie cell.value() != ""
function findHighestNonEmptyRow(dummyRange){
var sheet = SpreadsheetApp.getActive();
var range = sheet.getRange("N:R");
var valuesRC = range.getValues();
var numRows = range.getNumRows();
var numCols = range.getNumColumns();
var highestNonEmptyRow = 0;
for (var row = 0; row < numRows; row++) {
for (var col = 0; col < numCols; col++) {
if (valuesRC[row][col] != ""){
highestNonEmptyRow = row+1; // +1 to offset loop variable
}
}
}
Logger.log(highestNonEmptyRow);
return highestNonEmptyRow;
}
Log show correct value of 38. You can delete the Logger.log(highestNonEmptyRow); line when you have tested.
I put the formula in W44 in your test sheet....
EDIT: Due to feedback that all was not as expected...
There was a typo in the first script: This line var range =
sheet.getRange("N:D"); should have been var range =
sheet.getRange("N:R");
I found out that Google scripts caches the result of custom
formulas, and just returns the cached value, even if things on the
sheet have changed. This is bizarre behavior, but is intended to
reduce CPU time. The workaround is to pass in a range that is likely
to change, and this causes the function to recalculate. I updated
the formula and the called the function like this:
=findHighestNonEmptyRow(N2:R42)
and hey it all works!
Stick to the formula... however, we both learned a lot from your
question I think, so thanks for that!
I am trying to tidy up a dataset. It contains country names stretched over two lines. For easier analysis, I am trying to have each year correspond to one country.
This is what I am going for. Each cell contains one country.
Is there a function that would transform the above table to the table below?
Thanks!
There's no function I know of to do this, but you could do it with a relatively simple Google App Script (overview and installation instructions). This script will unmerge all merged cells and replace empty cells with the value of the cell immediately above.
function unmergeAndExpand() {
var sheet = SpreadsheetApp.getActiveSheet();
var range = sheet.getDataRange();
// unmerge all of the cells in the sheet
range.breakApart();
var data = range.getValues();
var width = range.getLastColumn();
// walk over your spreadsheet column by column
for(var column = 0; column < width; column++){
var last = "";
// walk down the rows
for(var row = 0; row < data.length; row++){
// if the current cell is empty and
if(last && ! data[row][column]){
sheet.getRange(row+1, column+1).setValue( last );
}
// store the value of the current cell
// so that we can fill the next cell, if it is empty
last = data[row][column];
}
}
}
I am new at this so still trying to figure how everything works.
I have a sheet that collects responses from a Google Form. Based on the answer to one of those questions I would like the row from that sheet to move to a different sheet document all together (not a sheet in the same document).
I have it set on a time based trigger every minute so as new responses come in it would kick them over to the correct document and then delete the row from the original spreadsheet.
I have been able to get part of the way there. I would like for it to take the row, columns A through E, move those to the correct document, find where the next open row is and place the data in columns A through E on the new document.
Where my issue is coming in at the moment is when the row is moved to the new document. I have formulas saved in columns G - Z on the destination page. It is finding the last row with a formula and placing the row after that (which is at the very bottom of the page). I am pretty sure this has to do with using an array? But I may be wrong. Is there a way to just have that look at the destination page column A-E, find the next blank row, and copy A-E from the original file to the new page?
arr = [],
values = sheetOrg.getDataRange().getValues(),
i = values.length;
while (--i) {
if (value1ToWatch.indexOf(values[i][1]) > -1) {
arr.unshift(values[i])
sheetOrg.deleteRow(i + 1)
sheet1in.getRange(sheet1in.getLastRow()+1, 1, arr.length, arr[0].length).setValues(arr);
};
I have multiple If statements each with some changes to the "valueToWatch" and the "Sheet1in" for different values and destination pages. If that information helps at all.
You can find the last cell in a column with data in it like this:
function findLastValueInColumn() {
var column = "A"; // change to whatever column you want to check
var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheets()[0];
var lastDataRow = sheet.getDataRange().getLastRow();
for (var currentRow = lastDataRow; currentRow > 0; currentRow--) {
var cellName = column + currentRow;
var cellval = sheet.getRange( cellName ).getValue();
if (cellval != "") {
Logger.log("Last value in Column " + column + " is in cell " + currentRow);
break;
}
}
}
You can then use this function to figure out where to start your new data.
I am using Kendo Grid and using the methods suggested in this Article by Kendo. I am more interested towards the first approach as I find it faster than the 2nd approach.
The problem is if the number of records 65535, then it throws error
Invalid Row number (65536) outside allowable range (0..65535)
I am not able to find any solution to this. Done lot of research, tried the other method but that seems way too slow for my clients liking.
First you need to check if the row numbers are greater than 65535, if they are then you need to split the data in multiple sheets like so...
//create new workbook
var workbook = new HSSFWorkbook();
//create sheet
var sheet = workbook.CreateSheet();
//declare row number
int numberOfRow = 1;
//add value to sheet name inorder not to receive error that the sheet name already exists
int i = 0;
if(numberOfRow > 65535)
{
sheet = workbook.CreateSheet("(Name of sheet " + ++i + ")");
numberOfRow = 1;
//include your header row here
}