I want to retrieve the nodes and relationships stored in the Neo4j DB.
This could be done easily using two queries:
match (x) return id(x)
match ()-[r]-() return distinct(id(r))
A way to do this using a single query would be as follows:
match (x) optional match (x)-[r]-() return id(x), id(r)
However, this returns pairs such of IDs of x and r, such as: (123, 11), (100, null) and so on.
Is there a way to retrieve all the IDs without retrieving such kind of ordered pairs?
You can just use two collections and a WITH:
MATCH (n) WITH collect(id(n)) as nodeIds
MATCH ()-[r]-() RETURN collect(distinct id(r)) as relIds, nodeIds
Related
In the latest version of Cypher, I can use this query to get all nodes with relationships:
MATCH (n)-[r]-(m) RETURN n,r,m
However, I'm missing nodes without any relationships.
In trying to query the missing nodes, this attempt gives me the error: Variable 'r' not defined
MATCH (n) WHERE NOT (n)-[r]->() RETURN n
And, this attempt shows zero results:
MATCH (n)-[r]->() WHERE r is null RETURN n
I can see the stragglers with:
MATCH (n) RETURN n
But, then I'm missing the relationships.
How do I phrase my query to find all nodes and all relationships without duplicates?
You can try the OPTIONAL MATCH:
MATCH (n)
OPTIONAL MATCH (n)-[r]-(m)
RETURN n, r, m
To find a node's neighbors,I use query sentence as below
MATCH (self:Person {id:"13619240353"})-[r*1..2]-(N) return collect(r)
Then I get the result like this
enter image description here
Here r is a list of relations,thus collect(r) is a list of lists,but I expect to
return a list of relations including all the relations in the collect(r),and without the duplicates.How to write the query?
Since with the variable length of the pattern, the named result is an list, then you need to UNWIND it and use a DISTINCT to remove duplicates:
MATCH (self:Person {id:"13619240353"})-[rs*1..2]-(N)
UNWIND rs AS r
RETURN collect(DISTINCT r)
With Labels A, B, and Z, A and B have their own relationships to Z. With the query
MATCH (a:A)
MATCH (b:B { uuid: {id} })
MATCH (a)-[:rel1]->(z:Z)<-[:rel2]-(b)
WITH a, COLLECT(z) AS matched_z
RETURN DISTINCT a, matched_z
Which returns the nodes of A and all the Nodes Z that have a relationship to A and B
I'm stuck on trying to ALSO return a separate array of the Z Nodes that B has with Z but not with A (i.e. missing_z). I am attempting to do an initial query to return all the relationships between B & Z
results = MATCH (b:B { uuid: {id} })
MATCH (b)-[:rel2]->(z:Z)
RETURN DISTINCT COLLECT(z.uuid) AS z
MATCH (a:A)
MATCH (b:B { uuid: {id} })
MATCH (a)-[:rel1]->(z:Z)<-[:rel2]-(b)
WITH a, COLLECT(z) AS matched_z, z
RETURN DISTINCT a, matched_z, filter(skill IN z.array WHERE NOT z.uuid IN {results}) AS missing_z
The results seem to have nil for missing_z where one would assume it should be populated. Not sure if filter is the correct way to go with a WHERE NOT / IN scenario. Can the above 2 queries be combined into 1?
The hard part here, in my opinion, is that any failed matches will drop everything you have matched so far. But your starting point seems to be "All Z related by B.uuid", So start by collecting that and filtering/copying from there.
Use WITH + aggregation functions to copy+filter columns
Use OPTIONAL MATCH if a failure to match shouldn't drop already collected rows.
If I understand what you are trying to do well enough, This cypher should do the job, and just adjust it as needed (let me know if you need help understanding any part of it/adapting it)
// Match base set
MATCH (z:Z)<-[:rel2]-(b:B { uuid: {id} })
// Collect into single list
WITH COLLECT(z) as zs
// Match all A (ignore relation to Zs)
MATCH (a:A)
// For each a, return a, the sub-list of Zs related to a, and the sub-list of Zs not related to a
RETURN a as a, FILTER(n in zs WHERE (a)-[:rel1]->(n)) as matched, FILTER(n in zs WHERE NOT (a)-[:rel1]->(n)) as unmatched
This query might do what you want:
MATCH (z:Z)<-[:rel2]-(b:B { uuid: {id} })
WITH COLLECT(z) as all_zs
UNWIND all_zs AS z
MATCH (a)-[:rel1]->(z)
WITH all_zs, COLLECT(DISTINCT z) AS matched_zs
RETURN matched_zs, apoc.coll.subtract(all_zs, matched_zs) AS missing_zs;
It first stores in the all_zs variable all the Z nodes that have a rel2 relationship from b. This collection's contents remain unaffected even if the second MATCH clause matches a subset of those Z nodes.
It then stores in matched_zs the distinct all_zs nodes that have a rel1 relationship from any A node.
Finally, it returns:
the matched_zs collection, and
the unique nodes from all_zs that are not also in matched_zs, as missing_zs.
The query uses the convenient APOC function apoc.coll.subtract to generate the latter return value.
So as a complication to this question, I basically want to do
MATCH (n:TEST) OPTIONAL MATCH (n)-[r]->() RETURN DISTINCT n, r
And I want to return n and r as one column with no repeat values. However, running
MATCH (n:TEST) OPTIONAL MATCH (n)-[r]->() UNWIND n+r AS x RETURN DISTINCT x
gives a "Type mismatch: expected List but was Relationship (line 1, column 47)" error. And this query
MATCH (n:TEST) RETURN DISTINCT n UNION MATCH ()-[n]->() RETURN DISTINCT n
Puts nodes and relationships in the same column, but the context from the first match is lost in the second half.
So how can I return all matched nodes and relationships as one minimal list?
UPDATE:
This is the final modified version of the answer query I am using
MATCH (n:TEST)
OPTIONAL MATCH (n)-[r]->()
RETURN n {.*, rels:collect(r {properties:properties(r), id:id(r), type:type(r), startNode:id(startNode(r)), endNode:id(endNode(r))})} as n
There are a couple ways to handle this, depending on if you want to hold these within lists, or within maps, or if you want a map projection of a node to include its relationships.
If you're using Neo4j 3.1 or newer, then map projection is probably the easiest approach. Using this, we can output the properties of a node and include its relationships as a collected property:
MATCH (n:TEST)
OPTIONAL MATCH (n)-[r]->()
RETURN n {.*, rels:collect(r)} as n
Here's what you might do if you wanted each row to be its own pairing of a node and a single one of its relationships as a list:
...
RETURN [n, r] as pair
And as a map:
...
RETURN {node:n, rel:r} as pair
EDIT
As far as returning more data from each relationship, if you check the Code results tab, you'll see that the id, relationship type, and start and end node ids are included, and accessible from your back-end code.
However, if you want to explicitly return this data, then we just need to include it in the query, using another map projection for each relationship:
MATCH (n:TEST)
OPTIONAL MATCH (n)-[r]->()
RETURN n {.*, rels:collect(r {.*, id:id(r), type:type(r), startNode:startNode(r), endNode:endNode(r)})} as n
I have a graph in that contains two types of nodes (objects and pieces) and two types of links (similarTo and contains). Some pieces are made of the pieces.
I would like to extract the path to each piece starting from a set of objects.
MATCH (o:Object)
WITH o
OPTIONAL MATCH path = (p:Piece) <-[:contains*]- (o) -[:similarTo]- (:Object)
RETURN path
The above query only returns part of the pieces. In the returned graph, some objects do not directly connect to any pieces, the latter are not returned, although they actually do!
I can change the query to:
MATCH (o:Object) -[:contains*]-> (p:Piece)
OPTIONAL MATCH (o) –[:similarTo]- (:Object)
However, I did not manage to return the whole path for that query, which I need to return collection of nodes and links with:
WITH rels(path) as relations , nodes(path) as nodes
UNWIND relations as r unwind nodes as n
RETURN {nodes: collect(distinct n), links: collect(distinct {source: id(startNode(r)), target: id(endNode(r))})}
I'd be grateful to any recommendation.
Would something like this do the trick ?
I created a small graph representing objects and pieces here : http://console.neo4j.org/r/abztz4
Execute distinct queries with UNION ALL
Here you'll combine the two use cases in one set of paths :
MATCH (o:Object)
WITH o
OPTIONAL MATCH p=(o)-[:CONTAINS]->(piece)
RETURN p
UNION ALL
MATCH (o:Object)
WITH o
OPTIONAL MATCH p=(o)-[:SIMILAR_TO]-()-[:CONTAINS]->(piece)
RETURN p