NSPredicate for exact match - ios

Question

NSArray *arrData = [NSArray arrayWithObjects:
#"cloud,country,plant",
#"country,cloud,plant",
#"country,plant,cloud",
#"clouds,country,plant"
,#"country,clouds,plant",
nil];
From above NSArray, I want objects which having a word "cloud"
I tried below code
NSPredicate *predicate = [NSPredicate predicateWithFormat:#"(self beginswith %# OR self contains[CD] %#)",#"cloud",#",cloud"];
NSArray *arrResult = [arrData filteredArrayUsingPredicate:predicate];
But it's giving all 5 objects in arrResult. But I need only 3 (0,1,2) objects.

Answer 1

Try:
NSPredicate* predicate = [NSPredicate predicateWithBlock:^(NSString* string, NSDictionary* options){
NSArray* array = [string componentsSeparatedByString:#","];
return [array containsObject:#"cloud"];
}];

Answer 2

Try below code,
It will work,
NSPredicate *hsPredicate = [NSPredicate predicateWithBlock:^BOOL(id _Nonnull evaluatedObject, NSDictionary<NSString *,id> * _Nullable bindings) {
NSArray *sepretArray =[((NSString*)evaluatedObject) componentsSeparatedByString:#","];
NSPredicate *subPredicate = [NSPredicate predicateWithFormat:#"self == %#",#"cloud"];
return ([sepretArray filteredArrayUsingPredicate:subPredicate].count > 0);
}];
NSArray *arrResult = [arrData filteredArrayUsingPredicate:hsPredicate];

Answer 3

This one do the trick.But i don't know whether it is the efficient way of doing this.
NSArray *arrData = [NSArray arrayWithObjects:
#"cloud,country,plant",
#"country,cloud,plant",
#"country,plant,cloud",
#"clouds,country,plant"
,#"country,clouds,plant",
nil];
NSMutableArray *resArray = [[NSMutableArray alloc]init];
for(NSString *tempString in arrData)
{
NSArray *cache = [tempString componentsSeparatedByString:#","];
if([cache containsObject:#"cloud"])
{
[resArray addObject:tempString];
}
}