How to stop a do-while loop in this instance - do-while

Question

Here is the code. I need to be able to stop the loop when ALL 3 of the entered sides are 0, not just 1 or 2. If 1 or 2 of the entered sides are 0 then it should prompt the user again. Is there an operator that will terminate the program when ALL 3 conditions are met?
Thanks in advance!
import java.util.Scanner;
public class Program2
{
public static void main(String[] args)
{
// Read user inputs
#SuppressWarnings("resource")
Scanner key = new Scanner(System.in);
// User inputed sides of triangle
double side1, side2, side3;
// Opening messages
System.out.println("\t\t\t\t\tTriangle Identifier Program");
System.out.print("This program will tell you what type of tringle you have,");
System.out.println("\nif it is a right triangle, and the area of the triangle.");
System.out.println("Use input of 0 0 0 to terminate the program.\n");
do
{
// Get sides
System.out.print("Enter side 1 of the triangle: ");
side1 = key.nextInt();
System.out.print("Enter side 2 of the triangle: ");
side2 = key.nextInt();
System.out.print("Enter side 3 of the triangle: ");
side3 = key.nextInt();
double longest = 0;
double shorter1 = 0;
double shorter2 = 0;
if (side1 == 0 || side2 == 0 || side3 == 0)
System.out.println("These numbers do not satisfy the triangle inequality. Please try again.");
// Find the largest side
if(side1 > side2 && side1 > side3)
{
longest = side1;
shorter1 = side2;
shorter2 = side3;
}
if(side2 > side1 && side2 > side3)
{
longest = side2;
shorter1 = side1;
shorter2 = side3;
}
if(side3 > side2 && side3 > side1)
{
longest = side3;
shorter1 = side1;
shorter2 = side2;
}
if(side1 > 0 && side2 > 0 && side3 > 0)
{
if(side1==side2 && side2==side3 && side3==side1)
System.out.println("The triangle is equilateral");
if((side1==side2 && side2!=side3) || (side2==side3 && side2!=side1) || (side1==side3 && side2 !=side3))
System.out.println("The triangle is isosceles");
if(side1 != side2 && side2 != side3 && side1 != side3)
System.out.println("The triangle is scalene");
if(longest == Math.sqrt((shorter1*shorter1)+(shorter2*shorter2)))
System.out.println("The triangle is a right triangle");
else
System.out.println("The tringle is not a right triangle");
}
} while (side1 != 0 & side2 != 0 & side3 != 0);
}
}

Answer 1

Add another if condition to check whether all 3 are 0.
do
{
// Get sides
System.out.print("Enter side 1 of the triangle: ");
side1 = key.nextInt();
System.out.print("Enter side 2 of the triangle: ");
side2 = key.nextInt();
System.out.print("Enter side 3 of the triangle: ");
side3 = key.nextInt();
double longest = 0;
double shorter1 = 0;
double shorter2 = 0;
if (side1 == 0 && side2 == 0 && side3 == 0){
break;
} else{
if (side1 == 0 || side2 == 0 || side3 == 0)
System.out.println("These numbers do not satisfy the triangle inequality. Please try again.");
// Find the largest side
if(side1 > side2 && side1 > side3)
{
longest = side1;
shorter1 = side2;
shorter2 = side3;
}
if(side2 > side1 && side2 > side3)
{
longest = side2;
shorter1 = side1;
shorter2 = side3;
}
if(side3 > side2 && side3 > side1)
{
longest = side3;
shorter1 = side1;
shorter2 = side2;
}
if(side1 > 0 && side2 > 0 && side3 > 0)
{
if(side1==side2 && side2==side3 && side3==side1)
System.out.println("The triangle is equilateral");
if((side1==side2 && side2!=side3) || (side2==side3 && side2!=side1) || (side1==side3 && side2 !=side3))
System.out.println("The triangle is isosceles");
if(side1 != side2 && side2 != side3 && side1 != side3)
System.out.println("The triangle is scalene");
if(longest == Math.sqrt((shorter1*shorter1)+(shorter2*shorter2)))
System.out.println("The triangle is a right triangle");
else
System.out.println("The tringle is not a right triangle");
}
}
} while (side1 != 0 & side2 != 0 & side3 != 0);