How to send a HTTP POST like this in Swift? - ios

Question

{
"appId":"YOUR_APP_ID",
"appKey":"YOU_APP_KEY",
"queries":{
"item_name":"Kids Fries",
"brand_name":"McDonalds"
}
}
I know how to handle the first two items(appId,appKey) in postString, but I don't know what the format be for "queries", I tried the following, it did not work:
let request = NSMutableURLRequest(URL: url! )
request.HTTPMethod = "POST"
let postString = "appId=myId9&appKey=myKey&queries={item_name=burger&brand_name=McDonalds}"
request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding)

Answer 1

What Content-Type does the server expect?
You are showing application/json in the first part, but application/x-www-form-urlencoded in the second part.
If you need application/json, then
let request = NSMutableURLRequest(URL: url!)
request.HTTPMethod = "POST"
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
let postString = "{\"appId\":\"myId\", \"appKey\":\"myKey\", \"queries\":{\"item_name\":\"Kids Fries\", \"brand_name\":\"McDonalds\"}}"
request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding)
If you really need application/x-www-form-urlencoded, then some guessing is involved. Why not try using the dot-syntax.
let request = NSMutableURLRequest(URL: url!)
request.HTTPMethod = "POST"
request.addValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
let postString = "appId=myId&appKey=myKey&queries.item_name=burger&queries.brand_name=McDonalds"
request.HTTPBody = postString.dataUsingEncoding(NSUTF8StringEncoding)

Answer 2

Have you tried Alamofire. Its really easy to do this in that.
All you have to do is do something like the following and it post;
let myParams = [
"key1": value1 ,
"key2": value2,
"key3": value3,
"Key4": value4
]
Alamofire.request(.POST, posturl, parameters: myParams, encoding: .JSON)
.authenticate(user: self.postUser, password: self.postPass)
.validate(statusCode: 200..<300)
.responseString { response in
print("Response String: \(response.result.value)")
if response.result.value != nil{
let rJ = response.result.value!
print("Response: " + rJ)
}else
{
print("Fail")
}
}
Hopes this helps. And Alamofire makes get request easier too.

Answer 3

You can also try this code with Alamofire
let parameters = [“Username”:”name”]
let headers = ["Content-Type":"application/json"]
Alamofire.request(.POST, “your URL here”, parameters: parameters, encoding: .JSON, headers: headers)
.responseJSON { response in
print("Response JSON: \(response.result.value)")
//--------------------
switch response.result {
case .Success:
self.successGetData(response.result.value!)
case .Failure(let error):
self.failedGetData()
print(error)
}
}