i have string value
NSString *str = #"12:15"
now how to convert it in to integer value??
i tryNSInteger i =[str integerValue];
but it's return only 12 and i want 1215.
Please suggest.
Thank you
A more generic approach would be to replace everything but the numeric values with an empty string like below:
NSString *str = #"12: a15xx";
str = [str stringByReplacingOccurrencesOfString:#"[^0-9]"
withString:#""
options:NSRegularExpressionSearch
range:NSMakeRange(0, str.length)];
NSLog(#"%d", str.integerValue); // prints 1215
a simple answer would be
NSString *str=#"12:15";
str = [str stringByReplacingOccurrencesOfString:#":" withString:#""];
NSInteger i =[str integerValue];
NSArray* arr = [#"12:15" componentsSeparatedByString: #":"];
NSString* strValue = [NSString stringWithFormat:#"%#%#",[arr objectAtIndex:0],[arr objectAtIndex:1]];
int value=(int)strValue;
Related
I need to split NSString to array by specific word.
I've tried to use [componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:#" "]]
But the split is performed by a single character, and I need a few chars.
Example:
NSString #"Hello great world";
Split key == #" great ";
result:
array[0] == #"Hello";
array[1] == #"world";
Try
NSString *str = #"Hello great world";
//you can use the bellow line to remove space
//str = [str stringByReplacingOccurrencesOfString:#" " withString:#""];
// split key = #"great"
NSArray *arr = [str componentsSeparatedByString:#"great"];
Code:
NSString *string = #"Hello great world";
NSArray *stringArray = [string componentsSeparatedByString: #" great "];
NSLog(#"Array 0: %#" [stringArray objectAtIndex:0]);
NSLog(#"Array 1: %#" [stringArray objectAtIndex:1]);
The easiest way is the following:
NSString *string = #"Hello Great World";
NSArray *stringArray = [string componentsSeparatedByString: #" "];
This can help you.
I have a requirement where in first letter of all words in a sentence need to be capitalised. I achieved this through the below code
myString = [myString capitalizedString];
But there is an issue with this.. if the word starts with a numeric for eg "32abc", after capitalisation it changes to "32Abc". I need it to be "32abc".
Help would be appreciated.
Method 1
NSString *input = #"32abc";
/* get first char */
NSString *firstChar = [input substringToIndex:1];
/* remove any diacritic mark */
NSString *folded = [firstChar stringByFoldingWithOptions:NSDiacriticInsensitiveSearch locale:[NSLocale currentLocale]];
/* create the new string */
NSString *capitalisedSentence = [[folded uppercaseString] stringByAppendingString:[input substringFromIndex:1]];
Method 2 (Optimized)
NSString *input = #"32abc";
NSString *capitalisedSentence = [input stringByReplacingCharactersInRange:NSMakeRange(0,1)
withString:[[input substringToIndex:1] capitalizedString]];
Try this:
myString = [myString stringByReplacingCharactersInRange:NSMakeRange(0,1) withString:[[myString substringToIndex:1] uppercaseString]];
I have a number which will be represented as string. It is longer than 4 chars. I need to create new string from 5th till the end for that number.
For example if I have 56789623, I need to have 9623 as a result (5678 | 9623).
How to do that?
P.S. I suppose that this is very simple question, but I don't know how properly ask Google about that.
NSString *str = #"56789623";
NSString *first, *second;
if ([str length] > 4) {
first = [str substringWithRange:NSMakeRange(0, 4)];
second = [str substringWithRange:NSMakeRange(4, [str length] - 4)];
} else {
first = str;
second = nil;
}
Use this Simple functions
- (NSString *)substringFromIndex:(NSUInteger)from;
- (NSString *)substringToIndex:(NSUInteger)to;
- (NSString *)substringWithRange:(NSRange)range;
You can use:
- (NSString *)substringFromIndex:(NSUInteger)anIndex
NSString *number = #"56789623";
NSString *result = [number substringFromIndex:4];
NSLog(#"%#", result);
result contains the string: #"9623"
The keywords you were looking for are: substring and range. There are several ways to use them. Example code split string into 2 equal (if number of characters is even almost equal) substrings:
NSString *str = #"56789623";
NSInteger middleIndex = (NSInteger)(str.length/2);
NSString *strFirstPart = [str substringToIndex:middleIndex];
NSString *strSecondPart = [str substringFromIndex:middleIndex];
NSString *strFirstPart2 = [str substringWithRange:NSMakeRange(0, middleIndex)];
NSString *strSecondPart2 = [str substringWithRange:NSMakeRange(middleIndex, [str length]-middleIndex)];
This question already has answers here:
Comma-separated string to NSArray in Objective-C
(2 answers)
Closed 8 years ago.
I have a string like
NSString* str = #"[90, 5, 6]";
I need to convert it to an array like
NSArray * numbers = [90, 5 , 6];
I did a quite long way like this:
+ (NSArray*) stringToArray:(NSString*)str
{
NSString *sep = #"[,";
NSCharacterSet *set = [NSCharacterSet characterSetWithCharactersInString:sep];
NSArray *temp=[str componentsSeparatedByCharactersInSet:set];
NSMutableArray* numbers = [[NSMutableArray alloc] init];
for (NSString* s in temp) {
NSNumber *n = [NSNumber numberWithInteger:[s integerValue]];
[numbers addObject:n];
}
return numbers;
}
Is there any neat and quick way to do such conversion?
Thanks
First remove the unwanted characters from the string, like white spaces and braces:
NSString* str = #"[90, 5, 6]";
NSCharacterSet* characterSet = [[NSCharacterSet
characterSetWithCharactersInString:#"0123456789,"] invertedSet];
NSString* newString = [[str componentsSeparatedByCharactersInSet:characterSet]
componentsJoinedByString:#""];
You will have a string like this: 90,5,6. Then simply split using the comma and convert to NSNumber:
NSArray* arrayOfStrings = [newString componentsSeparatedByString:#","];
NSMutableArray* arrayOfNumbers = [NSMutableArray arrayWithCapacity:arrayOfStrings.count];
for (NSString* string in arrayOfStrings) {
[arrayOfNumbers addObject:[NSDecimalNumber decimalNumberWithString:string]];
}
Using the NSString category from this response it can be simplified to:
NSArray* arrayOfStrings = [newString componentsSeparatedByString:#","];
NSArray* arrayOfNumbers = [arrayOfStrings valueForKey: #"decimalNumberValue"];
NSString* str = #"[90, 5, 6]";
NSCharacterSet *characterSet = [NSCharacterSet characterSetWithCharactersInString:#"[] "];
NSArray *array = [[[str componentsSeparatedByCharactersInSet:characterSet]
componentsJoinedByString:#""]
componentsSeparatedByString:#","];
Try like this
NSArray *arr = [string componentsSeparatedByString:#","];
NSString *newSTR = [str stringByReplacingOccurrencesOfString:#"[" withString:#""];
newSTR = [newSTR stringByReplacingOccurrencesOfString:#"]" withString:#""];
NSArray *items = [newSTR componentsSeparatedByString:#","];
You can achieve that using regular expression　
([0-9]+)
NSError* error = nil;
NSString* str = #"[90, 5, 6]";
NSRegularExpression* regex = [NSRegularExpression regularExpressionWithPattern:#"([0-9]+)" options:0 error:&error];
NSArray* matches = [regex matchesInString:str options:0 range:NSMakeRange(0, [str length])];
Then you have a NSArray of string, you just need to iterate it and convert the strings to number and insert them into an array.
I have a long string of some characters. I want to replace some chars with other chars.
For example
string1="Hello WORLD12";
string2="world";
string1= search string2 in string1 and replace it;
//need this method in objective c
string1="Hello world12";
If by case insensitive you mean the lower case replacement, Ken Pespisa has your answer, but if case insensitivity is about your search string you can do this:
[mystring stringByReplacingOccurrencesOfString:#"searchString" withString:#"replaceString" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [mystring length])];
for more info see documentation of:
- (NSString *)stringByReplacingOccurrencesOfString:(NSString *)target withString:(NSString *)replacement options:(NSStringCompareOptions)options range:(NSRange)searchRange;
NSString *myString = #"select name SELECT college Select row";
[myString stringByReplacingOccurrencesOfString:#"select" withString:#"update" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [myString length])];
output: #"update name update college update row";
You can call the NSString method stringByReplacingOccurrencesOfString:withString:
NSString *string1 = "Hello WORLD12";
NSString *string2 = "world";
NSString *string3 = [string1 stringByReplacingOccurrencesOfString:#"WORLD" withString:string2];
Use NSRange to grab the replacing string and then usestringByReplacingOccurrencesOfString function to replace the characters in string.
NSString *string1 = "Hello WORLD12";
NSString *string2 = "world";
NSRange *range = [string1 rangeOfString:string2];
if (range.length > 0){
NSString *newString = [string1 substringFromIndex:range.location+6];
[string1 stringByReplacingOccurrencesOfString:newString withString:string2];
}