StarScream websocketDidReceivePong is not getting called for writePing - ios

I would like to send periodic pings to server to keep the connection alive.
This is the function to send ping
socket.writePing(NSData())
But I am not getting the pong back
func websocketDidReceivePong(socket: WebSocket){
wsConsole.text = wsConsole.text .stringByAppendingString("\n websocket received pong")
}
the above delegate will get fired when server sends back the pong.
FYI:
I am able to successfully establish web socket connect send message and close connection and I have implemented and I have given socket.delegate=self
WebSocketPongDelegate
Here is the web socket url that I am using for testing purposes
ws://echo.websocket.org/
I am wondering why I am not getting the pong back from web socket server.

Is your socket a property of your class to make sure it sticks around? If you allocate it just on a function stack it will fall out of scope and the delegates will never get called. Also the pongDelegate is separate from the regular delegate, so you need to set that to self as well:
socket.pongDelegate = self

Related

How does the connection manager discard unconsumed connection?

I am trying to debug a connection leak issue in my app where the connection manager is using more connections than I would have wanted. One lead I have is the following:
According to Apache HttpClient quick start, if response content is not fully consumed for any reason, the pooling connection manager can not safely reuse the underlying connection and will discard it.
Can anyone point me to the code block that does the checking of unconsumed content in a connection and the discarding of the connection?
// Please note that if response content is not fully consumed the underlying
// connection cannot be safely re-used and will be shut down and discarded
// by the connection manager.
try (CloseableHttpResponse response1 = httpclient.execute(httpGet)) {
System.out.println(response1.getCode() + " " + response1.getReasonPhrase());
HttpEntity entity1 = response1.getEntity();
// do something useful with the response body
// and ensure it is fully consumed
EntityUtils.consume(entity1);
}
HttpClient version 4.x and 5.x wrap HTTP response entity with a proxy that releases the underlying connection back to the pool upon reaching the end of the message stream. In all other cases HttpClient assumes the message has not been fully consumed and the underlying connection cannot be re-used.
https://github.com/apache/httpcomponents-client/blob/master/httpclient5/src/main/java/org/apache/hc/client5/http/impl/classic/ResponseEntityProxy.java

How to get the remote host from a rsocket

I now receive an rsocket connection in my spring project, and then I want to get its remote address and port, how should I get it?Similar to using socket.getRemoteSocketAddress() to get the remote address of the socket.
#ConnectMapping
public void connectMapping(RSocketRequester requester) {
// there is a resockt connect, how can i get the remote host from it
RSocket rSocket = requester.rsocket();
// TODO
logger.info("host port");
}
Unfortunately, I think even if you grab the RSocketRequester in #ConnectMapping or #MessageMapping method it is an internal detail. io.rsocket.core.RSocketRequester via RequesterResponderSupport holds the DuplexConnection which represents a connection over tcp, web socket or in-process. It is not exposed via a public API.
This is a worthy request but you will need to file a feature request to get this added unless I'm missing something obvious.
It isn't clear that there is a hook in https://docs.spring.io/spring-boot/docs/2.3.0.RELEASE/api/org/springframework/boot/rsocket/server/RSocketServerCustomizer.html to let you see the DuplexConnection (tcp or web socket etc) as it's established.

Mirth Connect HTTP Listener Mapping Response ACK message

We are trying to merge two Mirth servers. One server (let's call it Server 1) is keeping all records and another server (Server 2) is getting HL7 message from the first one and writes messages to the database.
Everything was perfect so far. But Server 1, after sending each HL7 message, waits for ACK to consider this transaction as completed and to send another message from the list.
The success status coming from the Server 2 (which writes to the database) contains MySQL response such as "Success: Database write success. 1 rows updated.". This is not what Server 1 is expecting.
Therefore, the Server 1 considers this ACK as invalid, produces an error "Message Read Error - Will Retry" and keeps trying to send the same message again, causing Server 2 to duplicate messages in the database.
We are using Mirth Connect HTTP listener and we could not find any solution to send ACK msg to our first server the same screen HTTP listener.
Is there any way to do this? Any Suggestion?
Really need help.
The problem is you are not setting the response from server 2 correctly, so it just returns what the destination has. You can create an ACK by code on the destination transformer:
var ackMessage = ACKGenerator.generateAckResponse(connectorMessage.getRawData(), "AA", "Message Successfully Received");
responseMap.put("ackresp", ResponseFactory.getSentResponse(ackMessage));
And on your source connector select "ackresp" as response. Your server 1 will receive that ACK instead of the log of the database write.

receive TCP/IP data on a rails application

I have a custom device with a TCP/IP stack implemented that's sending a byte each 5 seconds to a remote IP.
On that remote IP, I'm building a site with rails 3.1.3 that will have to receive, store and display the data sent by the custom device.
I was thinking on having a TCP Socket running in the background, something like this, but i don't have a clue on how to integrate this with a rails site. Where to place it, how to start it and how to propagate the data to the views.
Does anybody have a clue on how shall I proceed?
To solve this I created a raketask that starts a TCP Server that will handle messages.
Note: This code has more than a year so I'm not 100% sure how it behaves, but I think the core part is this:
#server = TCPServer.new(#host, port)
loop do
Thread.start(#server.accept) do |tcpSocket|
port, ip = Socket.unpack_sockaddr_in(tcpSocket.getpeername)
begin
loop do
line = tcpSocket.recv(100).strip # Read lines from the socket
handle_message line # method to handle messages from the socket
end
rescue SystemCallError
#close the sockets logic
end
end
end

How to check server connection

i want to check my server connection to know if its available or not to inform the user..
so how to send a pkg or msg to the server (it's not SQL server; it's a server contains some serviecs) ...
thnx in adcvance ..
With all the possibilities for firewalls blocking ICMP packets or specific ports, the only way to guarantee that a service is running is to do something that uses that service.
For instance, if it were a JDBC server, you could execute a non-destructive SQL query, such as select * from sysibm.sysdummy1 for DB2. If it's a HTTP server, you could create a GET packet for index.htm.
If you actually have control over the service, it's a simple matter to create a special sub-service to handle these requests (such as you send through a CHECK packet and get back an OKAY response).
That way, you avoid all the possible firewall issues and the test is a true end-to-end one. PINGs and traceroutes will be able to tell if you can get to the machine (firewalls permitting) but they won't tell you if your service is functioning.
Take this from someone who's had to battle the network gods in a corporate environment where machines are locked up as tight as the proverbial fishes ...
If you can open a port but don't want to use ping (i dont know why but hey) you could use something like this:
import socket
host = ''
port = 55555
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
s.bind((host, port))
s.listen(1)
while 1:
try:
clientsock, clientaddr = s.accept()
clientsock.sendall('alive')
clientsock.close()
except:
pass
which is nothing more then a simple python socket server listening on 55555 and returning alive

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